Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-21 00:11:13 +0100: Roman Neuhauser wrote: # [EMAIL PROTECTED] / 2007-01-17 16:59:26 +0100: wouldn't it be fair to assume (safety through paranoia) that ctype_alnum() would suffer the same problem? (given the manual's indication that ctype_alnum() and the offending regexp are equivalent?) isalnum(3) uses isalpha(3) and isdigit(3), so yes, their results are locale-dependent (LC_CTYPE, see setlocale(3)), but don't depend on collating sequence. so really the doc's are slightly misleading or even incorrect, Slightly, in a usually-behaves-as-described-but-for-different-reasons way. as a side note: do you have any real world example of where this collation issue might actually bite someone making use of the aforementioned regexp range? Not off the top of my head. :( -- How many Vietnam vets does it take to screw in a light bulb? You don't know, man. You don't KNOW. Cause you weren't THERE. http://bash.org/?255991 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-21 10:48:30 +:
# [EMAIL PROTECTED] / 2007-01-21 00:11:13 +0100:
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 16:59:26 +0100:
wouldn't it be fair to assume (safety through paranoia) that
ctype_alnum() would suffer the same problem? (given the manual's
indication that ctype_alnum() and the offending regexp are equivalent?)
isalnum(3) uses isalpha(3) and isdigit(3), so yes, their results are
locale-dependent (LC_CTYPE, see setlocale(3)), but don't depend on
collating sequence.
so really the doc's are slightly misleading or even incorrect,
Slightly, in a usually-behaves-as-described-but-for-different-reasons
way.
as a side note: do you have any real world example of where this
collation issue might actually bite someone making use of the aforementioned
regexp range?
Not off the top of my head. :(
Trying the Czech locale (I normally run with the values below), I've
come across some unexpected behavior.
0xE8 is c caron, and sorts between c and d, but not on this computer.
0xBE is z caron, and sorts just after z.
I'd expect [a-z] to match 0xE8 but it does not.
LANG=cs_CZ.ISO8859-2
LC_COLLATE=en_US.ISO8859-1
LC_CTYPE=en_US.ISO8859-1
LC_MESSAGES=en_US.ISO8859-1
LC_NUMERIC=en_US.ISO8859-1
LC_TIME=en_US.ISO8859-1
[EMAIL PROTECTED] ~/tmp/blemc 1042:0 uname -srm
FreeBSD 6.1-PRERELEASE amd64
[EMAIL PROTECTED] ~/tmp/blemc 1043:0 cat ./collseq.php
#!/usr/bin/env php
?php
function f($c, $l)
{
printf(char=%c locale=%s\n, $c, $l);
setlocale(LC_COLLATE, $l);
setlocale(LC_CTYPE, $l);
printf([a-z] = %s\n, var_export(preg_match('~[a-z]~', chr($c)), 1));
printf([[:lower:]] = %s\n, var_export(preg_match('~[[:lower:]]~',
chr($c)), 1));
printf(islower(3) = %s\n, var_export(ctype_lower(chr($c)), 1));
print \n;
}
f(0xE8, 'C'); f(0xE8, 'cs_CZ.ISO8859-2');
f(0xBE, 'C'); f(0xBE, 'cs_CZ.ISO8859-2');
[EMAIL PROTECTED] ~/tmp/blemc 1044:0 ./collseq.php
char=č locale=C
[a-z] = 0
[[:lower:]] = 0
islower(3) = false
char=č locale=cs_CZ.ISO8859-2
[a-z] = 0
[[:lower:]] = 1
islower(3) = true
char=ž locale=C
[a-z] = 0
[[:lower:]] = 0
islower(3) = false
char=ž locale=cs_CZ.ISO8859-2
[a-z] = 0
[[:lower:]] = 1
islower(3) = true
--
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Re: [PHP] I lied, another question / problem
Roman Neuhauser wrote: # [EMAIL PROTECTED] / 2007-01-17 16:59:26 +0100: Roman Neuhauser wrote: re_format(7) on FreeBSD: A bracket expression is a list of characters enclosed in `[]'. (...) If two characters in the list are separated by `-', this is shorthand for the full range of characters between those two (inclusive) in the collating sequence, e.g. `[0-9]' in ASCII matches any decimal digit. (...) Ranges are very collating-sequence-dependent, and portable programs should avoid relying on them. one other thing ... wouldn't it be fair to assume (safety through paranoia) that ctype_alnum() would