[PHP] Re: Regex Problem
The solution don't need to be with regex, if anyone can solve this with other way will be very helpfull . Regards, Igor Escobar Systems Analyst Interface Designer + http://blog.igorescobar.com + http://www.igorescobar.com + @igorescobar (twitter) On Fri, Jul 31, 2009 at 2:23 PM, Igor Escobar titiolin...@gmail.com wrote: Hi Folks, I have a serious problem. must create a regular expression against all that is between single quote or double quotes. Easy? Ok, i know, but i need that everything must to be too an single quote or double quote. If i have this SQL command: SELECT * FROM TSTRENIC.MEI_ACESSO WHERE UPPER(DS_MEI_ACS) LIKE *'%NOME' ASD ' AS'ASD'%' *AND USUARIO = *'oaksdpokasd'asda'* ORDER BY DS_MEI_ACS ASC; SELECT * FROM TSTRENIC.MEI_ACESSO WHERE USUARIO_DATA BETWEEN *'2007-01-02' * AND *'2008-07-08'* Anyone have any idea? I need an expression which case the fields in bold. Regards, Igor Escobar Systems Analyst Interface Designer + http://blog.igorescobar.com + http://www.igorescobar.com + @igorescobar (twitter)
[PHP] Re: Regex Problem
Igor Escobar wrote:
The solution don't need to be with regex, if anyone can solve this with
other way will be very helpfull .
Regards,
Igor Escobar
Systems Analyst Interface Designer
+ http://blog.igorescobar.com
+ http://www.igorescobar.com
+ @igorescobar (twitter)
On Fri, Jul 31, 2009 at 2:23 PM, Igor Escobar titiolin...@gmail.com wrote:
Hi Folks,
I have a serious problem.
must create a regular expression against all that is between single quote
or double quotes. Easy? Ok, i know, but i need that everything must to be
too an single quote or double quote.
If i have this SQL command:
SELECT * FROM TSTRENIC.MEI_ACESSO WHERE UPPER(DS_MEI_ACS) LIKE *'%NOME'
ASD ' AS'ASD'%' *AND USUARIO = *'oaksdpokasd'asda'* ORDER BY DS_MEI_ACS
ASC;
SELECT * FROM TSTRENIC.MEI_ACESSO WHERE USUARIO_DATA BETWEEN *'2007-01-02'
* AND *'2008-07-08'*
Anyone have any idea?
I need an expression which case the fields in bold.
Regards,
Igor Escobar
Systems Analyst Interface Designer
+ http://blog.igorescobar.com
+ http://www.igorescobar.com
+ @igorescobar (twitter)
Not entirely sure I understand. You want to BOLD the things contained
in quotes and you put the * there to show that? If so, this is not tested:
$bolded = preg_replace('#([\'])(.*?)\1#', 'b\1\2\1/b', $text);
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Re: [PHP] Re: Regex Problem
Igor Escobar wrote: No no, i need to make an regex to match the bold areas in my string. Anything between single quotes or double quotes (including quotes and double quotes). Understand? Regards, Igor Escobar Systems Analyst Interface Designer + http://blog.igorescobar.com + http://www.igorescobar.com + @igorescobar (twitter) That's not going to happen without some other criteria. There is no way for the regex engine to guess at which sets of quotes belong inside another set of quotes. -Shawn -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Regex Problem
Shawn McKenzie wrote: Igor Escobar wrote: No no, i need to make an regex to match the bold areas in my string. Anything between single quotes or double quotes (including quotes and double quotes). Understand? Regards, Igor Escobar Systems Analyst Interface Designer + http://blog.igorescobar.com + http://www.igorescobar.com + @igorescobar (twitter) That's not going to happen without some other criteria. There is no way for the regex engine to guess at which sets of quotes belong inside another set of quotes. -Shawn Especially since in one of your examples you don't even have an even number of quotes. -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
Josh Close wrote: I'm trying to get a simple regex to work. Here is the test script I have. #!/usr/bin/php -q ? $string = hello\nworld\n; $string = preg_replace(/[^\r]\n/i,\r\n,$string); First, the short version. You can fix this by using backreferences: $string = preg_replace(/([^\r])\n/i, \\1\r\n, $string); Now, the reason: preg_replace() replaces everything which matched, so both the \n and the character before it will be replaced (as they both had to match to make the pattern match). Luckily, preg_replace() stores a list of matches, which you can use either later in the same pattern or in the replace string. This is called a 'backreference'. You can tell preg_replace() which part(s) of the pattern you want to store in this fashion by enclosing those parts in parentheses. In your case, you want to store the character before the \n which matched, so you would enclose it