[PHP] Problem with function
So, I am fighting with a problem function... I have used this function
on a previous project and it worked just fine, so I'm not sure what
changed...
The only difference is that on this site, I'm using mod_rewrite to
write all non-existent folder requests into a php file to process what
to do with it.
here's some code:
processing file:
?PHP
require(php.ini.php);
require(dbmysqliconnect.php);
require(defaults.php);
require(notify_email.php);
$link = dbmysqliconnect($server, $username, $password, $database,
$link);
$date = time();
//Do NOT insert or update sales rep database through this method...
Only included to be supplied to the notify_email function. JP
$salesRepID = $_POST['txtSalesRepID'];
$Record= $_POST['txtRecord'];
notify_email($Record, $salesRepID);
$stmt = mysqli_stmt_init($link);
//Create the statement
mysqli_stmt_prepare($stmt, UPDATE purl.schreur SET
FName = ?,
LName = ?,
email = ?,
phone = ?,
record = ?,
subscribed = ?,
date = ?,
IPAddress = ?,
Business = ?,
Address1 = ?,
City = ?,
State = ?,
Zip = ?,
Coffee = ?,
Meeting = ?,
time = ?)
or die(prepare error . mysqli_error($link));
mysqli_stmt_bind_param($stmt, '',
$_POST['txtFName'],
$_POST['txtLName'],
$_POST['txtEmail'],
$_POST['txtPhone'],
$_POST['record'],
$_POST['subscribed'],
$date,
$_SERVER['REMOTE_ADDR'],
$_POST['txtBusiness'],
$_POST['txtAddress1'],
$_POST['txtCity'],
$_POST['txtState'],
$_POST['txtZip'],
$_POST['rdoCoffee'],
$_POST['rdoTime'],
$_POST['areaPlans'])
or die( bind error . mysqli_error($link));
//Add the record
mysqli_stmt_execute($stmt) or die( execute error .
mysqli_error($link));
?
notify_email.php file:
?PHP
function notify_email($Record, $salesRepID) {
require(defaults.php);
require(func.sendemail.php);
require(dbmysqliconnect.php);
$salesRep = array(1 = [EMAIL PROTECTED], [EMAIL PROTECTED]
, 2 = [EMAIL PROTECTED], [EMAIL PROTECTED], 3
=[EMAIL PROTECTED], 4=[EMAIL PROTECTED]);
echo 1;
$link1 = dbmysqliconnect($server, $username, $password, $database,
$link);
echo 2;
$sql = SELECT * FROM schreur WHERE record='{$Record}';
$row[] = mysqli_query($link1, $sql) or die(Could not perform query:
.mysqli_errno($link1));
echo 3;
$result = $row[0];
echo 4;
// $dataSet = array();
// while ($row = mysqli_fetch_assoc($result)) {
//echo brwhileBR;
// $dataSet[] = $row;
// }
$from= [EMAIL PROTECTED];
echo 5;
$returnPath = [EMAIL PROTECTED];
$replyTo = [EMAIL PROTECTED];
echo $Record;
echo 6;
// echo brJust before while in notify_email.phpbr;
// echo brdirectly above whilebr;
// echo BRdataset print: ;
// print_r($dataSet);
// echo BR;
// echo brdirectly above foreachbr;
//foreach ( $dataSet AS $row ) {
echo 6;
while ($row = mysqli_fetch_assoc($result)) {
Re: [PHP] Problem with function
Jason Pruim schreef:
So, I am fighting with a problem function... I have used this function
on a previous project and it worked just fine, so I'm not sure what
changed...
The only difference is that on this site, I'm using mod_rewrite to write
all non-existent folder requests into a php file to process what to do
with it.
so no difference in php versions, etc etc. check phpinfo() output for
the current error_reporting/display_errors settings. and learn about
error_log() and how to 'tail' the error log (fuck knows how you go about
that on windows ... then there are reasons I have a Mac ;-))
here's some code:
processing file:
?PHP
require(php.ini.php);
require(dbmysqliconnect.php);
require(defaults.php);
require(notify_email.php);
the echo '10'; occurs when you include notify_email.php, the other echos only
when you call the function in that file.