suffer the same problem? (given the manual's indication that ctype_alnum() and the offending regexp are equivalent?) isalnum(3) uses isalpha(3) and isdigit(3), so yes, their results are locale-dependent (LC_CTYPE, see setlocale(3)), but don't depend on collating sequence. so really the doc's are slightly misleading or even incorrect, I will try to formulate a succinct question for internals@ to ask whether this should be reported as documentation bug. as a side note: do you have any real world example of where this collation issue might actually bite someone making use of the aforementioned regexp range? isdigit(3): The isdigit() function tests for a decimal digit character. Regardless of locale, this includes the following characters only: ``0'' ``1'' ``2'' ``3'' ``4'' ``5'' ``6'' ``7'' ``8'' ``9'' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-17 01:42:09 +0100:
Beauford wrote:
Further to my previous email, there is something weird going on here. I just
tried using this:
if (!ereg('^[A-Za-z0-9]', $strvalue)) {
return error;
}
stop using bleeding ereg*() function - move to preg_*() funcs like the rest of
the world did 5+ years ago.
Or even better: how about using the right tool for the job? :)
if (!ctype_isalnum($strvalue)) {
return error;
}
if (!preg_match(#^[A-Z0-9]+\$#i, $s)) {
(ps the above is a crappy regexp for real world use imho, but it serves
the purpose of example)
It's dangerous.
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Re: [PHP] I lied, another question / problem
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 01:42:09 +0100:
Beauford wrote:
Further to my previous email, there is something weird going on here. I just
tried using this:
if (!ereg('^[A-Za-z0-9]', $strvalue)) {
return error;
}
stop using bleeding ereg*() function - move to preg_*() funcs like the rest
of
the world did 5+ years ago.
Or even better: how about using the right tool for the job? :)
true, although the function should be spelled correct to avoid fatal errors ;-)
if (!ctype_isalnum($strvalue)) {
return error;
}
if (!preg_match(#^[A-Z0-9]+\$#i, $s)) {
(ps the above is a crappy regexp for real world use imho, but it serves
the purpose of example)
It's dangerous.
why dangerous?
given that this page: http://php.net/manual/en/function.ctype-alnum.php
says, and I quote:
Checks if all of the characters in the provided string, text, are
alphanumeric. In the standard C locale letters are
just [A-Za-z] and the function is equivalent to preg_match('/^[a-z0-9]+$/iD',
$text).
the 'D' modifier being the only difference in my example regexp and the
equilavent given on the
ctype_alnum() page ... I grant that the 'D' modifier might the difference
between dangerous and
not dangerous, if that's the case please explain (because I'm not seeing it :-)
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Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-17 11:41:54 +0100:
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 01:42:09 +0100:
if (!preg_match(#^[A-Z0-9]+\$#i, $s)) {
(ps the above is a crappy regexp for real world use imho, but it serves
the purpose of example)
It's dangerous.
why dangerous?
given that this page: http://php.net/manual/en/function.ctype-alnum.php
says, and I quote:
Checks if all of the characters in the provided string, text, are
alphanumeric. In the standard C locale letters are just [A-Za-z] and
the function is equivalent to preg_match('/^[a-z0-9]+$/iD', $text).
re_format(7) on FreeBSD:
A bracket expression is a list of characters enclosed in `[]'.
(...)
If two characters in the list are separated by `-', this is
shorthand for the full range of characters between those two
(inclusive) in the collating sequence, e.g. `[0-9]' in ASCII
matches any decimal digit.
(...)
Ranges are very collating-sequence-dependent, and portable programs
should avoid relying on them.
