[PHP] Variable variable using constant

[Marc Guay]

Hi folks,

Let's say that I have 2 constants

DEFINE('DESKTOP_URL_en', http://www.website.com/index.php?page=home;); 
DEFINE('DESKTOP_URL_fr', http://www.website.com/index.php?page=accueil;);  


and I would like to populate the value of an href with them depending
on the user's language.  $_SESSION['lang'] is either 'en' or 'fr'.
How would I go about referring to this variable?

I have tried:

${'DESKTOP_URL_'.$_SESSION['lang']};
${DESKTOP_URL'.'_'.$_SESSION['lang']};
{DESKTOP_URL'.'_'.$_SESSION['lang']};
etc, to no avail.

If it is a regular variable I'm fine, it's the CONSTANT_FORMAT that
seems to be causing my brain some issues.

Thanks,
Marc

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Re: [PHP] Variable variable using constant

[Robert Williams]

On 10/12/11 11:51, Marc Guay marc.g...@gmail.com wrote:


Let's say that I have 2 constants

DEFINE('DESKTOP_URL_en', http://www.website.com/index.php?page=home;);
DEFINE('DESKTOP_URL_fr',
http://www.website.com/index.php?page=accueil;);

and I would like to populate the value of an href with them depending
on the user's language.  $_SESSION['lang'] is either 'en' or 'fr'.
How would I go about referring to this variable?


Try:

   $var = constant('DESKTOP_URL_' . $_SESSION['lang']);


Regards,
Bob

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Re: [PHP] Variable variable using constant

[Marc Guay]

   $var = constant('DESKTOP_URL_' . $_SESSION['lang']);

Very nice, thank you.

Marc

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RE: [PHP] Variable variable names...

[Jason Lustig]

There's a number of things you can do with variable variables... they're
quite powerful, I like 'em a lot. :)

Anyway, you can do


?php

$myvar2 = 'stuff';
$othervar = 2;
if (isset($myvar{$othervar}))
echo $myvar{$othervar};

?

This would output

snip

stuff

/snip

I think that's what you were asking... You've got to use the { and } around
the variables you're using to make teh variable variable.

--Jason


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[PHP] Variable variable names...

[Brian Weisenthal]

let say i wanted to see if a variable existed by the name of $myvar2  . how
can i make the '2' come from a variable. so i want to say something like
$myvar$othervar .(but obviously that wont work) anyone have  a clue? i tried
using eval but i couldn't get it right




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Re: [PHP] Variable variable names...

[Brian Weisenthal]

turns out my subject was right on anyone interested check this page
out.
http://www.phpbuilder.com/manual/language.variables.variable.php

Brian Weisenthal [EMAIL PROTECTED] wrote in message
9h02nm$n7c$[EMAIL PROTECTED]">news:9h02nm$n7c$[EMAIL PROTECTED]...
 let say i wanted to see if a variable existed by the name of $myvar2  .
how
 can i make the '2' come from a variable. so i want to say something like
 $myvar$othervar .(but obviously that wont work) anyone have  a clue? i
tried
 using eval but i couldn't get it right




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[PHP] Variable Variable with array

[Brandon Orther]

Hello,

I am trying to use variable variable.  with arrays.  this may be hard to
understand so here is an example:

$menu1[0] = 1;
$menu1[1] = 2;
$menu1[2] = 3;

$menu2[0] = 1;
$menu2[1] = 2;
$menu2[2] = 3;

$menu3[0] = 1;
$menu3[1] = 2;
$menu3[2] = 3;

does anyone know the proper way to use variable variable with arrays?

