Re: [PHP] Re: Everything works...Unless they hit the back button...
Kristen G. Thorson wrote:
You said If the user makes changes, those changes get error checked but
do not become part of the sql query. Where in your code is it failing
to become part of the query? Put a check at each level and see where
*exactly* it fails to get deep enough to become one with the query.
Also, I'm confused. I asked if the query was what you're expecting, and
you answered yes, which implies the data becomes part of the query.
Thanks for this; yes I was confused before and thank you for the
clarification.
Now I am confused by how to check the logic: I echo out the sql as it is
built, and if I'm going forward in the questionnaire it shows clearly but
$qidlist_sql=DELETE FROM teresa WHERE q_id IN ( .
(implode(,,$qidlist)) . );;
echo br /br /;
echo br /\$ cqidlist_sql: . $qidlist_sql . br /;
$q_a_sql=INSERT INTO teresa (u_id, q_id, a_id )
VALUES . (implode(,,$qanda)) . ;;
mysql_query($qidlist_sql);
echo br /br /;
echo br /\$ q_a_sql: . $q_a_sql . br /;
if($q_a_result = mysql_query($q_a_sql))
{
unset($_SESSION['required_fields']);
$cat = $_POST['cat']+1;
include_once(QUESTIONS . 'q.inc');
}
shows NOTHING if I hit the BACK button. I'm still not seeing where the
logic error is which makes it so that when I hit the BACK button it
loses the plot.
Sorry for my misunderstanding
JJ
kgt
Jack Jackson wrote:
I've tried playing with the $_SERVER['HTTP_REFERER'] and that's no
good because it's all coming from the same page - index.php!!
What am I missing. . . ?
Jack Jackson wrote:
Hi Kristen, there's a misunderstanding:
Kristen G. Thorson wrote:
The code below isn't much help to debug. Do some checking to figure
out how far into your IF statement you're getting. Is the query
running?
Yes it runs successfully
Is it the query you expect?
Yes it is perfect, and provided this is a new session and we're going
forward page by page, it properly deletes from and inserts to the db
as expected
(Step #1 when inserting or creating dynamic
queries that aren't working: print them out to make sure they are
what you think they are.) Is the category being incremented?
Yes, absolutely
You say you can go back, but you can't go forward.
Actually no. In a new session, I can start and go forward page by
page to the end of the questionnaire, advancing each stage perfectly,
storing all values exactly as I'd expect.
The trouble starts if, during the process, the user hits the BACK
button. At that point, user can reload the last page of questions,
displaying the answers they gave. If the user makes changes, those
changes get error checked but do not become part of the sql query.
Also, user can not move forwards any more. So it's as the subject
says - everything works...until they hit the back button, from which
point the whole thing goes gablooey.
Look at the page source, is the
form action what it should be?
Yes
Look at the form hidden variables (if
any) are they what you expect?
No. $cat remains what it was BEFORE the user hit the BACK button.
However the questions dispayed are from the $cat which is in fact $cat-1
??!!
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[PHP] Everything works...Unless they hit the back button...
Hi all. This has been an interesting week.
Now the form works, and I am able to error check, if no errors look into
user answer table and delete from that all q_ids matching the ones just
picked, insert this page of question/answer info (q_id/a_id) into the
user answer db, and if successful advance the category by 1 and get more
questions. It works.
I must have a logic error though because for some reason even though I
say to delete matching q_ids and reinsert, then move on, if the user
hits the back button, changes answers and hits submit again, the table
does not update . . . and the category does not increment. We get stuck
on this page of questions/answers forever.
What DOES happen after BACK is that the answers they select get passed
back to error check (eg if they select a select box to nothing, error
checking reenters its value into $message) and those values get passed
back to the display page (eg $_POST[$qname] == $aid) because the
selected answers change. It's just the db call and category advance
which get stuck.
Any help will be greatly appreciated - Here's the code:
?php
//Start the session
session_start();
//Error announcements
echo POST:BR /;
print_r($_POST);
echo br /br /;
echo required session:BR /;
var_dump($_SESSION['required_fields']);
echo br /\$ cat: . $cat . br /;
echo \$message: ;
var_dump($message);
//error_reporting(E_ALL);
/* A script to retrieve from database questions and answers,
* create a multi-page HTML form, error check answers and
* submit them to the database on a per-user basis.
* August 2005
*/
//Some basic vars
if (!isset($cat)) { $cat = 1; }
$error=0;
$SUCCESS=0;
if (!isset($message))
{
$message = array();
}
if (!isset($_SESSION['required_fields']))
{
$_SESSION['required_fields'] = array();
}
if(!sizeof($_POST))
{
include_once(QUESTIONS . 'q.inc');
}
//error checking
reset($_SESSION['required_fields']);
foreach ($_SESSION['required_fields'] as $fieldname)
{
if (!isset($_POST[$fieldname]) || empty($_POST[$fieldname]))
{
$message[$fieldname]=1;
}
}//error check
if (!empty($message))
{ $cat=$_POST['cat'];
include_once(QUESTIONS . 'q.inc');
}
//No errors? Store what's been done so far
if ( ($_POST['action'] == 'process') (!sizeof($message) ) )
{
foreach($_POST as $key=$val)
{
//find key/val sets within posts which are both numeric
if(is_numeric($key) is_numeric($val))
{
$nkey=$key;
//add keys to the qidlist
$qidlist[] .= $key;
//add these values ( q_id, a_id ) to sql statement
$qanda[] .= ('1' , ' . $nkey . ' , ' . $val .
');
}
//find key/val sets within sub-arrays of $_POST
which are numeric
if(is_array($val))
{
foreach ($val as $akey=$aval)
{
//add these values ( q_id, a_id ) to sql
statement
$qanda[] .= ('1' , ' . $key . ' , ' .
$aval . ');
var_dump($qanda);
}
}
}
$qidlist_sql=DELETE FROM $userAnswers WHERE q_id IN (
. (implode(,,$qidlist)) . );;
$q_a_sql=INSERT INTO $userAnswers (u_id, q_id, a_id )
VALUES . (implode(,,$qanda)) . ;;
mysql_query($qidlist_sql);
if($q_a_result = mysql_query($q_a_sql))
{
unset($_SESSION['required_fields']);
$cat = $_POST['cat']+1;
include_once(QUESTIONS . 'q.inc');
}
else
{
echo bA fatal MySQL error occured/b.\n
br /Query: . $q_a_sql . br /\nError: ( .
mysql_error();
die;
}
}
?
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Re: [PHP] Re: Everything works...Unless they hit the back button...
Hi, mark, snip Mark Rees wrote: Do you want to allow people to go back and change things ? If so, write a suitable UPDATE statement /snip Thanks, but I think the update function should be built in -- the sql checks whether the userAnswer table contains the q_id the user has just entered; if so, it deletes the row containing it and then the second query inserts the new values. $qidlist_sql=DELETE FROM teresa WHERE q_id IN ( . (implode(,,$qidlist)) . ); $q_a_sql=INSERT INTO teresa (u_id, q_id, a_id ) VALUES . (implode(,,$qanda)) . ;; I think there's something wrong with the logic of how I'm handling $_POST info and passing it back and forth: here's why: if I close the browser and reopen it and refill the same questions, the answer table shows the updated answers. there's something in the logic I am using about how I am advancing the $cat and managing the $_POST information. I think . But I cannot find it. Anyone? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Everything works...Unless they hit the back button...
Hi Kristen, there's a misunderstanding: Kristen G. Thorson wrote: The code below isn't much help to debug. Do some checking to figure out how far into your IF statement you're getting. Is the query running? Yes it runs successfully Is it the query you expect? Yes it is perfect, and provided this is a new session and we're going forward page by page, it properly deletes from and inserts to the db as expected (Step #1 when inserting or creating dynamic queries that aren't working: print them out to make sure they are what you think they are.) Is the category being incremented? Yes, absolutely You say you can go back, but you can't go forward. Actually no. In a new session, I can start and go forward page by page to the end of the questionnaire, advancing each stage perfectly, storing all values exactly as I'd expect. The trouble starts if, during the process, the user hits the BACK button. At that point, user can reload the last page of questions, displaying the answers they gave. If the user makes changes, those changes get error checked but do not become part of the sql query. Also, user can not move forwards any more. So it's as the subject says - everything works...until they hit the back button, from which point the whole thing goes gablooey. Look at the page source, is the form action what it should be? Yes Look at the form hidden variables (if any) are they what you expect? No. $cat remains what it was BEFORE the user hit the BACK button. However the questions dispayed are from the $cat which is in fact $cat-1 ??!! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Everything works...Unless they hit the back button...
I've tried playing with the $_SERVER['HTTP_REFERER'] and that's no good because it's all coming from the same page - index.php!! What am I missing. . . ? Jack Jackson wrote: Hi Kristen, there's a misunderstanding: Kristen G. Thorson wrote: The code below isn't much help to debug. Do some checking to figure out how far into your IF statement you're getting. Is the query running? Yes it runs successfully Is it the query you expect? Yes it is perfect, and provided this is a new session and we're going forward page by page, it properly deletes from and inserts to the db as expected (Step #1 when inserting or creating dynamic queries that aren't working: print them out to make sure they are what you think they are.) Is the category being incremented? Yes, absolutely You say you can go back, but you can't go forward. Actually no. In a new session, I can start and go forward page by page to the end of the questionnaire, advancing each stage perfectly, storing all values exactly as I'd expect. The trouble starts if, during the process, the user hits the BACK button. At that point, user can reload the last page of questions, displaying the answers they gave. If the user makes changes, those changes get error checked but do not become part of the sql query. Also, user can not move forwards any more. So it's as the subject says - everything works...until they hit the back button, from which point the whole thing goes gablooey. Look at the page source, is the form action what it should be? Yes Look at the form hidden variables (if any) are they what you expect? No. $cat remains what it was BEFORE the user hit the BACK button. However the questions dispayed are from the $cat which is in fact $cat-1 ??!! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Forming an SQL query
Hi, Thanks to everyone's help, that multipage monster of a form is now working properly (yay!). One problem I have though is that I stick the answers as each page is completed into a table. If the user hits the back button, rather than adding a new row to the table I'd rather update it if it's there. That's fairly straightforward when it's 1:1 questions to answers: $q_a_sql='INSERT INTO $userAnswerTable ( q_id, a_id ) VALUES ' . (implode(,,$qanda)) . ' on duplicate key UPDATE a_id = VALUES(a_id);'; But when it's 1:n, such as with checkboxes, this neat little plan of mine is thwarted. So if I change the userAnswerTable to three columns, u_id, q_id and a_id, is there a way I can do all the 1:1 and 1:n in the manner I wish? TIA, JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Forming an SQL query
Ah, I had left out the third column the first time! Thanks.
Now I can insert and not create dupes but for some reason it is not
updating.
Here's the code:
if ( ($_POST['action'] == 'process') (!sizeof($message) ) )
{
foreach($_POST as $key=$val)
{
//find key/val sets within posts which are both numeric
if(is_numeric($key) is_numeric($val))
{
$nkey=$key;
//add these values ( q_id, a_id ) to sql statement
$qanda[] .= ('1' , ' . $nkey . ' , ' . $val .
');
}
//find key/val sets within sub-arrays of $_POST
which are numeric
if(is_array($val))
{
foreach ($val as $akey=$aval)
{
//add these values ( q_id, a_id ) to sql
statement
$qanda[] .= ('1' , ' . $key . ' , ' .
$aval . ');
}
}
}
$q_a_sql=INSERT INTO . $userTable . (u_id, q_id, a_id )
VALUES . (implode(,,$qanda)) . on duplicate key
UPDATE a_id = VALUES(a_id);;
if($q_a_result = mysql_query($q_a_sql))
{
unset($_SESSION['required_fields']);
$cat = $_POST['cat']+1;
include_once(QUESTIONS . 'q.inc');
}
?
Kristen G. Thorson wrote:
How is it your plan thwarted? It looks fine to me, but maybe I'm
missing something. The only thing I can think is that you're not
defining your table keys correctly to correctly use ON DUPLICATE KEY.
Do you have a key defined for all three columns *together*?
mysql create table user_answers (u_id int(11) not null, q_id int(11)
not null, a_id int(11) not null, unique( u_id, q_id, a_id ) );
Query OK 0 rows affected (0.22 sec)
mysql insert into user_answers (u_id,q_id,a_id) values
(1,1,1),(1,1,2),(1,2,1),(1,1,1) on duplicate key update a_id=values(a_id);
Query OK, 5 rows affected (0.01 sec)
Records: 4 Duplicates: 1 Warnings: 0
mysqlselect * from user_answers;
+--+--+--+
| u_id | q_id | a_id |
+--+--+--+
|1 |1 |1 |
|1 |1 |2 |
|1 |1 |3 |
+--+--+--+
3 rows in set (0.00 sec)
So, three different answers for the same user same question. The one
duplicate did not cause an error because of the ON DUPLICATE KEY. This
looks like it's what you're trying to do, so then what's your error?
kgt
Jack Jackson wrote:
Hi,
Thanks to everyone's help, that multipage monster of a form is now
working properly (yay!).
One problem I have though is that I stick the answers as each page is
completed into a table. If the user hits the back button, rather than
adding a new row to the table I'd rather update it if it's there.
That's fairly straightforward when it's 1:1 questions to answers:
$q_a_sql='INSERT INTO $userAnswerTable
( q_id, a_id )
VALUES ' . (implode(,,$qanda))
. ' on duplicate key UPDATE a_id = VALUES(a_id);';
But when it's 1:n, such as with checkboxes, this neat little plan of
mine is thwarted.
So if I change the userAnswerTable to three columns, u_id, q_id and
a_id, is there a way I can do all the 1:1 and 1:n in the manner I wish?
TIA,
JJ
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Re: [PHP] Re: error checking a null array
g.gill wrote: From what I understand the simplest solution here would be to check to see if you have $_POST['cb'] in the first place. That would indicate if checkbox was selected or not. After, you have posted the form just do the following test. $check_box_exits = ((isset($_POST['cb']))? true:false); That helped, sonu, thank you. The problem now is that, how can I pass through $_POST the names of each specific checkbox, whether filled in or not, and then parse each to see if they have any answer? I need to do that or else I can only tell the ones which *have* been filled in but not those which have not. Thanks -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: error checking a null array
Jochem Maas wrote:
snip
wtf are you smoking Jack? every checkbox that was checked will exist in the
$_POST array set with the value you gave it (I alway set a chekcboxes
value to 1
because the values mere existance in the submitted data indicates it's
chevckbox
was checked), if a checkbox does not exist in the $_POST array it
wasn't checked!!!
Oh, how I wish I were smoking something :) !
imagine you have 10 checkboxes named 'cb1' thru 'cb10' each with a value
of '1',
upon submitting the form they are in, your script sees the following in
the $_POST
array...
$_POST = array('cb1' = '1', 'cb9' = '1', 'cb10' = '1');
which tells you 3 checkboxes were checked... namely 'cb1', 'cb9' and 'cb10'
now how hard is it to determine which we're not checked?
Well, for me, it is - because I don't know the names of the other check
boxes which were not checked because they were dynamically created, and
I don't have the knowledge sufficient to pass the NAMES of all
checkboxes through to $_POST so that I can search through and see which
have been answered and which ones not.
maybe I'm not seeing the problem but I get the impression that you are
over complicating things regarding checkbox.
As always this is hugely possible.
JJ
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Re: [PHP] error checking woes
Kristen G. Thorson wrote:
Thanks for the == !
But I had set $message global within the buld-checkbox function, so that
part of it does work. . . .
Jack,
Read below:
Jack Jackson wrote:
Hi,
Now that the drop down is working properly (thanks!!), I am trying to
validate, and having LOTS of trouble. After being ceaselessly derided
last night on an irc channel for my dimwitedness, I am still not any
closer.
The code which works is this:
function GetQuestionsDropdown($cat){
//first get all the questions
$sql = SELECT * FROM questions WHERE questions.q_cat=$cat AND
questions.q_style=1;
$result = mysql_query($sql);
//now one-by-one go through the questions
while($row = mysql_fetch_assoc($result)) {
//if the form has been submitted, and the question
unanswered
//highlight this whole question and answer block in red.
if ($message[$row['q_name']] == 1){
How does this funtion have access to $message? You need to a) make it
global or b) pass it in.
echo div class='error';
}
//Make a question set div wrapper
echo div class='q_set'\n;
//State the question
echo div class='question';
echo $row['q_text'] . /div;
echo \n\n;
echo div class='answer';
echo \n;
//Create the dropdown for the answers
echo ' select name=' . $row['q_name'] . '';
echo \n;
//get all of the answers for THIS question
$ans_sql = select * from answers where answers.q_id= .
$row['q_id'];
$ans_result = mysql_query($ans_sql);
echo option value=\\Select from this list/option\n;
while($ans_row = mysql_fetch_assoc($ans_result)) {
//list the answers for THIS question
echo option ;
echo value=\ . $ans_row['a_id'] . \;
if ($row['q_name'] == $ans_row['a_id']) {
echo selected;
}
echo . $ans_row['a_answer'] . /option;
echo \n;
}
echo ' /select' . \n . ' /div' . \n;
echo /div!--q_set--\n\n;
//If there *was* an error div, close it
if (sizeof($message[$row['q_name']])){
echo /div!--/error--;
}
}
}//function GetQuestionsDropdown
NOW I have to validate after it's submitted. I am trying to look and
see, if $_POST[$row['q_name']] is empty then make message of the same
name = 1, so if
if(empty($_POST['partners'])) {
$message['partners'] = '1'
}
Then when I restate the dropdown function, and it shows the questions
again, those error checking things I built in will
a) show a div class=error around questions with a message
b) pre-select the previously selected answers (because I have put
in the thing in the dropdown which says
if ($row['q_name'] == $ans_row['a_id']) { echo selected;}
The validate code I was trying, the subject of such howling on IRC
(and I know it doesn't work, but not why) was:
function ValidatePost($cat){
//first get the q_names
$sql = SELECT * FROM questions WHERE q_cat=$cat;
$result = mysql_query($sql);
//go through the question set
while($row = mysql_fetch_assoc($result)) {
if(empty($_POST[$row['q_name']])){
$message[$row['q_name']] == 1;
You want $message = 1 here. = = is for comparison.
You're setting $message inside a function. This means it doesn't exist
outside this scope!
}
}
}//function ValidatePost
Can anyone tell me what I am doing wrong?
Thanks!
JJ
Hope this helps you get somewhere,
kgt
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Re: [PHP] returning info. from a form selection
It'd have to be in the form of a form and you'd need to add values to the options, wrap it inside form tags, specify a method like $_POST or $_GET, error check and then send. Bruce Gilbert wrote: can anyone give me an idea on how to return info. from a forl pulldown menu eg: select class=textbox name=loan_process option value= selected=selectedPurchase/option option value=Construct Home/option option /select and return that to an email address. thanks -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: error checking a null array
AAarg.
