[PHP] Display just 1 record in a query
I did a query... then I display records like:
table
?php do { ?
tr
td?php echo $row_cur['tid']; ?/td
tdnbsp;/td
/tr
?php } while ($row_cur = mysql_fetch_assoc($cur)); ?
/table
Q: but how I i just display a particular record with out the do /
while loop?
like just the 2nd record only:
i tried
?php echo $row_cur['tid',2]; ?
but this makes an error
or $row_cur('tid',2) --- hmmm what's the syntax?
Thanks,
deal...@gmail.com
[db-10]
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Re: [PHP] Display just 1 record in a query
though you can fetch twice to get the 2nd row
$row_cur = mysql_fetch_assoc($cur); //skip 1st row
$row_cur = mysql_fetch_assoc($cur);
echo $row_cur['tid'];
you should really modify your sql statement, like 'select xxx from xx order
by xx limit 1, 1' (limit 1,1 retrieve your 2nd row if you are using mysql)
On Tue, Jan 12, 2010 at 4:52 PM, deal...@gmail.com deal...@gmail.comwrote:
I did a query... then I display records like:
table
?php do { ?
tr
td?php echo $row_cur['tid']; ?/td
tdnbsp;/td
/tr
?php } while ($row_cur = mysql_fetch_assoc($cur)); ?
/table
Q: but how I i just display a particular record with out the do / while
loop?
like just the 2nd record only:
i tried
?php echo $row_cur['tid',2]; ?
but this makes an error
or $row_cur('tid',2) --- hmmm what's the syntax?
Thanks,
deal...@gmail.com
[db-10]
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Re: [PHP] Display just 1 record in a query
On Tue, 2010-01-12 at 13:52 -0800, deal...@gmail.com wrote:
I did a query... then I display records like:
table
?php do { ?
tr
td?php echo $row_cur['tid']; ?/td
tdnbsp;/td
/tr
?php } while ($row_cur = mysql_fetch_assoc($cur)); ?
/table
Q: but how I i just display a particular record with out the do /
while loop?
like just the 2nd record only:
i tried
?php echo $row_cur['tid',2]; ?
but this makes an error
or $row_cur('tid',2) --- hmmm what's the syntax?
Thanks,
deal...@gmail.com
[db-10]
Depends on how you're creating running the query. You could do something
like:
echo mysql_result($result, 1, 'fieldname');
Where $result is your result object and 1 is a 0 indexed array, so would
be the second result.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] Display just 1 record in a query
deal...@gmail.com wrote on 12/01/2010 22:52:
I did a query... then I display records like:
table
?php do { ?
tr
td?php echo $row_cur['tid']; ?/td
tdnbsp;/td
/tr
?php } while ($row_cur = mysql_fetch_assoc($cur)); ?
/table
Q: but how I i just display a particular record with out the do / while
loop?
Just use extract($row_cur); before the table starts. That would give you
first row only
Another approach could be to add LIMIT 1 to the end of your SQL statement
like just the 2nd record only:
i tried
?php echo $row_cur['tid',2]; ?
but this makes an error
or $row_cur('tid',2) --- hmmm what's the syntax?
Getting only second row, but not the first? That would be using a count
var and show only data if count == 2
table
?php
$count=0;
do {
$count++;
if($count == 2) {
echo '
tr
td'. $row_cur['tid'] .'/td
tdnbsp;/td
/tr';
}
} while ($row_cur = mysql_fetch_assoc($cur));
?
/table
Another thing: drop the do and use this syntax instead, it's more readable:
table
?php
$count=0;
while ($row_cur = mysql_fetch_assoc($cur)) {
$count++;
if($count == 2) {
echo '
tr
td'. $row_cur['tid'] .'/td
tdnbsp;/td
/tr';
}
}
?