Thanks

Brandon


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Re: [PHP] Variable Variable with array

[Gyozo Papp]

are you thinking of what this snippet does:

$menu = 'menu2';
$i = 2;
echo ${$menu}[$i];

- Original Message - 
From: Brandon Orther [EMAIL PROTECTED]
To: PHP User Group [EMAIL PROTECTED]
Sent: 2001. május 7. 22:16
Subject: [PHP] Variable Variable with array


 Hello,
 
 I am trying to use variable variable.  with arrays.  this may be hard to
 understand so here is an example:
 
 $menu1[0] = 1;
 $menu1[1] = 2;
 $menu1[2] = 3;
 
 $menu2[0] = 1;
 $menu2[1] = 2;
 $menu2[2] = 3;
 
 $menu3[0] = 1;
 $menu3[1] = 2;
 $menu3[2] = 3;
 
 does anyone know the proper way to use variable variable with arrays?
 
 Thanks
 
 Brandon
 
 
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[PHP] Variable Variable

[Brandon Orther]

Hello,

I can't find Variable Variable in the php manual.  If someone has a link to
the section in the PHP manual about this please send me a link.

Thank you,
Brandon Orther


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RE: [PHP] Variable Variable

[Altunergil, Oktay]

http://www.php.net/manual/en/language.variables.variable.php

-Original Message-
From: Brandon Orther [mailto:[EMAIL PROTECTED]]
Sent: Monday, May 07, 2001 4:53 PM
To: PHP User Group
Subject: [PHP] Variable Variable


Hello,

I can't find Variable Variable in the php manual.  If someone has a link to
the section in the PHP manual about this please send me a link.

Thank you,
Brandon Orther


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[PHP] Variable variable

[Jacky]

Hi all
I have a form with check box and name of those checkboxes is usuing variable lke this, 

!-- I got the value $id from a table and looping them and assign them to the check 
box name--
input type="checkbox" name ="$id" value="on"

and when I submit the form to page foo.php4, at that page, I use Variable variable to 
call the value of the check box to see if it checked like this

$quey = "select id from table";
$result = .. ( assumeing it is done and i got value for $id for all records from 
table)

if ($$id =="on"){
echo "on";
}else{
echo "off";
}

It always returns echo "off", why is that?
cheers
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for yourself"

Re: [PHP] Variable variable

[Ulf Wendel]

Jacky schrieb:
 !-- I got the value $id from a table and looping them and assign them to the check 
box name--
 input type="checkbox" name ="$id" value="on"
 
 and when I submit the form to page foo.php4, at that page, I use Variable variable 
to call the value of the check box to see if it checked like this
 
 $quey = "select id from table";
 $result = .. ( assumeing it is done and i got value for $id for all records from 
table)
 
 if ($$id =="on"){
 echo "on";
 }else{
 echo "off";
 }

What's the value of $id in the second snippet? Generally speaking using
$GLOBALS[$id] gives you more readable code but variable variables.

Ulf

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Re: [PHP] Variable variable

[Chris Fry]

Jacky,

You do not need the value. The variable $id will either exist (if the user checked it) 
or not (if the user did not check it).

Hope this helps.

Chris

Jacky wrote:

 Hi all
 I have a form with check box and name of those checkboxes is usuing variable lke 
this,

 !-- I got the value $id from a table and looping them and assign them to the check 
box name--
 input type="checkbox" name ="$id" value="on"

 and when I submit the form to page foo.php4, at that page, I use Variable variable 
to call the value of the check box to see if it checked like this

 $quey = "select id from table";
 $result = .. ( assumeing it is done and i got value for $id for all records from 
table)

 if ($$id =="on"){
 echo "on";
 }else{
 echo "off";
 }

 It always returns echo "off", why is that?
 cheers
 Jack
 [EMAIL PROTECTED]
 "There is nothing more rewarding than reaching the goal you set for yourself"

--
Chris Fry
Quillsoft Pty Ltd
Specialists in Secure Internet Services and E-Commerce Solutions
10 Gray Street
Kogarah
NSW  2217
Australia

Phone: +61 2 9553 1691
Fax: +61 2 9553 1692
Mobile: 0419 414 323
eMail: [EMAIL PROTECTED]
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Re: [PHP] Variable variable