Okay, thanks to all of you I've decided that any field name I need to
see will be sent to $_SESSION['required_fields'] and basta.
Then after the submit button is pressed, I am doing this:
reset($_SESSION['required_fields']);
foreach ($_SESSION['required_fields'] as $fieldname)
{
if (!isset($_POST[$fieldname]) || empty($_POST[$fieldname]))
{
$message[$fieldname]=1;
include_once(QUESTIONS . 'q.inc');
}
}//error check
And this is *almost* working: it seems to crap out after the first loop
through the $_SESSION['required_field'] array.
The array says:
Array ( [required_fields] = Array ( [0] = 1 [1] = 2 [2] = 3 [3] = 4
[4] = 1 [5] = 2 [6] = 3 [7] = 4 [8] = 1 [9] = 2 [10] = 3 [11] =
4 ) )
$_POST says:
Array ( [action] = [process]process [1] = [2] = 68 [3] = [4] = )
So you see, there's an answer specified for the value of question [2].
But $messages says only:
$message: array(1) { [1]= int(1) }
Why is it dying after the first loop through?
Thanks in advance
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Re: [PHP] Re: error checking a null array
I can only swear this to the entire list:
Before I come here for help, each time, I echo and var_dump and print_r
until, yes, I need a doctor.
So by the time I come here, it's not laziness or lack of looking in the
manual, it's head-swirling confusion infused with incompetence and a
complete lack of programming experience at any time before April of this
year which leads me to come back again and again with relatively foolish
questions.
My problem before, for example: In my error check function, I placed the
include file (to return to the form) *within* the foreach loop, and then
I wondered why it only ran through once.
D'oh.
Jochem Maas wrote:
Jack Jackson wrote:
AAarg.
Okay, thanks to all of you I've decided that any field name I need to
see will be sent to $_SESSION['required_fields'] and basta.
Then after the submit button is pressed, I am doing this:
reset($_SESSION['required_fields']);
reset is not required when using foreach. and given that you have probably
not looped that item
foreach ($_SESSION['required_fields'] as $fieldname)
{
if (!isset($_POST[$fieldname]) || empty($_POST[$fieldname]))
{
$message[$fieldname]=1;
include_once(QUESTIONS . 'q.inc');
}
}//error check
you may be getting into trouble because of php's typecasting - try using
fielnames that are strings that do not auto cast to integers (which can be
used as array keys for indexed arrays) e.g. cb1 instead of 1
And this is *almost* working: it seems to crap out after the first
loop through the $_SESSION['required_field'] array.
The array says:
Array ( [required_fields] = Array ( [0] = 1 [1] = 2 [2] = 3 [3] =
4 [4] = 1 [5] = 2 [6] = 3 [7] = 4 [8] = 1 [9] = 2 [10] = 3 [11]
= 4 ) )
$_POST says:
Array ( [action] = [process]process [1] = [2] = 68 [3] = [4] = )
that does not look like valid output from var_dump() neither does the
output you
show for $_SESSION['required_field'].
So you see, there's an answer specified for the value of question [2].
But $messages says only:
$message: array(1) { [1]= int(1) }
Why is it dying after the first loop through?
is it? (use print_r() or var_dump() inside the loop to see what is
happening)
NOT SO SUBTLE HINT: USE echo, print_r() and var_dump() until either you
fingers or
your eyes start to bleed ;-) if you still haven't figured it out by then
it's
time to see a doctor -
Thanks in advance
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Re: [PHP] error checking woes- SOLVED
I did the smart thing last night: nothing. I read some PHP books and
then realized that the answer to my error checking was a lot less
complex, once again, than I had initially suspected. I finally ended up
with:
//error checking
foreach($_POST as $qname=$value) {
if(empty($value)){
$message[$qname]=1;
}
}
I cannot believe what I started with and what I ended up with.
Thanks as usual for the help!!
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[PHP] error checking a null array
hi,
I have checkboxes beging dynamically generated. to seperate tasks in
error checking I have added he arrays not just to $_POST but to
$_POST[cb] so names (derived from question numbers) are for example:
$_POST[cb][7]
A dump of $_POST would therefore include something like
[cb]= array(1) { [7]= array(1) { [0]= string(3) 124 } }
So I did this:
//error checking for checkboxes
foreach ($cb as $cbkey = $cbvalue)
{
foreach($cbvalue as $cbkey2=$cb_answers)
{
if( !array_key_exists($_POST[$cbkey], $cb));
{
$message[$cbkey]=1;
}
}
}
This almost works. The problem is that if someone doesn't check a
checkbox, NOTHING related to the checkbox gets sent to $_POST; if I
insert a hidden value of something, then that hidden value gets passed
whether the user inputs something or not, since I need an entirely
server-side solution. Is there a way to send something to tell the error
checker whether for example $_POST[cb][7] is empty or null, so I can set
the error message to one if it's empty?
Dump of $_POST with no checkboxes checked
$_POST:
array(4) { [action]= string(7) process [cat]= string(1) 2
[rs]= array(3) { [5]= string(0) [6]= string(0) [9]=
string(0) } [b]= string(8) Continue }
Dump of $_POST with checkboxes checked
array(5) { [action]= string(7) process [cat]= string(1) 2
[cb]= array(2) { [7]= array(5) { [0]= string(1) 3 [1]=
string(3) 124 [2]= string(3) 125 [3]= string(3) 127 [4]=
string(3) 131 } [8]= array(3) { [0]= string(3) 141 [1]=
string(3) 145 [2]= string(1) 4 } } [rs]= array(3) { [5]=
string(0) [6]= string(0) [9]= string(0) } [b]=
string(8) Continue }
Thanks so much In advance
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Re: [PHP] Re: error checking a null array
David Robley wrote:
Jack Jackson wrote:
hi,
I have checkboxes beging dynamically generated. to seperate tasks in
error checking I have added he arrays not just to $_POST but to
$_POST[cb] so names (derived from question numbers) are for example:
$_POST[cb][7]
A dump of $_POST would therefore include something like
[cb]= array(1) { [7]= array(1) { [0]= string(3) 124 } }
So I did this:
//error checking for checkboxes
foreach ($cb as $cbkey = $cbvalue)
{
foreach($cbvalue as $cbkey2=$cb_answers)
{
if( !array_key_exists($_POST[$cbkey], $cb));
{
$message[$cbkey]=1;
}
}
}
This almost works. The problem is that if someone doesn't check a
checkbox, NOTHING related to the checkbox gets sent to $_POST; if I
insert a hidden value of something, then that hidden value gets passed
whether the user inputs something or not, since I need an entirely
server-side solution. Is there a way to send something to tell the error
checker whether for example $_POST[cb][7] is empty or null, so I can set
the error message to one if it's empty?
I think you might find empty() and isset() fairly useful here.
Cheers
I would have thought so too, but empty doesn't seem to work if it's not
there at all, (I guess it figures, how can it be empty if it isn't
there) and isset doesn't work if the array is there but null. or
something like that. IN any case I've yet to get them working using
either. I probably should have said that!
Thanks in advance
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[PHP] error checking woes
Hi,
Now that the drop down is working properly (thanks!!), I am trying to
validate, and having LOTS of trouble. After being ceaselessly derided
last night on an irc channel for my dimwitedness, I am still not any closer.
The code which works is this:
function GetQuestionsDropdown($cat){
//first get all the questions
$sql = SELECT * FROM questions WHERE questions.q_cat=$cat AND
questions.q_style=1;
$result = mysql_query($sql);
//now one-by-one go through the questions
while($row = mysql_fetch_assoc($result)) {
//if the form has been submitted, and the question unanswered
//highlight this whole question and answer block in red.
if ($message[$row['q_name']] == 1){
echo div class='error';
}
//Make a question set div wrapper
echo div class='q_set'\n;
//State the question
echo div class='question';
echo $row['q_text'] . /div;
echo \n\n;
echo div class='answer';
echo \n;
//Create the dropdown for the answers
echo ' select name=' . $row['q_name'] . '';
echo \n;
//get all of the answers for THIS question
$ans_sql = select * from answers where answers.q_id= . $row['q_id'];
$ans_result = mysql_query($ans_sql);
echo option value=\\Select from this list/option\n;
while($ans_row = mysql_fetch_assoc($ans_result)) {
//list the answers for THIS question
echo option ;
echo value=\ . $ans_row['a_id'] . \;
if ($row['q_name'] == $ans_row['a_id']) {
echo selected;
}
echo . $ans_row['a_answer'] . /option;
echo \n;
}
echo ' /select' . \n . ' /div' . \n;
echo /div!--q_set--\n\n;
//If there *was* an error div, close it
if (sizeof($message[$row['q_name']])){
echo /div!--/error--;
}
}
}//function GetQuestionsDropdown
NOW I have to validate after it's submitted. I am trying to look and
see, if $_POST[$row['q_name']] is empty then make message of the same
name = 1, so if
if(empty($_POST['partners'])) {
$message['partners'] = '1'
}
Then when I restate the dropdown function, and it shows the questions
again, those error checking things I built in will
a) show a div class=error around questions with a message
b) pre-select the previously selected answers (because I have put in
the thing in the dropdown which says
if ($row['q_name'] == $ans_row['a_id']) { echo selected;}
The validate code I was trying, the subject of such howling on IRC (and
I know it doesn't work, but not why) was:
function ValidatePost($cat){
//first get the q_names
$sql = SELECT * FROM questions WHERE q_cat=$cat;
$result = mysql_query($sql);
//go through the question set
while($row = mysql_fetch_assoc($result)) {
if(empty($_POST[$row['q_name']])){
$message[$row['q_name']] == 1;
}
}
}//function ValidatePost
Can anyone tell me what I am doing wrong?
Thanks!
JJ
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Re: [PHP] error checking woes
Okay, last attempt before I hit my head against wall. I thought perhaps
to add the error check to the dropdown function itself:
function GetQuestionsDropdown($cat){
//first get all the questions
$sql = SELECT * FROM questions WHERE questions.q_cat=$cat AND
questions.q_style=1;
$result = mysql_query($sql);
//now one-by-one go through the questions
while($row = mysql_fetch_assoc($result)) {
//if the form has been submitted, and the question unanswered
//highlight this whole question and answer block in red.
if ($message[$row['q_name']] == 1){
echo div class='error';
}
//Make a question set div wrapper
echo div class='q_set'\n;
//State the question
echo div class='question';
echo $row['q_text'] . /div;
echo \n\n;
echo div class='answer';
echo \n;
//Create the dropdown for the answers
echo ' select name=' . $row['q_name'] . '';
echo \n;
//get all of the answers for THIS question
$ans_sql = select * from answers where answers.q_id= . $row['q_id'];
$ans_result = mysql_query($ans_sql);
echo option value=\\Select from this list/option\n;
while($ans_row = mysql_fetch_assoc($ans_result)) {
//list the answers for THIS question
echo option ;
echo value=\ . $ans_row['a_id'] . \;
if ($row['q_name'] == $ans_row['a_id']) {
echo selected;
}
echo . $ans_row['a_answer'] . /option;
echo \n;
}
echo ' /select' . \n . ' /div' . \n;
echo /div!--q_set--\n\n;
//If there *was* an error div, close it
if (sizeof($message[$row['q_name']])){
echo /div!--/error--;
}
//error checking
if ( !strcmp($action,'process') ) {
if(empty($_POST[$row['q_name']])){
$message[$row['q_name']] == 1;
}
}
}
}//function GetQuestionsDropdown
it didn't work either.
Jack Jackson wrote:
Hi,
Now that the drop down is working properly (thanks!!), I am trying to
validate, and having LOTS of trouble. After being ceaselessly derided
last night on an irc channel for my dimwitedness, I am still not any
closer.
The code which works is this:
function GetQuestionsDropdown($cat){
//first get all the questions
$sql = SELECT * FROM questions WHERE questions.q_cat=$cat AND
questions.q_style=1;
$result = mysql_query($sql);
//now one-by-one go through the questions
while($row = mysql_fetch_assoc($result)) {
//if the form has been submitted, and the question unanswered
//highlight this whole question and answer block in red.
if ($message[$row['q_name']] == 1){
echo div class='error';
}
//Make a question set div wrapper
echo div class='q_set'\n;
//State the question
echo div class='question';
echo $row['q_text'] . /div;
echo \n\n;
echo div class='answer';
echo \n;
//Create the dropdown for the answers
echo ' select name=' . $row['q_name'] . '';
echo \n;
//get all of the answers for THIS question
$ans_sql = select * from answers where answers.q_id= . $row['q_id'];
$ans_result = mysql_query($ans_sql);
echo option value=\\Select from this list/option\n;
while($ans_row = mysql_fetch_assoc($ans_result)) {
//list the answers for THIS question
echo option ;
echo value=\ . $ans_row['a_id'] . \;
if ($row['q_name'] == $ans_row['a_id']) {
echo selected;
}
echo . $ans_row['a_answer'] . /option;
echo \n;
}
echo ' /select' . \n . ' /div' . \n;
echo /div!--q_set--\n\n;
//If there *was* an error div, close it
if (sizeof($message[$row['q_name']])){
echo /div!--/error--;
}
}
}//function GetQuestionsDropdown
NOW I have to validate after it's submitted. I am trying to look and
see, if $_POST[$row['q_name']] is empty then make message of the same
name = 1, so if
if(empty($_POST['partners'])) {
$message['partners'] = '1'
}
Then when I restate the dropdown function, and it shows the questions
again, those error checking things I built in will
a) show a div class=error around questions with a message
b) pre-select the previously selected answers (because I have put
Re: [PHP] Dropdown Building Function
Hi, can anyone even point me in a *direction*? I suppose this is the
most complex thing I've ever tried to do and I have been at it for tens
of hours and am still completely baffled.
Jack Jackson wrote:
Hi,
because that last topic on multipage forms was so exciting, I decided to
database the questions as well. I wonder if anyone can help me with a
function to pull rows into dropdown boxes.
It's a 1:n relationship between questions and answers, and I have a
table of questions
q_id
q_name
q_text
q_style //dropdown, radio, checkboxes
q_cat //question category
and a table full of answers
a_id
q_id
a_answer
When I do
$fields = 'SELECT *';
$from = 'FROM questions,answers';
$sort = ORDER BY questions.q_cat;
$where = WHERE answers.q_id=questions.q_id;
// construct the sql query:
$sql = $fields $from $where $sort;
// Run SQL query 1
if (!($result = mysql_query($sql))) {
echo Could not connect to the database ($sql) . mysql_error();
}
while ($row = mysql_fetch_assoc($result)) {
I need to loop through the results and make a dropdown list from them,
taking the question name as the select name, and then making each answer
id and answer text the makings of an option ros.
Based on a problem a while ago which was similar but different, someone
here actually made me a function *similar* to what I need to do now,
This one acts different and I just cannot adapt the old one, because I
still get confused at this level.
I think it wants to be something like (and note that part of the return
is the code to react to error checking results):
$dropdown[] = 'option ?php if (' . $q_name . ' == ' . $a_id . ')
echo selected ; ? value=\'' . $a_id . '\'' . $a_answer . '/option';
etc for all $a_answer(s)...
and then
return '?php if (sizeof($message[\'' . $q_name . '\'])){ echo div
class='error'; } ?
div class=\'row\'
select class=\'answer\' name=\'' . $q_name . '\'
option value=\'\'Select from this list/option'
join('',$dropdown)
. '/select/div'
. '?php if (sizeof($message[\''. $q_name '\'])){ echo
/div!--/error--; } ?';
Can anyone point me at the right direction?
Thanks!!
JJ
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Re: [PHP] Dropdown Building Function
Hi, Jay,
I see perhaps I *was* thinking too complex. However this is *just* a bit
off:
Jay Blanchard wrote:
[snip]
Hi, can anyone even point me in a *direction*? I suppose this is the
most complex thing I've ever tried to do and I have been at it for tens
of hours and am still completely baffled.
Jack Jackson wrote:
Hi,
because that last topic on multipage forms was so exciting, I decided
to
database the questions as well. I wonder if anyone can help me with a
function to pull rows into dropdown boxes.
It's a 1:n relationship between questions and answers, and I have a
table of questions
q_id
q_name
q_text
q_style //dropdown, radio, checkboxes
q_cat //question category
and a table full of answers
a_id
q_id
a_answer
When I do
$fields = 'SELECT *';
$from = 'FROM questions,answers';
$sort = ORDER BY questions.q_cat;
$where = WHERE answers.q_id=questions.q_id;
// construct the sql query:
$sql = $fields $from $where $sort;
// Run SQL query 1
if (!($result = mysql_query($sql))) {
echo Could not connect to the database ($sql) . mysql_error();
}
while ($row = mysql_fetch_assoc($result)) {
I need to loop through the results and make a dropdown list from them,
taking the question name as the select name, and then making each
answer
id and answer text the makings of an option ros.
Based on a problem a while ago which was similar but different,
someone
here actually made me a function *similar* to what I need to do now,
This one acts different and I just cannot adapt the old one, because I
still get confused at this level.
I think it wants to be something like (and note that part of the
return
is the code to react to error checking results):
$dropdown[] = 'option ?php if (' . $q_name . ' == ' . $a_id . ')
echo selected ; ? value=\'' . $a_id . '\'' . $a_answer .
'/option';
etc for all $a_answer(s)...
and then
return '?php if (sizeof($message[\'' . $q_name . '\'])){ echo div
class='error'; } ?
div class=\'row\'
select class=\'answer\' name=\'' . $q_name . '\'
option value=\'\'Select from this list/option'
join('',$dropdown)
. '/select/div'
. '?php if (sizeof($message[\''. $q_name '\'])){ echo
/div!--/error--; } ?';
Can anyone point me at the right direction?
Thanks!!
JJ
[/snip]
It seems that you have over-complicated the issue, let me boil it down a
little;
$sql = select answer from table ;
if(!($result = mysql_query($sql, $connection))){
echo mysql_error() . \n;
exit();
}
echo select name=\answers\\n;
while($row = mysql_fetch_array($result)){
echo option name=\. $row['answer'] . \;
echo $row['answer'];
echo /option\n;
}
echo /select\n;
Your out put will look like this;
select name=answers
option name=answer1answer1/option
option name=answer2answer2/option
option name=answer3answer3/option
/select
Is this what you're after?