--
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Cause you weren't THERE. http://bash.org/?255991
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Re: [PHP] I lied, another question / problem
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 11:41:54 +0100:
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 01:42:09 +0100:
if (!preg_match(#^[A-Z0-9]+\$#i, $s)) {
(ps the above is a crappy regexp for real world use imho, but it serves
the purpose of example)
It's dangerous.
why dangerous?
given that this page: http://php.net/manual/en/function.ctype-alnum.php
says, and I quote:
Checks if all of the characters in the provided string, text, are
alphanumeric. In the standard C locale letters are just [A-Za-z] and
the function is equivalent to preg_match('/^[a-z0-9]+$/iD', $text).
re_format(7) on FreeBSD:
A bracket expression is a list of characters enclosed in `[]'.
(...)
If two characters in the list are separated by `-', this is
shorthand for the full range of characters between those two
(inclusive) in the collating sequence, e.g. `[0-9]' in ASCII
matches any decimal digit.
(...)
Ranges are very collating-sequence-dependent, and portable programs
should avoid relying on them.
ah, thanks for that.
what would you suggest instead of 'a-z' in this instance, *if* the OP
wants *just* the chars [in ASCII] from a to Z then the only thing I could think
of would be to use a string of 26 chars ... is there a better way?
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Re: [PHP] I lied, another question / problem
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 11:41:54 +0100:
Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-17 01:42:09 +0100:
if (!preg_match(#^[A-Z0-9]+\$#i, $s)) {
(ps the above is a crappy regexp for real world use imho, but it serves
the purpose of example)
It's dangerous.
why dangerous?
given that this page: http://php.net/manual/en/function.ctype-alnum.php
says, and I quote:
Checks if all of the characters in the provided string, text, are
alphanumeric. In the standard C locale letters are just [A-Za-z] and
the function is equivalent to preg_match('/^[a-z0-9]+$/iD', $text).
re_format(7) on FreeBSD:
A bracket expression is a list of characters enclosed in `[]'.
(...)
If two characters in the list are separated by `-', this is
shorthand for the full range of characters between those two
(inclusive) in the collating sequence, e.g. `[0-9]' in ASCII
matches any decimal digit.
(...)
Ranges are very collating-sequence-dependent, and portable programs
should avoid relying on them.
one other thing ...
wouldn't it be fair to assume (safety through paranoia) that
ctype_alnum() would suffer the same problem? (given the manual's
indication that ctype_alnum() and the offending regexp are equivalent?)
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Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-17 16:59:26 +0100: Roman Neuhauser wrote: re_format(7) on FreeBSD: A bracket expression is a list of characters enclosed in `[]'. (...) If two characters in the list are separated by `-', this is shorthand for the full range of characters between those two (inclusive) in the collating sequence, e.g. `[0-9]' in ASCII matches any decimal digit. (...) Ranges are very collating-sequence-dependent, and portable programs should avoid relying on them. one other thing ... wouldn't it be fair to assume (safety through paranoia) that ctype_alnum() would suffer the same problem? (given the manual's indication that ctype_alnum() and the offending regexp are equivalent?) isalnum(3) uses isalpha(3) and isdigit(3), so yes, their results are locale-dependent (LC_CTYPE, see setlocale(3)), but don't depend on collating sequence. isdigit(3): The isdigit() function tests for a decimal digit character. Regardless of locale, this includes the following characters only: ``0'' ``1'' ``2'' ``3'' ``4'' ``5'' ``6'' ``7'' ``8'' ``9'' -- How many Vietnam vets does it take to screw in a light bulb? You don't know, man. You don't KNOW. Cause you weren't THERE. http://bash.org/?255991 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] I lied, another question / problem
I believe that only two things could be messing up your validation:
a) input data
b) your function
a) Do a var_dump on your input data. Is there any white space
characters or anything else that do not belong there in the string?
b) Rewrite your function/rethink what you are doing. You said that
your function should match letters from a to Z and some special
characters like ' - _ .
