Re: [PHP] Foreach and mydql_query problem
It works now and it was a php thing.When I combine a for and while loop
together with Limit in my query it works.
Karl
mandag 22. juli 2013 skrev Liam følgende:
Shouldn't $_POST['number_of_itemsi'] be $_POST['number_of_items']
Kind Regards,
Liam.
3Sharp Ltd.
T: 0845 6018370
F: 0845 6018369
-Original Message-
From: Karl-Arne Gjersøyen [mailto:karlar...@gmail.com javascript:;]
Sent: 22 July 2013 12:39
To: PHP Mailinglist
Subject: Re: [PHP] Foreach and mydql_query problem
2013/7/22 Tamara Temple tamouse.li...@gmail.com javascript:;
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen
karlar...@gmail.comjavascript:;
wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like
this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE
date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql
and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written
when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override
every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the errors
should be rather obvious. Post *actual* code.
// The acutual source code is below:
// ==
if(!empty($_POST['antall_kolli'])){
include('../../tilkobling.php');
foreach($antall_kolli as $kolli){
echo $kollibr;
//echo $kolli. br;
$sql = UPDATE transportdokument SET antall_kolli_stk =
'$kolli' WHERE dato = '$dagens_dato' AND signatur = '$brukernavn';
mysql_query($sql,$tilkobling) or die(mysql_error());
}
}
// THE PHP/HTML Form below:
include('../../tilkobling.php');
$sql = SELECT * FROM transportdokument WHERE dato = '$dagens_dato' AND
signatur = '$brukernavn';
$resultat = mysql_query($sql, $tilkobling) or die(mysql_error());
while($rad = mysql_fetch_array($resultat, MYSQL_ASSOC)){
$valgt_lager = $rad['valgt_lager'];
$un_nr = $rad['un_nr'];
$sprengstofftype = $rad['sprengstofftype'];
$varenavn = $rad['varenavn'];
$varenr = $rad['varenr'];
$antall_kolli = $rad['antall_kolli_stk'];
$adr_vekt_kg = $rad['adr_vekt_kg'];
$varenavn = $rad['varenavn'];
$emb = $rad['emb'];
?
tr
td align=left valign=top?php echo $un_nr; ?/td
td align=left valign=topstrongSprengstoff/strong,?php echo
$sprengstofftype; ?/td
td align=left valign=top?php echo $varenavn; ?/td
td align=left valign=topstrong1.1D/strong/td
td align=left valign=topnbsp;/td
td align=left valign=top?php echo $emb; ?/td
td align=left valign=top
input type=hidden name=varenr[] value=?php echo $varenr; ?
input type=number name=antall_kolli[] size=6 value=?php echo
$antall_kolli; ? required=required
/td
td align=left valign=topinput type=text name=exan_kg_ut[]
size=6 value=?php echo $adr_vekt_kg; ? required=required/td
/tr
?php
$total_mengde_kg_adr += $rad['adr_vekt_kg'];
$total_antall_kolli += $rad['antall_kolli_stk'];
}
?
include('../../tilkobling.php');
$sql = SELECT * FROM transportdokument WHERE dato = '$dagens_dato' AND
signatur = '$brukernavn';
$resultat = mysql_query($sql, $tilkobling) or die(mysql_error());
while($rad = mysql_fetch_array($resultat, MYSQL_ASSOC)){
$valgt_lager = $rad['valgt_lager'];
$un_nr = $rad['un_nr'];
$sprengstofftype = $rad['sprengstofftype'];
$varenavn = $rad['varenavn'];
$varenr = $rad['varenr'];
$antall_kolli = $rad['antall_kolli_stk'];
$adr_vekt_kg = $rad['adr_vekt_kg'];
$varenavn = $rad['varenavn'];
$emb = $rad['emb'];
?
tr
td align=left valign=top?php echo $un_nr; ?/td
td align=left valign=topstrongSprengstoff/strong,?php echo
$sprengstofftype; ?/td
td align=left valign=top?php echo $varenavn; ?/td
td align=left valign=topstrong1.1D/strong/td
td align=left valign=topnbsp;/td
td align=left valign=top?php echo $emb; ?/td
td align=left valign=top
input type=hidden name=varenr[] value=?php echo $varenr
[PHP] Foreach and mydql_query problem
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Re: [PHP] Foreach and mydql_query problem
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the errors
should be rather obvious. Post *actual* code.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach and mydql_query problem
On 22 Jul 2013, at 08:04, Tamara Temple tamouse.li...@gmail.com wrote:
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the errors
should be rather obvious. Post *actual* code.