Very close to it, thank you! However this completes the gap: I am still
not sure if my syntax is right:
$sql = 'SELECT *
FROM questions,answers
WHERE answers.q_id=questions.q_id
ORDER BY questions.q_cat,questions.q_id,answers.q_id';
if(!($result = mysql_query($sql, $connection))){
echo mysql_error() . \n;
exit();
}
/*each question has at least one answer, usually three to six
*I need to give the select the name of $q_name
*and dynamically loop through until all the question/answer
*sets have their own dropdown
*/
echo select name=\' . $q_name . \'\n;
while($row = mysql_fetch_array($result)){
echo option name=\. $row['a_id'] . \;
echo ?php if . \$$q_name . == . $a_id . echo \selected \
?\n;
echo $row['$a_answer'];
echo /option\n;
}
echo /select\n;
Then hopefully my output would look like
select name=question_name
option ?php if $question_name == 1 echo selected ?
value=1Answer One/option
select name=question_name
option ?php if $question_name == 2 echo selected ?
value=2Answer Two/option
select name=question_name
option ?php if $question_name == 1 echo selected ?
value=3Answer Two/option
/select
TIA!!
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Re: [PHP] Dropdown Building Function
Kristen,
Thank you so much this is precisely what I was trying to accomplish.
However I was also trying to learn how to do it with those arrays you
mentioned which I figure will help me emerge from total newbieness.
To date, I hope the list has seen I've progressed from absolutely *no*
programming experience whatever to the point where I feel comfortable
saying I am a newbie programmer (as opposed to a clueless one).
But Multidimensional arrays still baffle me and I believe that certain
aspects of them work by magic!
I hope that people here will help me figure out both approaches. And
thank you so much for the code here and the fix, which even I can follow!
JJ
Kristen G. Thorson wrote:
I'm not 100% sure where you're saying you're stuck, but I think you're
trying to do with one query what you will probably find is best to do
with several. Hopefully the following will help some:
//first get all the questions
$sql = select * from questions;
$result = mysql_query( $sql );
//now one-by-one go through the questions
while( $row = mysql_fetch_row( $result ) {
//create the drop down box for THIS question
echo 'select name='.$row['question_text'].'';
//get all of the answers for THIS question
$ans_sql = select * from answers where
question_id=.$row['question_id'];
$ans_result = mysql_query( $ans_sql );
while( $ans_row = mysql_fetch_row( $ans_result ) ) {
//list the answers for THIS question
echo 'option
value='.$ans_row['answer_id'].''.$ans_row['answer_text'].'/option';
}
echo '/select';
}
outputs:
select name=question1
option value=1answer 1/option
option value=2answer 2/option
option value=3answer 3/option
select name=question2
option value=1answer 1/option
option value=2answer 2/option
option value=3answer 3/option
option value=4answer 4/option
option value=5answer 5/option
It requires numerous DB calls, but I believe in most cases, it's still
better than what you'd have to do otherwise (create some arrays and do
some sorting, etc.). That is, if I've understood what you need ;)
kgt
Jack Jackson wrote:
Hi, can anyone even point me in a *direction*? I suppose this is the
most complex thing I've ever tried to do and I have been at it for
tens of hours and am still completely baffled.
Jack Jackson wrote:
Hi,
because that last topic on multipage forms was so exciting, I decided
to database the questions as well. I wonder if anyone can help me
with a function to pull rows into dropdown boxes.
It's a 1:n relationship between questions and answers, and I have a
table of questions
q_id
q_name
q_text
q_style //dropdown, radio, checkboxes
q_cat //question category
and a table full of answers
a_id
q_id
a_answer
When I do
$fields = 'SELECT *';
$from = 'FROM questions,answers';
$sort = ORDER BY questions.q_cat;
$where = WHERE answers.q_id=questions.q_id;
// construct the sql query:
$sql = $fields $from $where $sort;
// Run SQL query 1
if (!($result = mysql_query($sql))) {
echo Could not connect to the database ($sql) . mysql_error();
}
while ($row = mysql_fetch_assoc($result)) {
I need to loop through the results and make a dropdown list from
them, taking the question name as the select name, and then making
each answer id and answer text the makings of an option ros.
Based on a problem a while ago which was similar but different,
someone here actually made me a function *similar* to what I need to
do now, This one acts different and I just cannot adapt the old one,
because I still get confused at this level.
I think it wants to be something like (and note that part of the
return is the code to react to error checking results):
$dropdown[] = 'option ?php if (' . $q_name . ' == ' . $a_id . ')
echo selected ; ? value=\'' . $a_id . '\'' . $a_answer .
'/option';
etc for all $a_answer(s)...
and then
return '?php if (sizeof($message[\'' . $q_name . '\'])){ echo
div class='error'; } ?
div class=\'row\'
select class=\'answer\' name=\'' . $q_name . '\'
option value=\'\'Select from this list/option'
join('',$dropdown)
. '/select/div'
. '?php if (sizeof($message[\''. $q_name '\'])){ echo
/div!--/error--; } ?';
Can anyone point me at the right direction?
Thanks!!
JJ
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Re: [PHP] Dropdown Building Function
And of course, I am finding that this way of yours is the easiest!!
Thanks, again, Kristen
JJ
Kristen G. Thorson wrote:
I'm not 100% sure where you're saying you're stuck, but I think you're
trying to do with one query what you will probably find is best to do
with several. Hopefully the following will help some:
//first get all the questions
$sql = select * from questions;
$result = mysql_query( $sql );
//now one-by-one go through the questions
while( $row = mysql_fetch_row( $result ) {
//create the drop down box for THIS question
echo 'select name='.$row['question_text'].'';
//get all of the answers for THIS question
$ans_sql = select * from answers where
question_id=.$row['question_id'];
$ans_result = mysql_query( $ans_sql );
while( $ans_row = mysql_fetch_row( $ans_result ) ) {
//list the answers for THIS question
echo 'option
value='.$ans_row['answer_id'].''.$ans_row['answer_text'].'/option';
}
echo '/select';
}
outputs:
select name=question1
option value=1answer 1/option
option value=2answer 2/option
option value=3answer 3/option
select name=question2
option value=1answer 1/option
option value=2answer 2/option
option value=3answer 3/option
option value=4answer 4/option
option value=5answer 5/option
It requires numerous DB calls, but I believe in most cases, it's still
better than what you'd have to do otherwise (create some arrays and do
some sorting, etc.). That is, if I've understood what you need ;)
kgt
Jack Jackson wrote:
Hi, can anyone even point me in a *direction*? I suppose this is the
most complex thing I've ever tried to do and I have been at it for
tens of hours and am still completely baffled.
Jack Jackson wrote:
Hi,
because that last topic on multipage forms was so exciting, I decided
to database the questions as well. I wonder if anyone can help me
with a function to pull rows into dropdown boxes.
It's a 1:n relationship between questions and answers, and I have a
table of questions
q_id
q_name
q_text
q_style //dropdown, radio, checkboxes
q_cat //question category
and a table full of answers
a_id
q_id
a_answer
When I do
$fields = 'SELECT *';
$from = 'FROM questions,answers';
$sort = ORDER BY questions.q_cat;
$where = WHERE answers.q_id=questions.q_id;
// construct the sql query:
$sql = $fields $from $where $sort;
// Run SQL query 1
if (!($result = mysql_query($sql))) {
echo Could not connect to the database ($sql) . mysql_error();
}
while ($row = mysql_fetch_assoc($result)) {
I need to loop through the results and make a dropdown list from
them, taking the question name as the select name, and then making
each answer id and answer text the makings of an option ros.
Based on a problem a while ago which was similar but different,
someone here actually made me a function *similar* to what I need to
do now, This one acts different and I just cannot adapt the old one,
because I still get confused at this level.
I think it wants to be something like (and note that part of the
return is the code to react to error checking results):
$dropdown[] = 'option ?php if (' . $q_name . ' == ' . $a_id . ')
echo selected ; ? value=\'' . $a_id . '\'' . $a_answer .
'/option';
etc for all $a_answer(s)...
and then
return '?php if (sizeof($message[\'' . $q_name . '\'])){ echo
div class='error'; } ?
div class=\'row\'
select class=\'answer\' name=\'' . $q_name . '\'
option value=\'\'Select from this list/option'
join('',$dropdown)
. '/select/div'
. '?php if (sizeof($message[\''. $q_name '\'])){ echo
/div!--/error--; } ?';
Can anyone point me at the right direction?
Thanks!!
JJ
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Re: [PHP] Dropdown Building Function
Aaron,
Thanks for showing me this it is very cool indeed.
However maybe I am being dumb and obdurate but what I am really trying
to do is build some of these things myself (with, thankfully, help) so
that I understand enough that when I see a great tool like yours I'll
actually appreciate what it's doing for me. I can see that your tool is
doing everything in one line, and I think its really great. I just am
such a beginner that I think tools like that would encourage me to
*never* get above this level I'm at now.
I got the questions and answers thing working, starting with Kristen's
two-query code and moving from there. I would like to come back to see
how it can be done with one query and one function, but at this point my
eyes are so bleary I'm grateful for the fact that I can now focus on
getting the form to process!
Thanks again
JJ
Aaron Greenspan wrote:
Jay,
This is why I think frameworks are helpful Here's how I'd do it with
Lampshade in one line of code with my own hypothetical field names:
dropdownBox('answerid', SELECT answerid, CONCAT(questions.description,'
- ',answers.description) AS display FROM questions LEFT JOIN answers ON
questions.questionid=answers.questionid ORDER BY questions.description,
answers.description, $myrow['answerid'], 'Question and Answer', 'Choose
an Answer');
For more information on this function:
http://www.thinkcomputer.com/software/lampshade/documentation.html?function=dropdownBox
I'd be happy to help you get it set up if you have any questions.
Aaron
Aaron Greenspan
President CEO
Think Computer Corporation
http://www.thinkcomputer.com
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Re: [PHP] Dropdown Building Function
Kristen G. Thorson wrote:
I'm not 100% sure where you're saying you're stuck, but I think you're
trying to do with one query what you will probably find is best to do
with several. Hopefully the following will help some:
//first get all the questions
$sql = select * from questions;
$result = mysql_query( $sql );
//now one-by-one go through the questions
while( $row = mysql_fetch_row( $result ) {
//create the drop down box for THIS question
echo 'select name='.$row['question_text'].'';
//get all of the answers for THIS question
$ans_sql = select * from answers where
question_id=.$row['question_id'];
$ans_result = mysql_query( $ans_sql );
while( $ans_row = mysql_fetch_row( $ans_result ) ) {
//list the answers for THIS question
echo 'option
value='.$ans_row['answer_id'].''.$ans_row['answer_text'].'/option';
}
echo '/select';
}
outputs:
select name=question1
option value=1answer 1/option
option value=2answer 2/option
option value=3answer 3/option
select name=question2
option value=1answer 1/option
option value=2answer 2/option
option value=3answer 3/option
option value=4answer 4/option
option value=5answer 5/option
It requires numerous DB calls, but I believe in most cases, it's still
better than what you'd have to do otherwise (create some arrays and do
some sorting, etc.). That is, if I've understood what you need ;)
And it did!!
//first get all the questions
$sql = select * from questions ORDER BY q_cat;
$result = mysql_query($sql);
//now one-by-one go through the questions
while($row = mysql_fetch_assoc($result)) {
//if the form has been submitted, and the question unanswered
//highlight this whole question and answer block in red.
if (sizeof($message[$row['q_name']])){
echo div class='error';
}
//State the question
echo div class='question';
echo $row['q_text'] . /div;
echo \n\n;
echo div class='answer';
echo \n;
//Create the dropdown for the answers
echo ' select name=' . $row['q_name'] . '';
echo \n;
//get all of the answers for THIS question
$ans_sql = select * from answers where answers.q_id= . $row['q_id'];
$ans_result = mysql_query($ans_sql);
echo option value=\\Select from this list/option\n;
while($ans_row = mysql_fetch_assoc($ans_result)) {
//list the answers for THIS question
echo option ;
echo value=\ . $ans_row['a_id'] . \;
if ($row['q_name'] == $ans_row['a_id']) {
echo selected;
}
echo . $ans_row['a_answer'] . /option;
echo \n;
}
echo ' /select' . \n . ' /div' . \n\n;
//If there *was* an error div, close it
if (sizeof($message[$row['q_name']])){
echo /div!--/error--;
}
}
Thanks so much!
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Re: [PHP] Multipage form redux
Somehow my intent has been turned around here and I apologise. I do not want to use *any* client side validation. I only want to do server side validation and server side storage. My intent was to remove the client from as much as possible of this - if I didn't need their information I wouldn't even allow clients!! :) What I wanted to do was this: p. 1 : I send client page one, they send answers. SUBMIT sends to page 2 script. p 2. Before displaying anything to the client, Page 2 script validates input from page 1. If there are problems, page 2 script redisplays page one questions with highlights around problems. Clicking submit then resubmits page one data to page 2 script. Once page 2 script validates all page 1 answers, page 2 script stores all those answers to a SESSION, then sends PAGE 2 QUESTIONS ONLY (no $_POST information) to client. Client answers page 2 questions and clicking submit submits PAGE 2 QUESTIONS to page 3 script. p 3. Before displaying anything to the client, Page 3 script validates input from page 2 questions. If there are problems, page 3 script redisplays page 2 questions with highlights around problems. Clicking submit resubmits page 2 data to page 3 script. Once page 3 script validates all page 2 answers, the script stores all those answers to a SESSION, then sends PAGE 3 QUESTIONS ONLY (no $_POST information) to client. Client answers page 3 questions and clicking submit submits PAGE 3 QUESTIONS to page 4 script. At this point, if the client goes off for a bite, or two weeks backpacking in the Anapurna region, I'm fine, because the information is stored in the session (I have a very small group taking this questionnaire, all have a vested interested in filling it in, so I am not too worried abou their going aaway from it for more than a couple days max). Once they complete the last set of questions, I say thanks much, get all the information out of their SESSION, insert it into the db, send confirmation emails all around and we're done. Is this possible? How? Thanks! Marcus Bointon wrote: On 27 Jul 2005, at 21:22, Jack Jackson wrote: Right. Except I would rather have it working in a session because I specifically do not want to have the form sending $_POST data back and forth to the browser six times for several reasons. SO I'd like to Page1 // User enters first batch of data, presses SUBMIT at bottom. Data is cleaned and written to SESSION, user passed to Page2 repeat as necessary to last page. At last page, process and error check newest input, then commit it, plus all previously stored session info to db. As has also been said, Javascript can do this really nicely. The best example I've seen of this is in Mambo's (a popular PHP CMS) admin interface. It uses a tabbed multi-page form with client-side validation. It's really just one big page, so if the user has JS turned off, they will get one big form with no client-side validation, but it will still work. It's a really elegant way of working. It doesn't require any server interaction between pages - nothing is submitted until the form is complete. See here for a howto: http://www.devx.com/webdev/Article/10483/1763/ page/1 Admittedly this approach doesn't easily allow to you abandon and resume later (unless you get clever with JS and cookies). For keeping data in a session, you could combine this approach with Ajax: http://particletree.com/features/smart-validation-with-ajax Marcus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Multipage form redux
The light dawns. Thank you everyone for this explanation, and the help JJ Mark Rees wrote: Jack Jackson [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Somehow my intent has been turned around here and I apologise. I do not want to use *any* client side validation. I only want to do server side validation and server side storage. My intent was to remove the client from as much as possible of this - if I didn't need their information I wouldn't even allow clients!! :) What I wanted to do was this: p. 1 : I send client page one, they send answers. SUBMIT sends to page 2 script. p 2. Before displaying anything to the client, Page 2 script validates input from page 1. If there are problems, page 2 script redisplays page one questions with highlights around problems. Clicking submit then resubmits page one data to page 2 script. Once page 2 script validates all page 1 answers, page 2 script stores all those answers to a SESSION, then sends PAGE 2 QUESTIONS ONLY (no $_POST information) to client. Client answers page 2 questions and clicking submit submits PAGE 2 QUESTIONS to page 3 script. p 3. Before displaying anything to the client, Page 3 script validates input from page 2 questions. If there are problems, page 3 script redisplays page 2 questions with highlights around problems. Clicking submit resubmits page 2 data to page 3 script. Once page 3 script validates all page 2 answers, the script stores all those answers to a SESSION, then sends PAGE 3 QUESTIONS ONLY (no $_POST information) to client. Client answers page 3 questions and clicking submit submits PAGE 3 QUESTIONS to page 4 script. At this point, if the client goes off for a bite, or two weeks backpacking in the Anapurna region, I'm fine, because the information is stored in the session (I have a very small group taking this questionnaire, all have a vested interested in filling it in, so I am not too worried abou their going aaway from it for more than a couple days max). Once they complete the last set of questions, I say thanks much, get all the information out of their SESSION, insert it into the db, send confirmation emails all around and we're done. Sessions are used to identify users on a single visit to a website. They are not intended to track users who turn off their machines, then turn them on again and visit the website again. There are various ways of doing this, and for all I know it may be possible with sessions, but I don't recommend you try. Do as suggested previously by various posters, it is the simplest and most robust solution to your problem: 1. have the user register their details first up. Store this in a db, and use it to identify the user on any subsequent visit. 2. when each page is submitted, write the information into the db. This way it will definitely be associated with the right user 3. Whenever a user revisits the questionnaire, make them log in, then take them to wherever they were up to - you will be able to work this out from the amount of data you have recorded against them. e.g. database table userid question question question question question question Is this possible? How? Thanks! Marcus Bointon wrote: On 27 Jul 2005, at 21:22, Jack Jackson wrote: Right. Except I would rather have it working in a session because I specifically do not want to have the form sending $_POST data back and forth to the browser six times for several reasons. SO I'd like to Page1 // User enters first batch of data, presses SUBMIT at bottom. Data is cleaned and written to SESSION, user passed to Page2 repeat as necessary to last page. At last page, process and error check newest input, then commit it, plus all previously stored session info to db. As has also been said, Javascript can do this really nicely. The best example I've seen of this is in Mambo's (a popular PHP CMS) admin interface. It uses a tabbed multi-page form with client-side validation. It's really just one big page, so if the user has JS turned off, they will get one big form with no client-side validation, but it will still work. It's a really elegant way of working. It doesn't require any server interaction between pages - nothing is submitted until the form is complete. See here for a howto: http://www.devx.com/webdev/Article/10483/1763/ page/1 Admittedly this approach doesn't easily allow to you abandon and resume later (unless you get clever with JS and cookies). For keeping data in a session, you could combine this approach with Ajax: http://particletree.com/features/smart-validation-with-ajax Marcus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Multipage form redux
Mark Rees wrote: André Medeiros [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] The point of sessions is that when you close your browser, you loose it. I'm affraid that if you want sessions that last two weeks, you'll have to make your own session handler :) but yeah, it's possible, and it beats the crap out of the fill form, store in db, fill form, store in db method. Unless your user wishes to complete the form from a different machine, of course. I really don't understand the dogmatic antipathy to storing information in the database. Sometimes it is a better solution - horses for courses. Rolling your own session management tool, whilst undoubtedly fun and satisfying, is hardly an appropriate solution to this type of enquiry, which is apparently from someone taking their first steps in web development. I should probably explain that I come from an ASP background and so have an inherent mistrust of sessions, although I am coming to understand that PHP sessions are much more reliable. Sorry about the three posts before, my mistake. No, I think I wasn't clear because of a fundamental misunderstanding on my part of the problem of SESSIONS not lasting between ... uh... sessions. In fact I think my very first post on the subject did in fact say I wanted to store the answers on the db throughout the process, but I got so excited at the prospect of having sessions store things that I got distracted. Anyway, thanks again to all who replied and for all the help I generally receive here on the list!! JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Dropdown Building Function
Hi,
because that last topic on multipage forms was so exciting, I decided to
database the questions as well. I wonder if anyone can help me with a
function to pull rows into dropdown boxes.