[[EMAIL PROTECTED]]

the variable $id in the second sniplet come from the id from talble when I
run query and loop it using mysql_fetch_array. So I end up have value of $id
from the id field from table, right?But the value store in $id is now in
string value, and if I need to use that value for the if..then.. else
condition to check if which checkbox is checked, I will need to use Variable
variable to make the string back to be variable again , like $$id, for
instance after I run the query and get all Id value from table, it will be
like
$id = 1, $id=2, and so on
and as I used this for checkbox name at the previous page, in order to uset
it in the if..then..else condition in the second sniplet, it will be like
if ($1=="on") {
do something
}else{
do somehting
}
 but something is wrong here at the if then else bit. But I don't know what
is it.
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for
yourself"
- Original Message -
From: Ulf Wendel [EMAIL PROTECTED]
To: Jacky [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, April 18, 2001 2:20 AM
Subject: Re: [PHP] Variable variable




 Jacky schrieb:
  !-- I got the value $id from a table and looping them and assign them
to the check box name--
  input type="checkbox" name ="$id" value="on"
 
  and when I submit the form to page foo.php4, at that page, I use
Variable variable to call the value of the check box to see if it checked
like this
 
  $quey = "select id from table";
  $result = .. ( assumeing it is done and i got value for $id for all
records from table)
 
  if ($$id =="on"){
  echo "on";
  }else{
  echo "off";
  }

 What's the value of $id in the second snippet? Generally speaking using
 $GLOBALS[$id] gives you more readable code but variable variables.

 Ulf

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Re: [PHP] Variable variable

[Chris Fry]

Sorry - thought you only had one! - it's late.

To Name the checkboxes you need:
?php
while (get records from db) {
$id = id from record;
?
input type="checkbox" name ="?php print $id; ?"
?php
}
?

You would have to do a $HTTP_GET_VARS on the next page to find out which ones
exist.

Then your select statement would be:

$query = "select * from table where id IN ('comma delimited list of values')";

Messy but do-able!

Probably a better way - There usually is!

Chris

Jacky wrote:

 so how do I check at the next page which one is checked?
 Jack
 [EMAIL PROTECTED]
 "There is nothing more rewarding than reaching the goal you set for
 yourself"
 - Original Message -
 From: Chris Fry [EMAIL PROTECTED]
 To: Jacky [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Sent: Wednesday, April 18, 2001 2:31 AM
 Subject: Re: [PHP] Variable variable

  Jacky,
 
  You do not need the value. The variable $id will either exist (if the user
 checked it) or not (if the user did not check it).
 
  Hope this helps.
 
  Chris
 
  Jacky wrote:
 
   Hi all
   I have a form with check box and name of those checkboxes is usuing
 variable lke this,
  
   !-- I got the value $id from a table and looping them and assign them
 to the check box name--
   input type="checkbox" name ="$id" value="on"
  
   and when I submit the form to page foo.php4, at that page, I use
 Variable variable to call the value of the check box to see if it checked
 like this
  
   $quey = "select id from table";
   $result = .. ( assumeing it is done and i got value for $id for all
 records from table)
  
   if ($$id =="on"){
   echo "on";
   }else{
   echo "off";
   }
  
   It always returns echo "off", why is that?
   cheers
   Jack
   [EMAIL PROTECTED]
   "There is nothing more rewarding than reaching the goal you set for
 yourself"
 
  --
  Chris Fry
  Quillsoft Pty Ltd
  Specialists in Secure Internet Services and E-Commerce Solutions
  10 Gray Street
  Kogarah
  NSW  2217
  Australia
 
  Phone: +61 2 9553 1691
  Fax: +61 2 9553 1692
  Mobile: 0419 414 323
  eMail: [EMAIL PROTECTED]
  http://www.quillsoft.com.au
 
  You can download our Public CA Certificate from:-
  https://ca.secureanywhere.com/htdocs/cacert.crt
 
  **
 
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Quillsoft Pty Ltd
Specialists in Secure Internet Services and E-Commerce Solutions
10 Gray Street
Kogarah
NSW  2217
Australia

Phone: +61 2 9553 1691
Fax: +61 2 9553 1692
Mobile: 0419 414 323
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Re: [PHP] Variable variable

[Jacky]

I did look up in the manual for $HTTP_GET_VARS but could not find it? what
is it? a function?
sorry to ask this again, just try to find out how to use that.
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for
yourself"
- Original Message -
From: Chris Fry [EMAIL PROTECTED]
To: Jacky [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, April 18, 2001 2:59 AM
Subject: Re: [PHP] Variable variable


 Sorry - thought you only had one! - it's late.