$link = dbmysqliconnect($server, $username, $password, $database,
$link);
can you output anything after this line? chances are you don't have mysqli
$date = time();
//Do NOT insert or update sales rep database through this method...
Only included to be supplied to the notify_email function. JP
$salesRepID = $_POST['txtSalesRepID'];
$Record= $_POST['txtRecord'];
my guess is you never reach this line.
notify_email($Record, $salesRepID);
$stmt = mysqli_stmt_init($link);
//Create the statement
mysqli_stmt_prepare($stmt, UPDATE purl.schreur SET
FName = ?,
LName = ?,
email = ?,
phone = ?,
record = ?,
subscribed = ?,
date = ?,
IPAddress = ?,
Business = ?,
Address1 = ?,
City = ?,
State = ?,
Zip = ?,
Coffee = ?,
Meeting = ?,
time = ?)
or die(prepare error . mysqli_error($link));
mysqli_stmt_bind_param($stmt, '',
$_POST['txtFName'],
$_POST['txtLName'],
$_POST['txtEmail'],
$_POST['txtPhone'],
$_POST['record'],
$_POST['subscribed'],
$date,
$_SERVER['REMOTE_ADDR'],
$_POST['txtBusiness'],
$_POST['txtAddress1'],
$_POST['txtCity'],
$_POST['txtState'],
$_POST['txtZip'],
$_POST['rdoCoffee'],
$_POST['rdoTime'],
$_POST['areaPlans'])
or die( bind error . mysqli_error($link));
//Add the record
mysqli_stmt_execute($stmt) or die( execute error .
mysqli_error($link));
?
notify_email.php file:
?PHP
function notify_email($Record, $salesRepID) {
require(defaults.php);
require(func.sendemail.php);
require(dbmysqliconnect.php);
$salesRep = array(1 = [EMAIL PROTECTED],
[EMAIL PROTECTED], 2 = [EMAIL PROTECTED],
[EMAIL PROTECTED], 3 =[EMAIL PROTECTED],
4=[EMAIL PROTECTED]);
echo 1;
$link1 = dbmysqliconnect($server, $username, $password,
$database, $link);
echo 2;
$sql = SELECT * FROM schreur WHERE record='{$Record}';
$row[] = mysqli_query($link1, $sql) or die(Could not perform
query: .mysqli_errno($link1));
echo 3;
$result = $row[0];
echo 4;
//$dataSet = array();
//while ($row = mysqli_fetch_assoc($result)) {
//echo brwhileBR;
//$dataSet[] = $row;
//}
$from= [EMAIL PROTECTED];
echo 5;
$returnPath = [EMAIL PROTECTED];
$replyTo = [EMAIL PROTECTED];
echo $Record;
echo 6;
//echo brJust before while in notify_email.phpbr;
//echo brdirectly above whilebr;
//echo BRdataset print: ;
//print_r($dataSet);
//echo BR;
//echo brdirectly above foreachbr;
//foreach ( $dataSet AS $row ) {
echo 6;
while ($row = mysqli_fetch_assoc($result)) {
echo inside while;
//Build the e-mail headers
$ID = $row['salesRep'];
$to = $salesRep[$ID];
$headers = From: .$from.\n;
$headers .= Return-Path: .$returnPath.\n;
$headers .= Reply-To: .$replyTo.\n;
$subject = {$row['FName']} wants coffee!;
$message = First Name: {$row['FName']} \n;
$message .= Last Name: {$row['LName']}\n;
$message .= Company . $row['Business'] . \n;
Re: [PHP] Problem with function
On Sep 12, 2008, at 8:44 AM, Jochem Maas wrote:
Jason Pruim schreef:
So, I am fighting with a problem function... I have used this
function on a previous project and it worked just fine, so I'm not
sure what changed...