The error is rather obvious: it loops around an array running an update
statement that will modify a single row in the table, so it's not surprising
that it appears like only the last entry in the array has been stored.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach and mydql_query problem
2013/7/22 Tamara Temple tamouse.li...@gmail.com
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com
wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like
this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql
and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written
when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the errors
should be rather obvious. Post *actual* code.
// The acutual source code is below:
// ==
if(!empty($_POST['antall_kolli'])){
include('../../tilkobling.php');
foreach($antall_kolli as $kolli){
echo $kollibr;
//echo $kolli. br;
$sql = UPDATE transportdokument SET antall_kolli_stk =
'$kolli' WHERE dato = '$dagens_dato' AND signatur = '$brukernavn';
mysql_query($sql,$tilkobling) or die(mysql_error());
}
}
// THE PHP/HTML Form below:
include('../../tilkobling.php');
$sql = SELECT * FROM transportdokument WHERE dato = '$dagens_dato' AND
signatur = '$brukernavn';
$resultat = mysql_query($sql, $tilkobling) or die(mysql_error());
while($rad = mysql_fetch_array($resultat, MYSQL_ASSOC)){
$valgt_lager = $rad['valgt_lager'];
$un_nr = $rad['un_nr'];
$sprengstofftype = $rad['sprengstofftype'];
$varenavn = $rad['varenavn'];
$varenr = $rad['varenr'];
$antall_kolli = $rad['antall_kolli_stk'];
$adr_vekt_kg = $rad['adr_vekt_kg'];
$varenavn = $rad['varenavn'];
$emb = $rad['emb'];
?
tr
td align=left valign=top?php echo $un_nr; ?/td
td align=left valign=topstrongSprengstoff/strong,?php echo
$sprengstofftype; ?/td
td align=left valign=top?php echo $varenavn; ?/td
td align=left valign=topstrong1.1D/strong/td
td align=left valign=topnbsp;/td
td align=left valign=top?php echo $emb; ?/td
td align=left valign=top
input type=hidden name=varenr[] value=?php echo $varenr; ?
input type=number name=antall_kolli[] size=6 value=?php echo
$antall_kolli; ? required=required
/td
td align=left valign=topinput type=text name=exan_kg_ut[]
size=6 value=?php echo $adr_vekt_kg; ? required=required/td
/tr
?php
$total_mengde_kg_adr += $rad['adr_vekt_kg'];
$total_antall_kolli += $rad['antall_kolli_stk'];
}
?
include('../../tilkobling.php');
$sql = SELECT * FROM transportdokument WHERE dato = '$dagens_dato' AND
signatur = '$brukernavn';
$resultat = mysql_query($sql, $tilkobling) or die(mysql_error());
while($rad = mysql_fetch_array($resultat, MYSQL_ASSOC)){
$valgt_lager = $rad['valgt_lager'];
$un_nr = $rad['un_nr'];
$sprengstofftype = $rad['sprengstofftype'];
$varenavn = $rad['varenavn'];
$varenr = $rad['varenr'];
$antall_kolli = $rad['antall_kolli_stk'];
$adr_vekt_kg = $rad['adr_vekt_kg'];
$varenavn = $rad['varenavn'];
$emb = $rad['emb'];
?
tr
td align=left valign=top?php echo $un_nr; ?/td
td align=left valign=topstrongSprengstoff/strong,?php echo
$sprengstofftype; ?/td
td align=left valign=top?php echo $varenavn; ?/td
td align=left valign=topstrong1.1D/strong/td
td align=left valign=topnbsp;/td
td align=left valign=top?php echo $emb; ?/td
td align=left valign=top
input type=hidden name=varenr[] value=?php echo $varenr; ?
input type=number name=antall_kolli[] size=6 value=?php echo
$antall_kolli; ? required=required
/td
td align=left valign=topinput type=text name=exan_kg_ut[]
size=6 value=?php echo $adr_vekt_kg; ? required=required/td
/tr
?php
$total_mengde_kg_adr += $rad['adr_vekt_kg'];
$total_antall_kolli += $rad['antall_kolli_stk'];
}
?