Try this regex:
^(\w+\s?[\'\-\_\.]?)+$
I would write the function as follows:
function invalidchar ( $input )
{
if ( preg_match ( ^(\w+\s?[\'\-\_\.]?)+$, $input ) ) { // string
matches against the pattern, everything is ok
return $input;
} else {
return false;
}
}
if ( invalidchar ( $my_string ) == false ) {
// do some stuff
} else {
echo You passed the test;
}
// untested
// frank
16 jan 2007 kl. 04.47 skrev Beauford:
My apologies, but I am just so frustrated right now. It seems my
function
doesn't work either (if that's even the problem, which at this time
I just
don't know). Somehow my variable is still getting a value, and I
have no
idea how. Even if I don't return anything it still gets a value.
Basically
this has just broken my whole site.
If anyone can figure this out let me know, right now I just have to
put this
site up with no validation.
Thanks
-Original Message-
From: Beauford
Sent: January 15, 2007 10:26 PM
To: 'PHP'
Subject: RE: [PHP] I lied, another question / problem
Does anyone have any idea to this problem? All the code is in
the emails I have written to the list. I have temporarily
solved the problem by writing my own function not using any
pregs, eregs, or any other regs and it works perfectly. It's
probably not considered good programming, but it works the
way it is supposed to.
I would however like to know what the issue is with the
original code, or if this is actually a bug in PHP.
Thanks
-Original Message-
From: Beauford [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:22 PM
To: 'PHP'
Subject: RE: [PHP] I lied, another question / problem
-Original Message-
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:53 PM
To: Beauford
Cc: 'PHP'
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue) {
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences
of a letter, a whitespace character, and any character
whose numeric
value lies between the numeric values of ' and . in
your locale.
Zero or more means it also matches an empty string.
I'm still confused. This works perfectly on my other two
pages with
the exact same code. So why is it only this one page that
is causing a problem?
I don't know, I don't care. You have enough problems with
the single
regex, let's concentrate on fixing this first.
This certainly has a bearing. If the code works here then there is
nothing wrong with the code. There is something else going on.
If I enter the word test in my form, without the quotes,
then why is
the fuction returning anything since this is a valid entry.
Should it
not only return a value if there is a problem.
I don't understand that paragraph. The regexp matches, and the
function returns *nothing* just as you programmed it.
That, of course, means that the variable you are assigning this
*nothing* gets set to *nothing*, which, in PHP lingo, is null.
The problem is that it is returning *something*, and that's
what I am
trying to figure out.
If I put this in my code after I do the checking it works, but it
should not work if the function is retuning *nothing*.
So the original question remains, what is being returned and why?
If($formerror) echo Testing; This will display Testing -
it should
not display anything since nothing should be returned.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or are
you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and
(that's
three spaces) are valid entries?
Where do you see 3 spaces? In any event, I don't think this is the
problem.
As I have said the code works fine on two other pages,
which logically
suggests that there is something on this page that is causing a
problem.
Thanks
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Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 19:22:24 -0500:
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED]
# [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the numeric values of
' and . in your locale. Zero or more means it also matches
an empty string.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or are you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and (that's
three spaces) are valid entries?
Where do you see 3 spaces?
That's a value the regexp will match. Is that intended?
In any event, I don't think this is the problem.
As I have said the code works fine on two other pages, which logically
suggests that there is something on this page that is causing a problem.
You don't understand that single function, and it does something else
than you think it does. I told you what it actually does, but you chose
to ignore the information. I don't know how I could help you more.
--
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
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RE: [PHP] I lied, another question / problem
Obviously I'm not quite understanding, maybe a further explanation is needed
to help me understand.
This is how I see it from what you said - am in in the right ballpark.
The function is returning a null value if there is no error, and I guess PHP
sees 'null' or as a value. So how do I get around this?
This is how I call the function.
if($result = ValidateString($orgname, 1)) { $formerror['orgname'] = $result;
}
If there is an error an error string will be returned (i.e. Error in field),
if not I want nothing returned.
Later on in the page I use - if(!$formerror) blah blah.
This is where the problem is because if null or is being returned then
$formerror has a value which breaks the above if.
I hope this helps.