 To Name the checkboxes you need:
 ?php
 while (get records from db) {
 $id = id from record;
 ?
 input type="checkbox" name ="?php print $id; ?"
 ?php
 }
 ?

 You would have to do a $HTTP_GET_VARS on the next page to find out which
ones
 exist.

 Then your select statement would be:

 $query = "select * from table where id IN ('comma delimited list of
values')";

 Messy but do-able!

 Probably a better way - There usually is!

 Chris

 Jacky wrote:

  so how do I check at the next page which one is checked?
  Jack
  [EMAIL PROTECTED]
  "There is nothing more rewarding than reaching the goal you set for
  yourself"
  - Original Message -
  From: Chris Fry [EMAIL PROTECTED]
  To: Jacky [EMAIL PROTECTED]
  Cc: [EMAIL PROTECTED]
  Sent: Wednesday, April 18, 2001 2:31 AM
  Subject: Re: [PHP] Variable variable
 
   Jacky,
  
   You do not need the value. The variable $id will either exist (if the
user
  checked it) or not (if the user did not check it).
  
   Hope this helps.
  
   Chris
  
   Jacky wrote:
  
Hi all
I have a form with check box and name of those checkboxes is usuing
  variable lke this,
   
!-- I got the value $id from a table and looping them and assign
them
  to the check box name--
input type="checkbox" name ="$id" value="on"
   
and when I submit the form to page foo.php4, at that page, I use
  Variable variable to call the value of the check box to see if it
checked
  like this
   
$quey = "select id from table";
$result = .. ( assumeing it is done and i got value for $id for
all
  records from table)
   
if ($$id =="on"){
echo "on";
}else{
echo "off";
}
   
It always returns echo "off", why is that?
cheers
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for
  yourself"
  
   --
   Chris Fry
   Quillsoft Pty Ltd
   Specialists in Secure Internet Services and E-Commerce Solutions
   10 Gray Street
   Kogarah
   NSW  2217
   Australia
  
   Phone: +61 2 9553 1691
   Fax: +61 2 9553 1692
   Mobile: 0419 414 323
   eMail: [EMAIL PROTECTED]
   http://www.quillsoft.com.au
  
   You can download our Public CA Certificate from:-
   https://ca.secureanywhere.com/htdocs/cacert.crt
  
   **
  
   This information contains confidential information intended only for
   the use of the authorised recipient.  If you are not an authorised
   recipient of this e-mail, please contact Quillsoft Pty Ltd by return
   e-mail.
   In this case, you should not read, print, re-transmit, store or act
   in reliance on this e-mail or any attachments, and should destroy all
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   This e-mail and any attachments may also contain copyright material
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   The views expressed in this e-mail or attachments are the views of
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   You should only deal with the material contained in this e-mail if
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 --
 Chris Fry
 Quillsoft Pty Ltd
 Specialists in Secure Internet Services and E-Commerce Solutions
 10 Gray Street
 Kogarah
 NSW  2217
 Australia

 Phone: +61 2 9553 1691
 Fax: +61 2 9553 1692
 Mobile: 0419 414 323
 eMail: [EMAIL PROTECTED]
 http://www.quillsoft.com.au

 You can download our Public CA Certificate from:-
 https://ca.secureanywhere.com/htdocs/cacert.crt

 **

 This information contains confidential information intended only for
 the use of the authorised recipient.  If you are not an authorised
 recipient of this e-mail, please contact Quillsoft Pty Ltd by return
 e-mail.
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 copies o

Re: [PHP] Variable variable

[Chris Fry]

Sorry - try $HTTP_POST_VARS

Chris

Jacky wrote:

 I did look up in the manual for $HTTP_GET_VARS but could not find it? what
 is it? a function?
 sorry to ask this again, just try to find out how to use that.
 Jack
 [EMAIL PROTECTED]
 "There is nothing more rewarding than reaching the goal you set for
 yourself"
 - Original Message -
 From: Chris Fry [EMAIL PROTECTED]
 To: Jacky [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Sent: Wednesday, April 18, 2001 2:59 AM
 Subject: Re: [PHP] Variable variable

  Sorry - thought you only had one! - it's late.
 