The only difference is that on this site, I'm using mod_rewrite to
write all non-existent folder requests into a php file to process
what to do with it.
so no difference in php versions, etc etc. check phpinfo() output for
the current error_reporting/display_errors settings. and learn about
error_log() and how to 'tail' the error log (fuck knows how you go
about
that on windows ... then there are reasons I have a Mac ;-))
So Do I :)
The php versions are the same, they are on the same computer :)
PHP Version 5.2.0www.entropy.ch Release 3 (Universal Binary)
The server is a PowerPC Based comptuer running OS X Server 10.4.11
here's some code:
processing file:
?PHP
require(php.ini.php);
require(dbmysqliconnect.php);
require(defaults.php);
require(notify_email.php);
the echo '10'; occurs when you include notify_email.php, the other
echos only when you call the function in that file.
$link = dbmysqliconnect($server, $username, $password,
$database, $link);
can you output anything after this line? chances are you don't have
mysqli
mysqli is up and working on the computer... I use it for all my other
projects as well. And yes I can I echoed out no problem
$date = time();
//Do NOT insert or update sales rep database through this
method... Only included to be supplied to the notify_email
function. JP
$salesRepID = $_POST['txtSalesRepID'];
$Record= $_POST['txtRecord'];
my guess is you never reach this line.
notify_email($Record, $salesRepID);
$stmt = mysqli_stmt_init($link);
//Create the statement
mysqli_stmt_prepare($stmt, UPDATE purl.schreur SET
FName = ?,
LName = ?,
email = ?,
phone = ?,
record = ?,
subscribed = ?,
date = ?,
IPAddress = ?,
Business = ?,
Address1 = ?,
City = ?,
State = ?,
Zip = ?,
Coffee = ?,
Meeting = ?,
time = ?)
or die(prepare error . mysqli_error($link));
mysqli_stmt_bind_param($stmt, '',
$_POST['txtFName'],
$_POST['txtLName'],
$_POST['txtEmail'],
$_POST['txtPhone'],
$_POST['record'],
$_POST['subscribed'],
$date,
$_SERVER['REMOTE_ADDR'],
$_POST['txtBusiness'],
$_POST['txtAddress1'],
$_POST['txtCity'],
$_POST['txtState'],
$_POST['txtZip'],
$_POST['rdoCoffee'],
$_POST['rdoTime'],
$_POST['areaPlans'])
or die( bind error . mysqli_error($link));
//Add the record
mysqli_stmt_execute($stmt) or die( execute error .
mysqli_error($link));
?
notify_email.php file:
?PHP
function notify_email($Record, $salesRepID) {
require(defaults.php);
require(func.sendemail.php);
require(dbmysqliconnect.php);
$salesRep = array(1 = [EMAIL PROTECTED], [EMAIL PROTECTED]
, 2 = [EMAIL PROTECTED], [EMAIL PROTECTED],
3 =[EMAIL PROTECTED], 4=[EMAIL PROTECTED]);
echo 1;
$link1 = dbmysqliconnect($server, $username, $password,
$database, $link);
echo 2;
$sql = SELECT * FROM schreur WHERE record='{$Record}';
$row[] = mysqli_query($link1, $sql) or die(Could not
perform query: .mysqli_errno($link1));
echo 3;
$result = $row[0];
echo 4;
//$dataSet = array();
//while ($row = mysqli_fetch_assoc($result)) {
//echo brwhileBR;
//$dataSet[] = $row;
//}
$from= [EMAIL PROTECTED];
echo 5;
$returnPath = [EMAIL PROTECTED];
$replyTo = [EMAIL PROTECTED];
echo $Record;
echo 6;
//echo brJust before while in notify_email.phpbr;
//echo brdirectly above whilebr;
//echo BRdataset print: ;
//print_r($dataSet);
//echo BR;
//echo brdirectly above foreachbr;
//foreach ( $dataSet AS $row ) {
echo 6;
while ($row = mysqli_fetch_assoc($result))
{ echo inside while;
//Build the e-mail headers
$ID = $row['salesRep'];
$to = $salesRep[$ID];
$headers = From: .$from.\n;
$headers .= Return-Path:
Re: [PHP] Problem with function
Jason Pruim schreef:
my guess is you never reach this line.