Thanks
-Original Message-
From: Roman Neuhauser [mailto:[EMAIL PROTECTED]
Sent: January 16, 2007 5:49 AM
To: Beauford
Cc: 'PHP'
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 19:22:24 -0500:
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue) {
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the
numeric values of
' and . in your locale. Zero or more means it
also matches
an empty string.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or
are you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and
(that's
three spaces) are valid entries?
Where do you see 3 spaces?
That's a value the regexp will match. Is that intended?
In any event, I don't think this is the problem.
As I have said the code works fine on two other pages,
which logically
suggests that there is something on this page that is
causing a problem.
You don't understand that single function, and it does
something else than you think it does. I told you what it
actually does, but you chose to ignore the information. I
don't know how I could help you more.
--
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
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Re: [PHP] I lied, another question / problem
Beauford wrote:
Obviously I'm not quite understanding, maybe a further explanation is needed
to help me understand.
This is how I see it from what you said - am in in the right ballpark.
The function is returning a null value if there is no error, and I guess PHP
sees 'null' or as a value. So how do I get around this?
This is how I call the function.
if($result = ValidateString($orgname, 1)) { $formerror['orgname'] = $result;
}
If there is an error an error string will be returned (i.e. Error in field),
if not I want nothing returned.
Later on in the page I use - if(!$formerror) blah blah.
This is a bad way to test for a value also, unless you expecting only
TRUE or FALSE and you are sure that it will always be set.
Otherwise you should do something like this
if ( isset($formerror) $formerror != '' ) {
// Display Error
}
Also, going back to your original post, the function
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
return *;
}
}
You would always return SOMETHING.
Even if it is FALSE
Give this a try:
?PHP
function invalidchar($strvalue) {
if ( preg_match(|^[[:alpha:][:space:]\'\.-]+$|, $strvalue) ) {
return $strvalue;
}
return 'BAD'; //-- For testing only
return FALSE; //-- Left this so you could return false and not a
string
}
echo '('.invalidchar('something').')';
?
Jim Lucas
This is where the problem is because if null or is being returned then
$formerror has a value which breaks the above if.
I hope this helps.
Thanks
-Original Message-
From: Roman Neuhauser [mailto:[EMAIL PROTECTED]
Sent: January 16, 2007 5:49 AM
To: Beauford
Cc: 'PHP'
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 19:22:24 -0500:
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue) {
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the
numeric values of
' and . in your locale. Zero or more means it
also matches
an empty string.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or
are you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and
(that's
three spaces) are valid entries?
Where do you see 3 spaces?
That's a value the regexp will match. Is that intended?
In any event, I don't think this is the problem.
As I have said the code works fine on two other pages,
which logically
suggests that there is something on this page that is
causing a problem.
You don't understand that single function, and it does
something else than you think it does. I told you what it
actually does, but you chose to ignore the information. I
don't know how I could help you more.
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RE: [PHP] I lied, another question / problem
This is a bad way to test for a value also, unless you
expecting only TRUE or FALSE and you are sure that it will
always be set.
Otherwise you should do something like this
if ( isset($formerror) $formerror != '' ) {
// Display Error
}
The problem here is this. formerror is an array and can have formerror['a'],
formerror['b'], etc. I don't care how many errors there are, I only want to
know if there was an error somewhere along the way.
Example: if I have two fields, Name and Age and they both have errors, I
would echo $formerror['name'] and $formerror['age']
Then I check if(!$formerror) { do something.. This would not get done as
the above two have errors, which is what I want.
The problem still lies with something being returned from the function even
if there are no errors. So if(!$formerror) never gets done. Which is the
problem.
Another question, and not related, how do I kill a session when someone
leaves a particular page.
Thanks
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Re: [PHP] I lied, another question / problem
Beauford wrote:
...
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the numeric values
of ' and . in your locale.
Zero or more means it also matches an empty string.
..
Further to my previous email, there is something weird going on here. I just
tried using this:
if (!ereg('^[A-Za-z0-9]', $strvalue)) {
return error;
}
stop using bleeding ereg*() function - move to preg_*() funcs like the rest of
the world did 5+ years ago.
