php-general Digest 6 Nov 2009 07:26:50 -0000 Issue 6429
php-general Digest 6 Nov 2009 07:26:50 - Issue 6429
Topics (messages 299649 through 299674):
How do I get reliable COMPUTERNAME?
299649 by: Andrew Ballard
299658 by: Jim Lucas
299662 by: Andrew Ballard
Re: Plotting a Line Graph
299650 by: cool.hosting4days.com
Re: Creating a Dynamic PHP/CSS Page (newbie design question)
299651 by: Ashley Sheridan
299652 by: Shawn McKenzie
299653 by: Shawn McKenzie
299654 by: Andrew Ballard
299656 by: tedd
299660 by: cool.hosting4days.com
299663 by: Shawn McKenzie
299664 by: Ashley Sheridan
299667 by: tedd
Re: Should I care about these errors?
299655 by: tedd
299657 by: Robert Cummings
Re: Imagick question
299659 by: Ashley M. Kirchner
299661 by: Ashley Sheridan
299665 by: Ashley M. Kirchner
Re: Custom function for inserting values into MySQL
299666 by: Daevid Vincent
Re: Free tech talk by Percona tonight in Palo Alto, CA
299668 by: Michael Shadle
299670 by: Sam Ghods
question about smarty
299669 by: Sudhakar
299674 by: Fernando Castillo Aparicio
Function Not Working...Little help
299671 by: Don Wieland
Re: Why getcwd() returs different results?
299672 by: Raymond Irving
Preview button to show PDF without submitting post data?
299673 by: Dave M G
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--
---BeginMessage---
I want to store the name of the computer that is executing a script in
some log tables. (Our servers are load balanced, and I'd like to be
able to determine which physical machine is serving each request.)
On my development machine (Windows PC running the debugger in Zend
Studio), I can find the name in three places:
getenv('COMPUTERNAME')
$_ENV['COMPUTERNAME']
$_SERVER['COMPUTERNAME']
On the development server, only the first works; $_ENV and $_SERVER
both return NULL and throw an undefined index notice.
I'm concerned about the reliability of all of these methods, since it
seems that they are not always available and all three can be easily
overridden inside a script. However, I notice that the header
generated by phpinfo() remains correct even when I manually spoofed
all three values on my development machine. Is there a reliable way to
find this value?
Andrew
---End Message---
---BeginMessage---
Andrew Ballard wrote:
I want to store the name of the computer that is executing a script in
some log tables. (Our servers are load balanced, and I'd like to be
able to determine which physical machine is serving each request.)
On my development machine (Windows PC running the debugger in Zend
Studio), I can find the name in three places:
getenv('COMPUTERNAME')
$_ENV['COMPUTERNAME']
$_SERVER['COMPUTERNAME']
On the development server, only the first works; $_ENV and $_SERVER
both return NULL and throw an undefined index notice.
I'm concerned about the reliability of all of these methods, since it
seems that they are not always available and all three can be easily
overridden inside a script. However, I notice that the header
generated by phpinfo() remains correct even when I manually spoofed
all three values on my development machine. Is there a reliable way to
find this value?
Andrew
Well, I looked at all the variables that are available. Then I looked at the
data in the output of phpinfo().
The only place that I can find the information that you are looking for is
available in the PHP Configuration section and it is in the System
information.
So, looking at the phpinfo() page, I noticed the first comment down had a
method/function for converting the output of phpinfo() into a multidimensional
array. Taking the output of that users function, you can access the data the
data you are looking for.
So, here is a link to the phpinfo() page.
http://php.net/phpinfo
From there, get the function called phpinfo_array()
take the output of that and run it through the following set of commands.
$data = phpinfo_array(TRUE);
list(, $server_name) = explode(' ', $data['PHP Configuration']['System']);
print( $server_name );
This will give you what you are looking for.
Jim
---End Message---
---BeginMessage---
On Thu, Nov 5, 2009 at 2:03 PM, Jim Lucas li...@cmsws.com wrote:
Andrew Ballard wrote:
I want to store the name of the computer that is executing a script in
some log tables. (Our servers are load balanced, and I'd like to be
able to determine which physical machine is serving each request.)