Re: [PHP] Foreach and mydql_query problem
2013/7/22 Stuart Dallas stu...@3ft9.com
On 22 Jul 2013, at 08:04, Tamara Temple tamouse.li...@gmail.com wrote:
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com
wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like
this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql
and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written
when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override
every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the
errors should be rather obvious. Post *actual* code.
The error is rather obvious: it loops around an array running an update
statement that will modify a single row in the table, so it's not
surprising that it appears like only the last entry in the array has been
stored.
Yes, i know that only one a singe row is updated and that is the problem.
What can I do to update several rows at the same time?
Thank you very much for all your good adivce.
Karl
Re: [PHP] Foreach and mydql_query problem
On 22 Jul 2013, at 12:56, Karl-Arne Gjersøyen karlar...@gmail.com wrote:
2013/7/22 Stuart Dallas stu...@3ft9.com
On 22 Jul 2013, at 08:04, Tamara Temple tamouse.li...@gmail.com wrote:
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com
wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like
this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql
and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written
when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override
every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the
errors should be rather obvious. Post *actual* code.
The error is rather obvious: it loops around an array running an update
statement that will modify a single row in the table, so it's not
surprising that it appears like only the last entry in the array has been
stored.
Yes, i know that only one a singe row is updated and that is the problem.
What can I do to update several rows at the same time?
Thank you very much for all your good advice.
Are you sure you want to update several rows, or do you actually want to insert
several rows?
This is pretty basic database stuff, and is off-topic for this list.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach and mydql_query problem
2013/7/22 Stuart Dallas stu...@3ft9.com
On 22 Jul 2013, at 12:56, Karl-Arne Gjersøyen karlar...@gmail.com wrote:
2013/7/22 Stuart Dallas stu...@3ft9.com
On 22 Jul 2013, at 08:04, Tamara Temple tamouse.li...@gmail.com
wrote:
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com
wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like
this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE
date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that
$sql
and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written
when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override
every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the
errors should be rather obvious. Post *actual* code.
The error is rather obvious: it loops around an array running an update
statement that will modify a single row in the table, so it's not
surprising that it appears like only the last entry in the array has
been
stored.
Yes, i know that only one a singe row is updated and that is the
problem.
What can I do to update several rows at the same time?
Thank you very much for all your good advice.
Are you sure you want to update several rows, or do you actually want to
insert several rows?
This is pretty basic database stuff, and is off-topic for this list.
OK. Sorry. I thought it was a PHP question for a way to update several
mysql rows by PHP code.
Karl
Re: [PHP] Foreach and mydql_query problem
On 22 Jul 2013, at 13:25, Karl-Arne Gjersøyen karlar...@gmail.com wrote:
2013/7/22 Stuart Dallas stu...@3ft9.com
On 22 Jul 2013, at 12:56, Karl-Arne Gjersøyen karlar...@gmail.com wrote:
2013/7/22 Stuart Dallas stu...@3ft9.com
On 22 Jul 2013, at 08:04, Tamara Temple tamouse.li...@gmail.com wrote:
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen karlar...@gmail.com
wrote:
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like
this:
input type=number name=number_of_items[] size=6 value=?hp
echo $item; ? required=required
the php source code look like this:
?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo $itemibr;
$sql = UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username';
mysql_query($sql,$connect) or die(mysql_error());
}
}
?
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql
and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written
when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override
every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
Either the code you posted isn't the actual code, or if it is, the
errors should be rather obvious. Post *actual* code.