in parentheses like so: /([^\r])\n/i. Thereafter you can refer to that portion of the pattern match with the sequence \1. If you add another set of parens, you would refer to it with \2...and so on. You can even nest pattern matches like this, in which case they are counted by the opening paren. So the replacement string would then become \\1\r\n. (You need the extra \ in front of \1 to prevent PHP's string interpolation parsing the \1 before it gets passed to preg_replace()). A lot more information is available from the manual page on preg_replace(): http://www.php.net/preg_replace There is also an extensive pages on pattern syntax: http://www.php.net/manual/en/pcre.pattern.syntax.php Hope this helps, Torben $string = addcslashes($string, \r\n); print $string; ? This outputs hell\r\nworl\r\n so it's removing the char before the \n also. I just want it to replace a lone \n with \r\n -Josh -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
Thanks, that's exactly what I was looking for. -Josh On Thu, 01 Jul 2004 15:17:41 -0700, Lars Torben Wilson [EMAIL PROTECTED] wrote: Josh Close wrote: I'm trying to get a simple regex to work. Here is the test script I have. #!/usr/bin/php -q ? $string = hello\nworld\n; $string = preg_replace(/[^\r]\n/i,\r\n,$string); First, the short version. You can fix this by using backreferences: $string = preg_replace(/([^\r])\n/i, \\1\r\n, $string); Now, the reason: preg_replace() replaces everything which matched, so both the \n and the character before it will be replaced (as they both had to match to make the pattern match). Luckily, preg_replace() stores a list of matches, which you can use either later in the same pattern or in the replace string. This is called a 'backreference'. You can tell preg_replace() which part(s) of the pattern you want to store in this fashion by enclosing those parts in parentheses. In your case, you want to store the character before the \n which matched, so you would enclose it in parentheses like so: /([^\r])\n/i. Thereafter you can refer to that portion of the pattern match with the sequence \1. If you add another set of parens, you would refer to it with \2...and so on. You can even nest pattern matches like this, in which case they are counted by the opening paren. So the replacement string would then become \\1\r\n. (You need the extra \ in front of \1 to prevent PHP's string interpolation parsing the \1 before it gets passed to preg_replace()). A lot more information is available from the manual page on preg_replace(): http://www.php.net/preg_replace There is also an extensive pages on pattern syntax: http://www.php.net/manual/en/pcre.pattern.syntax.php Hope this helps, Torben $string = addcslashes($string, \r\n); print $string; ? This outputs hell\r\nworl\r\n so it's removing the char before the \n also. I just want it to replace a lone \n with \r\n -Josh -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
Merlin wrote: Hi there, I have a regex problem. Basicly I do not want to match: /dir/test/contact.html But I do want to match: /test/contact.html I tryed this one: ^[!dir]/(.*)/contact(.*).html$ but it does not work and I tryed thousands of other ways plus read tutorials. Can anybody please help? ^\/test\/contact.html$ Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
^\/test\/contact.html$ does not work. I am sorry, I just found that it has to be: test/contact.html and not dir/test/contact.html there is no leading slash. Do you have any other suggestion? -- lt;IFRAME SRC=http://saratoga.globosapiens/associates/report_member.php?u=3color=EEE EEE scrolling=no frameborder=0 TITLE=My travel articles width=330 height=155 ALLOWTRANSPARENCY=truea href=http://www.globosapiens.net; title=Worldwide Travel CommunityaTravel Communitya/ /IFRAME Kae Verens [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] Merlin wrote: Hi there, I have a regex problem. Basicly I do not want to match: /dir/test/contact.html But I do want to match: /test/contact.html I tryed this one: ^[!dir]/(.*)/contact(.*).html$ but it does not work and I tryed thousands of other ways plus read tutorials. Can anybody please help? ^\/test\/contact.html$ Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
Merlin wrote:
^\/test\/contact.html$
does not work. I am sorry, I just found that
it has to be:
test/contact.html
and not
dir/test/contact.html
there is no leading slash.
Do you have any other suggestion?
Are you making this too hard?
if($string = 'test/contact.html')
{ echo 'good'; } else { echo 'bad'; }
??