When I enter the word Test, which is valid, I am still getting an error
'Test' is not valid according to the regexp your using.
?php
$strs = array(Test, Jochem, @##^%, , Test1, Test!, J*nk);
// match a non-empty string containing *only* alpha numeric chars
foreach ($strs as $s) {
if (!preg_match(#^[A-Z0-9]+\$#i, $s)) {
echo error in string: \$s\ \n;
} else {
echo no problemo: \$s\ \n;
}
}
?
(ps the above is a crappy regexp for real world use imho, but it serves
the purpose of example)
you need to read up and do lots of practicing with regexps - we do realise that
regexps are not easy, unfortunately there is no shortcut to learning how to use
them.
I doubt many on this list could be considered expert in the field of regexps,
but
you have to get yourself a basic grasp or these things will bite you in the ass
until
the cows come home.
start here:
http://php.net/pcre
http://php.net/manual/en/reference.pcre.pattern.modifiers.php
http://php.net/manual/en/reference.pcre.pattern.syntax.php
returned - but only on this one page. So there has got to be something on
this page that is screwing this up, but what. I have been over and over this
and can't see a problem.
I could really use another pair of eyes on this as it is driving me nuts. I
regexps drives everyone nuts to start with. first there is only the mountain,
then the
mountain is not a mountain, finally there is just mountain.
am now into hour 6 with this. Absolutely ridiculous.
thats nothing. most people take months to get anywhere useful with regexps,
well okay I'm speaking for myself - I was in your position somewhere back in
2001,
I was regularly sweating it for weeks trying to understand and getting certain
regexps
work 'properly'.
don't give up.
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Re: [PHP] I lied, another question / problem
Beauford wrote:
This is a bad way to test for a value also, unless you
expecting only TRUE or FALSE and you are sure that it will
always be set.
Otherwise you should do something like this
if ( isset($formerror) $formerror != '' ) {
// Display Error
}
The problem here is this. formerror is an array
Then check it as an array.
$formerror = array();
... do your validation here which may/may not add to the array.
if (!empty($formerror)) {
echo Something went wrong!;
print_r($formerror);
} else {
echo Everything is ok!;
}
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RE: [PHP] I lied, another question / problem
$formerror = array();
... do your validation here which may/may not add to the array.
if (!empty($formerror)) {
echo Something went wrong!;
print_r($formerror);
} else {
echo Everything is ok!;
}
As I said the problem is that a value is being returned, how I check it is
really not an issue as I know there is value there. I guess I need to figure
out how to only return something if there is an error, and not return
anything if there is no error, or just totally revise the way I am doing
this period.
I have corrected the problem, but it is messy and it is cumbersome, but it
will have to do until I can work out something better. At least now I can
take my time and work on this.
I appreciate all the suggestions and maybe I can incorporate some of them
once I do a rewrite.
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Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more ocurrences
of a letter, a whitespace character, and any character whose numeric
value lies between the numeric values of ' and . in your locale.
Zero or more means it also matches an empty string.
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RE: [PHP] I lied, another question / problem
-Original Message-
From: Roman Neuhauser [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:09 PM
To: Beauford
Cc: PHP
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the numeric values
of ' and . in your locale.
Zero or more means it also matches an empty string.
I'm still confused. This works perfectly on my other two pages with the
exact same code. So why is it only this one page that is causing a problem?
If I enter the word test in my form, without the quotes, then why is the
fuction returning anything since this is a valid entry. Should it not only
return a value if there is a problem.
All I want to accomplish here is to allow the user to enter a to z, A to Z,
and /\'-_. and a space. Is there a better way to do this?
Thanks
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Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED]
# [EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the numeric values
of ' and . in your locale.
Zero or more means it also matches an empty string.
I'm still confused. This works perfectly on my other two pages with the
exact same code. So why is it only this one page that is causing a problem?
I don't know, I don't care. You have enough problems with the single
regex, let's concentrate on fixing this first.
