Re: [PHP] Function-return-array idea

2008-01-17 Thread Nathan Nobbe
On Jan 16, 2008 6:32 PM, Stijn Leenknegt [EMAIL PROTECTED] wrote:

 Hello

 I've an idea for PHP6. Let's kickoff with an example.

 ?php
 $info = getUserInformation($id); //return an array with all the
 information
 of an user.
 echo $info['naam'];
 ?

 This is nice, but when I want one element of the returned array, I have to
 store the returned array into a variable and then call the variable.
 The next code example is my idea.

 ?php
 echo getUserInformation($id)['naam'];
 ?

 Let's look further then this small example.

 ?php
 echo $object-fetchObjects()[0]-method();
 ?

 This example is more realistic when you use OO. This code style is faster
 for developing applications. This code style is available in Java,
 Javascript, C, C++, Perl, Python, ... So why not in PHP(6)? You can read
 more on my blog


i think this is pretty much a dup of a thread from about a week ago;
http://www.nabble.com/Why-is-some_function()-some_index--invalid-syntax--td14749459.html

-nathan


Re: [PHP] Function-return-array idea

2008-01-17 Thread Eric Butera
On Jan 16, 2008 6:32 PM, Stijn Leenknegt [EMAIL PROTECTED] wrote:
 Hello

 I've an idea for PHP6. Let's kickoff with an example.

 ?php
 $info = getUserInformation($id); //return an array with all the information
 of an user.
 echo $info['naam'];
 ?

 This is nice, but when I want one element of the returned array, I have to
 store the returned array into a variable and then call the variable.
 The next code example is my idea.

 ?php
 echo getUserInformation($id)['naam'];
 ?

 Let's look further then this small example.

 ?php
 echo $object-fetchObjects()[0]-method();
 ?

 This example is more realistic when you use OO. This code style is faster
 for developing applications. This code style is available in Java,
 Javascript, C, C++, Perl, Python, ... So why not in PHP(6)? You can read
 more on my blog.

 http://www.eos-team.org/2007/09/06/php6-function-return-array-idea.html

 I hope for good response and also response from php-dev team.

 Greetings
 Stijn Leenknegt


My reply is a bit pointless as I'd never do/rely on this.  But
nonetheless it was an interesting test.

function testObj() {
$arr = array();
$arr['key1'] = array(1, 2, 3);
$arr['key3'] = array('a','b','c');
return (object)$arr;
}

echo 'pre';

echo Key1: \n;
print_r(testObj()-key1);
echo Key3: \n;
print_r(testObj()-key3);


--- output 
Key1:
Array
(
[0] = 1
[1] = 2
[2] = 3
)
Key3:
Array
(
[0] = a
[1] = b
[2] = c
)

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Re: [PHP] Function-return-array idea

2008-01-17 Thread Jim Lucas

Jim Lucas wrote:
I think this would be an easier/quicker fix for you then requesting that 
the PHP developers re-write a large portion of the way PHP currently works.




Here is the reference that I have been looking for.

http://en.wikipedia.org/wiki/Message_passing

Jim

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Re: [PHP] Function-return-array idea

2008-01-16 Thread Richard Lynch
On Wed, January 16, 2008 5:32 pm, Stijn Leenknegt wrote:
 I've an idea for PHP6. Let's kickoff with an example.

This belongs on php-internals...

 ?php
 echo getUserInformation($id)['naam'];
 ?

where it has already been discussed at length, and, as I recall,
rejected as too obfuscated for the intent of PHP.

I apologize to php-internals for my gross over-simplification of a
zillion posts. :-)

Read the php-internals archives for the gory details.

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Re: [PHP] Function-return-array idea

2008-01-16 Thread Jim Lucas
I think this would be an easier/quicker fix for you then requesting that 
the PHP developers re-write a large portion of the way PHP currently works.



?php

function i($arr, $i) {
return $arr[$i];
}

echo i(getUserInformation($id), 'naam');
#or
echo i($object-fetchObjects(), 0)-method();

?

Stijn Leenknegt wrote:

Hello

I've an idea for PHP6. Let's kickoff with an example.

?php
$info = getUserInformation($id); //return an array with all the information
of an user.
echo $info['naam'];
?

This is nice, but when I want one element of the returned array, I have to
store the returned array into a variable and then call the variable.
The next code example is my idea.

?php
echo getUserInformation($id)['naam'];
?

Let's look further then this small example.

?php
echo $object-fetchObjects()[0]-method();
?

This example is more realistic when you use OO. This code style is faster
for developing applications. This code style is available in Java,
Javascript, C, C++, Perl, Python, ... So why not in PHP(6)? You can read
more on my blog.

http://www.eos-team.org/2007/09/06/php6-function-return-array-idea.html

I hope for good response and also response from php-dev team.

Greetings
Stijn Leenknegt




--
Jim Lucas

   Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them.

Twelfth Night, Act II, Scene V
by William Shakespeare

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Re: [PHP] Function-return-array idea

2008-01-16 Thread Per Jessen
Stijn Leenknegt wrote:

 This is nice, but when I want one element of the returned array, I
 have to store the returned array into a variable and then call the
 variable. The next code example is my idea.
 
