Re: [PHP] $_ENV not working for me with PHP 4.2.0
John Wilcox wrote: I've been trying to make a simple script which just outputs the username that the script is currently executing under (in order to test that suexec is working properly). I've tried using the following line: ?php print $_ENV['USER']; ? and it fails to produce any output and returns the following error in my log file: [Sun Oct 5 14:02:35 2003] [error] PHP Notice: Undefined index: USER in /home/test/test.php on line 1 Now, I've tried the same command on another server running PHP 4.2.0 and it correctly outputs the username as expected. Both these machines are running Debian Linux. Try echo pre; print_r($_ENV); echo /pre; to see what information is available in the ENV array. Are both servers running the same implementation of PHP? (CGI/SAPI, etc.) -- Burhan Khalid phplist[at]meidomus[dot]com http://www.meidomus.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Passing POST args to PHP when run as a CGI (was Re: [PHP] $_ENV not working for me with PHP 4.2.0)
--- Curt Zirzow [EMAIL PROTECTED] wrote:
Technically it is 4.1.0 (where did you see the
4.2.0?) but anything
prior to that you should use $HTTP_ENV_VARS
my mistake, you're right, it was 4.1.0.
http://php.net/manual/en/language.variables.predefined.php
http://php.net/manual/en/reserved.variables.php
A diff of your php.ini will tell the story I'll bet
a diff output
would be something like:
306c306
variables_order = GPCS
---
variables_order = EGPCS
yes, you're correct, my php.ini uses 'variable_order =
GPCS'. I tried changing this to EGPCS, but
$_ENV['USER']; would still not work.
To get the user that apache is really running as you
want to do
something like:
print `whoami`;
I've been playing around a bit more, and made a simple
script:
?php
echo getenv('USER'), br /;
print `whoami` . br /;
print $_ENV['USER'];
?
It produces the following output:
john
nobody
(and an error is produced in the logfile for
$_ENV['USER']: Undefined index: USER)
Now, I'm running this PHP script from within a virtual
host with a certain user/group (test/test - made
possible by using suEXEC), so I can't understand why
getenv('USER'); is returning john..
Anyway, I've been reading up on using suEXEC with PHP
scripts, and it looks like the scripts have to be run
as a .cgi in order to inherit the user/group of the
virtual host.. I've tried changing around one of my
PHP scripts so that it runs as a cgi (basically I just
renamed the file to test.cgi and added
#!/usr/local/bin/php to the beginning of the script).
The only problem is that now my $_POST['TEST'];
doesn't work within the script, so my new problem is
how to figure out passing variables from one script to
another when using PHP as a .cgi. Am I doing
something wrong, or does something need to be changed
in order for PHP to be able to receive these POST
variables?
If anyone has any ideas, please let me know. Thanks
in advance,
John
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[PHP] $_ENV not working for me with PHP 4.2.0
I've been trying to make a simple script which just outputs the username that the script is currently executing under (in order to test that suexec is working properly). I've tried using the following line: ?php print $_ENV['USER']; ? and it fails to produce any output and returns the following error in my log file: [Sun Oct 5 14:02:35 2003] [error] PHP Notice: Undefined index: USER in /home/test/test.php on line 1 Now, I've tried the same command on another server running PHP 4.2.0 and it correctly outputs the username as expected. Both these machines are running Debian Linux. Now I figure it must be some configuration setting that is messing this up somehow, but I have no idea where to look. I've checked out the documentation and it states that PHP versions later than 4.2.0 use the $_ENV global variable to access environment variables, so it seems like I'm using it correctly. Anyways, if anyone has any suggestions, please let me know! Thanks in advance, John Wilcox __ Do you Yahoo!? The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] $_ENV not working for me with PHP 4.2.0
Hi, Monday, October 6, 2003, 4:43:20 AM, you wrote: JW I've been trying to make a simple script which just JW outputs the username that the script is currently JW executing under (in order to test that suexec is JW working properly). I've tried using the following JW line: JW ?php print $_ENV['USER']; ? JW and it fails to produce any output and returns the JW following error in my log file: [Sun Oct 5 14:02:35 JW 2003] [error] PHP Notice: Undefined index: USER in JW /home/test/test.php on line 1 JW Now, I've tried the same command on another server JW running PHP 4.2.0 and it correctly outputs the JW username as expected. Both these machines are running JW Debian Linux. JW Now I figure it must be some configuration setting JW that is messing this up somehow, but I have no idea JW where to look. I've checked out the documentation and JW it states that PHP versions later than 4.2.0 use the JW $_ENV global variable to access environment variables, JW so it seems like I'm using it correctly. Anyways, if JW anyone has any suggestions, please let me know! JW Thanks in advance, JW John Wilcox JW __ JW Do you Yahoo!? JW The New Yahoo! Shopping - with improved product search JW http://shopping.yahoo.com Do this to see what is available in your enviroment, it would seem that USER is not being set by the system or is called something else. echo `printenv`; (use backticks) -- regards, Tom -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] $_ENV not working for me with PHP 4.2.0
* Thus wrote John Wilcox ([EMAIL PROTECTED]):
I've been trying to make a simple script which just
outputs the username that the script is currently
executing under (in order to test that suexec is
working properly). I've tried using the following
line:
?php print $_ENV['USER']; ?