I don't think notify_email() is called, find out what is dying before you
get to this line.
note you'll get 'echo '10';' before you get 'echo '1';'
notify_email($Record, $salesRepID);
$stmt = mysqli_stmt_init($link);
//Create the statement
mysqli_stmt_prepare($stmt, UPDATE purl.schreur SET
FName = ?,
LName = ?,
email = ?,
phone = ?,
record = ?,
subscribed = ?,
date = ?,
IPAddress = ?,
Business = ?,
Address1 = ?,
City = ?,
State = ?,
Zip = ?,
Coffee = ?,
Meeting = ?,
time = ?)
or die(prepare error . mysqli_error($link));
mysqli_stmt_bind_param($stmt, '',
$_POST['txtFName'],
$_POST['txtLName'],
$_POST['txtEmail'],
$_POST['txtPhone'],
$_POST['record'],
$_POST['subscribed'],
$date,
$_SERVER['REMOTE_ADDR'],
$_POST['txtBusiness'],
$_POST['txtAddress1'],
$_POST['txtCity'],
$_POST['txtState'],
$_POST['txtZip'],
$_POST['rdoCoffee'],
$_POST['rdoTime'],
$_POST['areaPlans'])
or die( bind error . mysqli_error($link));
//Add the record
mysqli_stmt_execute($stmt) or die( execute error .
mysqli_error($link));
?
notify_email.php file:
?PHP
function notify_email($Record, $salesRepID) {
require(defaults.php);
require(func.sendemail.php);
require(dbmysqliconnect.php);
$salesRep = array(1 = [EMAIL PROTECTED],
[EMAIL PROTECTED], 2 = [EMAIL PROTECTED],
[EMAIL PROTECTED], 3 =[EMAIL PROTECTED],
4=[EMAIL PROTECTED]);
echo 1;
$link1 = dbmysqliconnect($server, $username, $password,
$database, $link);
echo 2;
$sql = SELECT * FROM schreur WHERE record='{$Record}';
$row[] = mysqli_query($link1, $sql) or die(Could not perform
query: .mysqli_errno($link1));
echo 3;
$result = $row[0];
echo 4;
//$dataSet = array();
//while ($row = mysqli_fetch_assoc($result)) {
//echo brwhileBR;
//$dataSet[] = $row;
//}
$from= [EMAIL PROTECTED];
echo 5;
$returnPath = [EMAIL PROTECTED];
$replyTo = [EMAIL PROTECTED];
echo $Record;
echo 6;
//echo brJust before while in notify_email.phpbr;
//echo brdirectly above whilebr;
//echo BRdataset print: ;
//print_r($dataSet);
//echo BR;
//echo brdirectly above foreachbr;
//foreach ( $dataSet AS $row ) {
echo 6;
while ($row = mysqli_fetch_assoc($result)) {
echo inside while;
//Build the e-mail headers
$ID = $row['salesRep'];
$to = $salesRep[$ID];
$headers = From: .$from.\n;
$headers .= Return-Path: .$returnPath.\n;
$headers .= Reply-To: .$replyTo.\n;
$subject = {$row['FName']} wants coffee!;
$message = First Name: {$row['FName']} \n;
$message .= Last Name: {$row['LName']}\n;
$message .= Company . $row['Business'] . \n;
$message .= Email: .$row['email'] . \n;
$message .= Phone: .$row['phone'] . \n;
$message .= Address: . $row['Address1'] . \n;
$message .= City: . $row['City'] . \n;
$message .= State: .$row['State'] . \n;
$message .= Zip: . $row['Zip'] . \n;
$message .= Coffee of choice: .$row['Coffee'] . \n\n;
$message .= When a good time would be:
\n.$row['Meeting'] . \n\n;
$message .= Current plans: \n\n;
$message .= $row['plans'] . \n\n;
send_email($to, $subject, $message, $headers);
}
echo 7;
echo PRE
pre
Headers: $headers
To: $to
Subject: $subject
Message:
$message
/pre
PRE;
echo 8;
echo Just after end of while in notify_email.php;
//header(Location: index.php);
echo 9;
} //Function closed
echo 10;
?
yes all of the echo's in there are for testing purposes to see where
it's choking.