/table
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Kind regards
Kim Emax - masterminds.dk
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RE: [PHP] Display just 1 record in a query
-Original Message-
From: Kim Madsen [mailto:php@emax.dk]
Sent: Tuesday, January 12, 2010 2:17 PM
To: deal...@gmail.com
Cc: php-general@lists.php.net
Subject: Re: [PHP] Display just 1 record in a query
deal...@gmail.com wrote on 12/01/2010 22:52:
I did a query... then I display records like:
table
?php do { ?
tr
td?php echo $row_cur['tid']; ?/td
tdnbsp;/td
/tr
?php } while ($row_cur = mysql_fetch_assoc($cur)); ?
/table
Q: but how I i just display a particular record with out
the do / while
loop?
Just use extract($row_cur); before the table starts. That
would give you
first row only
Another approach could be to add LIMIT 1 to the end of
your SQL statement
like just the 2nd record only:
i tried
?php echo $row_cur['tid',2]; ?
but this makes an error
or $row_cur('tid',2) --- hmmm what's the syntax?
Getting only second row, but not the first? That would be
using a count
var and show only data if count == 2
table
?php
$count=0;
do {
$count++;
if($count == 2) {
echo '
tr
td'. $row_cur['tid'] .'/td
tdnbsp;/td
/tr';
}
} while ($row_cur = mysql_fetch_assoc($cur));
?
/table
Another thing: drop the do and use this syntax instead, it's
more readable:
table
?php
$count=0;
while ($row_cur = mysql_fetch_assoc($cur)) {
$count++;
if($count == 2) {
echo '
tr
td'. $row_cur['tid'] .'/td
tdnbsp;/td
/tr';
}
}
?
/table
Holy, Jesus, Marry and Joseph! You can't be serious with that?!
So you're going to loop over potentially hundreds or thousands of records
and only display one?
Wow. Speechless.
http://www.php.net/manual/en/function.mysql-data-seek.php
$result = mysql_query($query);
mysql_data_seek($result, 1); //rows start at 0, so second row is 1
$row = mysql_fetch_assoc($result);
echo $row['tid'];
But the real way I suggest is using the LIMIT portion of your SELECT
http://dev.mysql.com/doc/refman/5.0/en/select.html
Then you don't need to data_seek() as you would have pulled the exact row
you wanted.
If you wanted the second row, you would LIMIT 1,1
Also, if you just did a basic loop and stored all your results in a
multi-dimensional array, then you would just pull that element.
$mydata = array();
while ($row = mysql_fetch_assoc($result)) $mydata[] = $row;
Then you would just echo $mydata[1]['tid'];
Or what I like to do:
while ($row = mysql_fetch_assoc($result)) $mydata[$row['id']] = $row;
Assuming you were trying to pull a specific record $tid = ID:
echo $mydata[$tid];
ÐÆ5ÏÐ
Light travels faster than sound. This is why some people appear bright
until you hear them speak.
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Re: [PHP] Display just 1 record in a query
Daevid Vincent wrote on 13/01/2010 00:00: Holy, Jesus, Marry and Joseph! You can't be serious with that?! So you're going to loop over potentially hundreds or thousands of records and only display one? Wow. Speechless. Either you're talking to dealtek or you didn't read my post very well: Another approach could be to add LIMIT 1 to the end of your SQL statement I just pointed out different approaches and answered his questions. Of course I would use last or break on the count == 2 approach, not running through _any_ records after getting what I wanted. I don't really get the like just the 2nd record only, but again, from the material we've seen it's hard to give the right advice -- Kind regards Kim Emax - masterminds.dk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Display just 1 record in a query
On Jan 12, 2010, at 1:57 PM, Ashley Sheridan wrote: Depends on how you're creating running the query. You could do something like: echo mysql_result($result, 1, 'fieldname'); Where $result is your result object and 1 is a 0 indexed array, so would be the second result. Thanks Ryan, Ashley Kim for the good techniques... - in my case I was trying to pull a random record from a query of Table1 - then do a 2nd query from 1st so mysql_result worked fine for my needs like: ... do query 1... 'cur' - SELECT id FROM myTable1 $ran = rand(0, $totalRows_cur - 1); // pick random rec row within total count $pick1 = mysql_result($cur, $ran); // get the ID from the choice - (like id=252) ... do query 2 // where relatedID = $pick1 of myTable2 cool - THANKS ALL! Thanks, deal...@gmail.com [db-10] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Display just 1 record in a query
