"bar");
var_dump($my_array);
?>
array(1) { [0]=> string(3) "bar" }
Regards Frank
-Ursprüngliche Nachricht-
Von: Shaun [mailto:[EMAIL PROTECTED]
Gesendet: Donnerstag, 29. November 2007 13:57
An: php-general@lists.php.net
Betreff: [PHP] Variable Names
"bar");
var_dump($my_array);
?>
array(1) { [0]=> string(3) "bar" }
Regards Frank
-Ursprüngliche Nachricht-
Von: Shaun [mailto:[EMAIL PROTECTED]
Gesendet: Donnerstag, 29. November 2007 13:57
An: php-general@lists.php.net
Betreff: [PHP] Variable Names
Hi,
I seem to be having a problem in assigning a value to an array where the
array is called dynamically.
e.g. the physical name for the array is "my_array", so:
my_array[1] = "test";
works fine.
$array_name = "my_array";
$array_name[1] = "test";
does not work.
I have tried $$array_name[1] = "t
> function somefunction($myvar) {
> do something...
> ...
> ...
$variablealacon = "\$myvar";
return $variablealacon;
> }
>
> $varname = somefunction($myvar);
> echo "$varname";
kodrik a écrit :
> > function somefunction($myvar) {
> function somefunction($myvar) {
> do something...
> ...
> ...
> return \$myvar;
> }
>
> $varname = somefunction($myvar);
> echo "$varname";
That won't work, because you escaped the $ sign, the variable won't get
processed and the name returned w
Hello Kodrik,
I would do the following code. Excuse me if there are many mistakes. I
am only a newbie. So:
function somefunction($myvar) {
do something...
...
...
return \$myvar;
}
$varname = somefunction($myvar);
echo "$varname";
Hope it helps y
If I have a variable, how do I extract the name of the variable.
In principle:
$varname=somefunction($myvar);
The value of $varname is then "myvar"
How do I do it?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
7 matches
Mail list logo