It's a 1:n relationship between questions and answers, and I have a
table of questions
q_id
q_name
q_text
q_style //dropdown, radio, checkboxes
q_cat //question category
and a table full of answers
a_id
q_id
a_answer
When I do
$fields = 'SELECT *';
$from = 'FROM questions,answers';
$sort = ORDER BY questions.q_cat;
$where = WHERE answers.q_id=questions.q_id;
// construct the sql query:
$sql = $fields $from $where $sort;
// Run SQL query 1
if (!($result = mysql_query($sql))) {
echo Could not connect to the database ($sql) . mysql_error();
}
while ($row = mysql_fetch_assoc($result)) {
I need to loop through the results and make a dropdown list from them,
taking the question name as the select name, and then making each answer
id and answer text the makings of an option ros.
Based on a problem a while ago which was similar but different, someone
here actually made me a function *similar* to what I need to do now,
This one acts different and I just cannot adapt the old one, because I
still get confused at this level.
I think it wants to be something like (and note that part of the return
is the code to react to error checking results):
$dropdown[] = 'option ?php if (' . $q_name . ' == ' . $a_id . ')
echo selected ; ? value=\'' . $a_id . '\'' . $a_answer . '/option';
etc for all $a_answer(s)...
and then
return '?php if (sizeof($message[\'' . $q_name . '\'])){ echo div
class='error'; } ?
div class=\'row\'
select class=\'answer\' name=\'' . $q_name . '\'
option value=\'\'Select from this list/option'
join('',$dropdown)
. '/select/div'
. '?php if (sizeof($message[\''. $q_name '\'])){ echo
/div!--/error--; } ?';
Can anyone point me at the right direction?
Thanks!!
JJ
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[PHP] Multipage form redux
Hi, I have searched the archives and seen links to tutorials at phpclasses (which seem to be down) and not found an answer to my question: I have a long form I want to break into seven pages. Rather than pass values from page to page as hidden, I'd rather write the results to the db after each page then move on. Anyone know of any tutorials on this? Thanks in advance, JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Multipage form redux
Thanks everyone. I take the point of Andre, but believe that the depth and sensitivity of the data require it be stored server side. I think that Richard and Mark have put their fingers on it - it's gotta be cookie based. Someone on the IRC suggested sessions and I think that it the way it goes. As for the idea that new users would be sent packing by such a ridiculously long form, right on! This is a form to be filled in by a client of the company after they've hired to company to provide an assessment of ther practices, so they'd expect a long form. But point taken Thanks everyone for replying so quickly! I'll come back when I botch the sessions and need help fixing!! JJ Richard Davey wrote: Hello André, Wednesday, July 27, 2005, 2:22:30 PM, you wrote: AM That's not a very good idea. Imagine the user gets to the fourth AM form and gets a cup of coffee, or goes out to lunch. By the time AM he gets to the computer he might have lost the session, thus AM having data on your DB that is wasting space. AM And what if the user closes the browser window? :) All of those things are unavoidable no matter what technique you use :) I've seen multi-page forms with a Finish this later option that issues a cookie to your browser, allowing you to visit the site at any (realistic) point in the future and carry on. In which cases the part-filled contents must already be in a database somewhere. This isn't a bad thing imho, it's a nice touch. Of course it's prone to the usual browser doesn't accept cookies / browser deletes cookies syndrome though. If you don't want to pass the form values across in a hidden manner (and I don't blame you) then it's either dump it all in a session and hope it doesn't time-out, or dump it into a database, issue the visitor some link to that entry (cookie, session var) and again hope they don't time out. The only real difference being the DB option will need purging to get rid of incomplete forms X days old. But that in itself could prove a useful statistic for reports. Unless you're dealing with thousands of sign-ups an hour, I don't see any issue with this option. Another technique might be the following - rethink how your forms work. Exactly what is it you're collecting data about? If it's part of a long sign-up process then you could consider changing the process around a bit - so that the VERY first thing the user does is create a temporary account on your site (call them incomplete users). So you grab some method of login + authentication details from them. Then the form pages following this can all be saved to a DB and linked to that user. So, as long as they complete this first step, they can always come back and finish the job off - whenever they want, avoiding cookie and session time-out issues. This won't work for all forms of course, it depends what the nature of the process is, but it's certainly an option. Best regards, Richard Davey -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Multipage form redux
hi, my first attempt at a sessions-based form is starting at
http://pastebin.com/322696
and I have a question. What I want to do is, after the user answers the
questions in section one and they are error checked, I want to write the
answers to $_SESSION() and then continue down the script to the next
page of questions. I do *not* want to re-send the answers from page one
as $_POST vars back to the user and have the user submit the answers to
page 2 plus the $_POST answers from page 1.
What I am doing now is clearly wrong, basically :
if (empty($error)) {
include_once($page2);
}
because that's keeping it all in one script. But how should I be getting
to the next page, sending headers to a new script, and at the end of the
chain the script which pulls it all together?
Thanks in advance,
JJ
Jack Jackson wrote:
Thanks everyone. I take the point of Andre, but believe that the depth
and sensitivity of the data require it be stored server side. I think
that Richard and Mark have put their fingers on it - it's gotta be
cookie based. Someone on the IRC suggested sessions and I think that it
the way it goes. As for the idea that new users would be sent packing by
such a ridiculously long form, right on! This is a form to be filled in
by a client of the company after they've hired to company to provide an
assessment of ther practices, so they'd expect a long form. But point taken
Thanks everyone for replying so quickly!
I'll come back when I botch the sessions and need help fixing!!
JJ
Richard Davey wrote:
Hello André,
Wednesday, July 27, 2005, 2:22:30 PM, you wrote:
AM That's not a very good idea. Imagine the user gets to the fourth
AM form and gets a cup of coffee, or goes out to lunch. By the time
AM he gets to the computer he might have lost the session, thus
AM having data on your DB that is wasting space.
AM And what if the user closes the browser window? :)
All of those things are unavoidable no matter what technique you use
:)
I've seen multi-page forms with a Finish this later option that
issues a cookie to your browser, allowing you to visit the site at any
(realistic) point in the future and carry on. In which cases the
part-filled contents must already be in a database somewhere. This
isn't a bad thing imho, it's a nice touch.
Of course it's prone to the usual browser doesn't accept cookies /
browser deletes cookies syndrome though.
If you don't want to pass the form values across in a hidden manner
(and I don't blame you) then it's either dump it all in a session and
hope it doesn't time-out, or dump it into a database, issue the
visitor some link to that entry (cookie, session var) and again hope
they don't time out.
The only real difference being the DB option will need purging to get
rid of incomplete forms X days old. But that in itself could prove a
useful statistic for reports. Unless you're dealing with thousands of
sign-ups an hour, I don't see any issue with this option.
Another technique might be the following - rethink how your forms
work. Exactly what is it you're collecting data about? If it's part of
a long sign-up process then you could consider changing the process
around a bit - so that the VERY first thing the user does is create a
temporary account on your site (call them incomplete users). So you
grab some method of login + authentication details from them. Then the
form pages following this can all be saved to a DB and linked to that
user.
So, as long as they complete this first step, they can always come
back and finish the job off - whenever they want, avoiding cookie and
session time-out issues.
This won't work for all forms of course, it depends what the nature of
the process is, but it's certainly an option.
Best regards,
Richard Davey
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Re: [PHP] Multipage form redux
Jim Moseby wrote:
-Original Message-
From: Jack Jackson [mailto:[EMAIL PROTECTED]
Sent: Wednesday, July 27, 2005 3:47 PM
To: php [php] PHP General List
Subject: Re: [PHP] Multipage form redux
hi, my first attempt at a sessions-based form is starting at
http://pastebin.com/322696
and I have a question. What I want to do is, after the user
answers the
questions in section one and they are error checked, I want
to write the
answers to $_SESSION() and then continue down the script to the next
page of questions. I do *not* want to re-send the answers
from page one
as $_POST vars back to the user and have the user submit the
answers to
page 2 plus the $_POST answers from page 1.
What I am doing now is clearly wrong, basically :
if (empty($error)) {
include_once($page2);
}
because that's keeping it all in one script. But how should I
be getting
to the next page, sending headers to a new script, and at the
end of the
chain the script which pulls it all together?
Thanks in advance,
JJ
This seems so simple to me. As I understand it, you want to split a data
entry session into several pages. You don't want to collect the data and
submit it all at the end, but instead commit it to session variables along
the way. Am I missing something?
Here's how I would do it in a nutshell:
Page1 // User enters first batch of data, presses SUBMIT at bottom. Data is
POSTed to Page2
Page2 // Commit data from page 1 to session variables, then displays form
for next batch of data. User presses SUBMIT, posts data to Page 3.
Page3 // Commit data from page 2 to session variables, then displays form
for next batch of data. User presses SUBMIT, posts data to Page 4.
... etc etc etc (Each page begins by assigning data from the previous page
to session variables)
Page515 // Displays all session variables set in previous pages, asks user
to confirm. User confirms by pressing SUBMIT, confirmation POSTed to page
516, who writes it all to the database, and sends confirmation email.
Personally, I would take the advice of a previous poster and start off
assigning a username and password to the user. Then store each page in the
database as the user progresses. That way, if he is interrupted in the
middle of the process, he won't lose all his data and have to start over.
He can just enter his username and pick up where he left off. You will just
have to write a script that purges old incomplete records. (A great job for
cron!)
JM
Right. Except I would rather have it working in a session because I
specifically do not want to have the form sending $_POST data back and
forth to the browser six times for several reasons. SO I'd like to
Page1 // User enters first batch of data, presses SUBMIT at bottom.
Data is cleaned and written to SESSION, user passed to Page2
repeat as necessary to last page. At last page, process and error check
newest input, then commit it, plus all previously stored session info to
db.
Does this make sense?
Thanks in advance
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[PHP] Prepopulating form fields afer an error
Hi,
I have a form and it does basic error checking after submission; when
the user omits required fields it kicks back the form with highlighted
errors telling them the error of their ways.
I've sussed out that by populating the value of the field with
$fieldvalue I can have that form field populated with the data the
user *did* enter for that field:
something like
input type=text name=email_address value=?php echo $email_address?
That works great. But how can I do the same thing for drop down boxes,
when they select an option?
I tried the unwieldy,
select name='blah'
?php if (!empty(blah)) {
echo option value=';
echo $blah;
echo '
echo $blah;
echo /option\n;
}
?
And that, lo and behold, didn't work. Can anyone offer a suggestion?
Thanks in advance
JJ
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Re: [PHP] Prepopulating form fields afer an error
Thanks so much, Mark, Matt and John! I'll play with all those.
Much appreciated,
JJ
Mark Cain wrote:
Here's the way I do it:
The following is an HTML code snippet with embedded PHP code for the
intelligence.
select name=shipper
option value=DHL ? if ($shipped_via == DHL) echo selected;
?DHL
option value=FedEx ? if ($shipped_via == FedEx) echo selected;
?FedEx
option value=UPS ? if ($shipped_via == UPS) echo selected;
?UPS
/select
Mark Cain
- Original Message -
From: Jack Jackson [EMAIL PROTECTED]
To: [php] PHP General List php-general@lists.php.net
Sent: Monday, July 25, 2005 2:37 PM
Subject: [PHP] Prepopulating form fields afer an error
Hi,
I have a form and it does basic error checking after submission; when
the user omits required fields it kicks back the form with highlighted
errors telling them the error of their ways.
I've sussed out that by populating the value of the field with
$fieldvalue I can have that form field populated with the data the
user *did* enter for that field:
something like
input type=text name=email_address value=?php echo $email_address?
That works great. But how can I do the same thing for drop down boxes,
when they select an option?
I tried the unwieldy,
select name='blah'
?php if (!empty(blah)) {
echo option value=';
echo $blah;
echo '
echo $blah;
echo /option\n;
}
?
And that, lo and behold, didn't work. Can anyone offer a suggestion?
Thanks in advance
JJ
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[PHP] Zipping on the fly
hi, I'm providing a download script which lets trusted users view a directory and select a file to download; I don't want to store the files zipped on the server. Is there a fast, built-in way to zip the selected file on the fly and let the user download the zipped copy? I looked at php.net/zip and didn't see any... Thanks in advance -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Zipping on the fly
Thanks for this Philip and Andre! Philip Hallstrom wrote: hi, I'm providing a download script which lets trusted users view a directory and select a file to download; I don't want to store the files zipped on the server. Is there a fast, built-in way to zip the selected file on the fly and let the user download the zipped copy? I looked at php.net/zip and didn't see any... http://marc.theaimsgroup.com/?r=1w=2q=bl=php-generals=zip Read the PHP ZIP Class messages... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Verifying images with getimagesize()
Edward Vermillion wrote: Sorry to reply to this message but I wanted the OP to find it too... On Jun 23, 2005, at 9:42 AM, Jack Jackson wrote: [snip] Through your help I was able to validate image files using getimagesize() and have made a nice script to upload and rename images. [\snip] I've been meaning to post a reply to a problem I ran into a while back that included validating images with getimagesize(). I've seen a few posts from folks saying this is the way to go and just want to share my experiences. My original problem was that a script I had for batch generating thumbnails from uploaded images was running out of memory. With Richard Lynch's help I was able to track the problem to createimagefromjpeg() using an unholy amount of memory on one particular file, a file that had passed through getimagesize() with no problems. What I found was that if an image ( in this case a jpeg ) is corrupted, but just barely, getimagesize() will let it through. Just for the record I could open it up in Photoshop and that's how I discovered that it was corrupted, the last ten or fifteen rows on the image were gone. Photoshop showed an uncompressed file size of 11M for this image. But what I had to end up doing is setting my memory limit to 48M before createimagefromjpeg() could get enough memory to work with that it finally failed. Just a heads up to anyone that's using getimagesize() to verify an image before running it through createimagefromjpeg(), just because it passes getimagesize() doesn't necessarily mean it's a good image. Edward Vermillion [EMAIL PROTECTED] Thanks for telling me about that, Edward. I apprecate it. Actually in this case I was using it only to verify that it was something like an image to validate the file type before allowing it on the server. But you raise a very good point and I appreciate it. JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Uploading and verifying word and excel files
Thank you for ALL this great information, Richard! I really appreciate all the help. JJ Richard Lynch wrote: On Thu, June 23, 2005 7:42 am, Jack Jackson said: I cannot see a way to validate or examine Word or Excel files for validity (and assume that older word files would validate differently from newer ones). If your PHP does not have the mime_type functions, you could probably use http://php.net/exec with the file utility which does much the same thing under Un*x-like systems. man file on the command line for more info. The PEAR http upload script mentioned twice in the user notes at that manual page does not *seem* to validate other than denying certain extensions like php, php3, etc. I could be wrong of course. Does it catch .asp, .cgi, .pl, .htm, .html, .jpg, .png, .gif, .jpeg, .pdf, and .swf? Cuz at certain directories on *my* server, those are all PHP scripts! Well, okay, .pl and .cgi aren't. Actually, I think I still have a .cgi somewhere that *is* a PHP script... It's equally dangerous either way. Maybe someday they will be on your server, too, once you run into the zillion IE bugs where the URL counts for more than the Content-type: header. It's really Bad Practice to rely on the last N characters of a filename as some kind of Security Measure to stop a serious attack... Also, it seems that directories must be blown wide open (777) to allow the script to copy the file over from /tmp. My ISP won't allow directories to be set to 777 under public_html/ -- but we need to access the files via web browser which is the whole point. Well, requring 777 just plain sucks... You *should* have a directory writable by the PHP user/group as the minimum requirement. If PEAR really and truly requires 777, then that feature of PEAR sucks, and you shouldn't use it. Sorry, PEAR guys. Gotta call 'em as I see 'em. And if the best it can do is outlaw .php .php3 ..., then that ain't much either. I'd rather code it myself than have that weak of a safety. So my questions: 1. How do you validate Word and Excel files before upload? You don't. Any validation done before upload is done on the client, and is therefore something that can be easily bypassed by the savvy user. It might be useful as a User-Interface feature to catch obvious stupid mistakes by honest folk... But it's USELESS as a Security Measure to stop Bad Guys. Oh yeah: You may need to use move_uploaded_file to move the files to a staging area before you use exec/file on them... At least, under *MY* webhost's setup, I can't directly read PHP uploaded files from /tmp, even though PHP can move_uploaded_file() them... That may have been changed/fixed, but it's a possible configuration issue. So, use move_uploaded_file to let PHP do its checks, but put stuff in a staging area that the PHP user can read/write, and is *NOT* in the web-tree. Then, do all of YOUR checks. getimagesize, exec(/usr/bin/file $file...) etc. If that all passes, move the file (again) to its final destination, which should *still* be out-side the web tree on most shared servers. Write a PHP script that only allows files already listed in your database to be served up, and which readfile's the data from outside the webtree to spew it out. *IF* you are on a dedicated server, or *IF* your webhost has a unique UID/GID for you to have directories that no *OTHER* user on that webhost can write to your PHP-writable directories/files, *then* it is probably/maybe just as safe to put stuff in your webtree as to readfile it from outside the web tree... Even then, I'd only do the direct to webtree if performance was a major issue. It just doesn't make sense to me to let untrusted users put stuff in the webtree where they might manage to trick the server into executing it as Perl, PHP, JSP, ASP, or [deity] knows what code to do Evil things. It's gonna be a lot tougher for them to fool PHP's readfile into executing code. Hell, if they can do that, they already own your server. 2. How can I make a passthrough from a file above public_html to one below it so that people can surf in with a browser and download files which have been uploaded by the script? There's an easy one. :-) Put the files *OUTSIDE* your webtree. Then write a PHP script that takes an ID of a valid uploaded file that your previously stored in your database, looks up the path to that file, and use http://php.net/readfile on it. You were real close with passthrough which is http://php.net/passthru which is kind of the same, only not. You'd only put files in the webtree if PHP readfile proved too slow, *AND* you were sure no user on the box could ever manage to infiltrate a damaging file into the webtree... That second one is a pretty Tall Order... I can see somebody justifying it, but, honestly, if the overhead of readfile is that big of a deal, then maybe you're living too close to the edge on performance in the first place, and it's time to buy more/better hardware anyway
[PHP] Uploading and verifying word and excel files
Hi, I checked at http://www.php.net/manual/en/features.file-upload.php and all the user notes, and also the PEAR solution for uploading files and I still have a couple of questions. I need to create a form to allow users to upload (and later to delete) MS word, excel and jpg files. Through your help I was able to validate image files using getimagesize() and have made a nice script to upload and rename images. I cannot see a way to validate or examine Word or Excel files for validity (and assume that older word files would validate differently from newer ones). The PEAR http upload script mentioned twice in the user notes at that manual page does not *seem* to validate other than denying certain extensions like php, php3, etc. I could be wrong of course. Also, it seems that directories must be blown wide open (777) to allow the script to copy the file over from /tmp. My ISP won't allow directories to be set to 777 under public_html/ -- but we need to access the files via web browser which is the whole point. So my questions: 1. How do you validate Word and Excel files before upload? 2. How can I make a passthrough from a file above public_html to one below it so that people can surf in with a browser and download files which have been uploaded by the script? Thanks in advance, JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Uploading and verifying word and excel files
John Nichel wrote: Jack Jackson wrote: snip Also, it seems that directories must be blown wide open (777) to allow the script to copy the file over from /tmp. My ISP won't allow directories to be set to 777 under public_html/ -- but we need to access the files via web browser which is the whole point. It shouldn't have to be this way. The webserver should be configured to run as your virtual user, or belong to a group which has write permission to that directory, or.I'm getting a bit off track with that. This is something you'll have to take up with your ISP. Will do. So my questions: 1. How do you validate Word and Excel files before upload? Before? JavaScript...if JavaScript can even do it (I haven't touched the stuff in ages). After upload, you can check the mime type, but that's not foolproof. Okay, sorry I miswrote: after upload to the temp directory, BEFORE using move_uploaded_file(). Checking the mime type is the problem - if I can't trust the browsers am I really reliant on the file extension? Can't I peek in some manner into it as we do with getimagesize()? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Uploading and verifying word and excel files
Tom Rogers wrote: Hi, Friday, June 24, 2005, 12:42:33 AM, you wrote: JJ Hi, JJ I checked at JJ http://www.php.net/manual/en/features.file-upload.php and JJ all the user notes, and also the PEAR solution for uploading files and I JJ still have a couple of questions. JJ I need to create a form to allow users to upload (and later to delete) JJ MS word, excel and jpg files. Through your help I was able to validate JJ image files using getimagesize() and have made a nice script to upload JJ and rename images. JJ I cannot see a way to validate or examine Word or Excel files for JJ validity (and assume that older word files would validate differently JJ from newer ones). JJ The PEAR http upload script mentioned twice in the user notes at that JJ manual page does not *seem* to validate other than denying certain JJ extensions like php, php3, etc. I could be wrong of course. JJ Also, it seems that directories must be blown wide open (777) to allow JJ the script to copy the file over from /tmp. My ISP won't allow JJ directories to be set to 777 under public_html/ -- but we need to access JJ the files via web browser which is the whole point. JJ So my questions: JJ 1. How do you validate Word and Excel files before upload? JJ 2. How can I make a passthrough from a file above public_html to one JJ below it so that people can surf in with a browser and download files JJ which have been uploaded by the script? JJ Thanks in advance, JJ JJ The first 8 bytes of an ole2 file (exel and word are ole2 files I think) should have the following hex sequence: \xD0\xCF\x11\xE0\xA1\xB1\x1A\xE1 So do an fopen and read in the first 8 bytes and compare it to that string should give some indication. Cl. Thank you Tom and all those who replied. I always learn so much here! JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Amy's Site question
Hello, On a site I'm listing measurements in both inches and cm; in the db they're stored as inches. To convert them to cm I'm doing: ?php echo ($cartoon['art_width'] * 2.54); ? x ?php echo ($cartoon['art_height'] * 2.54); ? cm How can I limit the result of that math to one decimal place, ie, 9.5 cm, not 9.523 cm? Thanks in advance, JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Amy's Site question
Thanks everyone! I did look in the manual under operators and must have missed the link to round. Thanks to all who replied! Simon Allison wrote: http://au3.php.net/round -Original Message- From: Jack Jackson [mailto:[EMAIL PROTECTED] Sent: Wednesday, 22 June 2005 9:18 PM To: [php] PHP General List Subject: [PHP] Amy's Site question Hello, On a site I'm listing measurements in both inches and cm; in the db they're stored as inches. To convert them to cm I'm doing: ?php echo ($cartoon['art_width'] * 2.54); ? x ?php echo ($cartoon['art_height'] * 2.54); ? cm How can I limit the result of that math to one decimal place, ie, 9.5 cm, not 9.523 cm? Thanks in advance, JJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Those checkboxes again
hi,
I'm severely frustrated and perhaps you can help with what I have done
wrong. The checkboxes I use to populate an intersection table work to
add the records, and now I am trying to update them. It's almost there
but producing some unexpected results when the form is submitted: the
idea is that it displays the checkboxes as pre-selected if they're
associated with the art_id in the intersection table. They're now
appearing as all unselected. Any help is appreciated.