On my development machine (Windows PC running the debugger in Zend
Studio), I can find the name in three places:
getenv('COMPUTERNAME')
Re: [PHP] Imagick question
Brady Mitchell wrote: I'm sure it can be done, but without seeing your code we can't really help. Easily solved. From the PHP manual (http://www.php.net/manual/en/function.imagick-roundcorners.php): ?php $image = new Imagick(); $image-newPseudoImage(100, 100, magick:rose); $image-setImageFormat(png); $image-roundCorners(5,3); $image-writeImage(rounded.png); ? That produces a nice transparent cornered image, as it should. However, try saving it as a JEPG instead. Set the image format to 'jpeg' and write it out as 'rounded.jpg' and you'll notice the corners are now black. I know JPEG doesn't support transparency, that's fine. What I want is to change the black to white instead. -- A -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How do I get reliable COMPUTERNAME?
Andrew Ballard wrote:
I want to store the name of the computer that is executing a script in
some log tables. (Our servers are load balanced, and I'd like to be
able to determine which physical machine is serving each request.)
On my development machine (Windows PC running the debugger in Zend
Studio), I can find the name in three places:
getenv('COMPUTERNAME')
$_ENV['COMPUTERNAME']
$_SERVER['COMPUTERNAME']
On the development server, only the first works; $_ENV and $_SERVER
both return NULL and throw an undefined index notice.
I'm concerned about the reliability of all of these methods, since it
seems that they are not always available and all three can be easily
overridden inside a script. However, I notice that the header
generated by phpinfo() remains correct even when I manually spoofed
all three values on my development machine. Is there a reliable way to
find this value?
Andrew
Well, I looked at all the variables that are available. Then I looked at the
data in the output of phpinfo().
The only place that I can find the information that you are looking for is
available in the PHP Configuration section and it is in the System
information.
So, looking at the phpinfo() page, I noticed the first comment down had a
method/function for converting the output of phpinfo() into a multidimensional
array. Taking the output of that users function, you can access the data the
data you are looking for.
So, here is a link to the phpinfo() page.
http://php.net/phpinfo
From there, get the function called phpinfo_array()
take the output of that and run it through the following set of commands.
$data = phpinfo_array(TRUE);
list(, $server_name) = explode(' ', $data['PHP Configuration']['System']);
print( $server_name );
This will give you what you are looking for.
Jim
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Creating a Dynamic PHP/CSS Page (newbie design question)
SORRY FOR THE EXTRA 2 BAD pre SENDS (accident...)
Thank for all the help!
Getting there... as a baby step - I'm trying this:
(part of this is from - http://sperling.com/examples/pcss/)
1 - I created this style sheet page called css.php with these contents:
.test1 {
font-family: Verdana, Arial, Helvetica, sans-serif;
color: #0099FF;
font-size: 18px;
}
?php
header(Content-type: text/css);
$color = green;// --- define the variable
echo CSS
/* --- start of css --- */
.title-text
{
color: $color; /* --- use the variable */
font-weight: bold;
font-size: 1.2em;
text-align: left;
}
/* --- end of css --- */
CSS;
?
-
2 - I created this test page called testcss.php with these contents:
PROBLEM: the 'test1' style shows up - but the 'title-text' doesn't
seem to work
btw: even added this : media=screen from demo
How do I get it to show up?
==
!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0 Transitional//EN
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd;
html xmlns=http://www.w3.org/1999/xhtml;
head
meta http-equiv=Content-Type content=text/html; charset=UTF-8 /
titleUntitled Document/title
link href=css.php rel=stylesheet type=text/css media=screen /
/head
body
ptest span class=test1this/span/p
p class=title-textand this/p
/body
/html
===
Thanks,
c...@hosting4days.com
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Imagick question
On Thu, 2009-11-05 at 12:22 -0700, Ashley M. Kirchner wrote: Brady Mitchell wrote: I'm sure it can be done, but without seeing your code we can't really help. Easily solved. From the PHP manual (http://www.php.net/manual/en/function.imagick-roundcorners.php): ?php $image = new Imagick(); $image-newPseudoImage(100, 100, magick:rose); $image-setImageFormat(png); $image-roundCorners(5,3); $image-writeImage(rounded.png); ? That produces a nice transparent cornered image, as it should. However, try saving it as a JEPG instead. Set the image format to 'jpeg' and write it out as 'rounded.jpg' and you'll notice the corners are now black. I know JPEG doesn't support transparency, that's fine. What I want is to change the black to white instead. -- A Fill the background with white before you create the corners. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] How do I get reliable COMPUTERNAME?
