Re: [PHP] file_exists() question

2003-03-08 Thread Jim Lucas
what does $annrow[id] return?

I HAVE found that I have to refer to a file when using file_exists() from /

so
file_exists(/path/to/me/cherpdocs/filename.doc)

for it to work right.

Jim
- Original Message - 
From: Charles Kline [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, March 08, 2003 1:10 PM
Subject: [PHP] file_exists() question


 Can anyone tell me why this code does not return true when the file in 
 the directory cherpdocs/ with the file (which I see as being there) 
 does exist?
 
 if(file_exists('cherpdocs/$annrow[id].doc')){
  echo br /a href=\cherpdocs/$annrow[id].doc\Funding 
 details paper/a;
   }
 
 This is a path relative to the file calling it, should it be otherwise?
 
 Thanks
 Charles
 
 
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Re: [PHP] file_exists() question

2003-03-08 Thread Khalid El-Kary
because you can't directly use the $annrow[id] within single quotes, you 
should use double quotes to do so.

file_exists(cherpdocs/$annrow[id].doc)

or

file_exists('cherpdocs/'.$annrow[id].'.doc')

or

file_exists(cherpdocs/.$annrow[id]..doc)

Note: i heared it's prefered to always use the . when including variables 
within strings.

Regards,
Khalid Al-Kary
http://creaturesx.ma.cx/kxparse/



Can anyone tell me why this code does not return true when the file in the 
directory cherpdocs/ with the file (which I see as being there) does exist?

if(file_exists('cherpdocs/$annrow[id].doc')){
echo br /a href=\cherpdocs/$annrow[id].doc\Funding details 
paper/a;
 }

This is a path relative to the file calling it, should it be otherwise?

Thanks
Charles
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Re: [PHP] file_exists() question

2003-03-08 Thread Jason Sheets
You will probably need to use

file_exists(cherpdocs/{$annrow['id']}.doc) you could also use
file_exists('cherpdocs/' . $annrow['id'] . '.doc')

You should use single quotes to identify your element in an array,
otherwise PHP will try to use it as a constant first.

Jason
On Sat, 2003-03-08 at 14:40, Khalid El-Kary wrote:
 because you can't directly use the $annrow[id] within single quotes, you 
 should use double quotes to do so.
 
 file_exists(cherpdocs/$annrow[id].doc)
 
 or
 
 file_exists('cherpdocs/'.$annrow[id].'.doc')
 
 or
 
 file_exists(cherpdocs/.$annrow[id]..doc)
 
 Note: i heared it's prefered to always use the . when including variables 
 within strings.
 
 Regards,
 Khalid Al-Kary
 http://creaturesx.ma.cx/kxparse/
 
 
 
 
 Can anyone tell me why this code does not return true when the file in the 
 directory cherpdocs/ with the file (which I see as being there) does exist?
 
 if(file_exists('cherpdocs/$annrow[id].doc')){
  echo br /a href=\cherpdocs/$annrow[id].doc\Funding details 
 paper/a;
   }
 
 This is a path relative to the file calling it, should it be otherwise?
 
 Thanks
 Charles
 
 
 --
 PHP General Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php
 
 
 _
 Add photos to your e-mail with MSN 8. Get 2 months FREE*. 
 http://join.msn.com/?page=features/featuredemail
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Re: [PHP] file_exists() question

2003-03-08 Thread Ernest E Vogelsinger
At 22:40 08.03.2003, Khalid El-Kary said:
[snip]
because you can't directly use the $annrow[id] within single quotes, you 
should use double quotes to do so.

file_exists(cherpdocs/$annrow[id].doc)

or

file_exists('cherpdocs/'.$annrow[id].'.doc')

or

file_exists(cherpdocs/.$annrow[id]..doc)

Note: i heared it's prefered to always use the . when including variables 
within strings.
[snip] 

Hmm - that's a bit different.

1) You can't use variables in singlequoted strings - these don't get parsed
by PHP.
2) You can absolutely use variables in doublequoted strings as these do get
parsed.
3) Array indices and object references must be enclosed in curly brackets
when used within double quotes to tell PHP what the variable and what the
string text is.
Example:
cherpdocs/$annrow[id].doc  == doesn't work correctly
cherpdocs/{$annrow['id']}.doc == will work
cherpdocs/$object-docname.doc == will not work
cherpdocs/{$object-docname}.doc == will work

Note that you should quote non-numeric array indices to allow PHP to
recognize it's not a defined value. Omitting quotes for index data would
trigger a warning (something like 'using unknown identifier id, assuming
id').


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Re: [PHP] file_exists() question

2003-03-08 Thread Justin French
on 09/03/03 8:10 AM, Charles Kline ([EMAIL PROTECTED]) wrote:

 if(file_exists('cherpdocs/$annrow[id].doc')){
 echo br /a href=\cherpdocs/$annrow[id].doc\Funding
 details paper/a;
 }

This is a pretty simple debugging type query, so:

First things first, make sure that $annrow[id] is what you expect, by
echoing it to the screen.

?
echo $annrow[id] . br /;
?


Then your file_exists() line has to use double quotes, because you're using
a variable:

file_exists(cherpdocs/$annrow[id].doc)

Or better still, clarify exactly what you want by using {braces} or .'s
file_exists(cherpdocs/{$annrow[id]}.doc)

Or:
file_exists(cherpdocs/ . $annrow[id] . .doc)


Same applies to your echo line.



Summary, I think you can save yourself a little grief by making the
following changes to your code.  Personally, I prefer wrapping all vars in
{braces} if inside a string.  It also includes some minor debugging code, so
that you can hunt down the issue.

?
$file = cherpdocs/{$annrow[id]}.doc

if(file_exists($file)) {
echo br /a href=\{$file}\Funding details paper/a;
} else {
echo The file {$file} did not exist;
}
?


Justin


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