The error is rather obvious: it loops around an array running an update
statement that will modify a single row in the table, so it's not
surprising that it appears like only the last entry in the array has been
stored.
Yes, i know that only one a singe row is updated and that is the problem.
What can I do to update several rows at the same time?
Thank you very much for all your good advice.
Are you sure you want to update several rows, or do you actually want to
insert several rows?
This is pretty basic database stuff, and is off-topic for this list.
OK. Sorry. I thought it was a PHP question for a way to update several mysql
rows by PHP code.
If you want to UPDATE several rows then you must have unique identifiers for
those rows. If you don't then I'm guessing what you actually want to do is
INSERT those rows.
It's off-topic in the same way as asking a mechanic how to fit a bunch of stuff
in your car. It's the MySQL part that you're having a problem with, not the
PHP. I strongly recommend that you use the MySQL command line to run the
queries you think you need to run, checking what the table looks like after
each one. Once you know what queries you need to run you will more effectively
be able to write the PHP wrapper around those queries.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach and mydql_query problem
Your original code snippet had some errors. It really couldn't have been what you wanted to do. Example: You have a named field of 'number_of_items' and then you try to retreive $_POST['number_of_itemsi']. That won't work. Then you have a var called $number_of_items which we don't see defined, and you are assigning each to $itemi but then you use $item in your query. Very Confusing!! Perhaps if you clean up the errors you might see better results. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Foreach and mydql_query problem
On 07/22/2013 04:39 AM, Karl-Arne Gjersøyen wrote:
Might I suggest that you place your include for ../../tilkobling.php at
the very top of this page? It would save you from possibly including it
twice.
// The acutual source code is below:
// ==
if(!empty($_POST['antall_kolli'])){
include('../../tilkobling.php'); --- remove this line
foreach($antall_kolli as $kolli){
echo $kollibr;
//echo $kolli. br;
$sql = UPDATE transportdokument SET antall_kolli_stk =
'$kolli' WHERE dato = '$dagens_dato' AND signatur = '$brukernavn';
mysql_query($sql,$tilkobling) or die(mysql_error());
}
Your WHERE conditions are the same, that is why it is updating a single
row. Where are $dagens_dato and $brukernavn being defined? As others
have stated, you need to include a unique identifier in your query so
your query updates a specific record.
}
// THE PHP/HTML Form below:
include('../../tilkobling.php'); --- move this to the top of the
script
$sql = SELECT * FROM transportdokument WHERE dato = '$dagens_dato' AND
signatur = '$brukernavn';
$resultat = mysql_query($sql, $tilkobling) or die(mysql_error());
while($rad = mysql_fetch_array($resultat, MYSQL_ASSOC)){
$valgt_lager = $rad['valgt_lager'];
$un_nr = $rad['un_nr'];
$sprengstofftype = $rad['sprengstofftype'];
$varenavn = $rad['varenavn'];
$varenr = $rad['varenr'];
$antall_kolli = $rad['antall_kolli_stk'];
$adr_vekt_kg = $rad['adr_vekt_kg'];
$varenavn = $rad['varenavn'];
$emb = $rad['emb'];
?
tr
td align=left valign=top?php echo $un_nr; ?/td
td align=left valign=topstrongSprengstoff/strong,?php echo
$sprengstofftype; ?/td
td align=left valign=top?php echo $varenavn; ?/td
td align=left valign=topstrong1.1D/strong/td
td align=left valign=topnbsp;/td
td align=left valign=top?php echo $emb; ?/td
td align=left valign=top
input type=hidden name=varenr[] value=?php echo $varenr; ?
input type=number name=antall_kolli[] size=6 value=?php echo
$antall_kolli; ? required=required
/td
td align=left valign=topinput type=text name=exan_kg_ut[]
size=6 value=?php echo $adr_vekt_kg; ? required=required/td
/tr
?php
$total_mengde_kg_adr += $rad['adr_vekt_kg'];
$total_antall_kolli += $rad['antall_kolli_stk'];
}
?
--
Jim Lucas
http://www.cmsws.com/
http://www.cmsws.com/examples/
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