Du!
It would have made sense to direct it to /phpbb/login.php
Not
/phpbb/index.php
I know, the keyboard and the chair!
Brad
Did the error actually say Unexpected $end ? That would mean that PHP hit the
end of the script before it expected to, and could be caused by an unclosed string.
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Hello.
Cannot find any unexpected dollar-sign ($) in this code.
But please enclose the associative array-indexes within quotation-marks
and run your script again.
[code]
$foo = $_POST['assoc_index'];
[/code]
Daniel
Harlequin wrote:
I've checked my syntax but obviously missing something.
Would
Put all your values in the following {}...
So:
VALUES('{$Title}','{$ChristianName}','{$MiddleName}','{$Surname}'. and
so on.
HTH
Craig
Harlequin [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I've checked my syntax but obviously missing something.
Would anyone mind a quick
Really sorry for taking up so many people's time on such a small issue.
--
-
Michael Mason
Arras People
www.arraspeople.co.uk
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Harlequin [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I've checked my syntax but obviously
[EMAIL PROTECTED] wrote:
Using PHP 4 with this code:
if ($csvfile = fopen($csvpath, r)) {
while (!feof ($csvfile))
{
$filestring = fgets( $csvfile , 255);
}
}
I get a parse error on the line :
$filestring = fgets( $csvfile , 255);
Any ideas why this is happening?
?php
$args = array(a,b,b);
$keys = array(0,1,2);
function array_key_remove($args,$keys,$replacement=NULL)
{
echo Foo!;
}
?
Lasse Motroen [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I have received some code and am trying to run it. However, I get the
following error:
On Thu, 2004-03-04 at 21:39, Andre Cerqueira wrote:
? is tag for php code start
Enrique Martinez wrote:
Hello, I'm getting an error that says:
Parse error, unexpected T_STRING on line 73
line 73 is: ?xml version=1.0 encoding=iso-8859-1
?
this is what I have below line 73:
Mike Mapsnac wrote:
The script should upload files (images).
Error message is give below, any ideas why I get this errror message?
Parse error: parse error in /var/www/html/uploadproc.php on line 3
die() needs brackets around its arguments, eg:
die(Error! The expected file wasn't a part of the
: move_uploaded_file(): Unable to move '/tmp/phpiMrdlQ' to
'/var/www/html/upload/' in /var/www/html/uploadproc.php on line 11
Error Moving the uploaded file failed.
From: Michael Nolan [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Parse error ???
Date: Thu, 04 Mar 2004 13:40:46 +
11
Warning: move_uploaded_file(): Unable to move '/tmp/phpiMrdlQ' to
'/var/www/html/upload/' in /var/www/html/uploadproc.php on line 11
Error Moving the uploaded file failed.
From: Michael Nolan [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Parse error ???
Date: Thu, 04 Mar 2004 13
PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Parse error ???
Date: Thu, 04 Mar 2004 13:40:46 +
Mike Mapsnac wrote:
The script should upload files (images).
Error message is give below, any ideas why I get this errror message?
Parse error: parse error in /var/www/html/uploadproc.php on line 3
PROTECTED], [EMAIL PROTECTED]
Subject: Re: [PHP] Re: Parse error ???
Date: Thu, 04 Mar 2004 13:58:26 +
If I remember correctly the second parameter of move_uploaded_file() needs
to be the full filename, ie path plus required filename.
so...
if(!move_uploaded_file($_FILES['myfile']['tmp_name
is
apache:apache. Why the owner of the file is not mike ?
thanks
From: Neil Freeman [EMAIL PROTECTED]
To: Mike Mapsnac [EMAIL PROTECTED]
CC: [EMAIL PROTECTED], [EMAIL PROTECTED]
Subject: Re: [PHP] Re: Parse error ???
Date: Thu, 04 Mar 2004 13:58:26 +
If I remember correctly the second
Hello Mike,
Thursday, March 4, 2004, 6:16:17 PM, you wrote:
MM I run the script as user mike and mike:mike is owner of the directory, when
MM I upload something to directory the owner of the file is apache:apache.
MM Why the owner of the file is not mike ?
Because Apache is not running as mike
? is tag for php code start
Enrique Martinez wrote:
Hello, I'm getting an error that says:
Parse error, unexpected T_STRING on line 73
line 73 is: ?xml version=1.0 encoding=iso-8859-1
?
this is what I have below line 73:
!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0
Transitional//EN
Hi,
The prototype for mysql_connect is:
resource mysql_connect ( [string server [, string username [, string
password [, bool new_link [, int client_flags ] )
As you can see you get parse error because the fourth argument
should be boolean, not string.