  To Name the checkboxes you need:
  ?php
  while (get records from db) {
  $id = id from record;
  ?
  input type="checkbox" name ="?php print $id; ?"
  ?php
  }
  ?
 
  You would have to do a $HTTP_GET_VARS on the next page to find out which
 ones
  exist.
 
  Then your select statement would be:
 
  $query = "select * from table where id IN ('comma delimited list of
 values')";
 
  Messy but do-able!
 
  Probably a better way - There usually is!
 
  Chris
 
  Jacky wrote:
 
   so how do I check at the next page which one is checked?
   Jack
   [EMAIL PROTECTED]
   "There is nothing more rewarding than reaching the goal you set for
   yourself"
   - Original Message -
   From: Chris Fry [EMAIL PROTECTED]
   To: Jacky [EMAIL PROTECTED]
   Cc: [EMAIL PROTECTED]
   Sent: Wednesday, April 18, 2001 2:31 AM
   Subject: Re: [PHP] Variable variable
  
Jacky,
   
You do not need the value. The variable $id will either exist (if the
 user
   checked it) or not (if the user did not check it).
   
Hope this helps.
   
Chris
   
Jacky wrote:
   
 Hi all
 I have a form with check box and name of those checkboxes is usuing
   variable lke this,

 !-- I got the value $id from a table and looping them and assign
 them
   to the check box name--
 input type="checkbox" name ="$id" value="on"

 and when I submit the form to page foo.php4, at that page, I use
   Variable variable to call the value of the check box to see if it
 checked
   like this

 $quey = "select id from table";
 $result = .. ( assumeing it is done and i got value for $id for
 all
   records from table)

 if ($$id =="on"){
 echo "on";
 }else{
 echo "off";
 }

 It always returns echo "off", why is that?
 cheers
 Jack
 [EMAIL PROTECTED]
 "There is nothing more rewarding than reaching the goal you set for
   yourself"
   
--
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Quillsoft Pty Ltd
Specialists in Secure Internet Services and E-Commerce Solutions
10 Gray Street
Kogarah
NSW  2217
Australia
   
Phone: +61 2 9553 1691
Fax: +61 2 9553 1692
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  Chris Fry
  Quillsoft Pty Ltd
  Specialists in Secure Internet Services and E-Commerce Solutions
  10 Gray Street
  Kogarah
  NSW  2217
  Australia
 
  Phone: +61 2 9553 1691
  Fax: +61 2 9553 1692
  Mobile: 0419 414 323
  eMail: [EMAIL PROTECTED]
  http://www.quillsoft.com.au
 
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  https://ca.secureanywhere.com/htdocs/cacert.crt
 
  **
 
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  the use of the authorised recipient.  If you are not an authorised
  r

Re: [PHP] Variable variable

[Plutarck]

Your problem has little to do with the things mentioned.

First of all, you are refering to a variable variable incorrectly. You must
use brackets, like this:

${$id}

If ID has the value "Blue", then the above is the same as:

$Blue

So in your examble if you had the checkbox with the value "on", and you want
to see if it was checked, use this:

if (${$id} == "on")
{
echo 'on';
} else
{
echo 'off';
}

But that's an overly complicated way of doing it if you know the "name" of
the checkbox. If the name of the checkbox is "id", then use this piece of
code to access it if it was submitted via POST or GET (which works even if
register_globals is turned off):

$f = 'HTTP_' . $HTTP_ENV_VARS["REQUEST_METHOD"] . '_VARS';

if (${$f}["id"] == "on")
{
echo 'The checkbox with the name "id" has the value "on"';
} else
{
echo "The checkbox with the name "id" was not selected";
}


But if register globals was on, all you have to use is:

if ($id == "on")
{
echo 'The checkbox with the name "id" has the value "on"';
} else
{
echo "The checkbox with the name "id" was not selected";
}


Tell me if that doesn't answer your questions.