On Thu, Nov 5, 2009 at 2:03 PM, Jim Lucas li...@cmsws.com wrote:
Andrew Ballard wrote:
I want to store the name of the computer that is executing a script in
some log tables. (Our servers are load balanced, and I'd like to be
able to determine which physical machine is serving each request.)
On my development machine (Windows PC running the debugger in Zend
Studio), I can find the name in three places:
getenv('COMPUTERNAME')
$_ENV['COMPUTERNAME']
$_SERVER['COMPUTERNAME']
On the development server, only the first works; $_ENV and $_SERVER
both return NULL and throw an undefined index notice.
I'm concerned about the reliability of all of these methods, since it
seems that they are not always available and all three can be easily
overridden inside a script. However, I notice that the header
generated by phpinfo() remains correct even when I manually spoofed
all three values on my development machine. Is there a reliable way to
find this value?
Andrew
Well, I looked at all the variables that are available. Then I looked at the
data in the output of phpinfo().
The only place that I can find the information that you are looking for is
available in the PHP Configuration section and it is in the System
information.
So, looking at the phpinfo() page, I noticed the first comment down had a
method/function for converting the output of phpinfo() into a multidimensional
array. Taking the output of that users function, you can access the data the
data you are looking for.
So, here is a link to the phpinfo() page.
http://php.net/phpinfo
From there, get the function called phpinfo_array()
take the output of that and run it through the following set of commands.
$data = phpinfo_array(TRUE);
list(, $server_name) = explode(' ', $data['PHP Configuration']['System']);
print( $server_name );
This will give you what you are looking for.
Jim
Close, but not quite what I need. On the Windows systems, the System
value is Windows NT [hostname] [build], so that just returns NT.
Thanks, though. :-) You never know when something like that might be
useful.
I found php_uname('n') which looks like it will return the information
I'm after without having to dissect strings, and it appears to work
just fine across platforms.
Andrew
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Re: [PHP] Creating a Dynamic PHP/CSS Page (newbie design question)
c...@hosting4days.com wrote:
SORRY FOR THE EXTRA 2 BAD pre SENDS (accident...)
Thank for all the help!
Getting there... as a baby step - I'm trying this:
(part of this is from - http://sperling.com/examples/pcss/)
1 - I created this style sheet page called css.php with these contents:
.test1 {
font-family: Verdana, Arial, Helvetica, sans-serif;
color: #0099FF;
font-size: 18px;
}
?php
header(Content-type: text/css);
$color = green;// --- define the variable
echo CSS
/* --- start of css --- */
.title-text
{
color: $color; /* --- use the variable */
font-weight: bold;
font-size: 1.2em;
text-align: left;
}
/* --- end of css --- */
CSS;
?
-
2 - I created this test page called testcss.php with these contents:
PROBLEM: the 'test1' style shows up - but the 'title-text' doesn't seem
to work
btw: even added this : media=screen from demo
How do I get it to show up?
==
!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0 Transitional//EN
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd;
html xmlns=http://www.w3.org/1999/xhtml;
head
meta http-equiv=Content-Type content=text/html; charset=UTF-8 /
titleUntitled Document/title
link href=css.php rel=stylesheet type=text/css media=screen /
/head
body
ptest span class=test1this/span/p
p class=title-textand this/p
/body
/html
===
Thanks,
c...@hosting4days.com
You need to do the header() before anything else.
--
Thanks!
-Shawn
http://www.spidean.com
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Creating a Dynamic PHP/CSS Page (newbie design question)
On Thu, 2009-11-05 at 14:13 -0600, Shawn McKenzie wrote:
c...@hosting4days.com wrote:
SORRY FOR THE EXTRA 2 BAD pre SENDS (accident...)
Thank for all the help!
