I am trying to start using functions on some pages to layout a header
row in a table.
I have defined the function as below...
?php
function (headerrow)
{ ?
table width=750 border=0 cellpadding=0 cellspacing=0
bgcolor=#FF0066
tr
td class=table_head?php echo $tablehead;
variables are passed between
functions? It's all in the call and definition.
Andrew Darrow
Kronos1 Productions
www.pudlz.com
- Original Message -
From: Tom Chubb [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Saturday, July 30, 2005 9:23 AM
Subject: [PHP] Help with Functions
I am
You're declaring your function wrong.
You're doing:
function (function_name)
You should be doing
function function_name($arg1, $arg2, $arg3) // with as many comma
seperated arguments as you want.
or if you don´t want to pass any arguments
function function_name()
Try this out:
function
Thanks guys for all your help.
I've managed to get it working.
I tried calling the function from within the file and it turned out
that somehow I had messed up my include statement.
I understood about adding argument variables to the syntax, but I
needed to add a text argument as I couldn't think
Beauford 2002 wrote:
Hi,
I have form that a user would input information and that info is sent to
a function, but I need to be able to return a result of this function
and is where I am having a problem.
For example:
testfunction($var1, $var2, $var3, $var4); //the form fills these
values.
Try:
$meat = testfunction ($var1, $var2, $var3, $var4);
echo $meat;
Or, alternatively,
print (testfunction ($var1, $var2, $var3, $var4));
hope this helps.
--t
On 11/20/02 8:40 PM, Beauford 2002 [EMAIL PROTECTED] wrote:
Hi,
I have form that a user would input information and that info
You don't need the () around print.
print testfunction($var1, $var2, $var3, $var4);
Jason
On Wed, 2002-11-20 at 17:48, Tracy Finifter Rotton wrote:
Try:
$meat = testfunction ($var1, $var2, $var3, $var4);
echo $meat;
Or, alternatively,
print (testfunction ($var1, $var2, $var3,
Hi,
I have form that a user would input information and that info is sent to
a function, but I need to be able to return a result of this function
and is where I am having a problem.
For example:
testfunction($var1, $var2, $var3, $var4); //the form fills these
values.
echo $meat;
function
echo testfunction($var1, $var2, $var3, $var4);
Or if you need to do something else with the value before echo()ing it:
$meat = testfunction($var1, $var2, $var3, $var4);
//Do something with $meat
Beauford 2002 wrote:
Hi,
I have form that a user would input information and that info is sent to
Hello,
I need some help with functions Does anyone know of a good place to learn
about functions? Will someone be willing to teach me what I need to know about
functions in PHP? Thank you,
-Sean Kennedy
-http://wwwgdesignsvcncom
--
PHP General Mailing List (http://wwwphpnet/)
To
I need some help with functions. Does anyone know of a good place to learn
about functions? Will someone be willing to teach me what I need to know
about
functions in PHP? Thank you,
Here's a really simple example:
?
// regular variable that exists outside any functions
$global_var = 5;
//
Hi!!
My name is Bruno, From Brazil!!!
I need to know how can i discovery the ip address when somebody access my
home page
What function can I use
Thanks!!
Bruno.
Use the variable $REMOTE_ADDR. It contains the request ip address.
Jason
- Original Message -
From: "Bruno Freire" [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, February 19, 2001 12:34 PM
Subject: [PHP] Help!! IP functions!!!
Hi!!
My name is Bruno, From Braz
Mensaje citado por: Bruno Freire [EMAIL PROTECTED]:
Hi!!
My name is Bruno, From Brazil!!!
I need to know how can i discovery the ip address when somebody access
my
home page
What function can I use
Bruno, check the phpinfo() function, which will give you lots of information
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