Re: [PHP] Need help with regular expression

2008-07-10 Thread Maxim Antonov 

Hello.

But I need no td and tr inside regular expression
It is a part of my templater.


In real code it looks like:
  if(strlen($item[$key])1){
return 
preg_replace('#\{%%%.*?\{%'.$key.'%\}.*?%%%\}#is','',$tpl);

}

if one of $key inside  {%%%  %%%} points to empty array item - all 
section between {%%% %%%} must be deleted.




Daniel Brown :

On Wed, Jul 9, 2008 at 5:21 AM, Maxim Antonov [EMAIL PROTECTED] wrote:

Hi, all!

I try to use folowing regular expression:
$out =
preg_replace('#\{%%%.*?\{%bigfoto%\}.*?%%%\}#is','==REPLACEMENT==',$str);


[snip!]

I need result as:

trtdNAME:/tdtdinput type=text name=name value=
size=80//td/tr
 trtdFoto:/tdtdinput type=file name=foto value={%foto%} /
 {%%%br/img alt={%name%} src={%foto%}/%%%}
 /td/tr
==REPLACEMENT==

[snip!]

To get it *exactly* as you've mentioned here, use this instead:

?php
$out = 
preg_replace('/trtdBig.*\{%%%.*\{%bigfoto%\}.*%%%\}.*\/tr/Uis','==REPLACEMENT==',$str);
?



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RE: [PHP] Need help with regular expression

2008-07-10 Thread Boyd, Todd M. 
 -Original Message-
 From: Maxim Antonov [mailto:[EMAIL PROTECTED]
 Sent: Thursday, July 10, 2008 4:24 AM
 To: php-general@lists.php.net; Daniel Brown
 Subject: Re: [PHP] Need help with regular expression
 
 Hello.
 
 But I need no td and tr inside regular expression
 It is a part of my templater.
 
 
 In real code it looks like:
if(strlen($item[$key])1){
  return
 preg_replace('#\{%%%.*?\{%'.$key.'%\}.*?%%%\}#is','',$tpl);
  }
 
 if one of $key inside  {%%%  %%%} points to empty array item - all
 section between {%%% %%%} must be deleted.

---8--- snip

Maxim,

You could try using a capture group, and re-assemble the match with
the match group inbetween your {%%% %%%} omitted. Just an idea.


Todd Boyd
Web Programmer




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Re: [PHP] Need help with regular expression

2008-07-10 Thread Al 

Your description of the problem is confusing.

Do you simply want to delete a table row if it contains a variable, e.g., $var='bigfoto' and append 
==REPLACEMENT== ? Where $var can be anything you assign.



Maxim Antonov wrote:

Hello.

But I need no td and tr inside regular expression
It is a part of my templater.


In real code it looks like:
  if(strlen($item[$key])1){
return 
preg_replace('#\{%%%.*?\{%'.$key.'%\}.*?%%%\}#is','',$tpl);

}

if one of $key inside  {%%%  %%%} points to empty array item - all 
section between {%%% %%%} must be deleted.




Daniel Brown :
On Wed, Jul 9, 2008 at 5:21 AM, Maxim Antonov [EMAIL PROTECTED] 
wrote:

Hi, all!

I try to use folowing regular expression:
$out =
preg_replace('#\{%%%.*?\{%bigfoto%\}.*?%%%\}#is','==REPLACEMENT==',$str); 




[snip!]

I need result as:

trtdNAME:/tdtdinput type=text name=name value=
size=80//td/tr
 trtdFoto:/tdtdinput type=file name=foto 
value={%foto%} /

 {%%%br/img alt={%name%} src={%foto%}/%%%}
 /td/tr
==REPLACEMENT==

[snip!]

To get it *exactly* as you've mentioned here, use this instead:

?php
$out = 
preg_replace('/trtdBig.*\{%%%.*\{%bigfoto%\}.*%%%\}.*\/tr/Uis','==REPLACEMENT==',$str); 


?



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Re: [PHP] Need help with regular expression

2008-07-10 Thread Eric Butera 
On Wed, Jul 9, 2008 at 5:21 AM, Maxim Antonov [EMAIL PROTECTED] wrote:
 Hi, all!

 I try to use folowing regular expression:
 $out =
 preg_replace('#\{%%%.*?\{%bigfoto%\}.*?%%%\}#is','==REPLACEMENT==',$str);

 It not work as I need. Please tell me - what I do wrong?

 I have string:


   trtdNAME:/tdtdinput type=text name=name value=
 size=80//td/tr
  trtdFoto:/tdtdinput type=file name=foto value={%foto%} /
  {%%%br/img alt={%name%} src={%foto%}/%%%}
  /td/tr
  trtdBig foto:/tdtdinput type=file name=bigfoto value= /
  {%%%br/img alt={%name%} src={%bigfoto%}/%%%}
  /td/tr



 I need result as:


 trtdNAME:/tdtdinput type=text name=name value=
 size=80//td/tr
  trtdFoto:/tdtdinput type=file name=foto value={%foto%} /
  {%%%br/img alt={%name%} src={%foto%}/%%%}
  /td/tr
 ==REPLACEMENT==


 And I have this result:

   trtdNAME:/tdtdinput type=text name=name value=
 size=80//td/tr
  trtdFoto:/tdtdinput type=file name=foto value={%foto%} /
 ==REPLACEMENT==
  /td/tr


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I'm sure it won't be this easy because of who knows what (like
inheriting code, etc), but why not just use something easier like:


$replace = array(
'{%key1%}' = 'value1',
'{%key2%}' = 'value2'
);

$html = str_replace(
array_keys($replace),
array_values($replace),
file_get_contents('tpl.html')
);


Or the easiest is to just use raw php code seeing as php is a
templating language. :)

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Re: [PHP] Need help with regular expression

2008-07-09 Thread Daniel Brown 
On Wed, Jul 9, 2008 at 5:21 AM, Maxim Antonov [EMAIL PROTECTED] wrote:
 Hi, all!

 I try to use folowing regular expression:
 $out =
 preg_replace('#\{%%%.*?\{%bigfoto%\}.*?%%%\}#is','==REPLACEMENT==',$str);

[snip!]

 I need result as:

 trtdNAME:/tdtdinput type=text name=name value=
 size=80//td/tr
  trtdFoto:/tdtdinput type=file name=foto value={%foto%} /
  {%%%br/img alt={%name%} src={%foto%}/%%%}
  /td/tr
 ==REPLACEMENT==
[snip!]

To get it *exactly* as you've mentioned here, use this instead:

?php
$out = 
preg_replace('/trtdBig.*\{%%%.*\{%bigfoto%\}.*%%%\}.*\/tr/Uis','==REPLACEMENT==',$str);
?

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