Getting there... as a baby step - I'm trying this:
(part of this is from - http://sperling.com/examples/pcss/)
1 - I created this style sheet page called css.php with these contents:
.test1 {
font-family: Verdana, Arial, Helvetica, sans-serif;
color: #0099FF;
font-size: 18px;
}
?php
header(Content-type: text/css);
$color = green;// --- define the variable
echo CSS
/* --- start of css --- */
.title-text
{
color: $color; /* --- use the variable */
font-weight: bold;
font-size: 1.2em;
text-align: left;
}
/* --- end of css --- */
CSS;
?
-
2 - I created this test page called testcss.php with these contents:
PROBLEM: the 'test1' style shows up - but the 'title-text' doesn't seem
to work
btw: even added this : media=screen from demo
How do I get it to show up?
==
!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0 Transitional//EN
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd;
html xmlns=http://www.w3.org/1999/xhtml;
head
meta http-equiv=Content-Type content=text/html; charset=UTF-8 /
titleUntitled Document/title
link href=css.php rel=stylesheet type=text/css media=screen /
/head
body
ptest span class=test1this/span/p
p class=title-textand this/p
/body
/html
===
Thanks,
c...@hosting4days.com
You need to do the header() before anything else.
--
Thanks!
-Shawn
http://www.spidean.com
Like I mentioned in my first reply to this, you need to set the content
type of the output in css.php:
header(Content-Type: text/css);
That way, the server sends down the right headers to the agent that is
requesting the CSS. By default, PHP outputs a content type of text/html,
and your browser thinks it got HTML instead of CSS so does nothing.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] Imagick question
Ashley Sheridan wrote:
Fill the background with white before you create the corners.
Well, I tried that, with no luck. This is my actual code:
$width = 150;
$height = 150;
$im = new Imagick('original/' . $filename);
$im-thumbnailImage($width, $height, true);
$im-sharpenImage(50, 1);
$im-setImageBackgroundColor('white');
$im-roundCorners(5, 5, 7);
$im-setImageFormat('jpeg');
$im-writeImage('thumbnail/' . $filename);
$im-clear();
$im-destroy();
--
H | It's not a bug - it's an undocumented feature.
+
Ashley M. Kirchner mailto:ash...@pcraft.com . 303.442.6410 x130
IT Director / SysAdmin. 800.441.3873 x130
Photo Craft Imaging . 2901 55th Street
http://www.pcraft.com . . .. Boulder, CO 80301, U.S.A.
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RE: [PHP] Custom function for inserting values into MySQL
-Original Message- From: Shawn McKenzie [mailto:nos...@mckenzies.net] Sent: Thursday, November 05, 2009 6:14 AM To: Daevid Vincent Cc: 'Allen McCabe'; 'PHP General' Subject: Re: [PHP] Custom function for inserting values into MySQL Daevid Vincent wrote: -Original Message- From: Shawn McKenzie [mailto:nos...@mckenzies.net] Sent: Wednesday, November 04, 2009 4:59 PM To: Daevid Vincent Cc: 'Allen McCabe'; 'PHP General' Subject: Re: [PHP] Custom function for inserting values into MySQL Daevid Vincent wrote: -Original Message- From: Shawn McKenzie [mailto:nos...@mckenzies.net] Sent: Wednesday, November 04, 2009 6:20 AM To: Allen McCabe; PHP General Subject: Re: [PHP] Custom function for inserting values into MySQL In your example, I would name my form inputs similar to name =data[user_id]. Then you just pass the $_POST['data'] array to your function. -Shawn Allen McCabe wrote: You raise some good points. I always name my input fields after the entity names ( eg. input type=hidden name =user_id value= ?php echo $resultRow['user_id'] ? ). I suppose I am still in the phase of learning efficiency, and perhaps trying to 'get out it' by writing functions that I can just call and pass parameters instead of fully learning the core concepts. I just think functions are so damn cool :) I'll echo what the others have said about the parameters. For me personally, if I am passing more than three parameters (sometimes even three) I rethink my function. I'm not sure what you envision using this function for, but the approach I use for forms and databases is always arrays. I get an array from my forms, I insert that array into the database, and of course I fetch arrays out of the database. These are all indexed the same with the index as the field name of the table so it's easy. -- Thanks! -Shawn http://www.spidean.com There are pro's and cons to this type of thing. In general that is how I do it too, but you have to be aware of security and organization. It's not always smart to expose your DB field names directly so you might want to obscure them for some critical values. If your passing from one controlled function/method to another then this isnt an issue so much. I also follow the ruby/rails ideal where tables are plural names (users) and classes are singular names (user.class.php). Tables always have fields for 'id','created_on','timestamp','enabled'. Except in 'glue table' cases (1:n or n:m). Classes extend a base class which handles a lot of the minutea including the magic __get() and __set() routines as well as knowing what table they should be through introspection (ie. Their own file name). No need to name your fields as arrays. $_POST is already an array. You've just added more complexity/dimensions. When you submit your form just pass $_POST to your function instead. In the function, is where you should do any normalizing, scrubbing and