[PHP] help, array values echoed as Array on loop!
I have tried both ways to loop through an array and output the data and
verify that the array is an array and I get no erros but I get this
value, which should not be so.
Here I'm checking if it's an array:
if (!is_array($ID_arr)) { # show error if no array
echo '$ID_arr is not an array.';
}
here I'm counting the keys but it only outputs as 1:
$key = count($ID_arr);
echo $key;
here are two loops that do the same thing and they both output Array:
for($i = 0; $i count($ID_arr); $i++) {
echo $ID_arr[$i];
}
foreach($ID_arr as $ind_picture) {
echo $ind_picture;
}
Why? If it helps, in order to get the array, the values were taken from
a database and exploded from a coma delimited string.
$ID_arr[] = explode(',', $pictures); # make db data into array
This is the string:
15,16,17,18,19
I want each array element to contain
= 15
= 16
= 17
etc...
why does it echo as Array?
- Victor www.argilent.com
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Re: [PHP] help, array values echoed as Array on loop!
On Mon, 2 Sep 2002, Victor wrote:
$ID_arr[] = explode(',', $pictures); # make db data into array
This is the string:
15,16,17,18,19
why does it echo as Array?
... because you've created an array ($ID_arr) with an array as the first
value (the result of the call to explode()). Take the brackets off
$ID_arr, and you'll get what you want. You don't want your array in an
array ... you just want an array.
$ID_arr = explode(',', $pictures);
If you really wanted your array in the array, then loop over $ID_arr[0].
(I doubt that's what you were going for, though.)
hth,
~Chris
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RE: [PHP] help, array values echoed as Array on loop!
Thank you, I figured it out 30 seconds after I posted the question, you
were right about the problem.
- Victor www.argilent.com
-Original Message-
From: Chris Wesley [mailto:[EMAIL PROTECTED]]
Sent: Monday, September 02, 2002 4:11 PM
To: 'PHP'
Cc: Victor
Subject: Re: [PHP] help, array values echoed as Array on loop!
On Mon, 2 Sep 2002, Victor wrote:
$ID_arr[] = explode(',', $pictures); # make db data into array
This is the string:
15,16,17,18,19
why does it echo as Array?
... because you've created an array ($ID_arr) with an array as the first
value (the result of the call to explode()). Take the brackets off
$ID_arr, and you'll get what you want. You don't want your array in an
array ... you just want an array.
$ID_arr = explode(',', $pictures);
If you really wanted your array in the array, then loop over $ID_arr[0].
(I doubt that's what you were going for, though.)
hth,
~Chris
__
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