?php
$query = '';
$result = 0;
$art_id = $_POST['art_id'];
print_r($_POST);
if (isset($_POST['editrecordMedia'])){
if (!empty($_POST['media_types'])) {
foreach($_POST['media_types'] as $type)
{
$query = UPDATE media_art SET
media_id='$type',
art_id='$art_id';
var_dump($query);
mysql_query($query) or die(mysql_error());
}
}
else {echo mediatypes is empty;}
//Closes if (!empty($media_types))
}//closes if (isset($_POST['editrecordMedia'])
//If editrecord hasn't been set, but selectcartoon has, get the
cartoon's recordset
//This is just to get the title for display purposes
$query = SELECT art_title
FROM art
WHERE art_id='$art_id';
//end
$media_query = SELECT media.media_id,
media.media_name,
media_art.art_id
FROM media
LEFT JOIN media_art
ON media_art.media_id=media.media_id
AND media_art.art_id='$art_id';
//These $art results are just to get the title for display purposes
$art_result = mysql_query($query);
$art_rows = mysql_fetch_assoc($art_result);
//end
$media_result = mysql_query($media_query);
$checkbox_media = array ();
while ($media_rows = mysql_fetch_assoc($media_result)){
$checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}' ;
if ($media_rows['art_id'] === $art_id) {
$checkbox_media[] .= checked ;
}
$checkbox_media[] .= /{$media_rows['media_name']} ;
}
?
table align=center
trth colspan=4Main Menu/th/tr
tr
tda href=addrecord.phpAdd A Record/a/td
tda href=chooserecord.phpEdit A Record/a/td
tda href=deleterecord.phpDelete A Record/a/td
/tr
/table
form action=?php echo $_SERVER['PHP_SELF']; ? method=post
name=editrecordMedia
input type=hidden name=art_id value=?php echo $art_id ;?
Choose media related to strong?php echo
$art_rows['art_title'];?/strongbr /br /
Media: ?php echo join($checkbox_media); ?
input type=submit name=editrecordMedia value=Update
/form
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Re: [PHP] Re: Image upload form
Nadim Attari wrote:
http://www.php-help.net/sources-php/image.upload.function.353.html
Thanks, Nadim,
I'm sure that is a great script. I am really trying to learn how it's
working, so I'm trying to stay away from pre-rolled stuff as much as I
can and beg for the mercy of the list in building these simple scripts.
Believe it or not I'm actually improving pretty fast (despite
scriptorial evidence to the contrary on this list)!
Thanks again,
JJ
Regards,
Nadim Attari
Alienworkers.com
Hi, After a disastrous first attempt (which uploaded images but only by
chance) it was suggested I rework the entire thing. This one seems to
check the file against getimagesize and if that doesn't prove false,
check the type and make the extension then rename the file. But the
moving part is not working, and it does not kick back any error, it just
fails.
Can anyone tell me what I am doing wrong, and also if this is sufficient
to a) upload images safely and b) protect against tampering?
Thanks in advance,
JJ
?php
error_reporting(E_ALL);
$uploaddir = images/jpg/test/;
// print_r($_FILES);
$local_file = $_FILES['userfile']['tmp_name'];
if (sizeof($local_file))
{
//try to get image size; this returns false if this is not an actual
image file.
$image_test = getimagesize($local_file);
if ($image_test !== false) {
$mime_type = $_FILES['userfile']['type'];
switch($mime_type) {
case image/jpeg:
$pext = 'jpg';
break;
case image/tiff:
$pext = 'tif';
break;
default:
echo The file you are trying to upload is an image, but it is not
a tif or jpeg and therefore unacceptable.;
}
} else {
echo The file you are trying to upload is not a valid image file;
}
$main_image = md5(date(l-F-j-Y i:s)).'.'.$pext;
move_uploaded_file($main_image,$uploaddir);
}
?
form enctype=multipart/form-data action=?php echo
$_SERVER['PHP_SELF']; ? method=POST
input type=hidden name=MAX_FILE_SIZE value=30 /
!-- Name of input element determines name in $_FILES array --
Cartoon: input name=userfile type=file /
input type=submit value=Upload File /
/form
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[PHP] A more sane problem description
Sorry,
The last post I made was fairly incomprehensible.
I'm trying to
a) edit information which is already in an intersection table, while
b) allowing the user to add new information to the intersection table
The information in it is pulled from the table media_art and I grab the
media_art_id, media_id and art_id.
If a media_id is associated with an art_id in the table, I grab all
three and make the checkbox for that media_id checked.
I need to understand how I can make it so that
a) if the user UNchecks the box, then the row containing that media_id
will be deleted.
AND
b) if the user checks a new box, a new row will be inserted into the
media_art table containing the media_id and the art_id.
This is so far beyond my comprehension it's not even funny.
This is what I have so far - thank you in advance for the help.:
?php
$query = '';
$result = 0;
$art_id = $_POST['art_id'];
$media_art_id = $_POST['media_art_id'];
//print_r($_POST);
if (isset($_POST['editrecordMedia'])){
if (!empty($_POST['media_types'])) {
foreach($_POST['media_types'] as $type)
{
$query = UPDATE media_art SET
media_id='$type',
art_id='$art_id'
WHERE media_art_id='$media_art_id'
LIMIT 1;
print_r($query);
mysql_query($query) or die(mysql_error());
}
}
else {echo mediatypes is empty;}
//Closes if (!empty($media_types))
}//closes if (isset($_POST['editrecordMedia'])
//If editrecord hasn't been set, but selectcartoon has, get the
cartoon's recordset
//This is just to get the title for display purposes
$query = SELECT art_title
FROM art
WHERE art_id='$art_id';
//end
$media_query = SELECT media.media_id,
media.media_name,
media_art.art_id,
media_art.media_art_id
FROM media
LEFT JOIN media_art
ON media_art.media_id=media.media_id
AND media_art.art_id='$art_id';
//These $art results are just to get the title for display purposes
$art_result = mysql_query($query);
$art_rows = mysql_fetch_assoc($art_result);
//end
$media_result = mysql_query($media_query);
$checkbox_media = array ();
while ($media_rows = mysql_fetch_assoc($media_result)){
$checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}' ;
if ($media_rows['art_id'] === $art_id) {
$checkbox_media[] .= checked
media_art_id='{$media_rows['media_art_id']}';
}
$checkbox_media[] .= /{$media_rows['media_name']} ;
}
?
table align=center
trth colspan=4Main Menu/th/tr
tr
tda href=addrecord.phpAdd A Record/a/td
tda href=chooserecord.phpEdit A Record/a/td
tda href=deleterecord.phpDelete A Record/a/td
/tr
/table
form action=?php echo $_SERVER['PHP_SELF']; ? method=post
name=editrecordMedia
input type=hidden name=art_id value=?php echo $art_id ;?
Choose media related to strong?php echo
$art_rows['art_title'];?/strongbr /br /
Media: ?php echo join($checkbox_media); ?
input type=submit name=editrecordMedia value=Update
/form
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Re: [PHP] Those checkboxes again
Thanks, Joe!
I see what you weer going after. I had several problems including the
fact that I really didn't understand what I was trying to do until after
I did it. And I had some log errors a friend helped with.
What I needed to do was delete the media types from the intersection
table and then insert them anew; that way I don't have to do all sorts
of looping through finding the status of checked and unchecked boxes etc.
Eventually I came to:
if (isset($_POST['editrecordMedia'])){
if (!empty($_POST['media_types'])) {
//TO make sure art_id isn't empty
if (!empty($art_id)) { //delete media_art entries for this art_id
$query=DELETE FROM media_art WHERE art_id='$art_id';
mysql_query($query);
$query = INSERT INTO `media_art`
(`media_id`,`art_id`) VALUES ;
$sep = ;
foreach($_POST['media_types'] as $type)
{
$query .= $sep ('$type','$art_id');
$sep = , ;
Anyway, thanks so much for your help!!
JJ
Joe Harman wrote:
if ($media_rows['art_id'] === $art_id) {
$checkbox_media[] .= checked ;
}
$checkbox_media[] .= /{$media_rows['media_name']} ;
if think you only need 2 '=' signs... i do this alot with arrays of
check boxes .. now don't quote me on this... but i do something like
this.. using arrays for the check box values
if($permissions_data NULL)
{
if(in_array($row_rsPermissions['permission_short_name'], $permissions_data))
{ $checked_per = checked; } else { $checked_per = ; }
}
hope that helps you out
Joe
On 6/16/05, Jack Jackson [EMAIL PROTECTED] wrote:
hi,
I'm severely frustrated and perhaps you can help with what I have done
wrong. The checkboxes I use to populate an intersection table work to
add the records, and now I am trying to update them. It's almost there
but producing some unexpected results when the form is submitted: the
idea is that it displays the checkboxes as pre-selected if they're
associated with the art_id in the intersection table. They're now
appearing as all unselected. Any help is appreciated.
?php
$query = '';
$result = 0;
$art_id = $_POST['art_id'];
print_r($_POST);
if (isset($_POST['editrecordMedia'])){
if (!empty($_POST['media_types'])) {
foreach($_POST['media_types'] as $type)
{
$query = UPDATE media_art SET
media_id='$type',
art_id='$art_id';
var_dump($query);
mysql_query($query) or die(mysql_error());
}
}
else {echo mediatypes is empty;}
//Closes if (!empty($media_types))
}//closes if (isset($_POST['editrecordMedia'])
//If editrecord hasn't been set, but selectcartoon has, get the
cartoon's recordset
//This is just to get the title for display purposes
$query = SELECT art_title
FROM art
WHERE art_id='$art_id';
//end
$media_query = SELECT media.media_id,
media.media_name,
media_art.art_id
FROM media
LEFT JOIN media_art
ON media_art.media_id=media.media_id
AND media_art.art_id='$art_id';
//These $art results are just to get the title for display purposes
$art_result = mysql_query($query);
$art_rows = mysql_fetch_assoc($art_result);
//end
$media_result = mysql_query($media_query);
$checkbox_media = array ();
while ($media_rows = mysql_fetch_assoc($media_result)){
$checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}' ;
if ($media_rows['art_id'] === $art_id) {
$checkbox_media[] .= checked ;
}
$checkbox_media[] .= /{$media_rows['media_name']} ;
}
?
table align=center
trth colspan=4Main Menu/th/tr
tr
tda href=addrecord.phpAdd A Record/a/td
tda href=chooserecord.phpEdit A Record/a/td
tda href=deleterecord.phpDelete A Record/a/td
/tr
/table
form action=?php echo $_SERVER['PHP_SELF']; ? method=post
name=editrecordMedia
input type=hidden name=art_id value=?php echo $art_id ;?
Choose media related to strong?php echo
$art_rows['art_title'];?/strongbr /br /
Media: ?php echo join($checkbox_media); ?
input type=submit name=editrecordMedia value=Update
/form
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[PHP] Image upload form
Hi, After a disastrous first attempt (which uploaded images but only by
chance) it was suggested I rework the entire thing. This one seems to
check the file against getimagesize and if that doesn't prove false,
check the type and make the extension then rename the file. But the
moving part is not working, and it does not kick back any error, it just
fails.
Can anyone tell me what I am doing wrong, and also if this is sufficient
to a) upload images safely and b) protect against tampering?
Thanks in advance,
JJ
?php
error_reporting(E_ALL);
$uploaddir = images/jpg/test/;
// print_r($_FILES);
$local_file = $_FILES['userfile']['tmp_name'];
if (sizeof($local_file))
{
//try to get image size; this returns false if this is not an actual
image file.
$image_test = getimagesize($local_file);
if ($image_test !== false) {
$mime_type = $_FILES['userfile']['type'];
switch($mime_type) {
case image/jpeg:
$pext = 'jpg';
break;
case image/tiff:
$pext = 'tif';
break;
default:
echo The file you are trying to upload is an image, but it is not
a tif or jpeg and therefore unacceptable.;
}
} else {
echo The file you are trying to upload is not a valid image file;
}
$main_image = md5(date(l-F-j-Y i:s)).'.'.$pext;
move_uploaded_file($main_image,$uploaddir);
}
?
form enctype=multipart/form-data action=?php echo
$_SERVER['PHP_SELF']; ? method=POST
input type=hidden name=MAX_FILE_SIZE value=30 /
!-- Name of input element determines name in $_FILES array --
Cartoon: input name=userfile type=file /
input type=submit value=Upload File /
/form
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Re: [PHP] Image upload form
Okay, I started seeing some of my mistakes.
I am still having a great deal of trouble:
newfile returns: 0fdae2e9e6aa43f067a9dd780a5a36a6.jpg
image_file returns: images/jpg/test/0fdae2e9e6aa43f067a9dd780a5a36a6.jpg
images/jpg/test is set to 777 but I still get (Could not move file to
destination). What am I missing? Thanks!
?php
error_reporting(E_ALL);
$uploaddir = images/jpg/test/;
print_r($_FILES);
$local_file = $_FILES['userfile']['tmp_name'];
if (sizeof($local_file))
{
//try to get image size; this returns false if this is not an actual
image file.
$image_test = getimagesize($local_file);
if ($image_test !== false) {
$mime_type = $_FILES['userfile']['type'];
switch($mime_type) {
case image/jpeg:
$pext = 'jpg';
break;
case image/tiff:
$pext = 'tif';
break;
default:
echo The file you are trying to upload is an image, but it is not
a tif or jpeg and therefore unacceptable.;
}
} else {
echo The file you are trying to upload is not a valid image file;
}
$newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;
$image_file = $uploaddir . $newfile;
// print_r($newfile);
// print_r($image_file);
if(!move_uploaded_file($newfile,$image_file)) {
echo 'Could not move file to destination';
exit;
}
else {
echo 'image file ?php echo $newfile ? uploaded.';
}
}
?
form enctype=multipart/form-data action=?php echo
$_SERVER['PHP_SELF']; ? method=POST
input type=hidden name=MAX_FILE_SIZE value=30 /
!-- Name of input element determines name in $_FILES array --
Cartoon: input name=userfile type=file /
input type=submit value=Upload File /
/form
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Re: [PHP] Image upload form
Richard Davey wrote:
Hello Jack,
Wednesday, June 15, 2005, 5:38:11 PM, you wrote:
JJ newfile returns: 0fdae2e9e6aa43f067a9dd780a5a36a6.jpg
JJ image_file returns:
JJ images/jpg/test/0fdae2e9e6aa43f067a9dd780a5a36a6.jpg
JJ images/jpg/test is set to 777 but I still get (Could not move file to
JJ destination). What am I missing? Thanks!