unsetting (as per good MVC ideology)... The way I normally do it I learned from the CakePHP framework which is very similar to (I think an attempt at a clone of) Rails. I'm not sure if they do it the same way in Rails, but as you were mentioning, in a Cake view of a form they use the table name as the array name (name=Users[username]). Internally to the framework this may make things easier, but imagine you have a page with 2 or more forms that update different tables, or if your form had some fields that you wanted to check after submission but are not DB fields. The $_POST array will ONLY contain the key/values for the FORM that contained the submit button. form name=form_add input type=text name=foo value=bar input type=submit name=action value=Add /form form name=form_update input type=text name=bee value=boo input type=submit name=action value=Update /form So if you click the 'Add' button, you get back: $_POST['foo'] = 'bar', $_POST['action'] = 'Add' if you click the 'Update' button, you get back: $_POST['bee'] = 'boo', $_POST['action'] = 'Update' where's the confusion? You can only submit one form on a page at a time. Why would you use the entire POST array? Presumably, anything in the form is of some value to your database and you'd want it. Otherwise why is it in the form? I guess I was going for multiple tables and not multiple forms. Consider a form that takes input for a Users table and a Groups table. As for the inputs not needed by the DB, there are too many examples I could give with lots of inputs, but here is the simplest example I can think of: username password captcha rememberme Presumably you don't need the
Re: [PHP] Creating a Dynamic PHP/CSS Page (newbie design question)
At 8:16 PM + 11/5/09, Ashley Sheridan wrote: On Thu, 2009-11-05 at 14:13 -0600, Shawn McKenzie wrote: Getting there... as a baby step - I'm trying this: (part of this is from - http://sperling.com/examples/pcss/) You need to do the header() before anything else. I'm not ragging on you Ashley, but what he needs to do is follow the directions as outlined in my example. I really find it frustrating when I take the time to make things as simple as possible and then have people who don't want to take the time to understand what's being presented to them. He could have his entire problem solved if he would only read and follow the documentation instead of throwing stuff together as if it will somehow work. This reminds me of my first memory when I was two years old. You see, I had a wagon and I wanted it to run like cars do. I knew that my wagon didn't have what it took to make it run, so I started throwing stuff into it in the hopes that somehow everything would come together and the wagon would automagically run. Well... it didn't run! So, I stopped trying to solve things that way when I was two. I'm just surprised how long it takes others to discover that simple fact. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Free tech talk by Percona tonight in Palo Alto, CA
On Tue, Nov 3, 2009 at 10:17 AM, Sam Ghods s...@box.net wrote: Hi all, I would like to invite everyone to a Box.net sponsored free tech talk (and free dinner!) in Palo Alto tonight on Goal Oriented Performance Optimization, given by Peter Zaitsev of Percona, the leading MySQL/LAMP performance consulting firm. Learn more about the event from our blog post http://blog.box.net/?p=1363 and RSVP here: got any slides? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] question about smarty
i am using smarty template engine at work place, following is the situation
i already have 1 template that has already been created example =
http://localhost/sites/template1.com this works fine
following is the folder structure i have for smarty on xampp
1. C:\xampp\htdocs\sites\template1.com where i have .htaccess index.php and
siteconf.php
2. C:\xampp\htdocs\sites\_templates\templates\template1
in the siteconf.php file there are all the major variables defined which are
accessed in other tpl file of the templates example in aboutus page,
contactus page etc of this template1
now i have created another template called template2 and this also has the
same structure
1. C:\xampp\htdocs\sites\template2.com where i have .htaccess index.php and
siteconf.php
2. C:\xampp\htdocs\sites\_templates\templates\template2
my question is the look and feel when i access
http://localhost/sites/template1.com and
http://localhost/sites/template2.com
is the same the only thing that needs to be done is for template2 when i
access http://localhost/sites/template2.com ONLY the header image should be
different compared to the header i have for
http://localhost/sites/template1.com this is the only change i need
i am not aware as to the php code i need to write so that when i access
http://localhost/sites/template2.com the header image changes and this new
header image remains for the entire pages of
http://localhost/sites/template2.com
presently in header.tpl of template1 is written as follows
{if strpos($Data.KEYWORD,rv rental) === false}
div class=header
style=background:url(images/header_{$siteData.COUNTRY3}.gif) no-repeat top
left;
{else}
div class=header
style=background:url(images/header_{$siteData.COUNTRY3}_rv.gif) no-repeat
top left;
{/if}
/div
so i need to chane the {if} {else} where i need to mention that if i am
accessing http://localhost/sites/template2.com then the header image should
be different.
