Re: [PHP] stupid error, please kick me (and send me a solution)

2002-06-03 Thread Sqlcoders.com Programming Dept

Hiya,
You're using single quotes around all your strings,
for variables to be replaced with their values, you must use double quotes.
Try replacing every ' with .

HTH,
Dw

Sqlcoders.com Dynamic data driven web solutions
- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
To: mysql [EMAIL PROTECTED]; php-general
[EMAIL PROTECTED]
Sent: June 03 2002 03:09 PM
Subject: [PHP] stupid error, please kick me (and send me a solution)


 Hey guys,
 i'm getting this error with the following sql script using php:
 --error--
 Warning: Supplied argument is not a valid MySQL-Link resource in
 /var/www/phpquiz/register_user.php on line 12
 --error--

 --script--
 $link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
 $query = INSERT INTO user values('0', '$fname', '$lname', '$email',
 '$username', PASSWORD('$password');
 $result = mysql_db_query('$db_glob', '$query', $link_glob');
 if (!$result) {
 echo font size=+1Your Information could not be entered into the
database,
 Please contact the a
 href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
 :  . mysql_error() . brbr;
 } else {
 echo font size=+1Your Information has successfully been entered into
the
 database!/fontbr;

 --
 Jule Slootbeek
 [EMAIL PROTECTED]

 http://blindtheory.cjb.net



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[PHP] stupid error, please kick me (and send me a solution)

2002-06-03 Thread Jule Slootbeek

Hey guys,
i'm getting this error with the following sql script using php:
--error--
Warning: Supplied argument is not a valid MySQL-Link resource in 
/var/www/phpquiz/register_user.php on line 12
--error--

--script--
$link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
$query = INSERT INTO user values('0', '$fname', '$lname', '$email', 
'$username', PASSWORD('$password');
$result = mysql_db_query('$db_glob', '$query', $link_glob');
if (!$result) {
echo font size=+1Your Information could not be 
entered into the database, 
Please contact the a 
href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() . 
:  . mysql_error() . brbr;
} else {
echo font size=+1Your Information has successfully 
been entered into the 
database!/fontbr;

-- 
Jule Slootbeek  
[EMAIL PROTECTED] 

http://blindtheory.cjb.net 



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Re: [PHP] stupid error, please kick me (and send me a solution)

2002-06-03 Thread Lejanson C. Go

try this jule..

 $link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
 $temp= PASSWORD($password);
 $query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', '$temp');;



i think this will work..=) i hope ive done something.



- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
To: mysql [EMAIL PROTECTED]; php-general
[EMAIL PROTECTED]
Sent: Tuesday, June 04, 2002 6:09 AM
Subject: [PHP] stupid error, please kick me (and send me a solution)


 Hey guys,
 i'm getting this error with the following sql script using php:
 --error--
 Warning: Supplied argument is not a valid MySQL-Link resource in
 /var/www/phpquiz/register_user.php on line 12
 --error--

 --script--
 $link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
 $query = INSERT INTO user values('0', '$fname', '$lname', '$email',
 '$username', PASSWORD('$password');
 $result = mysql_db_query('$db_glob', '$query', $link_glob');
 if (!$result) {
 echo font size=+1Your Information could not be entered into the
database,
 Please contact the a
 href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
 :  . mysql_error() . brbr;
 } else {
 echo font size=+1Your Information has successfully been entered into
the
 database!/fontbr;

 --
 Jule Slootbeek
 [EMAIL PROTECTED]

 http://blindtheory.cjb.net



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Re: [PHP] stupid error, please kick me (and send me a solution)

2002-06-03 Thread Brad McCrorey

Please note that this only neccesarily applies to MySQL. I've run into a 
lot of problems by assuming double-quote syntax with postgres and mssql.

A better solution is to stop writing your own queries and use an 
abstraction library.

Cheers,

Brad
Sqlcoders.com Programming Dept wrote:

Hiya,
You're using single quotes around all your strings,
for variables to be replaced with their values, you must use double quotes.
Try replacing every ' with .

HTH,
Dw

Sqlcoders.com Dynamic data driven web solutions
- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
To: mysql [EMAIL PROTECTED]; php-general
[EMAIL PROTECTED]
Sent: June 03 2002 03:09 PM
Subject: [PHP] stupid error, please kick me (and send me a solution)


  

Hey guys,
i'm getting this error with the following sql script using php:
--error--
Warning: Supplied argument is not a valid MySQL-Link resource in
/var/www/phpquiz/register_user.php on line 12
--error--

--script--
$link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
$result = mysql_db_query('$db_glob', '$query', $link_glob');
if (!$result) {
echo font size=+1Your Information could not be entered into the


database,
  

Please contact the a
href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
:  . mysql_error() . brbr;
} else {
echo font size=+1Your Information has successfully been entered into


the
  

database!/fontbr;

--
Jule Slootbeek
[EMAIL PROTECTED]

http://blindtheory.cjb.net



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To unsubscribe, visit: http://www.php.net/unsub.php






  





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