This var isn't the USER that the process is running under, it is
the USER that started apache (assuming thats your webserver). You
can see all the same vars if you execute the command `env`.
I also tested this:
shutting down apache
setenv TEST putvarinenv
started apache
test.php:
echo getenv('TEST');
yields:
'putvarinenv'
and it fails to produce any output and returns the
following error in my log file: [Sun Oct 5 14:02:35
2003] [error] PHP Notice: Undefined index: USER in
/home/test/test.php on line 1
Now, I've tried the same command on another server
running PHP 4.2.0 and it correctly outputs the
username as expected. Both these machines are running
Debian Linux.
if the username was expected, I'm guessing your output was root, you should
really change the webserver process to something other than root
(an unprivlaged user).
Now I figure it must be some configuration setting
that is messing this up somehow, but I have no idea
where to look. I've checked out the documentation and
it states that PHP versions later than 4.2.0 use the
$_ENV global variable to access environment variables,
so it seems like I'm using it correctly. Anyways, if
anyone has any suggestions, please let me know!
Thanks in advance,
Technically it is 4.1.0 (where did you see the 4.2.0?) but anything
prior to that you should use $HTTP_ENV_VARS
http://php.net/manual/en/language.variables.predefined.php
http://php.net/manual/en/reserved.variables.php
A diff of your php.ini will tell the story I'll bet a diff output
would be something like:
306c306
variables_order = GPCS
---
variables_order = EGPCS
To get the user that apache is really running as you want to do
something like:
print `whoami`;
Curt
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Re: [PHP] $_ENV not working for me with PHP 4.2.0
Hi Tom, when I put echo `printenv`; into a script, I
see in big bold letters: USER=john so this environment
variable seems to be available.. getenv('USER');
works fine, so I guess I'll just use that instead.. No
idea why $_ENV['USER']; doesn't work though. Thanks
for the suggestion,
John
--- Tom Rogers [EMAIL PROTECTED] wrote:
Hi,
Monday, October 6, 2003, 4:43:20 AM, you wrote:
JW I've been trying to make a simple script which
just
JW outputs the username that the script is
currently
JW executing under (in order to test that suexec is
JW working properly). I've tried using the
following
JW line:
JW ?php print $_ENV['USER']; ?
JW and it fails to produce any output and returns
the
JW following error in my log file: [Sun Oct 5
14:02:35
JW 2003] [error] PHP Notice: Undefined index:
USER in
JW /home/test/test.php on line 1
JW Now, I've tried the same command on another
server
JW running PHP 4.2.0 and it correctly outputs the
JW username as expected. Both these machines are
running
JW Debian Linux.
JW Now I figure it must be some configuration
setting
JW that is messing this up somehow, but I have no
idea
JW where to look. I've checked out the
documentation and
JW it states that PHP versions later than 4.2.0 use
the
JW $_ENV global variable to access environment
variables,
JW so it seems like I'm using it correctly.
Anyways, if
JW anyone has any suggestions, please let me know!
JW Thanks in advance,
JW John Wilcox
JW __
JW Do you Yahoo!?
JW The New Yahoo! Shopping - with improved product
search
JW http://shopping.yahoo.com
Do this to see what is available in your enviroment,
it would seem that USER is
not being set by the system or is called something
else.
echo `printenv`;
(use backticks)
--
regards,
Tom
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