Re: [PHP] php://input

2012-01-15 Thread Frank Arensmeier
15 jan 2012 kl. 06.18 skrev Adam Tong:

 Hi,
 
 I am trying to read variables from input method.
 I am using this tuorial:
 http://www.lornajane.net/posts/2008/Accessing-Incoming-PUT-Data-from-PHP.
 Here is my code:
 ?php
 if($_SERVER['REQUEST_METHOD'] == 'GET') {
echo this is a get request\n;
echo $_GET['fruit']. is the fruit\n;
echo I want .$_GET['quantity']. of them\n\n;
 } elseif($_SERVER['REQUEST_METHOD'] == 'PUT') {
echo this is a put request\n;
parse_str(file_get_contents(php://input),$post_vars);
echo $post_vars['fruit']. is the fruit\n;
echo I want .$post_vars['quantity']. of them\n\n;
 }
 ?
 
 I am using the firefox extension  poster to run this example. GET
 works fine but when using PUT, file_get_contents(php://input)
 returns an empty string.
 
 I found a bug related to this: https://bugs.php.net/bug.php?id=51592
 
 I am using xampp on win7 (
 + Apache 2.2.17
  + MySQL 5.5.8 (Community Server)
  + PHP 5.3.5 (VC6 X86 32bit) + PEAR)
 
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Hi Adam.

Although I've never worked with PUT/DELETE requests, here are my thoughts.

1) According to the manual, file_get_contents only allows URL's as filenames if 
fopen wrappers are enabled. Make sure that this is the case (have a look at 
the settings in your php ini file). Do you get any data when changing 
'file_get_contents' to e.g. (as found here: 
http://php.net/manual/en/features.file-upload.put-method.php)?

?php
/* PUT data comes in on the stdin stream */
$putdata = fopen(php://input, r);

/* Open a file for writing */
$fp = fopen(myputfile.ext, w);

/* Read the data 1 KB at a time
   and write to the file */
while ($data = fread($putdata, 1024))
  fwrite($fp, $data);

/* Close the streams */
fclose($fp);
fclose($putdata);
?

2) Have a look in your Appache log files and make sure the client is actually 
making a valid PUT request.

/frank


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[PHP] Measuring CPU time

2012-01-15 Thread Tim Streater
I haven't found a function to allow me to see elapsed CPU time to date in a 
function. Am I right in thinking none such exists?

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[PHP] Numeric help needed

2012-01-15 Thread Christopher J Payne
Hi everyone,

 

I am having a hard time with a numerical problem.

 

I need to round some numbers up and I've tried $round($number) and it
doesn't work so I'm misunderstanding something.

 

For example, if a user inputs 685000 I need it to round up to 69 or if
they input 149560 I need it to round up to 15.  What is the correct way
to do this as everything I have tried doesn't seem to affect the user
inputted figure at all.

 

Anyway help would REALLY be appreciated, I'm sure it's really simple but for
the life of me I'm stumped on why it's not working.

 

Chris



Re: [PHP] Numeric help needed

2012-01-15 Thread Jason Pruim


Sent from my iPhone

On Jan 15, 2012, at 8:25 PM, Christopher J Payne oxygene...@gmail.com wrote:

 Hi everyone,
 
 
 
 I am having a hard time with a numerical problem.
 
 
 
 I need to round some numbers up and I've tried $round($number) and it
 doesn't work so I'm misunderstanding something.
 
 
 
 For example, if a user inputs 685000 I need it to round up to 69 or if
 they input 149560 I need it to round up to 15.  What is the correct way
 to do this as everything I have tried doesn't seem to affect the user
 inputted figure at all.
 
 
 
 Anyway help would REALLY be appreciated, I'm sure it's really simple but for
 the life of me I'm stumped on why it's not working.
 

Maybe it's just a typo in your email but you put a $ infront of round() try 
removing that and see if it helps. If not are there any error messages that are 
showing up?
 

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Re: [PHP] Numeric help needed

2012-01-15 Thread Chris Payne
Hi Jason,

I've tried lots of different things, including:

 echo br . round(68500, 1000) .  ROUNDED;

thinking that might be it, but i'm stumped

This is the example I was given (And have to go by):

If the loan amount is $68500.00, the insurace will be based on
$69000.00 as the amount is always rounded up to the next $1000.

Maybe i'm just looking at it wrong but i'm stumped.

Chris


On Sun, Jan 15, 2012 at 8:41 PM, Jason Pruim li...@pruimphotography.com wrote:


 Sent from my iPhone

 On Jan 15, 2012, at 8:25 PM, Christopher J Payne oxygene...@gmail.com 
 wrote:

 Hi everyone,



 I am having a hard time with a numerical problem.



 I need to round some numbers up and I've tried $round($number) and it
 doesn't work so I'm misunderstanding something.



 For example, if a user inputs 685000 I need it to round up to 69 or if
 they input 149560 I need it to round up to 15.  What is the correct way
 to do this as everything I have tried doesn't seem to affect the user
 inputted figure at all.



 Anyway help would REALLY be appreciated, I'm sure it's really simple but for
 the life of me I'm stumped on why it's not working.


 Maybe it's just a typo in your email but you put a $ infront of round() try 
 removing that and see if it helps. If not are there any error messages that 
 are showing up?