This directory needs to be absolute - i.e. the COMPLETE path:
/usr/home/jack/images/jpg/test
Thanks, Richard,
Still no soap: I changed
$uploaddir = /home/jack/public_html/amyportnoy/images/jpg/test;
and
$image_file = $uploaddir . '/' . $newfile;
Now $image_file returns the valid path of:
/home/jack/public_html/amyportnoy/images/jpg/test/09992d5379dd0a0cf376aab82241a66d.jpg
but it still does not copy the file to that location. However the error
has changed:
if (is_uploaded_file($newfile)) {
if(!move_uploaded_file($newfile,$image_file)) {
echo 'Could not move file to destination';
exit;
}
else {
echo 'image file ?php echo $newfile ? uploaded.';
}
}
else {
echo 'Problem with ' . $newfile;
}
}
And I'm getting an error message of Problem with
6a26590fb45fd86e58954ba91d5580a4.jpg
So i guess it's not uploading for some reason?
Here's the whole thing I have so far once again, with several mods:
?php
error_reporting(E_ALL);
$uploaddir = /home/jack/public_html/amyportnoy/images/jpg/test;
print_r($_FILES);
if ($_FILES['userfile']['error'] 0) {
echo 'Problem: ';
switch ($_FILES['userfile']['error']) {
case 1:
echo 'File exceeds maximum upload size limit
(upload_max_filesize).';
break;
case 2:
echo 'File exceeds maximum size limit (max_file_size).';
break;
case 3:
echo 'File was only partially uploaded.';
break;
case 4:
echo 'No file was uploaded.';
break;
}//end switch
}//end if error 0
$local_file = $_FILES['userfile']['tmp_name'];
if (sizeof($local_file))
{
//try to get image size; this returns false if this is not an actual
image file.
$image_test = getimagesize($local_file);
if ($image_test !== false) {
$mime_type = $_FILES['userfile']['type'];
switch($mime_type) {
case image/jpeg:
$pext = 'jpg';
break;
case image/tiff:
$pext = 'tif';
break;
default:
echo The file you are trying to upload is an image, but it is not
a tif or jpeg and therefore unacceptable.;
}
} else {
echo The file you are trying to upload is not a valid image file;
}
$newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;
$image_file = $uploaddir . '/' . $newfile;
// print_r($newfile);
print_r($image_file);
if (is_uploaded_file($newfile)) {
if(!move_uploaded_file($newfile,$image_file)) {
echo 'Could not move file to destination';
exit;
}
else {
echo 'image file ' . $newfile . 'uploaded.';
}
}
else {
echo 'Problem with ' . $newfile;
}
}
?
form enctype=multipart/form-data action=?php echo
$_SERVER['PHP_SELF']; ? method=POST
input type=hidden name=MAX_FILE_SIZE value=30 /
!-- Name of input element determines name in $_FILES array --
Cartoon: input name=userfile type=file /
input type=submit value=Upload File /
/form
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Re: [PHP] Image upload form
Yes, Jason,
Those did it!
Thanks so much for the help!
Jason Wong wrote:
On Thursday 16 June 2005 00:38, Jack Jackson wrote:
//try to get image size; this returns false if this is not an actual
image file.
$image_test = getimagesize($local_file);
if ($image_test !== false) {
$mime_type = $_FILES['userfile']['type'];
$_FILES['userfile']['type'] contains the mime-type that is provided by the
browser and will vary depending on browser and hence extremely
unreliable.
In fact the returned value from getimagesize() already has mime-type info,
use that instead.
$newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;
$image_file = $uploaddir . $newfile;
// print_r($newfile);
// print_r($image_file);
if(!move_uploaded_file($newfile,$image_file)) {
echo 'Could not move file to destination';
exit;
}
The file pointed to by $newfile doesn't exist. You need to move ...
$local_file = $_FILES['userfile']['tmp_name'];
... $localfile
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Re: [PHP] Checkboxes From Intersection Redux
That did it exactly, Kristen
Thanks so much for the help! (and sorry for sending this to you and not
the list the first time!)
JJ
Kristen G. Thorson wrote:
Hopefully I understand your question correctly.
You have this SQL:
$media_query = 'SELECT media_id,media_name FROM media GROUP BY media_name';
And
For every media_id which is associated with $cartoon in the table
media_art, check the box; for all others leave them unchecked.
The problem is, the SQL you have is not returning every media_id
(because you're grouping on media_name). I wonder if you truly need to
group on media_name. I would assume that media_name is unique in the
media table. If it is not, then you need to rethink your table
structure. If you group on media_name and there are duplicate
media_names, you can have data like this:
media_id media_name
4Name1
16 Name1
Grouping by media_name as in your query above will produce a line like:
media_idmedia_name
4 Name1
You then output this to check boxes and use those to set the relation to
art and media. But what's the difference between media_id 4 and
media_id 16? In this case, if the database always returns the group by
this way, you would never set the media_id 16. If there is a distinct
difference between media_names with different ids, then I think you
probably need to make some changes.
That being said, if you do not need to group by media_name, then you can
simply do something like this:
select media.media_id, media.media_name, media_art.art_id, from media
left join media_art on media_art.media_id=media.media_id and
media_art.art_id=$cartoon['art_id']
Which would return a table like this if $cartoon['art_id']=15:
media_idmedia_name art_id
4 Name1 NULL
8 Name2 15
12 Name3 NULL
16 Name4 15
17 Name5 NULL
18 Name6 NULL
You could then test the output of art_id:
$checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}'
.(rows['art_id']==$cartoon['art_id']?
checked:)./{$media_rows['media_name']} ;
HTH
kgt
Jack Jackson wrote:
Hi,
With your help I got some checkboxes generated the other day for a
form. I would like some help getting a similar problem solved.
I am now making a form to edit db entries made in the previous form. I
have three tables involved: art, media and media_art. I need to show
checkboxes for all available media. For the chosen record ($cartoon,
which equals an art_id selected by the user) I must also go into the
media_art table, and where the selected art ID has a corresponding
media_id, display that media_id's media_name as a checked box.
TABLE media:
media_id media_name
1 ink
2 pencil
3 watercolor
4 gauche
5 watercolor pencil
To find out the art_id of the chosen record, the user is selecting
from a dropdown box in the form. I'm doing queries like this to make a
publisher dropdown in a similar vein:
$query = SELECT * FROM art WHERE art.art_id = '$cartoon';
$publisher_query = 'SELECT * FROM publisher';
$result = mysql_query($query);
$publisher_result = mysql_query($publisher_query);
while ($rows = mysql_fetch_assoc($result)){
$publisher_dropdown = 'select name=publisher_id';
while ($pub = mysql_fetch_assoc($publisher_result)){
$publisher_dropdown .= 'option value=' . $pub['publisher_id'];
if ($pub['publisher_id'] == $rows['publisher_id']){
$publisher_dropdown .= ' selected ';
}
$publisher_dropdown .= '' . htmlentities($pub['publisher_name']);
}
$publisher_dropdown .= '/select';
}
I now need to formulate how to make the checkboxes similarly. The
original setup to make the checkboxes was :
$media_query = 'SELECT media_id,media_name FROM media GROUP BY
media_name';
$media_result = mysql_query($media_query);
$checkbox_media = array ();
$media_types = array();
while ($media_rows = mysql_fetch_assoc($media_result)){
$checkbox_media[] = input type='checkbox'
name='media_types[]' value='{$media_rows['media_id']}'
/{$media_rows['media_name']} ;
}
Those which were checked were inserted into media_art thusly:
media_id art_id
31
41
51
What I want to do is say For every media_id which is associated with
$cartoon in the table media_art, check the box; for all others leave
them unchecked.
How can I do this?
Thanks very much in advance,
Jack
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[PHP] Checkboxes From Intersection Redux
Hi,
With your help I got some checkboxes generated the other day for a form.
I would like some help getting a similar problem solved.
I am now making a form to edit db entries made in the previous form. I
have three tables involved: art, media and media_art. I need to show
checkboxes for all available media. For the chosen record ($cartoon,
which equals an art_id selected by the user) I must also go into the
media_art table, and where the selected art ID has a corresponding
media_id, display that media_id's media_name as a checked box.
TABLE media:
media_id media_name
1 ink
2 pencil
3 watercolor
4 gauche
5 watercolor pencil
To find out the art_id of the chosen record, the user is selecting from
a dropdown box in the form. I'm doing queries like this to make a
publisher dropdown in a similar vein:
$query = SELECT * FROM art WHERE art.art_id = '$cartoon';
$publisher_query = 'SELECT * FROM publisher';
$result = mysql_query($query);
$publisher_result = mysql_query($publisher_query);
while ($rows = mysql_fetch_assoc($result)){
$publisher_dropdown = 'select name=publisher_id';
while ($pub = mysql_fetch_assoc($publisher_result)){
$publisher_dropdown .= 'option value=' . $pub['publisher_id'];
if ($pub['publisher_id'] == $rows['publisher_id']){
$publisher_dropdown .= ' selected ';
}
$publisher_dropdown .= '' . htmlentities($pub['publisher_name']);
}
$publisher_dropdown .= '/select';
}
I now need to formulate how to make the checkboxes similarly. The
original setup to make the checkboxes was :
$media_query = 'SELECT media_id,media_name FROM media GROUP BY media_name';
$media_result = mysql_query($media_query);
$checkbox_media = array ();
$media_types = array();
while ($media_rows = mysql_fetch_assoc($media_result)){
$checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}' /{$media_rows['media_name']} ;
}
Those which were checked were inserted into media_art thusly:
media_id art_id
31
41
51
What I want to do is say For every media_id which is associated with
$cartoon in the table media_art, check the box; for all others leave
them unchecked.
How can I do this?
Thanks very much in advance,
Jack
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Re: [PHP] Optimizing Help
Jochem,
I cannot believe you spent this much time helping me with this. I really
appreciate it. I will go through and make ALL those changes. I am
grateful. Especially the changes which cleaned up jibberish and
tightened from several lines to one - really! Thank you thank you thank you!
--JJ
Jochem Maas wrote:
jack jackson wrote:
Hello,
Recently with the help of several of you I got a script working. It's
complex, I'm still new, some parts of it came from other authors and I
adapted it, and generally despite the fact that it seems to work
perfectly at this point, I am certain that there is bloat, repetition
and simply useless crap.
I'd like to know if anyone can have a look and help me optimize what I
have. For example, there are several mysql queries - would it be
possible to combine them somehow? I use the image upload section twice
because I couldn't figure out how to make it work using different vars
within the same section. That kind of newbie stuff.
The code is here: http://hashphp.org/pastebin.php?pid=3701
# ?php
#
# require_once('nscfg.php');
#
# //Initialize vars
# $query = '';
# $dropdown = '';
# $result = 0;
# $errors = array();
# $msgArray = array();
# $msgText = '';
be neat, it helps:
$query = '';
$dropdown= '';
$result = 0;
#
# $query = 'SELECT art.*,publisher.*
# FROM art,subject,publisher,series
# GROUP BY publisher_name';
make good (ab)use of alignment (your style may differ ;-)
$query = 'SELECT art.*,
publisher.*
FROM art,
subject,
publisher,
series
GROUP BY publisher_name';
// ps - why is 'series' 'subject' in there?
#
# $subject_query = 'SELECT art.*,subject.*
# FROM art,subject
# GROUP BY subject_name';
#
# $series_query = 'SELECT art.*,series.*
# FROM art,series
# GROUP BY series_name';
#
# $media_query = 'SELECT media_id,media_name
# FROM media
# GROUP BY media_name';
#
# $result = mysql_query($query);
# $media_result = mysql_query($media_query);
# $subject_result = mysql_query($subject_query);
# $series_result = mysql_query($series_query);
#
instead of creating 4 result identifiers, run and loop thru 1 at a time,
its allows you to reuse a single $result var (as well as being better in
other ways)
# $dropdown_publishers = 'select name=publisher';
# while ($rows = mysql_fetch_assoc($result)){
# $dropdown_publishers .= 'option value=' . $rows['publisher_id']
. '' . htmlentities($rows['publisher_name']);
# }
# $dropdown_publishers .= '/select';
here is a candidate for a function:
buildOptionList($name, $result, $valKey, $nameKey)
{
while ($row = mysql_fetch_assoc($result)) {
$dropdown[] = 'option value='
. htmlentities($row[$valKey], ENT_QUOTES)
. ''
. htmlentities($row[$nameKey], ENT_QUOTES)
. '/option'; // options have closing tags
}
return 'select name=' . $name . '' .
join('',$dropdown) . '/select';
}
#
#
# $dropdown_subject = 'select name=subject';
# while ($rows = mysql_fetch_assoc($subject_result)){
^- white space?
# $dropdown_subject .= 'option value=' . $rows['subject_id'] .
'' . htmlentities($rows['subject_name']);
# }
# $dropdown_subject .= '/select';
#
# $dropdown_series = 'select name=seriesoption value=Select A
Series/option';
# while ($rows = mysql_fetch_assoc($series_result)){
# $dropdown_series .= 'option value=' . $rows['series_id'] . ''
. htmlentities($rows['series_name']);
# }
# $dropdown_series .= '/select';
#
# $checkbox_media = array ();
# $media_types = array();
# while ($media_rows = mysql_fetch_assoc($media_result)){
# $checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}' /{$media_rows['media_name']} ;
# }
#
# ///IMAGE SECTION - MAIN IMAGE (IMAGE UPLOAD SCRIPT COPYRIGHT INFO IN
CFG FILE)
# ///THIS SECTION Copyright (c) 2000 Marcus Kazmierczak, [EMAIL PROTECTED]
# if ($REQUEST_METHOD == POST)
# {
# $uploaddir = images/jpg;
#
# /*== checks the extension for .jpg or .tiff ==*/
# $pext = getFileExtension($imgfile_name);
TURN OFF register_globals, and access the $_FILES array instead.
#
# $pext = strtolower($pext);
#
#
# //If main image don't match extentions
# if (empty($POST['imgfile'])) {
# $errors[] = 'Please select an image. This is sort of the whole
point, yes?';
your error checking for whether the image was actually uploaded is
non-existent,
check the manual (+usernotes) for guidelines on how to check whether
anything
made it thru.
# }
#
# if (($pext != jpg) ($pext != jpeg) ($pext != tif)
($pext != tiff))
# {
or maybe:
$validExtensions = array(jpg,jpeg,tif,tiff);
if (!in_array($pext, $validExtensions)) { /* bad */ }
/*
having said that the file extension doesn't say anything - better to use
[PHP] Optimizing Help
Hello, Recently with the help of several of you I got a script working. It's complex, I'm still new, some parts of it came from other authors and I adapted it, and generally despite the fact that it seems to work perfectly at this point, I am certain that there is bloat, repetition and simply useless crap. I'd like to know if anyone can have a look and help me optimize what I have. For example, there are several mysql queries - would it be possible to combine them somehow? I use the image upload section twice because I couldn't figure out how to make it work using different vars within the same section. That kind of newbie stuff. The code is here: http://hashphp.org/pastebin.php?pid=3701 Thanks in advance! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Optimizing Help
Thanks, Chris, I see what you're getting at. I'm not sure I understand what you mean about looping through the array in the area you specified- isn't that just the definitions of the vars? Or is that what you meant and I'm missing the point!!? On 6/13/05, Chris Ramsay [EMAIL PROTECTED] wrote: Hey there Jackson, The first thing I would consider would be to see if you can classify the code into chunks that do a certain job, and then rewrite them as functions. I would also consider looping through arrays for repetitive jobs (lines 258 - 270 for example). Down the line you could consider the use of classes, your own or ready made - such as the ever useful PEAR (http://pear.php.net). I personally found that the greatest saver of time to be the re-use of code that I know works well for given situations. HTH Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Three queries. One Form.
Hi, I am trying to make one form on a single page insert info into three tables; query 1 creates an art_id (auto-increment) for the newly created row in table art; query2 creates a media_id in table media. Then I need to get the art_id and media_id created by the first two queries to insert into an intersection table as query three. Must I run an intermediate query to get the ids, and assign it to vars? What would it even look like? Thanks in advance, -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Three queries. One Form.
On 6/9/05, Matt Babineau [EMAIL PROTECTED] wrote: Well after the first query you could do this: $art_id = mysql_insert_id(); There is your new unique art_id you just created. Do this for the next table, the do the insert on your 3rd table. Thanks, Matt! Matt Babineau Criticalcode w: http://www.criticalcode.com p: 858.733.0160 e: [EMAIL PROTECTED] -Original Message- From: jack jackson [mailto:[EMAIL PROTECTED] Sent: Thursday, June 09, 2005 4:06 PM To: php-general@lists.php.net Subject: [PHP] Three queries. One Form. Hi, I am trying to make one form on a single page insert info into three tables; query 1 creates an art_id (auto-increment) for the newly created row in table art; query2 creates a media_id in table media. Then I need to get the art_id and media_id created by the first two queries to insert into an intersection table as query three. Must I run an intermediate query to get the ids, and assign it to vars? What would it even look like? Thanks in advance, -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Three queries. One Form.
Thanks for this Richard! On 6/9/05, Richard Davey [EMAIL PROTECTED] wrote: Hello jack, Friday, June 10, 2005, 12:05:35 AM, you wrote: jj I am trying to make one form on a single page insert info into three jj tables; query 1 creates an art_id (auto-increment) for the newly jj created row in table art; jj query2 creates a media_id in table media. jj Then I need to get the art_id and media_id created by the first two jj queries to insert into an intersection table as query three. Assuming MySQL - just use 2 insert statements and after each one get the last_insert_id. Once you've got both of those you can perform your third and final insert using both of those values. Best regards, Richard Davey -- http://www.launchcode.co.uk - PHP Development Services I do not fear computers. I fear the lack of them. - Isaac Asimov -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Getting checkboxes as array
HI I have a form which pulls values from the db, and thanks to help
from the irc chat, hopefully makes any checkboxes which are selected
part of an array to be gotten in post:
while ($media_rows = mysql_fetch_assoc($media_result)){
$checkbox_media[] = input type='checkbox' name='media_types[]'
value='{$media_rows['media_id']}' /{$media_rows['media_name']} ;
}
I'd like to now add the value of any checked box to an intersection
table based on my last question to the list:
$art_id = mysql_insert_id();
What I'd like to end up with is something which for each value in
media_types[] create a New row in the intersection table (media_art)
However how can I make this:
$query = INSERT INTO media_art (media_art_id,art_id, media_id)
VALUES ('',' . $art_id . ',' . $media_types[2]. ');
repeat as many or few times as possible to account for the number of
checked boxes, such as
$art_id $media_types[5]
$art_id $media_types[9]
etc
I suspect it's something to do with the foreach but I'm stuck in
figuring it out.