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[PHP] Re: regex problem
Merlin wrote: ^\/test\/contact.html$ does not work. I am sorry, I just found that it has to be: test/contact.html and not dir/test/contact.html there is no leading slash. Do you have any other suggestion? *sigh* ^test\/contact.html$ Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
John W. Holmes wrote: Merlin wrote: ^\/test\/contact.html$ does not work. I am sorry, I just found that it has to be: test/contact.html and not dir/test/contact.html there is no leading slash. Do you have any other suggestion? Are you making this too hard? if($string = 'test/contact.html') That's if($string == 'test/contact.html') of course... :) ---John Holmes... Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/ PHP|Architect: A magazine for PHP Professionals www.phparch.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: regex problem
[snip] if($string = 'test/contact.html') That's if($string == 'test/contact.html') of course... :) [/snip] it could be if($string == test/contact.html) couldn't resist :) Jay P.S. John, nothing on that thing yet. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! Thanx for any help, Merlin Kae Verens [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] Merlin wrote: ^\/test\/contact.html$ does not work. I am sorry, I just found that it has to be: test/contact.html and not dir/test/contact.html there is no leading slash. Do you have any other suggestion? *sigh* ^test\/contact.html$ Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
Jay Blanchard wrote: if($string == 'test/contact.html') it could be if($string == test/contact.html) not to start a flame war or anything, but isn't the apostrophe version quicker, as it doesn't ask the server to parse the string? Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
Merlin wrote: ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! ah - maybe a chain of rewrites would do? send all matches of /^partner\/(.*)\/contact.html$/ to partner\/\1\/blah send all matches of /^(.*)\/contact.html$/ to NEWLOCATION send all matches of /^partner\/(.*)\/blah$/ to partner\/\1\/contact.html Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
So ^[^/]+/[^/]* or ^!(partner/) Merlin wrote: ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! Thanx for any help, Merlin Kae Verens [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] Merlin wrote: ^\/test\/contact.html$ does not work. I am sorry, I just found that it has to be: test/contact.html and not dir/test/contact.html there is no leading slash. Do you have any other suggestion? *sigh* ^test\/contact.html$ Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
does not work. Is there not a way to exclude the word partner like you triede with !(partner) ? merlin Marek Kilimajer [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] So ^[^/]+/[^/]* or ^!(partner/) Merlin wrote: ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! Thanx for any help, Merlin Kae Verens [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] Merlin wrote: ^\/test\/contact.html$ does not work. I am sorry, I just found that it has to be: test/contact.html and not dir/test/contact.html there is no leading slash. Do you have any other suggestion? *sigh* ^test\/contact.html$ Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: regex problem
Good idea, but does not work either - surprisingly! - There should be a clean way with regex for this task. Andy regex expert in here? Merlin Kae Verens [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] Merlin wrote: ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! ah - maybe a chain of rewrites would do? send all matches of /^partner\/(.*)\/contact.html$/ to partner\/\1\/blah send all matches of /^(.*)\/contact.html$/ to NEWLOCATION send all matches of /^partner\/(.*)\/blah$/ to partner\/\1\/contact.html Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
* Thus wrote Merlin ([EMAIL PROTECTED]): ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) I'm not sure what you expect since this *is* a php mailing list. My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! Mod rewrite is a powerful tool and you can accomplish what you are doing several different ways. As you can tell most people have been giving attempts to fix your problem without success. This is because it is not entirely clear what you need done. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: regex problem
* Thus wrote Kae Verens ([EMAIL PROTECTED]): Jay Blanchard wrote: if($string == 'test/contact.html') it could be if($string == test/contact.html) not to start a flame war or anything, but isn't the apostrophe version quicker, as it doesn't ask the server to parse the string? heh, that is true. Although I havn't benched marked it but it prolly is somewhere around .01 difference :) your not the one that needs to be flamed, it seems that everytime a topic of 'regex' is posted there is always 20+ in the thread with 101% of them not doing what the person wants. Not to mention the OT'ness of the post. cheers, Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: regex problem