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Re: [PHP] Numeric help needed

2012-01-15 Thread Simon J Welsh
On 16/01/2012, at 2:48 PM, Chris Payne wrote:

 Hi Jason,
 
 I've tried lots of different things, including:
 
 echo br . round(68500, 1000) .  ROUNDED;
 
 thinking that might be it, but i'm stumped
 
 This is the example I was given (And have to go by):
 
 If the loan amount is $68500.00, the insurace will be based on
 $69000.00 as the amount is always rounded up to the next $1000.
 
 Maybe i'm just looking at it wrong but i'm stumped.
 
 Chris


The round() function only rounds decimal values. You can use this to emulate 
rounding to a near power of ten by dividing, rounding, then multiplying again. 
i.e. echo br . round(68500/1000) * 1000 .  ROUNDED;
---
Simon Welsh
Admin of http://simon.geek.nz/


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Re: [PHP] Numeric help needed

2012-01-15 Thread Curtis Maurand

On 1/15/2012 8:48 PM, Chris Payne wrote:

Hi Jason,

I've tried lots of different things, including:

  echo br . round(68500, 1000) .  ROUNDED;

thinking that might be it, but i'm stumped

This is the example I was given (And have to go by):

If the loan amount is $68500.00, the insurace will be based on
$69000.00 as the amount is always rounded up to the next $1000.

Maybe i'm just looking at it wrong but i'm stumped.

Chris


On Sun, Jan 15, 2012 at 8:41 PM, Jason Pruimli...@pruimphotography.com  wrote:


Sent from my iPhone

On Jan 15, 2012, at 8:25 PM, Christopher J Payneoxygene...@gmail.com  wrote:


Hi everyone,



I am having a hard time with a numerical problem.



I need to round some numbers up and I've tried $round($number) and it
doesn't work so I'm misunderstanding something.



For example, if a user inputs 685000 I need it to round up to 69 or if
they input 149560 I need it to round up to 15.  What is the correct way
to do this as everything I have tried doesn't seem to affect the user
inputted figure at all.



Anyway help would REALLY be appreciated, I'm sure it's really simple but for
the life of me I'm stumped on why it's not working.


Maybe it's just a typo in your email but you put a $ infront of round() try 
removing that and see if it helps. If not are there any error messages that are 
showing up?

http://php.net/manual/en/function.round.php

From the page:

|?php
echo round(3.4); // 3
echo round(3.5); // 4
echo round(3.6); // 4
echo round(3.6, 0); // 4
echo round(1.95583, 2); // 1.96
echo round(1241757, -3); // 1242000
echo round(5.045, 2); // 5.05
echo round(5.055, 2); // 5.06
? |




Re: [PHP] Numeric help needed

2012-01-15 Thread Robert Williams
On Jan 15, 2012, at 19:00, Simon J Welsh 
si...@welsh.co.nzmailto:si...@welsh.co.nz wrote:

On 16/01/2012, at 2:48 PM, Chris Payne wrote:

If the loan amount is $68500.00, the insurace will be based on
$69000.00 as the amount is always rounded up to the next $1000.

The round() function only rounds decimal values. You can use this to emulate 
rounding to a near power of ten by dividing, rounding, then multiplying again. 
i.e. echo br . round(68500/1000) * 1000 .  ROUNDED;

You can also pass a second parameter to round() that indicates the precision to 
round to. If you pass a negative precision value, you can round to higher-order 
digits. For example, pass -3 to round to the nearest thousand.

Having said that, based on the quote above, I believe this would be an 
incorrect solution to the problem. It sounds like the value is simply always 
rounded up to the nearest thousand, which means round() is not the function to 
use as it will sometimes round down. Instead ceil() should be used, as it 
always rounds up to the next whole number/integer. It lacks a precision 
argument, however, so the OP would need to use the divide-adjust-multiple trick 
you provided to make it work. That is, something like this:

$newValue = ceil(68500 / 1000) * 1000

Numbers smaller than 1000 will need to be handled as an edge case, since this 
algorithm will adjust them to zero for you (same as when using round(), 
incidentally). If negative numbers are valid inputs, they'll also need careful 
review to ensure correct behavior.

Hope that helps.

--
Bob Williams


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Re: [PHP] Numeric help needed

2012-01-15 Thread Curtis Maurand


On 1/15/2012 9:24 PM, Robert Williams wrote:

On Jan 15, 2012, at 19:00, Simon J 
Welshsi...@welsh.co.nzmailto:si...@welsh.co.nz  wrote:

On 16/01/2012, at 2:48 PM, Chris Payne wrote:

If the loan amount is $68500.00, the insurace will be based on
$69000.00 as the amount is always rounded up to the next $1000.

The round() function only rounds decimal values. You can use this to emulate rounding to a near power of 
ten by dividing, rounding, then multiplying again. i.e. echo br . round(68500/1000) * 
1000 .  ROUNDED;

round() rounds floating point which I suppose includes decimals, but 
decimal tends to have a fixed number of decimal places.



float *round* ( float $val [, int $precision= 0 [, int $mode= 
PHP_ROUND_HALF_UP ]] )





[PHP] Thank you all for your help

2012-01-15 Thread Chris Payne
Hi there,

A big thank you to all of you who took time to help me with my numeric
problem from earlier, it's been a huge help :-)

Chris

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