Thanks in advance!
$media_types[] = ($_POST['media_types[]']);
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Re: [PHP] Getting checkboxes as array
Thank you Sebastian! Saved me some hell there!!
On 6/9/05, Sebastian [EMAIL PROTECTED] wrote:
Don't forget to mention that even if you don't select a checkbox it will
still add a empty record to the db.. i know for sure the foreach loop
will add a record even if a box is not check, so you have to check its
actually set before you start inserting.
Richard Davey wrote:
Hello jack,
Friday, June 10, 2005, 2:16:06 AM, you wrote:
jj $query = INSERT INTO media_art (media_art_id,art_id, media_id)
jj VALUES ('',' . $art_id . ',' . $media_types[2]. ');
jj repeat as many or few times as possible to account for the number of
jj checked boxes, such as
One way:
for ($i = 0; $i count($media_types); $++)
{
$query = INSERT INTO media_art (media_art_id,art_id, media_id)
VALUES ('','$art_id','{$media_types[$i]}');
// perform query here
}
Another:
foreach ($media_types as $type)
{
$query = INSERT INTO media_art (media_art_id,art_id, media_id)
VALUES ('','$art_id','$type');
// perform query here
}
Best regards,
Richard Davey
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Re: [PHP] Getting checkboxes as array
Whoops. I must be botching this syntax because this is printing
,,0,, as the query:
All the first part of the query works and inserts records into the
database, and it's when I try to get mysql_insert_id () that I seem to
run into trouble. Ah. ave I not yet run the first query? The part of
the code that actually runs it was given to me in a class and I don't
quite understand how it's suppose to be working ...
Thanks in advance:
$trimblog = (trim($_POST['blog']));
$blog = (nl2br($trimblog));
$image = mysql_real_escape_string($final_imgname);
$image_thb = mysql_real_escape_string($final_thb_filename);
$pubwidth = mysql_real_escape_string(trim($_POST['art_width']));
$pubheight = mysql_real_escape_string(trim($_POST['art_height']));
$origwidth = mysql_real_escape_string(trim($_POST['orig_width']));
$origheight = mysql_real_escape_string(trim($_POST['orig_height']));
$publisher = mysql_real_escape_string(trim($_POST['publisher']));
$series = mysql_real_escape_string(trim($_POST['series']));
$subject = mysql_real_escape_string(trim($_POST['subject']));
$title = mysql_real_escape_string(trim($_POST['title']));
$caption = mysql_real_escape_string(trim($_POST['art_caption']));
$blog = mysql_real_escape_string($blog);
$keywords = mysql_real_escape_string(trim($_POST['keywords']));
$query = INSERT INTO art (art_id,art_thumbnail, art_image,
art_width, art_height, orig_width, orig_height, art_pub_date,
publisher_id, art_creation_date, series_id, subject_id, art_title,
art_caption, art_keywords, art_blog)
VALUES ('',' . $image_thb . ',' . $image . ',' . $pubwidth .
',' . $pubheight . ',' . $origwidth . ',' . $origheight . ','
. $pubdate . ',' . $publisher . ',' . $orig_date . ',' .
$series . ',' . $subject . ',' . $title . ',' . $caption . ','
. $keywords . ',' . $blog . ');
$art_id = mysql_insert_id();
foreach ($media_types[] as $type)
{
$query .= INSERT INTO media_art (media_art_id,media_id,
art_id)
VALUES ('',' . $type . ',' . $art_id . ');
// perform query here
}
if (!mysql_query($query) || mysql_error($query)!= ''){
$errMsg = mysql_error($query);
trigger_error(Problem with addrecord: $query\r\n$errMsg\r\n,
E_USER_ERROR);
} else {
$msgText = 'trtdstrongYour record was
saved!/strong/td/tr';
}
On 6/9/05, Richard Davey [EMAIL PROTECTED] wrote:
Hello jack,
Friday, June 10, 2005, 2:16:06 AM, you wrote:
jj $query = INSERT INTO media_art (media_art_id,art_id, media_id)
jj VALUES ('',' . $art_id . ',' . $media_types[2]. ');
jj repeat as many or few times as possible to account for the number of
jj checked boxes, such as
One way:
for ($i = 0; $i count($media_types); $++)
{
$query = INSERT INTO media_art (media_art_id,art_id, media_id)
VALUES ('','$art_id','{$media_types[$i]}');
// perform query here
}
Another:
foreach ($media_types as $type)
{
$query = INSERT INTO media_art (media_art_id,art_id, media_id)
VALUES ('','$art_id','$type');
// perform query here
}
Best regards,
Richard Davey
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Re: [PHP] Beautiful HTML Invoice - Prints like crap! I need some suggestions!
Matt Babineau wrote: Hi all - I've got a great html invoice that prints like crap because of my user of background images and foreground images. Does anyone have any good suggestions other than turn on images in IE to get this thing to print the graphics? Is there a good way I could convert the HTML view to a JPG? I'm on a linux box and have php 4.3.10. Thanks for the help! Matt Babineau Criticalcode w: http://www.criticalcode.com p: 858.733.0160 e: [EMAIL PROTECTED] Make it a pdf? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beautiful HTML Invoice - Prints like crap! I need some suggestions!
Matt Babineau wrote: Hi all - I've got a great html invoice that prints like crap because of my user of background images and foreground images. Does anyone have any good suggestions other than turn on images in IE to get this thing to print the graphics? Is there a good way I could convert the HTML view to a JPG? I'm on a linux box and have php 4.3.10. Thanks for the help! Matt Babineau Criticalcode w: http://www.criticalcode.com p: 858.733.0160 e: [EMAIL PROTECTED] Sorry, more helpful:http://us4.php.net/pdf -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] linux php editor
Clive Zagno wrote: what php GUI editors do you recommend. Ive used bluefish before, any other recommendations, thanks clive I love Jedit http://www.jedit.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Implode? Explode?
Hi all, I'm trying to fetch similar things - in this case, rows which share a series ID no - and bring them into an array and display them grouped by what makes them similar (in this case, series id). I looked at implode and explode which seem wrong for this - the only separator I can see is that they're each in a table cell. The result of my query returns something like: art_id series_id art_titleseries_name 2 1 Weddings 2004Summer Special 4 1 Summer In The City Summer Special 5 2 Bags of NY Op-Art 7 2 Dogs of NY Op-Art I'd like to create a list of links to each art_id grouped together as series, href code obviously not complete but demonstrative: pSummer Specialbr / a href='2'Weddings 2004/a | a href='4'Summer In The City/p pOp-Artbr / a href='5'Bags of NY/a | a href='7'Dogs of NY/p ? Thanks in advance, Jack -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Implode? Explode?
Brent Baisley wrote:
You're close, but you need to group your data on the series_id first.
You can do that by looping through your array and creating another array
using series_id as the array key. You'll end up with a list of arrays
named after the series_id.
foreach( $result_set as $result_item ) {
//Add an array item to the series_id slot of the grouped_result array
$grouped_result[ $result_item['series_id'] ][]=
array('id'=$result_items['art_id'], 'title'=$result_item['art_title']);
}
That did the trick, Brent. Thanks so much for this useful information.
Now you have your data grouped by series_id. Each item of the
grouped_result array will contain one or more arrays which contain the
art_id and art_title.
If you are not familiar with multidimensional arrays, this may be a
little confusing.
A little is right! But tanks for the intro to multi-dimensional arrays!
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Re: [PHP] ampersands in href's
Thanks!
Leon Poon wrote:
The simplest way to make sure everything work well regardless of what
the values are:
?
$url = somepage.php?var1=.urlencode($var1).var2=.urlencode($var2);
echo a href=\.htmlspecialchars($url).\;
?
htmlspecialchars() changes characters '', '', ''', '', '' into the
HTML equivilant. And yup, you should do this for all *ML pages as long
as the thing being printed is not part of the mark-up syntax.
Jack Jackson wrote:
Rory Browne wrote:
On 6/4/05, Jack Jackson [EMAIL PROTECTED] wrote:
Hi, Rory
Rory Browne wrote:
I think you have the idea. The 's are used to seperate the various
variables. If you want to set $p to something like 'Tom Jerry' then
personally I'd do something like:
?php
$p = Tom Jerry;
$s = Cat Mouse;
printf(a href='{$_SERVER['PHP_SELF']}?p=%ss=%s, urlencode($p),
urlencode($s));
?
That's nice. To get more specific (because my code varies a bit from
yours and I don't wanna mess up the ) and ' and s:
$p and $c are actually row ID numbers so up to 3 digits. So for
example if
$p=1
$c=32
I was wanting to see a URL of
http://foo.com?r=1c=32
In that case, you can simply echo them out, once you're sure that $r,
and $c are actually integers.
I forgot to mention that above I did $r = intval($_GET[r])
!
Thanks, everyone!
echo a href='http://foo.com?r=$rc=$c'whatever/a
if not(sure they're integers, you could always
printf(a href=\http://foo.com?r=%dc=%d\;whatever/a, $r, $c);
Alternatively you could $r = (int)$r;
or echo a href='http://foo.com?r=; . (int)$r . c= . (int)$c .
'whatever/a;
There's more than one way to do it...
so was this the way to go?
//Make a thumbnail table of contents to display in the left sidebar
while ($sidebar = mysql_fetch_assoc($sidebar_result)) {
$sidebar_thumbnails[] = a class='img-link'
href='{$_SERVER['PHP_SELF']}?p=%pc={$sidebar['art_id']},
urlencode($p)'
title=\{$sidebar['art_title']}\img class='sidebar-img'
src='{$image_dir}{$sidebar['art_thumbnail']}' width='50' height='60'
border='0' alt=\{$sidebar['art_title']}\ //a;
}
?
Thanks in advance!
On 6/4/05, Jack Jackson [EMAIL PROTECTED] wrote:
Hi,
If I want to make a link to a URL which includes some GETs can I
just do:
a href='{$_SERVER['PHP_SELF']}?p={$p}c={$s}' ... etc etc
or must I escape the ampersand somehow?
TIA,
--Jack
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[PHP] looping through an array problem
This is something dumb I am doing but:
Trying to pull all names of publishers in db. This sql:
SELECT art.art_id,art.publisher_id,publisher.publisher_name,
FROM art
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id
pulls (in phpmyadmin) four rows:
artID pubID Publisher_name
17 The New York Times: Sunday Styles
23 The New York Sun
32 Metro NY
43 The New York Sun
I'm trying to make a sidebar which will make links to each unique
publisher name:
while ($cartoon = mysql_fetch_assoc($result)) {
$pub_sidebar[] = ul class='sidebar-menu'a class='img-link'
href='{$_SERVER['PHP_SELF']}?p={$cartoon['publisher_id']}'
title=\{$cartoon['publisher_name']}\{$cartoon['publisher_name']}/a/ul;
}
This prints:
The New York Times: Sunday Styles
The New York Sun
Metro NY
The New York Sun
I'd like to stop the NY Sun from appearing twice! What have i missed here?
Thanks in advance!
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Re: [PHP] looping through an array problem
Thanks for all the replies. Jochem, thank you for this code, which will
take me all night to understand (though I bet it works). I also note
that SELECT DISTINCT worked here, too
Also as many of you noticed before me, the art_id was in there as a fly
in the ointment.
Thanks all!
Jochem Maas wrote:
Jack Jackson wrote:
This is something dumb I am doing but:
Trying to pull all names of publishers in db. This sql:
its a mysql question in disguise, maybe...:
SELECT DISTINCT art.art_id,art.publisher_id,publisher.publisher_name
FROM art
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_iduse,
on the other hand if you want to pull every article
from the DB then that won't do it. maybe you
need to be extracting the name of the article instead/aswell?
on the other hand if you are trying to display a list of
publishers, why are you selecting from the arts table?
SELECT p.publisher_id,p.publisher_name
FROM publisher p ORDER BY p publisher_id DESC
(maybe you only want to show publishers with listed 'art's?)
what does this do for you?:
SELECT COUNT(a.art_id) as art_count,a.publisher_id,p.publisher_name
FROM art a, publisher p
WHERE p.publisher_id=a.publisher_id
AND art_count 0
GROUP BY a.publisher_id
SELECT art.art_id,art.publisher_id,publisher.publisher_name,
FROM art
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id
pulls (in phpmyadmin) four rows:
artID pubID Publisher_name
17 The New York Times: Sunday Styles
23 The New York Sun
32 Metro NY
43 The New York Sun
I'm trying to make a sidebar which will make links to each unique
publisher name:
and/or something like.:
?php
// $result = DB::doMagic();
$seenAlready = array();
$templet = 'ul class=sidebar-menua class=img-link href='
. $_SERVER['PHP_SELF']
. '?p=%1$s title=%2$s%2$s/a/ul';
while ($cartoon = mysql_fetch_assoc($result)) {
if (in_array($cartoon['publisher_id'], $seenAlready))
continue;
$seenAlready[] = $cartoon['publisher_id'];
$pub_sidebar[] = sprintf($templet,
$cartoon['publisher_id'],
$cartoon['publisher_name']);
}
while ($cartoon = mysql_fetch_assoc($result)) {
$pub_sidebar[] = ul class='sidebar-menu'a class='img-link'
href='{$_SERVER['PHP_SELF']}?p={$cartoon['publisher_id']}'
title=\{$cartoon['publisher_name']}\{$cartoon['publisher_name']}/a/ul;
}
This prints:
The New York Times: Sunday Styles
The New York Sun
Metro NY
The New York Sun
I'd like to stop the NY Sun from appearing twice! What have i missed
here?
Thanks in advance!
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Re: [PHP] looping through an array problem
M. Sokolewicz wrote: Jack Jackson wrote: Thanks for all the replies. Jochem, thank you for this code, which will take me all night to understand (though I bet it works). I also note that SELECT DISTINCT worked here, too Also as many of you noticed before me, the art_id was in there as a fly in the ointment. by that statement I ment the exact same thing Jochem ment in his 2nd part; I have NO idea why you're selecting *ANYTHING* from the arts table... it's *useless* if you don't need the data... Er, yes, that was what I meant: I had unintentionally included that bit.Thank you for your help. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] looping through an array problem
Forgive me if this comes twice: my ISP had a service blackout for three hours and I don't know what went: If my last post read (and I see that it did) that I was defending myself as opposed to falling ALL OVER my sword, I apologize: allow me to be clear: No, you're all correct and M. Sokolewicz doubly so: I had unintentionally selected fields from the wrong table for no reason other than lack of sleep coupled with lack of experience and a desperation to try to understand The problem was that I was pulling data in a manner both useless and complex from a thoroughly unnecessary table (I could tell you all why but you'll all just laugh at me more) I am grateful for all the help everyone has offered up to now and hope I did not offend - I was trying in my last post to indicate that I was an idiot, and it appears I've come off as arrogant. I promise it was not my intent! [Then I wrote::] Ah. I just remembered one reason I had done it involving the art_id field: I have more publishers in the db than are currently associated with artworks. I don't want a publisher to appear unless there is at least one image associated with it. So I did this to avoid having people see a link to the Sneezy Acres Tribune only to arrive at the next page and see, There are no images associated with this publisher. Jochem Maas wrote: Jack Jackson wrote: M. Sokolewicz wrote: Jack Jackson wrote: Thanks for all the replies. Jochem, thank you for this code, which will take me all night to understand (though I bet it works). I also note that SELECT DISTINCT worked here, too Also as many of you noticed before me, the art_id was in there as a fly in the ointment. by that statement I ment the exact same thing Jochem ment in his 2nd part; I have NO idea why you're selecting *ANYTHING* from the arts table... it's *useless* if you don't need the data... Er, yes, that was what I meant: I had unintentionally included that bit.Thank you for your help. Er, Jack - your original query was: SELECT art.art_id,art.publisher_id,publisher.publisher_name, FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id which is a selection on the art table... ( with a typo) if you did: SELECT art.publisher_id,publisher.publisher_name FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id nothing would change. and if you did: SELECT publisher.publisher_id,publisher.publisher_name publisher i.e. not 'unintentionally' selecting from the arts table. then you would not have had a problem in the first place?! I think I'm missing something ;-) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] looping through an array problem
Ah. I just remembered one reason I had done it involving the art_id field: I have more publishers in the db than are currently associated with artworks. I don't want a publisher to appear unless there is at least one image associated with it. So I did this to avoid having people see a link to the Sneezy Acres Tribune only to arrive at the next page and see, There are no images associated with this publisher. Jochem Maas wrote: Jack Jackson wrote: M. Sokolewicz wrote: Jack Jackson wrote: Thanks for all the replies. Jochem, thank you for this code, which will take me all night to understand (though I bet it works). I also note that SELECT DISTINCT worked here, too Also as many of you noticed before me, the art_id was in there as a fly in the ointment. by that statement I ment the exact same thing Jochem ment in his 2nd part; I have NO idea why you're selecting *ANYTHING* from the arts table... it's *useless* if you don't need the data... Er, yes, that was what I meant: I had unintentionally included that bit.Thank you for your help. Er, Jack - your original query was: SELECT art.art_id,art.publisher_id,publisher.publisher_name, FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id which is a selection on the art table... ( with a typo) if you did: SELECT art.publisher_id,publisher.publisher_name FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id nothing would change. and if you did: SELECT publisher.publisher_id,publisher.publisher_name publisher i.e. not 'unintentionally' selecting from the arts table. then you would not have had a problem in the first place?! I think I'm missing something ;-) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] looping through an array problem
If my last post read (and I see that it did) that I was defending myself as opposed to falling ALL OVER my sword, I apologize: allow me to be clear: No, you're all correct and M. Sokolewicz doubly so: I had unintentionally selected fields from the wrong table for no reason other than lack of sleep coupled with lack of experience and a desperation to try to understand The problem was that I was pulling data in a manner both useless and complex from a thoroughly unnecessary table (I could tell you all why but you'll all just laugh at me more) I am grateful for all the help everyone has offered up to now and hope I did not offend - I was trying in my last post to indicate that I was an idiot, and it appears I've come off as arrogant. I promise it was not my intent! Jochem Maas wrote: Jack Jackson wrote: M. Sokolewicz wrote: Jack Jackson wrote: Thanks for all the replies. Jochem, thank you for this code, which will take me all night to understand (though I bet it works). I also note that SELECT DISTINCT worked here, too Also as many of you noticed before me, the art_id was in there as a fly in the ointment. by that statement I ment the exact same thing Jochem ment in his 2nd part; I have NO idea why you're selecting *ANYTHING* from the arts table... it's *useless* if you don't need the data... Er, yes, that was what I meant: I had unintentionally included that bit.Thank you for your help. Er, Jack - your original query was: SELECT art.art_id,art.publisher_id,publisher.publisher_name, FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id which is a selection on the art table... ( with a typo) if you did: SELECT art.publisher_id,publisher.publisher_name FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id nothing would change. and if you did: SELECT publisher.publisher_id,publisher.publisher_name publisher i.e. not 'unintentionally' selecting from the arts table. then you would not have had a problem in the first place?! I think I'm missing something ;-) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] ampersands in href's
Hi,
If I want to make a link to a URL which includes some GETs can I just do:
a href='{$_SERVER['PHP_SELF']}?p={$p}c={$s}' ... etc etc
or must I escape the ampersand somehow?