any help will be greatly appreciated.
please advice.
thanks.
Re: [PHP] Free tech talk by Percona tonight in Palo Alto, CA
You can see the slides from the talk here: http://assets.en.oreilly.com/1/event/27/Goal%20Driven%20Performance%20Application%20Paper.pdf Sam Ghods s...@box.net Box.net - Vice President of Engineering office: (877) 269-6736 ext. 60 fax: (650) 529-0392 On Nov 5, 2009, at 2:45 PM, Michael Shadle wrote: On Tue, Nov 3, 2009 at 10:17 AM, Sam Ghods s...@box.net wrote: Hi all, I would like to invite everyone to a Box.net sponsored free tech talk (and free dinner!) in Palo Alto tonight on Goal Oriented Performance Optimization, given by Peter Zaitsev of Percona, the leading MySQL/ LAMP performance consulting firm. Learn more about the event from our blog post http://blog.box.net/?p=1363 and RSVP here: got any slides? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Function Not Working...Little help
Hello,
I am trying to get this function working but it gives me a PHP error
(blank page):
function Validate_Page_Nav($LastPage, $ErrorPage) {
$trimmed = str_replace($staffroot, '', $_SERVER['SCRIPT_NAME']);
$resul = $db-query(SELECT * FROM Page_Access WHERE URI =
'$trimmed') or die(failed to get access data);
$page_access = $resul-fetch_assoc();
$URI_access = explode(,, $page_access['User_Level']);
if($_SESSION['Last_Page'] != $LastPage}) {
header(location: {$ErrorPage}?message=Unable to update user
information.);
exit();
}
if(in_array($_SESSION['Staff_level'], $URI_access)) {
echo Access;
exit();
}else{
echo No Access;
//header(location: {$ErrorPage}?message=Unable to update user
information.);
exit();
}
}
Validate_Page_Nav(user_list.php, user_list.php);
There are parts of the code I was trying to debug.
Any help would be appreciated.
Don Wieland
D W D a t a C o n c e p t s
~
d...@dwdataconcepts.com
Direct Line - (949) 305-2771
Integrated data solutions to fit your business needs.
Need assistance in dialing in your FileMaker solution? Check out our
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Re: [PHP] Why getcwd() returs different results?
Here's an example from the PHP website:
This demonstrates the behaviour:
?php
function echocwd() { echo 'cwd: ', getcwd(), \n; }
echocwd();
register_shutdown_function('echocwd');
?
Outputs:
cwd: /path/to/my/site/docroot/test
cwd: /
http://php.net/manual/en/function.register-shutdown-function.php
It's a known problem but I can't see why this can't be fixed
From: Ashley Sheridan a...@ashleysheridan.co.uk
To: Raymond Irving xwis...@yahoo.com
Cc: PHP-General List php-general@lists.php.net
Sent: Thu, November 5, 2009 6:09:19 AM
Subject: Re: [PHP] Why getcwd() returs different results?
On Wed, 2009-11-04 at 17:36 -0800, Raymond Irving wrote:
Hello,
The getcwd() method returns a different path when called from inside a
shutdown function under Apache. On windows IIS it works just fine.
Can't this be fixed so that the path returned is consistent across servers?
It would appear that PHP should set the CWD path before calling the shut down
functions
__
Raymond Irving
What shutdown functions are you meaning? Do you have an example which shows the
problem?