Ever since I started using mod_rewrite, I seem to have lost my error
reporting from php so if someone knows a trick on how to fix that I
would appreciate it :)
On my page when I load it, all I see is the 10 I echo
Re: [PHP] Problem with function
On Sep 12, 2008, at 544AM, Jochem Maas wrote: the current error_reporting/display_errors settings. and learn about error_log() and how to 'tail' the error log (fuck knows how you go about that on windows ... then there are reasons I have a Mac ;-)) The ability to tail error logs is one of the main reasons I have cygwin installed on my windows machine at work. Once installed if you add the cygwin\bin dir to your path you don't even have to be in a cygwin prompt to use tail and the other *nix goodness it provides. http://bradym.net/windows/making-the-windows-command-prompt-usable Brady -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Problem calling function within a class
hi
i am new to classes and i have a problem with a class i wrote
here is the class
---
class Company {
var $Company_Name;
var $Company_Referrer_Table;
var $Company_Visitor_Table;
var $Company_ID;
var $Message;
var $File;
var $FileName;
var $Record_Data;
function CompanyInfo (){
$SQL_Query = mysql_query(SELECT * FROM company_list WHERE
Company_ID = $this-Company_ID);
$Record = mysql_fetch_array($SQL_Query);
$this-Company_ID = $Record['Company_ID'];
$this-Company_Name = $Record['Company_Name'];
$this-Company_Referrer_Table =
$Record['Company_Referrer_Table'];
$this-Company_Visitor_Table = $Record['Company_Visitor_Table'];
return $this-Company_Referrer_Table;
return $this-Company_Visitor_Table;
}
function GenerateUniqueID(){
return md5(uniqid(mt_rand(),TRUE));
}
function UploadFile($File) {
$this-File = $File;
$dst_file_name = $this-GenerateUniqueID();
$arr = split(\.,$this-File['name']);
$this-File['name'] = $dst_file_name;
$this-File['name'] .= ..$arr[count($arr)-1];
$dest_dir = 'temp';
$dest = $dest_dir . '/' .$this-File['name'];
$r = move_uploaded_file($this-File['tmp_name'], $dest);
$this-FileName = $this-File['name'];
chmod(temp/.$this-FileName, 777);
}
function TakeData($File, $Company_ID, $Destination) {
$this-Company_ID = $Company_ID;
$this-CompanyInfo();
if ($Destination == Referrer){
$SQL_Query = INSERT INTO $this-Company_Referrer_Table
( Record_ID
, Record_Data ) VALUES ( '', '$this-Record_Data');
}elseif ($Destination == Visitor){
$SQL_Query = INSERT INTO $this-Company_Visitor_Table
( Record_ID
, Record_Data ) VALUES ( '', '$this-Record_Data');
}
$this-UploadFile($File);
$fh = fopen(temp/.$this-FileName, r);
while (! feof($fh)) : $this-Record_Data = fgets($fh, 4096);
mysql_query($SQL_Query)or die(Error In Importing Records To
The Database);
endwhile;
fclose($fh);
$this-Message = Date Imported Successfully;
return $this-Message;
}
}
---
the problem occurs when i call the function TakeDate
i use this code to call it
$Company = new Company();
$File = $HTTP_POST_FILES['FileToUpload'];
$Company-TakeData($File, $Company_ID, $Destination);
$Message = $Company-Message;
the error i get is Error In Importing Records To The Database which
i defined as the error of mysql in the function.
i checked everything and found that the problem happens because i
can't retireve the values of
$this-Company_Referrer_Table and $this-Company_Visitor_Table by
calling the function CompanyInfo
from the function TakeData
can anyone advise me with the right way to call the CompanyInfo
function from the TakeData and get the values correctly?