If I enter the word test in my form, without the quotes, then why is the
fuction returning anything since this is a valid entry. Should it not only
return a value if there is a problem.
I don't understand that paragraph. The regexp matches, and the function
returns *nothing* just as you programmed it. That, of course, means
that the variable you are assigning this *nothing* gets set to
*nothing*, which, in PHP lingo, is null.
All I want to accomplish here is to allow the user to enter a to z, A to Z,
and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or are you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and (that's
three spaces) are valid entries?
--
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RE: [PHP] I lied, another question / problem
-Original Message-
From: Roman Neuhauser [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:09 PM
To: Beauford
Cc: PHP
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences of a letter, a whitespace character, and any
character whose numeric value lies between the numeric values
of ' and . in your locale.
Zero or more means it also matches an empty string.
--
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You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
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Further to my previous email, there is something weird going on here. I just
tried using this:
if (!ereg('^[A-Za-z0-9]', $strvalue)) {
return error;
}
When I enter the word Test, which is valid, I am still getting an error
returned - but only on this one page. So there has got to be something on
this page that is screwing this up, but what. I have been over and over this
and can't see a problem.
I could really use another pair of eyes on this as it is driving me nuts. I
am now into hour 6 with this. Absolutely ridiculous.
Thanks
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RE: [PHP] I lied, another question / problem
-Original Message-
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:53 PM
To: Beauford
Cc: 'PHP'
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences
of a letter, a whitespace character, and any character
whose numeric
value lies between the numeric values of ' and . in
your locale.
Zero or more means it also matches an empty string.
I'm still confused. This works perfectly on my other two pages with
the exact same code. So why is it only this one page that
is causing a problem?
I don't know, I don't care. You have enough problems with the
single regex, let's concentrate on fixing this first.
This certainly has a bearing. If the code works here then there is nothing
wrong with the code. There is something else going on.
If I enter the word test in my form, without the quotes,
then why is
the fuction returning anything since this is a valid entry.
Should it
not only return a value if there is a problem.
I don't understand that paragraph. The regexp matches, and
the function returns *nothing* just as you programmed it.
That, of course, means that the variable you are assigning
this *nothing* gets set to *nothing*, which, in PHP lingo, is null.
The problem is that it is returning *something*, and that's what I am trying
to figure out.
If I put this in my code after I do the checking it works, but it should not
work if the function is retuning *nothing*. So the original question
remains, what is being returned and why?
If($formerror) echo Testing; This will display Testing - it should not
display anything since nothing should be returned.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or are you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and (that's
three spaces) are valid entries?
Where do you see 3 spaces? In any event, I don't think this is the problem.
As I have said the code works fine on two other pages, which logically
suggests that there is something on this page that is causing a problem.
Thanks
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RE: [PHP] I lied, another question / problem
Does anyone have any idea to this problem? All the code is in the emails I
have written to the list. I have temporarily solved the problem by writing
my own function not using any pregs, eregs, or any other regs and it works
perfectly. It's probably not considered good programming, but it works the
way it is supposed to.
I would however like to know what the issue is with the original code, or if
this is actually a bug in PHP.
Thanks
-Original Message-
From: Beauford [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:22 PM
To: 'PHP'
Subject: RE: [PHP] I lied, another question / problem
-Original Message-
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:53 PM
To: Beauford
Cc: 'PHP'
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue)
{
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences
of a letter, a whitespace character, and any character
whose numeric
value lies between the numeric values of ' and . in
your locale.
Zero or more means it also matches an empty string.
I'm still confused. This works perfectly on my other two
pages with
the exact same code. So why is it only this one page that
is causing a problem?
I don't know, I don't care. You have enough problems with
the single
regex, let's concentrate on fixing this first.
This certainly has a bearing. If the code works here then
there is nothing wrong with the code. There is something else
going on.
If I enter the word test in my form, without the quotes,
then why is
the fuction returning anything since this is a valid entry.
Should it
not only return a value if there is a problem.
I don't understand that paragraph. The regexp matches, and the
function returns *nothing* just as you programmed it.