deal...@gmail.com wrote: On Jan 12, 2010, at 1:57 PM, Ashley Sheridan wrote: Depends on how you're creating running the query. You could do something like: echo mysql_result($result, 1, 'fieldname'); Where $result is your result object and 1 is a 0 indexed array, so would be the second result. Thanks Ryan, Ashley Kim for the good techniques... - in my case I was trying to pull a random record from a query of Table1 - then do a 2nd query from 1st so mysql_result worked fine for my needs like: ... do query 1... 'cur' - SELECT id FROM myTable1 $ran = rand(0, $totalRows_cur - 1); // pick random rec row within total count $pick1 = mysql_result($cur, $ran); // get the ID from the choice - (like id=252) ... do query 2 // where relatedID = $pick1 of myTable2 Put your random logic into the query: SELECT something FROM somewhere WHERE condition ORDER BY RAND() LIMIT 1 Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Display just 1 record in a query
Op 1/13/10 12:43 AM, Robert Cummings schreef: deal...@gmail.com wrote: On Jan 12, 2010, at 1:57 PM, Ashley Sheridan wrote: Depends on how you're creating running the query. You could do something like: echo mysql_result($result, 1, 'fieldname'); Where $result is your result object and 1 is a 0 indexed array, so would be the second result. Thanks Ryan, Ashley Kim for the good techniques... - in my case I was trying to pull a random record from a query of Table1 - then do a 2nd query from 1st so mysql_result worked fine for my needs like: ... do query 1... 'cur' - SELECT id FROM myTable1 $ran = rand(0, $totalRows_cur - 1); // pick random rec row within total count $pick1 = mysql_result($cur, $ran); // get the ID from the choice - (like id=252) ... do query 2 // where relatedID = $pick1 of myTable2 Put your random logic into the query: SELECT something FROM somewhere WHERE condition ORDER BY RAND() LIMIT 1 please read the following to understand the consequences and possible performance problems with this approach: http://www.titov.net/2005/09/21/do-not-use-order-by-rand-or-how-to-get-random-rows-from-table/ personally I go with the 2 query approach ... or even to use a specific field to store a generated random value (with suitable index) for each record, the stored values can be regenerated in an out-of-band process (e.g. cron job) ... such a setup would suffice in situations where frontend response speed is of primary concern and it's acceptable to return the same 'random' record over a given period (i.e. the time between random value regeneration) Cheers, Rob. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Display just 1 record in a query
Jochem Maas wrote: Op 1/13/10 12:43 AM, Robert Cummings schreef: deal...@gmail.com wrote: On Jan 12, 2010, at 1:57 PM, Ashley Sheridan wrote: Depends on how you're creating running the query. You could do something like: echo mysql_result($result, 1, 'fieldname'); Where $result is your result object and 1 is a 0 indexed array, so would be the second result. Thanks Ryan, Ashley Kim for the good techniques... - in my case I was trying to pull a random record from a query of Table1 - then do a 2nd query from 1st so mysql_result worked fine for my needs like: ... do query 1... 'cur' - SELECT id FROM myTable1 $ran = rand(0, $totalRows_cur - 1); // pick random rec row within total count $pick1 = mysql_result($cur, $ran); // get the ID from the choice - (like id=252) ... do query 2 // where relatedID = $pick1 of myTable2 Put your random logic into the query: SELECT something FROM somewhere WHERE condition ORDER BY RAND() LIMIT 1 please read the following to understand the consequences and possible performance problems with this approach: http://www.titov.net/2005/09/21/do-not-use-order-by-rand-or-how-to-get-random-rows-from-table/ I was already aware of the issues with RAND(). However, at the very top it says: if your table have just 50-100 rows, use whatever you want. Without more information about the person's particular use case I would use the RAND() version for its simplicity :) Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