So, what you want is to pretty much use this regex /^(.*)([^\/]+)\/([^\/]+)$/ when matched on this URI, the backreferences will contain \\1 partner/ \\2 name \\3 contact.html \\4 .html partner/name/contact.html I have not tested it, but I just guess it will work ;) Wanna know why? I'll tell you :D - It first looks at the beginning of the string and will go on untill a the next pair of () start (partner/) - That happens there where there is a string containing any character, but not a slash (partner) - as a seperator another slash is added - it starts to match the last part of the url and looks up untill the end. Again a string containing no slashes Hope it does do what I expect it to do .. ;) Wouter -Oorspronkelijk bericht- Van: Merlin [mailto:[EMAIL PROTECTED] Verzonden: vrijdag 15 augustus 2003 16:21 Aan: [EMAIL PROTECTED] Onderwerp: [PHP] Re: regex problem Good idea, but does not work either - surprisingly! - There should be a clean way with regex for this task. Andy regex expert in here? Merlin Kae Verens [EMAIL PROTECTED] schrieb im Newsbeitrag news:[EMAIL PROTECTED] Merlin wrote: ufff.. sorry guys, but I have to explain that better. I appreciate your help, maybe I did not give enough info. I am trying to redirect with apache modrewrite. To do this you have to use regex (not if functions:-) My problem is, that there are member accounts which look like that: membername/contact.html and there are partner accounts which look like this: partner/name/contact.html The goal is to redirect only if it is a member account. If I put a (.*)/contact.html it also matches the partner/ I tryed putting a root / infront, but there is not / root for the url from apaches point of view. So I would need a regex which will match the member account, but if the first word is partner it should not terminate. This seems to be a tough one! ah - maybe a chain of rewrites would do? send all matches of /^partner\/(.*)\/contact.html$/ to partner\/\1\/blah send all matches of /^(.*)\/contact.html$/ to NEWLOCATION send all matches of /^partner\/(.*)\/blah$/ to partner\/\1\/contact.html Kae -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: regex problem
-Original Message-
From: Monty [mailto:[EMAIL PROTECTED]
Sent: 31 May 2003 21:21
If you want the entire string to be tested for digits, you
need to add the
length of the string to the regex pattern:
$length = strlen($data);
preg_match([0-9]{$length}, $data);
Or anchor the pattern to both start and end of the string:
preg_match(^[0-9]+$, $data);
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
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[PHP] Re: regex problem
I don't understand what it is you're trying to accomplish, so, it's hard to
offer a solution. If you just want to verify whether or not a variable
contains numeric data, why not just use the is_numeric() function:
http://us4.php.net/manual/en/function.is-numeric.php
preg_match() will return TRUE if it finds the pattern ANYWHERE in the
string, so, that's why asdf789 passes the test because it contains digits,
whereas 'asdf' won't pass the test because the numbers 0-9 can't be found
anywhere in that string.
If you want the entire string to be tested for digits, you need to add the
length of the string to the regex pattern:
$length = strlen($data);
preg_match([0-9]{$length}, $data);
Monty
From: [EMAIL PROTECTED] (Daniel J. Rychlik)
Newsgroups: php.general
Date: Sat, 31 May 2003 13:46:44 -0500
To: [EMAIL PROTECTED]
Subject: regex problem
Hello,,
I have a preg_match issue matching numbers. I am currently using
!preg_match ('/([0-9\-\.\#:])/', $_POST['nums1']
throw error[]
This fails if you use something like ' asdf ' but if you use ' asdf789 ' it
passes false and does not throw an error.
This is not the obvious solution I know its a problem in my regular
expression. Should I ONLY be using
' /([0-9])/ ' , ?
Thanks in advance.
Daniel
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[PHP] Re: Regex problem
Hello Leon,
try this
if (preg_match(/^([[:space:]]*)?\*/s, $string)) {
echo Match.;
} else {
echo No match;
}
James
Leon Mergen [EMAIL PROTECTED] wrote in message
002f01c15d2a$e4ca3030$012aa8c0@leon">news:002f01c15d2a$e4ca3030$012aa8c0@leon...
Hi there,
I am camping with a little regular expressions problem...
Problem: I want to check if $variable begins with a * (star), and it doesn't
matter if it starts with plenty of spaces...
My solution:
ereg(^[:space:]*\*,$variable)
But, it doesn't seem to work with the space part... The regex:
ereg(^\*,$variable)
does work, but that doesn't include spaces at the start... How can I extend
this one so that it doesn't matter if there are a lot of spaces at the
begin?
Thanks in advance,
Leon Mergen
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[PHP] Re: Regex problem
$sNoSpaces = ltrim($variable);
if ('*' == $sNoSpaces[0])
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Leon Mergen [EMAIL PROTECTED] wrote in message
002f01c15d2a$e4ca3030$012aa8c0@leon">news:002f01c15d2a$e4ca3030$012aa8c0@leon...
Hi there,
I am camping with a little regular expressions problem...
Problem: I want to check if $variable begins with a * (star), and it doesn't
matter if it starts with plenty of spaces...
My solution:
ereg(^[:space:]*\*,$variable)
But, it doesn't seem to work with the space part... The regex:
ereg(^\*,$variable)
does work, but that doesn't include spaces at the start... How can I extend
this one so that it doesn't matter if there are a lot of spaces at the
begin?
Thanks in advance,
Leon Mergen
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