That, of course, means that the variable you are assigning this
*nothing* gets set to *nothing*, which, in PHP lingo, is null.
The problem is that it is returning *something*, and that's
what I am trying to figure out.
If I put this in my code after I do the checking it works,
but it should not work if the function is retuning *nothing*.
So the original question remains, what is being returned and why?
If($formerror) echo Testing; This will display Testing -
it should not display anything since nothing should be returned.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or are
you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and
(that's
three spaces) are valid entries?
Where do you see 3 spaces? In any event, I don't think this
is the problem.
As I have said the code works fine on two other pages, which
logically suggests that there is something on this page that
is causing a problem.
Thanks
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RE: [PHP] I lied, another question / problem
My apologies, but I am just so frustrated right now. It seems my function
doesn't work either (if that's even the problem, which at this time I just
don't know). Somehow my variable is still getting a value, and I have no
idea how. Even if I don't return anything it still gets a value. Basically
this has just broken my whole site.
If anyone can figure this out let me know, right now I just have to put this
site up with no validation.
Thanks
-Original Message-
From: Beauford
Sent: January 15, 2007 10:26 PM
To: 'PHP'
Subject: RE: [PHP] I lied, another question / problem
Does anyone have any idea to this problem? All the code is in
the emails I have written to the list. I have temporarily
solved the problem by writing my own function not using any
pregs, eregs, or any other regs and it works perfectly. It's
probably not considered good programming, but it works the
way it is supposed to.
I would however like to know what the issue is with the
original code, or if this is actually a bug in PHP.
Thanks
-Original Message-
From: Beauford [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:22 PM
To: 'PHP'
Subject: RE: [PHP] I lied, another question / problem
-Original Message-
From: 'Roman Neuhauser' [mailto:[EMAIL PROTECTED]
Sent: January 15, 2007 7:53 PM
To: Beauford
Cc: 'PHP'
Subject: Re: [PHP] I lied, another question / problem
# [EMAIL PROTECTED] / 2007-01-15 18:33:31 -0500:
From: Roman Neuhauser [mailto:[EMAIL PROTECTED] #
[EMAIL PROTECTED] / 2007-01-15 16:31:32 -0500:
I have file which I use for validating which includes the
following
function:
function invalidchar($strvalue) {
if(!ereg(^[[:alpha:][:space:]\'-.]*$, $strvalue)) {
That regexp matches if $strvalue consists of zero or more
ocurrences
of a letter, a whitespace character, and any character
whose numeric
value lies between the numeric values of ' and . in
your locale.
Zero or more means it also matches an empty string.
I'm still confused. This works perfectly on my other two
pages with
the exact same code. So why is it only this one page that
is causing a problem?
I don't know, I don't care. You have enough problems with
the single
regex, let's concentrate on fixing this first.
This certainly has a bearing. If the code works here then there is
nothing wrong with the code. There is something else going on.
If I enter the word test in my form, without the quotes,
then why is
the fuction returning anything since this is a valid entry.
Should it
not only return a value if there is a problem.
I don't understand that paragraph. The regexp matches, and the
function returns *nothing* just as you programmed it.
That, of course, means that the variable you are assigning this
*nothing* gets set to *nothing*, which, in PHP lingo, is null.
The problem is that it is returning *something*, and that's
what I am
trying to figure out.
If I put this in my code after I do the checking it works, but it
should not work if the function is retuning *nothing*.
So the original question remains, what is being returned and why?
If($formerror) echo Testing; This will display Testing -
it should
not display anything since nothing should be returned.
All I want to accomplish here is to allow the user to enter
a to z, A
to Z, and /\'-_. and a space. Is there a better way to do this?
1. Do you really want to let them enter backslashes, or are
you trying
to escape the apostrophe?
2. Does that mean that /\'-_. (without the quotes) and
(that's
three spaces) are valid entries?
Where do you see 3 spaces? In any event, I don't think this is the
problem.
As I have said the code works fine on two other pages,
which logically
suggests that there is something on this page that is causing a
problem.
Thanks
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