Re: [PHP] password=password('$password') <----- ? help me... :P

2002-01-19 Thread Miles Thompson
I've got a typo near the bottom: left(password('$cPasswordf),10)"; should be left(password('$cPassword'),10)"; (Strange, the "f" is nowhere near " ' ") mt At 05:41 PM 1/19/2002 -0400, Miles Thompson wrote: >Hawk, > >Pardon me for not following this thread very closely, but I just played

Re: [PHP] password=password('$password') <----- ? help me... :P

2002-01-19 Thread Miles Thompson
Hawk, Pardon me for not following this thread very closely, but I just played around at the MySQL console. The fields I have are cName c(20) and cPassword(10) This executed OK insert admin (cName, cPassword) values ('Deb', password('peaches')); select cName, cPassword from admin; returned Deb

AW: [PHP] password=password('$password') <----- ? help me... :P

2002-01-19 Thread Wolf-Dietrich von Loeffelholz
liche Nachricht- Von: Hawk [mailto:[EMAIL PROTECTED]] Gesendet: Samstag, 19. Januar 2002 20:41 An: [EMAIL PROTECTED] Betreff: [PHP] password=password('$password') <- ? help me... :P I've been trying to get this to work for a while, and everyone says that I should use the sam

[PHP] password=password('$password') <----- ? help me... :P

2002-01-19 Thread Hawk
I've been trying to get this to work for a while, and everyone says that I should use the same thing, but it doesn't work, can anyone tell me what I'm doing wrong? from the form on the previous page I have the $username and $password vars mysql_connect($host, $user, $pswd); mysql_select_db($db);