--
Ahmed Abdel-Aliem
Web Developer
www.ApexScript.com
0101108551
registered Linux user number 382789
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem calling function within a class
it shuold be:
$SQL_Query = INSERT INTO .$this-Company_Referrer_Table. ( Record_ID
, Record_Data ) VALUES ( '', '.$this-Record_Data.');
just use the operator '.' to connect two string. I think php could
only identify simple car direcctly as $foo to be its value in a string
contain it. The reference to a class data member would not work well
in a string. So you should use the operator '.' to connect them.
On Sat, 19 Mar 2005 02:43:15 +0200, Ahmed Abdel-Aliem [EMAIL PROTECTED] wrote:
hi
i am new to classes and i have a problem with a class i wrote
here is the class
---
class Company {
var $Company_Name;
var $Company_Referrer_Table;
var $Company_Visitor_Table;
var $Company_ID;
var $Message;
var $File;
var $FileName;
var $Record_Data;
function CompanyInfo (){
$SQL_Query = mysql_query(SELECT * FROM company_list WHERE
Company_ID = $this-Company_ID);
$Record = mysql_fetch_array($SQL_Query);
$this-Company_ID = $Record['Company_ID'];
$this-Company_Name = $Record['Company_Name'];
$this-Company_Referrer_Table =
$Record['Company_Referrer_Table'];
$this-Company_Visitor_Table =
$Record['Company_Visitor_Table'];
return $this-Company_Referrer_Table;
return $this-Company_Visitor_Table;
}
function GenerateUniqueID(){
return md5(uniqid(mt_rand(),TRUE));
}
function UploadFile($File) {
$this-File = $File;
$dst_file_name = $this-GenerateUniqueID();
$arr = split(\.,$this-File['name']);
$this-File['name'] = $dst_file_name;
$this-File['name'] .= ..$arr[count($arr)-1];
$dest_dir = 'temp';
$dest = $dest_dir . '/' .$this-File['name'];
$r = move_uploaded_file($this-File['tmp_name'], $dest);
$this-FileName = $this-File['name'];
chmod(temp/.$this-FileName, 777);
}
function TakeData($File, $Company_ID, $Destination) {
$this-Company_ID = $Company_ID;
$this-CompanyInfo();
if ($Destination == Referrer){
$SQL_Query = INSERT INTO
$this-Company_Referrer_Table ( Record_ID
, Record_Data ) VALUES ( '', '$this-Record_Data');
}elseif ($Destination == Visitor){
$SQL_Query = INSERT INTO $this-Company_Visitor_Table
( Record_ID
, Record_Data ) VALUES ( '', '$this-Record_Data');
}
$this-UploadFile($File);
$fh = fopen(temp/.$this-FileName, r);
while (! feof($fh)) : $this-Record_Data = fgets($fh, 4096);
mysql_query($SQL_Query)or die(Error In Importing Records To
The Database);
endwhile;
fclose($fh);
$this-Message = Date Imported Successfully;
return $this-Message;
}
}
---
the problem occurs when i call the function TakeDate
i use this code to call it
$Company = new Company();
$File = $HTTP_POST_FILES['FileToUpload'];
$Company-TakeData($File, $Company_ID, $Destination);
$Message = $Company-Message;
the error i get is Error In Importing Records To The Database which
i defined as the error of mysql in the function.
i checked everything and found that the problem happens because i
can't retireve the values of
$this-Company_Referrer_Table and $this-Company_Visitor_Table by
calling the function CompanyInfo
from the function TakeData
can anyone advise me with the right way to call the CompanyInfo
function from the TakeData and get the values correctly?
--
Ahmed Abdel-Aliem
Web Developer
www.ApexScript.com
0101108551
registered Linux user number 382789
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
Sincerely,
Forest Liu()
--
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[PHP] Problem with function declaration in include files
I have been using the following function declaration syntax for ages with no
problems.