--
Plutarck
Should be working on something...
...but forgot what it was.


""Jacky"" [EMAIL PROTECTED] wrote in message
011001c0c839$ebfb9b40$[EMAIL PROTECTED]">news:011001c0c839$ebfb9b40$[EMAIL PROTECTED]...
Hi all
I have a form with check box and name of those checkboxes is usuing variable
lke this,

!-- I got the value $id from a table and looping them and assign them to
the check box name--
input type="checkbox" name ="$id" value="on"

and when I submit the form to page foo.php4, at that page, I use Variable
variable to call the value of the check box to see if it checked like this

$quey = "select id from table";
$result = .. ( assumeing it is done and i got value for $id for all
records from table)

if ($$id =="on"){
echo "on";
}else{
echo "off";
}

It always returns echo "off", why is that?
cheers
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for
yourself"




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Re: [PHP] Variable variable

[Steve Werby]

"Plutarck" [EMAIL PROTECTED] wrote:
 Your problem has little to do with the things mentioned.

 First of all, you are refering to a variable variable incorrectly.

Actually, he's not.

You must
 use brackets, like this:

 ${$id}

The braces aren't required in this case.  Of the four examples below, only
the 3rd won't return the expected results - because the first $ is
interpreted as a literal $.  Paste the code below into a webpage and see for
yourself.

?php
$field = 'name';
$name = 'Steve';

echo 'br' . $$field;
echo 'br' . ${$field};
echo 'br' . "My name is $$field.";
echo 'br' . "My name is ${$field}.";
?

I have a few possible explanations for the problem of the original poster
(see below).

 if (${$id} == "on")
 {
 echo 'on';
 } else
 {
 echo 'off';
 }

1. If $id is a number I believe PHP will choke b/c I don't believe numbers
can be used as variable names.

2. Assume $id = 'age_bracket'.  The control structure checks to see if
$age_bracket == "on".  To set $id in the first place for your multiple
checkbox values, you'd have to loop through the values sent from the form.
Jack (original poster), did you do that?  If your form's method = post then
you would loop through $HTTP_POST_VARS and if it was get $HTTP_GET_VARS (and
then only loop through the checkbox variables).  Or you could predefine the
checkbox variables using:

$checkbox_fields = array( 'age_bracket', 'weight', 'gender', 'occupation' );

And then loop through as follows:

while( list( , $val ) = each( $checkbox_fields ) )
{
// may have to set as $$GLOBALS[$val] if within a function or declare $val
as global first.
if ( $$val == 'on' )
{
echo 'on';
}
else
{
echo 'off';
 }
}

--
Steve Werby
President, Befriend Internet Services LLC
http://www.befriend.com/


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Re: [PHP] Variable variable

[Rasmus Lerdorf]

 1. If $id is a number I believe PHP will choke b/c I don't believe numbers
 can be used as variable names.

Well, generally that is true.  If you try to assign a value directly to a
variable that is a number such as:

 $1 = "Hello World";

Then it won't work.  However, due to a somewhat quirky implementation you
can get arund this by doing:

 $a=1;
 $$a = "Hello World";

You can verify that you do indeed have a variable named $1 in your global
symbol table by doing:

 echo $GLOBALS[1];

-Rasmus


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Re: [PHP] Variable variable

[Steve Werby]

"Rasmus Lerdorf" [EMAIL PROTECTED] wrote:
  1. If $id is a number I believe PHP will choke b/c I don't believe
numbers
  can be used as variable names.