Thanks,
Ash
http://www.ashleysheridan.co.uk
[PHP] Preview button to show PDF without submitting post data?
PHP Users, I have a page that generates a PDF document using PHP. It takes form data filled in by the user to fill out the PDF When the user clicks submit, it emails that PDF document to the intended recipient. However, I would like to add a preview function as well. But for a variety of reasons, instead of submitting the form data through post and re-filling all the fields with the selected data, I'd like to be able to open a new window with an example PDF without actually submitting the form. I think this might need JavaScript, but I'm not sure. Is this possible? Thank you for any advice. -- Dave M G -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] question about smarty
I'm not sure where is the problem, but can't you just define every changing
part in your template as variables and assign them as needed from php?
If you need to change the image url, just make it a variable, like in
background:url(images/{$img})
Then you just assign the variable as needed in each file:
//template1.php
$img = 'mi_image_1.gif';
$smarty-assign( 'img', $img );
//template2.php
$img = 'mi_image_2.gif';
$smarty-assign( 'img', $img );
That way you don't need to use the {if} inside smarty and make your template
lighter.
De: Sudhakar sudhakarar...@gmail.com
Para: php-general@lists.php.net
Enviado: vie,6 noviembre, 2009 00:14
Asunto: [PHP] question about smarty
i am using smarty template engine at work place, following is the situation
i already have 1 template that has already been created example =
http://localhost/sites/template1.com this works fine
following is the folder structure i have for smarty on xampp
1. C:\xampp\htdocs\sites\template1.com where i have .htaccess index.php and
siteconf.php
2. C:\xampp\htdocs\sites\_templates\templates\template1
in the siteconf.php file there are all the major variables defined which are
accessed in other tpl file of the templates example in aboutus page,
contactus page etc of this template1
now i have created another template called template2 and this also has the
same structure
1. C:\xampp\htdocs\sites\template2.com where i have .htaccess index.php and
siteconf.php
2. C:\xampp\htdocs\sites\_templates\templates\template2
my question is the look and feel when i access
http://localhost/sites/template1.com and
http://localhost/sites/template2.com
is the same the only thing that needs to be done is for template2 when i
access http://localhost/sites/template2.com ONLY the header image should be
different compared to the header i have for
http://localhost/sites/template1.com this is the only change i need
i am not aware as to the php code i need to write so that when i access
http://localhost/sites/template2.com the header image changes and this new
header image remains for the entire pages of
http://localhost/sites/template2.com
presently in header.tpl of template1 is written as follows
{if strpos($Data.KEYWORD,rv rental) === false}
div class=header
style=background:url(images/header_{$siteData.COUNTRY3}.gif) no-repeat top
left;
{else}
div class=header
style=background:url(images/header_{$siteData.COUNTRY3}_rv.gif) no-repeat
top left;
{/if}
/div
so i need to chane the {if} {else} where i need to mention that if i am
accessing http://localhost/sites/template2.com then the header image should
be different.
any help will be greatly appreciated.
please advice.
thanks.
Re: [PHP] Preview button to show PDF without submitting post data?
You could just open in a new window a php script that generates the preview pdf with a content-type header for pdf. header(Content-type: application/pdf); Or if the preview pdf is not dinamic, just point the url to the pdf. No javascript needed, just a link, o a submit button on a form with the url as the action attribute. If you need it to open on a new window, use target=_blank, or better target=pdf if you want consecutive requests to open in the same window instead of a new one everytime. Note: if you are not using transitional html and care about validation, the target attribute is not allowed. In that case you would need javascript to open a new window. De: Dave M G mar...@autotelic.com Para: PHP-General List php-general@lists.php.net Enviado: vie,6 noviembre, 2009 04:58 Asunto: [PHP] Preview button to show PDF without submitting post data? PHP Users, I have a page that generates a PDF document using PHP. It takes form data filled in by the user to fill out the PDF When the user clicks submit, it emails that PDF document to the intended recipient. However, I would like to add a preview function as well. But for a variety of reasons, instead of submitting the form data through post and re-filling all the fields with the selected data, I'd like to be able to open a new window with an example PDF without actually submitting the form. I think this might need JavaScript, but I'm not sure. Is this possible? Thank you for any advice. -- Dave M G -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