Main php file:
?php
include my-inc.php;
...
FuncExample(arg1,arg2);
...
?
Include file:
?php
...
FuncExample(arg1,arg2){
Function Content
}
...
?php
I have just finished some work for a client, after full testing on both my
Unix and Win32 test servers I moved the site over to their hosting company
and I get the following problem.
All my functions that are declared in my Inc files are spitting back the
error:
Fatal error: Call to undefined function:...
I have spoken with the hosting company, but they have considerable trouble
with 'backside' and 'elbow' recognition.
Are there any PHP.ini settings that affect this type of function
declaration?
Any help would be appreciated.
Bobby
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For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Problem with function declaration in include files
The problem is most likely with your include statement. The include
path imay be incorrect...
"Bobby" [EMAIL PROTECTED] wrote in
message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I have been using the following function declaration syntax for ages with
no problems. Main php file:
?php include "my-inc.php"; ...
FuncExample(arg1,arg2); ... ?
Include file: ?php ...
FuncExample(arg1,arg2){ Function Content }
... ?php I have just finished some work for a
client, after full testing on both my Unix and Win32 test servers I
moved the site over to their hosting company and I get the following
problem. All my functions that are declared in my Inc files are
spitting back the error: "Fatal error: Call to
undefined function:..." I have spoken with the hosting company,
but they have considerable trouble with 'backside' and 'elbow'
recognition. Are there any PHP.ini settings that affect this
type of function declaration? Any help would be
appreciated. Bobby
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Re: [PHP] Problem with function declaration in include files
I wish it was that simple, I have already added debug 'echo' statements to
make sure the included file is being included correctly and it is?
This problem really has me beat, I never usually send out desperate pleas,
but I am not a happy bunny atm.
Any thoughts would be appreciated
Cheers
Bobby
Dennis Moore [EMAIL PROTECTED] wrote in message
003501c19526$a0968740$[EMAIL PROTECTED]">news:003501c19526$a0968740$[EMAIL PROTECTED]...
The problem is most likely with your include statement. The include path
imay be incorrect...
Bobby [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I have been using the following function declaration syntax for ages with
no
problems.
Main php file:
?php
include my-inc.php;
...
FuncExample(arg1,arg2);
...
?
Include file:
?php
...
FuncExample(arg1,arg2){
Function Content
}
...
?php
I have just finished some work for a client, after full testing on both my
Unix and Win32 test servers I moved the site over to their hosting company
and I get the following problem.
All my functions that are declared in my Inc files are spitting back the
error:
Fatal error: Call to undefined function:...
I have spoken with the hosting company, but they have considerable trouble
with 'backside' and 'elbow' recognition.
Are there any PHP.ini settings that affect this type of function
declaration?
Any help would be appreciated.
Bobby
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Re: [PHP] problem with function array_* that preserved the key
On Sat, Nov 03, 2001 at 03:54:23PM -0500, Reuben D Budiardja wrote: since the key are preserved, arrC is no longer indexed from 0. Well, in most cases I don't care about the key if it's just indexed array. But since the key I preserved, I can no longer do for($i=0; $icount($arrC);$i++) echo $arrC[$i]; if it happens that the returned indedex in array C 19, 20,25, for example. Any workaround? There are many other ways you could traverse the array, but I think array_values() does what you want. Stig -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] problem with function array_* that preserved the key
Hi, I have problem with array function that return an array and preserved the key of the array argument. Take example of array_diff: I have 2 arrays that has index 0,1,2, ... as the key, and use it as the argument, say $arrA, and $arrB, $arrC = array_diff($arrA, $arrB); since the key are preserved, arrC is no longer indexed from 0. Well, in most cases I don't care about the key if it's just indexed array. But since the key I preserved, I can no longer do for($i=0; $icount($arrC);$i++) echo $arrC[$i]; if it happens that the returned indedex in array C 19, 20,25, for example. Any workaround? Thanks. Reuben D. Budiardja -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