 Well, generally that is true.  If you try to assign a value directly to a
 variable that is a number such as:

  $1 = "Hello World";

 Then it won't work.  However, due to a somewhat quirky implementation you
 can get arund this by doing:

  $a=1;
  $$a = "Hello World";

Sure enough, it works.  Rasmus, can we expect this behavior to exist in
future releases of PHP?  I prefer to give variables a meaningful name, but
since I spend a fair amount of time working with other people's code and
clients who sometimes insist on things that aren't preferable, it would be
nice to know.

--
Steve Werby
President, Befriend Internet Services LLC
http://www.befriend.com/


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Re: [PHP] Variable variable

[Rasmus Lerdorf]

 "Rasmus Lerdorf" [EMAIL PROTECTED] wrote:
   1. If $id is a number I believe PHP will choke b/c I don't believe
 numbers
   can be used as variable names.
 
  Well, generally that is true.  If you try to assign a value directly to a
  variable that is a number such as:
 
   $1 = "Hello World";
 
  Then it won't work.  However, due to a somewhat quirky implementation you
  can get arund this by doing:
 
   $a=1;
   $$a = "Hello World";

 Sure enough, it works.  Rasmus, can we expect this behavior to exist in
 future releases of PHP?  I prefer to give variables a meaningful name, but
 since I spend a fair amount of time working with other people's code and
 clients who sometimes insist on things that aren't preferable, it would be
 nice to know.

Writing code that relies on this behaviour is a bad idea.  It is unlikely
to change in PHP 4, but who knows what will happen in the longer term...

-Rasmus


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Re: [PHP] Variable variable

[Plutarck]

 The braces aren't required in this case.

Yup, your right. I stand corrected.

I had forgotten that multiple $s are fine, and that I simply don't use them
because I have trouble reading them.

The joys of learning ;\


--
Plutarck
Should be working on something...
...but forgot what it was.


""Steve Werby"" [EMAIL PROTECTED] wrote in message
001e01c0c80e$45410400$6501a8c0@workstation7">news:001e01c0c80e$45410400$6501a8c0@workstation7...
 "Plutarck" [EMAIL PROTECTED] wrote:
  Your problem has little to do with the things mentioned.
 
  First of all, you are refering to a variable variable incorrectly.

 Actually, he's not.

 You must
  use brackets, like this:
 
  ${$id}

 The braces aren't required in this case.  Of the four examples below, only
 the 3rd won't return the expected results - because the first $ is
 interpreted as a literal $.  Paste the code below into a webpage and see
for
 yourself.

 ?php
 $field = 'name';
 $name = 'Steve';

 echo 'br' . $$field;
 echo 'br' . ${$field};
 echo 'br' . "My name is $$field.";
 echo 'br' . "My name is ${$field}.";
 ?

 I have a few possible explanations for the problem of the original poster
 (see below).

  if (${$id} == "on")
  {
  echo 'on';
  } else
  {
  echo 'off';
  }

 1. If $id is a number I believe PHP will choke b/c I don't believe numbers
 can be used as variable names.

 2. Assume $id = 'age_bracket'.  The control structure checks to see if
 $age_bracket == "on".  To set $id in the first place for your multiple
 checkbox values, you'd have to loop through the values sent from the form.
 Jack (original poster), did you do that?  If your form's method = post
then
 you would loop through $HTTP_POST_VARS and if it was get $HTTP_GET_VARS
(and
 then only loop through the checkbox variables).  Or you could predefine
the
 checkbox variables using:

 $checkbox_fields = array( 'age_bracket', 'weight', 'gender',
'occupation' );

 And then loop through as follows:

 while( list( , $val ) = each( $checkbox_fields ) )
 {
 // may have to set as $$GLOBALS[$val] if within a function or declare $val
 as global first.
 if ( $$val == 'on' )
 {
 echo 'on';
 }
 else
 {
 echo 'off';
  }
 }

 --
 Steve Werby
 President, Befriend Internet Services LLC
 http://www.befriend.com/


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 To unsubscribe, e-mail: [EMAIL PROTECTED]
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 To contact the list administrators, e-mail: [EMAIL PROTECTED]




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