Re: [PHP] fopen - warnings

2001-07-26 Thread david jarvis
try @fopen(categories.txt,r+); - Original Message - From: Vanessa [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, July 26, 2001 12:05 PM Subject: [PHP] fopen - warnings Hello List, this is probably a very stupid question, but I dont know how to solve this little problem: I

RE: [PHP] fopen - warnings

2001-07-26 Thread Taylor, Stewart
Assuming that your code works fine apart from the warning message you can use @ so suppress any warning messages e.g. @fopen( -Stewart -Original Message- From: Vanessa [mailto:[EMAIL PROTECTED]] Sent: 26 July 2001 17:06 To: [EMAIL PROTECTED] Subject: [PHP] fopen - warnings Hello

Re: [PHP] fopen question

2001-05-07 Thread Kelvin
Hi sean, try to put a file name not a directory or path. $file = fopen(filename.withextension,r+ Kelvin. [EMAIL PROTECTED] wrote in message 9d6apq$eka$[EMAIL PROTECTED]">news:9d6apq$eka$[EMAIL PROTECTED]... hi I am running the following on my redhat 7.0 / php4 / apache box and

Re: [PHP] fopen question

2001-05-07 Thread sean
even when you are trying to access a COM port? Kelvin [EMAIL PROTECTED] wrote in message 9d6dc8$eug$[EMAIL PROTECTED]">news:9d6dc8$eug$[EMAIL PROTECTED]... Hi sean, try to put a file name not a directory or path. $file = fopen(filename.withextension,r+ Kelvin. [EMAIL PROTECTED]

Re: [PHP] fopen wierdness

2001-04-06 Thread Christian Reiniger
On Friday 06 April 2001 03:12, you wrote: Technically yes. In an HTTP session, the server returns a header "Content-length" which lists the more or less exact size of the file being sent. Caution: The server is not required to send this header - PHP for example doesn't do it automatically.

Re: [PHP] fopen wierdness

2001-04-05 Thread Steve Werby
"Jerry" [EMAIL PROTECTED] wrote: im trying to fopen a url with something like to following : fopen("something.com/something.txt", r); this returns a "0" If you're trying to open an external file make sure you prepend the URL with 'http://'. If that's a local file and it's not finding the

Re: [PHP] fopen wierdness

2001-04-05 Thread Richard
No, you receive the handle to the file. You cannot rename the handle. ? $filename = "http://www.latest.txt"; $fd = fopen ($filename, "r"); $contents = fread ($fd, filesize ($filename)); echo $contents; fclose ($fd); ? Should do the trick.. or something.. Modify it or whatever. - Richard

Re: [PHP] fopen wierdness

2001-04-05 Thread Jerry
acutally i found my problem, what was happening was that script1 that was on the server that file resides had that file open at the same time that scirpt2 was trying to open via http, when i change that files name, the permissions changed, and script1 was unable to open the file, and so script2

Re: [PHP] fopen wierdness

2001-04-05 Thread Plutarck
Technically yes. In an HTTP session, the server returns a header "Content-length" which lists the more or less exact size of the file being sent. But there isn't really an easy way of reading HTTP headers in php, yet. I really wish there were. You can use fsockopen to make your own http

Re: [PHP] fopen wierdness

2001-04-05 Thread Steve Werby
"Steve Werby" [EMAIL PROTECTED] wrote: acutally i found my problem, what was happening was that script1 that was on the server that file resides had that file open at the same time that scirpt2 was trying to open via http, when i change that files name, the permissions changed, and script1

Re: [PHP] fopen with URL gives me a problem

2001-04-02 Thread Richard Lynch
Now i get a error window saying: "Document contained no data" That usually means PHP crashed. Check your web-server error logs. Also, try adding some debug output before each statement to pinpoint the crash line. --code- $noaa =

Re: [PHP] Fopen help

2001-03-23 Thread Richard Lynch
Basically, you shouldn't be checking for '1' as an answer. Either you got 0, and it didn't work, or you didn't, and the URL is valid. -- Visit the Zend Store at http://www.zend.com/store/ Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time:

Re: [PHP] Fopen image and print as binary/Image

2001-02-27 Thread Richard Lynch
? header( "Content-type: image/gif" ); $img = fopen($DOCUMENT_ROOT . "/store/include/TestingImage.gif","rb"); print($img); ? prints this: Resource id #1 I'm trying to print the image as binary or as an image. Have I missed a step? Hope i'm not being too confusing. $img is a "file

Re: [PHP] fopen

2001-02-23 Thread Richard Lynch
I'm trying to fopen a URL that I have no problems getting to if I just past it into the address field of my browser. However, when I use it in my fopen() function call, I'm getting an "Error 0" (zero) message. I've looked all over the documentation and I could not find what 'Error 0'

Re: [PHP] fopen problem... maybe?

2001-02-20 Thread David Robley
On Wed, 21 Feb 2001 15:23, Ben Weinberger wrote: Hi~ We're working on a page located at http://www.manageasy.com/request_offer.php3. The page comes up with a bunch of errors, and we don't know why-- the page worked on our old server, and we didn't change anything from there... we think it

Re: [PHP] Fopen

2001-01-26 Thread Richard Lynch
? $fp = fopen("http://www.parentprofiles.com/clicker.php?profile_id=" . $this-profile_id . "code=1","r"); echo $fp; ? to do it. however when I do all I get is a response that says: Resource id #1 instead of giving me the page. Any ideas? Basically, that Resource id # 1 is like a paper

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