Cheers,
Catalin
35:
//If Delete User is selected--
if ( $_REQUEST['useroption'] == 'delete')
{
//First, check that the user already exists
$query = select count(*) from pbpc_client where username = ' .
$_REQUEST['usernamebox'] . ';;
$result = mysql_query($query);
if(!$result)
{
echo 'Cannot run
Holy schmoley...something so small.I must get off this green tea,
all this good health stuff is causing havoc in my brain...
Thanks Fokkema, and Johnfor pointing out an obvious error...
Regards
On Wed, 2003-08-06 at 14:48, Fokkema, I.F.A.C. (HKG) wrote:
//If Delete User is
Miles Thompson [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Yes, I'm top posting, pls forgive.
This is a situation where an editor which has built-in brace matching
really helps - if in the midst of looking one remembers to use it.
Another tip, although it probably wouldn't help
Yes, I'm top posting, pls forgive.
This is a situation where an editor which has built-in brace matching
really helps - if in the midst of looking one remembers to use it.
Another tip, although it probably wouldn't help here: Save the code with a
.phps extension and look at it in the browser.
This is the source code
?
include(includes/encabezado_xml.php);
include(includes/conexion.php);
mysql_select_db(latinencounters);
$u_login=;
$u_pwd=;
if(isset($url_login)){
$u_login=$url_login; // parametro login del usuario
}
if(isset($url_pwd)){
$u_pwd=$url_pwd; // parametro
?
include(includes/encabezado_xml.php);
include(includes/conexion.php);
mysql_select_db(latinencounters);
$u_login=;
$u_pwd=;
if(isset($url_login)){
$u_login=$url_login; // parametro login del usuario
}
if(isset($url_pwd)){
$u_pwd=$url_pwd; // parametro password del usuario
Everything works great now. Thanks for the quick responses everyone.
Brent Lee [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I'm new to PHP and am slowly learning it. I have the following code that
is
giving me errors could someone take a look and suggest a
In addition to the other errors pointed out...
I assume you want a loop. change
while($row = mysql_fetch_array($response));
to
while($row = mysql_fetch_array($response))
{
Take care,
Greg
--
phpDocumentor
http://www.phpdoc.org
while($row = mysql_fetch_array($response));
echo(p
I had experienced similar problem like that in the past. Part of it had to
do with the header() function. Your script checked out fine, just like mine
did. Try remarking the line of code where hte header is and see if you
don't have hte parse error, if this is the case then it's the header().
?php
If ('GET' == $HTTP_SERVER_VARS['REQUEST_METHOD']) {
$MailToAddress = '[EMAIL PROTECTED]';
$MailSubject = 'Get Involved List';
?
?php
exit;
}
?
You appear to be moving in and out of PHP Mode that could be pretty
tough to follow... I've practically been looking at php Code
Hi JJ,
Looks OK to me, could it be that youa re missing a semi colon ; or a brace } from a
previous line, in this case PHP often reports the parse error as being the line where
the next ; is?
EG
$var1 = x
$var2 = y;
This will show an error on the second line.
KEvin
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
* and then Kevin Lowe declared
Looks OK to me, could it be that youa re missing a semi colon ; or a brace } from a
previous line, in this case PHP often reports the parse error as being the line where
the next ; is?
Yep, that would be me
In article 003601c20541$fdc31970$0100a8c0@JohnH, [EMAIL PROTECTED]
says...
I know it is probably something obvious but the following gives me a parse error and
as a newbie I am having trouble locating it.
$query = select * from news WHERE id = $_get['id'];
JJ Harrison
[EMAIL PROTECTED]
Error is absolute.
Don't use (double quotation mark) in yur queries. Use ' (single quot.)
instead
$query = SELECT DATE_FORMAT( exp_date, '%W, %M %d, %Y') AS thedate from
tifrequest where user='$user' limit 1,1;
Because the preprocessor think that your string is finished when it sees a
double
Try this:
var $VAL_ID;
var $VAL_TICKER;
var $VAL_ID_FEED;
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Jaxon,
do you have a line of white space after your closing tag?
Anyway, this looks fishy to me:
if (!isset($page_id))
{
$sql=select page_id from table where fieldname = $value;
$link_id = mysql_connect($host, $usr, $pass) or die (mysql_error());
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