TIA,
--Jack
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Re: [PHP] ampersands in href's
Hi, Rory
Rory Browne wrote:
I think you have the idea. The 's are used to seperate the various
variables. If you want to set $p to something like 'Tom Jerry' then
personally I'd do something like:
?php
$p = Tom Jerry;
$s = Cat Mouse;
printf(a href='{$_SERVER['PHP_SELF']}?p=%ss=%s, urlencode($p),
urlencode($s));
?
That's nice. To get more specific (because my code varies a bit from
yours and I don't wanna mess up the ) and ' and s:
$p and $c are actually row ID numbers so up to 3 digits. So for example if
$p=1
$c=32
I was wanting to see a URL of
http://foo.com?r=1c=32
so was this the way to go?
//Make a thumbnail table of contents to display in the left sidebar
while ($sidebar = mysql_fetch_assoc($sidebar_result)) {
$sidebar_thumbnails[] = a class='img-link'
href='{$_SERVER['PHP_SELF']}?p=%pc={$sidebar['art_id']}, urlencode($p)'
title=\{$sidebar['art_title']}\img class='sidebar-img'
src='{$image_dir}{$sidebar['art_thumbnail']}' width='50' height='60'
border='0' alt=\{$sidebar['art_title']}\ //a;
}
?
Thanks in advance!
On 6/4/05, Jack Jackson [EMAIL PROTECTED] wrote:
Hi,
If I want to make a link to a URL which includes some GETs can I just do:
a href='{$_SERVER['PHP_SELF']}?p={$p}c={$s}' ... etc etc
or must I escape the ampersand somehow?
TIA,
--Jack
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Re: [PHP] ampersands in href's
Murray @ PlanetThoughtful wrote:
If I want to make a link to a URL which includes some GETs can I just do:
a href='{$_SERVER['PHP_SELF']}?p={$p}c={$s}' ... etc etc
or must I escape the ampersand somehow?
Depends very much on the document type of your page. Valid XHTML
(transitional, at least), for example, doesn't like single ampersands in a
href= links. For XHTML, you need to replace s with amp;s.
So the following link:
a href='http://www.somewhere.com/index.php?id1=1id2=2'Something/a
...should be changed to:
a href='http://www.somewhere.com/index.php?id=1amp;id=2'Something/a
Thank you Murray. The page is in xhtml 1.0/transitional. That was
precisely what I was worried about. The amp; will be converted as part
of the URL right? I mean, the printed URL resulting from clicking on
that link won't say amp; it'll just say is this correct? Combined
with Rory's post this is really, really useful stuff and I thank you !
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Re: [PHP] ampersands in href's
Rory Browne wrote:
On 6/4/05, Jack Jackson [EMAIL PROTECTED] wrote:
Hi, Rory
Rory Browne wrote:
I think you have the idea. The 's are used to seperate the various
variables. If you want to set $p to something like 'Tom Jerry' then
personally I'd do something like:
?php
$p = Tom Jerry;
$s = Cat Mouse;
printf(a href='{$_SERVER['PHP_SELF']}?p=%ss=%s, urlencode($p),
urlencode($s));
?
That's nice. To get more specific (because my code varies a bit from
yours and I don't wanna mess up the ) and ' and s:
$p and $c are actually row ID numbers so up to 3 digits. So for example if
$p=1
$c=32
I was wanting to see a URL of
http://foo.com?r=1c=32
In that case, you can simply echo them out, once you're sure that $r,
and $c are actually integers.
I forgot to mention that above I did $r = intval($_GET[r])
!
Thanks, everyone!
echo a href='http://foo.com?r=$rc=$c'whatever/a
if not(sure they're integers, you could always
printf(a href=\http://foo.com?r=%dc=%d\;whatever/a, $r, $c);
Alternatively you could $r = (int)$r;
or
echo a href='http://foo.com?r=; . (int)$r . c= . (int)$c .
'whatever/a;
There's more than one way to do it...
so was this the way to go?
//Make a thumbnail table of contents to display in the left sidebar
while ($sidebar = mysql_fetch_assoc($sidebar_result)) {
$sidebar_thumbnails[] = a class='img-link'
href='{$_SERVER['PHP_SELF']}?p=%pc={$sidebar['art_id']}, urlencode($p)'
title=\{$sidebar['art_title']}\img class='sidebar-img'
src='{$image_dir}{$sidebar['art_thumbnail']}' width='50' height='60'
border='0' alt=\{$sidebar['art_title']}\ //a;
}
?
Thanks in advance!
On 6/4/05, Jack Jackson [EMAIL PROTECTED] wrote:
Hi,
If I want to make a link to a URL which includes some GETs can I just do:
a href='{$_SERVER['PHP_SELF']}?p={$p}c={$s}' ... etc etc
or must I escape the ampersand somehow?
TIA,
--Jack
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Re: [PHP] Site Design Strategy
asinning wrote: This is my first post to this group. I've been trying to figure this out on my own, but I keep running into complications, so I've decided to get some help. Much thanks for any help! I've been writing php server application for a couple of years, but now I'm turning my attention to re-building our company's aging website. This is a big project and is going to require a solid foundation. At the crux of this post is the following question: How do you develop a very robust, dynamic web-site, but also allow non-technical people to contribute? There must be an easier way. Here are my working assumptions and my strategy. Please help me if I'm thinking down the wrong path. Assumptions: 1) Non-technical people in the company need to be able to build pages, and they should be able to post their pages without bothering me. We have a tech-support person who will be able to help them, but she has zero programming knowledge and only a superficial understanding of HTML. 2) Every page needs to reside within he shell of the web site. This includes header(the top-level menu) left-side menu (a dynamic, context-specific menu) content (this is what the non-technical people will produce) footer (your standard fare text-based links) 3) I don't want to use frames, and I don't want to use Dreamweaver templates. Strategy: Currently, I am working on the following model: There is a top-level index.php page. This is the target of EVERY page on the site. The page that gets loaded in depends on the parameters of query-string. It's very simple, if the query string reads ?target=products/gsp, then my php will look for a site-relative document such as products/gsp.htm OR products/gsp/index.hml. Then, this document will get included as the content in my shell. Well, this works to a degree, but it requires that people use site-relative paths for all of their graphics and links, which is way, way to much to ask. After all, people are using WYSIWIG editors such as Dreamweaver and even Word to build their pages. Typically, site-relative paths don't work in these environments. They shouldn't need to upload their document to preview it. It also requires that they put their page within a 550 pixel wide -td- tag. I'd love to drop that requirement. So, now I considering the following: A parser that will convert any content into includable form. Relative paths will be translated to the site-root, etc. I'm a bit stuck here. Maybe I've misunderstood but here's a thought: I'm not sure what they're actually doing with these pages but it's usually in my experience something like a headline, a block of text in which you can allow certain HTML tags (you can use tidy within PHP) and some images and some links. Is there more that these folks are doing? Is there a reason to give them so much flexibility in design? Are these home pages as in personal showcases or department-specific offerings? You probably want to set up each user with their own directory or db area so they can upload all their images through your control panel, enter their text and have everything in one place for each user. If you give users the opportunity to put in unlimited matched sets of Headline, text block, image float right left or center (cna cation if required) plus strong, em and a limited href capability 99% of people will probably be happy. Make sure you rename all images they upload to remove spaces, weird characters and duplicate names. You can use a naming convention like user.image.x. or even md5(imagename). So this way, each user gets a user directory in which all image links are relative to that directory, all images are righ there and ties to the user. It also requires that they put their page within a 550 pixel wide -td- tag. I'd love to drop that requirement. AAARG. We use a wrapper in XHTML, putting everything in div tags so that later, when we change the format, they're not stuck in a td as you rightly worry about. Using div and CSS positioning increases exponentially your flexibility both now and later. And requires fairly modern browsers but according to our logs almost everyone has them. And if they come in using lynx it'll still *work* in that they get all the info in sensible order. Netscape 4 and IE 4 users are out of luck, but then, they often are anyway in terms of support on the web (please let's not devolve into a flame war over that statement). HTH and makes sense. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Using GET to build multiple sql queries
I'd love some help with http://hashphp.org/pastebin?pid=3443 if anyone can... Basically I want to make it so that, if the get in the url specifies no query or a query to a nonexistent row, send to vanilla index. If url specifies c= then set $c=c and use the number to build the mysql query; same for p= and s= - if they're valid build the query, if not kick em out. Can anyone offer any help? Thanks in advance! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Delay?
Has anyone else noticed significant delays in messages getting posted? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Using GET to build multiple sql queries
Thanks for the reply, Greg,
I see how that is useful. I am confused as to how I would implement it
here. Please bear with me as I am a newbie and am now perhaps more
confused than ever!:
I'm trying to use the number given in the $_GET URL to build one piece
of the sql:
If there is anything set in the $_GET field other than ?c=[valid int] or
?p=[valid int] or ?s=[valid int] then I want to bounce to a plain index.
If it's a valid int (a positive int which corresponds to a valid row)
then I want to set its value to the appropriate variable: either $c, $p
or $s, and thus set the values of $fields, $from and $where.
?php //IF there is a valid query by cartoon, use $c to build the SQL
$fields = 'SELECT art.*,publisher.*,subject.*';
$from = 'FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id';
$sort = ORDER BY art.art_pub_date;
$where = WHERE art.art_id = '$c' AND
subject.subject_id=art.subject_id;
?
If that were instead a $p then I would do:
?php //IF there is a valid query by publisher, use $p to build the SQL
$fields = SELECT art.*,publisher.*,subject.*;
$from = FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id;
$where = WHERE publisher.publisher_id=art.publisher_id AND
art.publisher_id = '$p' AND
subject.subject_id=art.subject_id;
?
If that were instead an $s then I would do:
?php //IF there is a valid query by subject, use $s to build the SQL
$fields = SELECT art.*,publisher.*,subject.*;
$from = FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id;
$where = WHERE publisher.publisher_id=art.publisher_id AND
art.subject_id = '1' AND
art.subject_id=subject.subject_id;
?
I'm sure your method works ( ;) ). If I understand it, as my friend
Darrell said about your suggestion:
'...We iterate through the array seeing if there's a submitted HTML form
field name that matches the current database column name. If so, we add
the column name and the value submitted in the form to a string that is
being built into a database query.'
I'm trying to see how this code lets me do that. I know it's right in
front of my face but I cannot see how to adapt it to the task. .
Thanks in advance!!
Greg Donald wrote:
On 6/2/05, Jack Jackson [EMAIL PROTECTED] wrote:
I'd love some help with http://hashphp.org/pastebin?pid=3443 if anyone
can...
Basically I want to make it so that, if the get in the url specifies no
query or a query to a nonexistent row, send to vanilla index. If url
specifies c= then set $c=c and use the number to build the mysql query;
same for p= and s= - if they're valid build the query, if not kick em out.
Can anyone offer any help?
I'd iterate over the $_GET array to build the query elements. Then
implode those elements.
$array = array();
while( list( $k, $v ) = each( $_GET ) )
{
if( $k == 'somekeynotindb' )
{
continue;
}
$array[] = $k . =' . $v . ';
}
if( $array )
{
$and = implode( ', ', $array );
}
$sql =
SELECT *
FROM table
WHERE 1
$and
;
$query = mysql_query( $sql );
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Re: [PHP] Using GET to build multiple sql queries
SORRY - one small correction below:
SNIP
If that were instead an $s then I would do:
?php //IF there is a valid query by subject, use $s to build the SQL
$fields = SELECT art.*,publisher.*,subject.*;
$from = FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id;
$where = WHERE publisher.publisher_id=art.publisher_id AND
art.subject_id = '$s' AND
art.subject_id=subject.subject_id;
?
/SNIP
I had accidentally put a number 1 in place of the $s in the above
example. Apologies for the extra mail and thanks in advance.
Greg Donald wrote:
On 6/2/05, Jack Jackson [EMAIL PROTECTED] wrote:
I'd love some help with http://hashphp.org/pastebin?pid=3443 if anyone
can...
Basically I want to make it so that, if the get in the url specifies no
query or a query to a nonexistent row, send to vanilla index. If url
specifies c= then set $c=c and use the number to build the mysql query;
same for p= and s= - if they're valid build the query, if not kick em out.
Can anyone offer any help?
I'd iterate over the $_GET array to build the query elements. Then
implode those elements.
$array = array();
while( list( $k, $v ) = each( $_GET ) )
{
if( $k == 'somekeynotindb' )
{
continue;
}
$array[] = $k . =' . $v . ';
}
if( $array )
{
$and = implode( ', ', $array );
}
$sql =
SELECT *
FROM table
WHERE 1
$and
;
$query = mysql_query( $sql );
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Re: [PHP] Using GET to build multiple sql queries
Greg, thank you for all this... See below
Greg Donald wrote:
On 6/2/05, Jack Jackson [EMAIL PROTECTED] wrote:
Thanks for the reply, Greg,
I see how that is useful. I am confused as to how I would implement it
here. Please bear with me as I am a newbie and am now perhaps more
confused than ever!:
Bummer, sorry.
Twasn't you; were me.
I'm trying to use the number given in the $_GET URL to build one piece
of the sql:
If there is anything set in the $_GET field other than ?c=[valid int] or
?p=[valid int] or ?s=[valid int] then I want to bounce to a plain index.
if( !( isset( $_GET[ 'c' ] ) is_int( $_GET[ 'c' ] )
|| isset( $_GET[ 'p' ] ) is_int( $_GET[ 'p' ] )
|| isset( $_GET[ 's' ] ) is_int( $_GET[ 's' ] ) ) )
{
header( 'Location: index.php' );
exit;
}
Of course, that almost did it. But I wanted to do it it *weren't* an
int. I put a ! in front and that works like a charm!
If it's a valid int (a positive int which corresponds to a valid row)
then I want to set its value to the appropriate variable: either $c, $p
or $s,
If it's in the URL it's already set as $_GET[ 'c' ], $_GET[ 'p' ], or
$_GET[ 's' ].
I get it. Thanks for that. Including it in the sql didn't work as you
suggested:
?php //IF there is a valid query by cartoon, use $c to build the SQL
$fields = 'SELECT art.*,publisher.*,subject.*';
$from = 'FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id';
$sort = ORDER BY art.art_pub_date;
$where = WHERE art.art_id = '$c' AND
WHERE art.art_id = '$_GET[c]'
I guess it was missing a print command or something. I did this up top
though:
$c = intval($_GET['c']);
$p = intval($_GET['p']);
$s = intval($_GET['s']);
and then did it as I had it in the sample above and it worked like a
charm, too.
subject.subject_id=art.subject_id;
?
If that were instead a $p then I would do:
?php //IF there is a valid query by publisher, use $p to build the SQL
$fields = SELECT art.*,publisher.*,subject.*;
$from = FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id;
$where = WHERE publisher.publisher_id=art.publisher_id AND
art.publisher_id = '$p' AND
art.publisher_id = '$_GET[p]' AND
subject.subject_id=art.subject_id;
?
If that were instead an $s then I would do:
?php //IF there is a valid query by subject, use $s to build the SQL
$fields = SELECT art.*,publisher.*,subject.*;
$from = FROM art,subject
LEFT JOIN publisher
ON publisher.publisher_id=art.publisher_id;
$where = WHERE publisher.publisher_id=art.publisher_id AND
art.subject_id = '1' AND
art.subject_id=subject.subject_id;
?
I'm sure your method works ( ;) ). If I understand it, as my friend
Darrell said about your suggestion:
'...We iterate through the array seeing if there's a submitted HTML form
field name that matches the current database column name. If so, we add
the column name and the value submitted in the form to a string that is
being built into a database query.'
It's just a matter of checking for variables in the $_GET array and
doing what you need to do if they exist and are valid or not. Do you
know about print_r() yet?
echo 'pre';
print_r( $_GET );
echo '/pre';
I did and thank you. This is close to working, though I still have to
deal with what happens once I run those queries. But thanks for sorting
out that mess for me,. I really appreciate it.
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[PHP] foreach ($media as $key = $val) problem
Hi, all,
This might look like a mysql problem but I assure you it's my botching
the PHP which is the problem!
I'm building a part of a page with info from three tables: art, media
and media_art. Media_art is the intersection table. For every entry in
art there can be one or more entries in media.
art.art_id 1 has two entries in media_art:
Media_id art_id
32
52
I do this SQL, which in phpmyadmin returns the two names of media as
expected
SELECT media.media_name
FROM art, media_art, media
WHERE art.art_id = 1
AND art.art_id = media_art.art_id
AND media.media_id = media_art.media_id
Yet here's where I mess up. To see if I've got them in an array, I do:
$media = mysql_fetch_assoc($media_result);
while ($media = mysql_fetch_assoc($media_result)) {
asort($media);
foreach($media as $key = $val) {
echo key: $key value: $val br /;
}
} //end while $media = mysql_fetch_assoc($media_result)
and this returns only the name of the HIGHer number of the two (that is,
5).
What have I done wrong to echo out each name of the media associated
with this record? I'm trying, eventually, to echo it out in the age so
that it appears as
[art_id 1] comprises Ink, watercolor.
Thanks in advance,
Jack
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[PHP] php not allowed in .htaccess
Hi, dumb config issue. I'm putting a php_value include_path statement in an .htaccess file php_value include_path .:/home/user/public_html/dis/admin/:/home/nick/ php_value auto_prepend_file /home/user/public_html/dis/admin/wcsconf.php and getting a 500 Server Error. Apache logs say, .htaccess: php_value not allowed here Where can I change this behavior - is this an apache httpd.conf or php.ini setting? Something else? Thanks in advance! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php not allowed in .htaccess
Sorry folks. Figured it out: in httpd.conf it wasn't in the first or second AllowOverride section (which I had set to All and that's why I was so gobsmacked) BUT it was in the Control access to UserDir directories section. Thanks everyone! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