 ?php
 echo getUserInformation($id)['naam'];
 ?
 
 Let's look further then this small example.
 
 ?php
 echo $object-fetchObjects()[0]-method();
 ?

Yeah, I like the idea.  I've often used that style out of habit, only to
have to revert to assigning the result to a variable etc. 
I don't know why it isn't supported by PHP, but I suspect it is related
to the type-concept. 


/Per Jessen, Zürich

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Re: [PHP] Function return

2007-11-02 Thread Daniel Brown
 On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:
  TGIF!!

I believe that's Copyright (C) TCompuserve.  Careful you don't get tsued.

-- 
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[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107

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Re: [PHP] Function return

2007-11-02 Thread Nathan Nobbe
On 11/2/07, Stut [EMAIL PROTECTED] wrote:

 Dan Shirah wrote:
  That is correct, the due_date field should only accept a valid date
 format,
  such as MM/DD/.  To bypass the need for a validation check for this
  field I simply set the text field to disabled and supplied the user with
 a
  javascript popup calendar that upon selection populates the date in the
  format I want. :)

 Client-side limits are not an effective defense against dangerous
 inputs. Server-side validation is a must regardless of any client-side
 checking that goes on.


this is an excellent point; consider the scenario where someone posts
directly
to your page,  bypasing the client side checks.  this is a trival technique;
inspect the form attributes; determine the submission url and the submission
method.  look at the name attributes of inputs on the page; and then build a
simple
form that posts those inputs to the same url with the same method.

-nathan


Re: [PHP] Function return

2007-11-02 Thread Stut

Dan Shirah wrote:

That is correct, the due_date field should only accept a valid date format,
such as MM/DD/.  To bypass the need for a validation check for this
field I simply set the text field to disabled and supplied the user with a
javascript popup calendar that upon selection populates the date in the
format I want. :)


Client-side limits are not an effective defense against dangerous 
inputs. Server-side validation is a must regardless of any client-side 
checking that goes on.


-Stut

--
http://stut.net/


On 11/2/07, Nathan Nobbe [EMAIL PROTECTED] wrote:

On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:

Ah, okay.  So I could probably simplfy it more by trimming it from the
start like this??

$due_date = trim($_POST['due_date']);



that works;
i personally prefer to initialize a variable then only set it if the user input 
meets some

conditions; its called white-box validation.

$due_date = '';

if(isset($_POST['due_date']))  !empty($POST['due_date'])) {
$due_date = trim($_POST['due_date']);
}


the more you know about what the contents of due_date are supposed to be, the

stronger you can make the check; for instance here, it sounds like it should be 
a date
so you wouldnt allow, say 'somecrazySting', to pass the validation.

-nathan







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Re: [PHP] Function return

2007-11-02 Thread Nathan Nobbe
On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:

 Ah, okay.  So I could probably simplfy it more by trimming it from the
 start like this??

 $due_date = trim($_POST['due_date']);



that works;
i personally prefer to initialize a variable then only set it if the
user input meets some
conditions; its called white-box validation.

$due_date = '';

if(isset($_POST['due_date']))  !empty($POST['due_date'])) {
$due_date = trim($_POST['due_date']);
}

the more you know about what the contents of due_date are supposed to be, the
stronger you can make the check; for instance here, it sounds like it
should be a date
so you wouldnt allow, say 'somecrazySting', to pass the validation.

-nathan


Re: [PHP] Function return

2007-11-02 Thread Nathan Nobbe
On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:

 Okay, so instead I should probably use:

 if($due_date != )
 $insert2.=, due_date='$due_date';

 Instead of using empty()


using emtpy is fine; just store the results of trim in a temporary variable:

$trimmed = trim($due_date);
if(!empty($trimmed)) {

 $insert2 .= , due_date='$due_date';

}

-nathan


Re: [PHP] Function return

2007-11-02 Thread Dan Shirah
Okay, so instead I should probably use:

if($due_date != )
$insert2.=, due_date='$due_date';

Instead of using empty()


On 11/2/07, Nathan Nobbe [EMAIL PROTECTED] wrote:

 On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:
 
  TGIF!!
 
  I have an insert statement that checks to see if a condition is met.  If
  it
  is, then it adds that value to the insert statement.  However, when I
  try to
  run it I get the error: Can't use function return value in write context
 
 
  Below is a sample of what I am using which gives me the error(The error
  occurs while trying to insert the due_date)
 
  $insert2 = INSERT INTO misc_service_payment_request SET;
 if(empty($_POST['max_id'])) {
$insert2.= id = scope_identity(),;
} else {
$insert2.= id = '$max_id',;
}
 if(!empty(trim('$due_date'))
 $insert2.=, due_date='$due_date';
  mssql_query($insert2) or die (Query failed: br
  /.mssql_get_last_message());
 
  Any ideas?
 


 dont call trim() as an argument to empty(); it doesnt work that way.
 see the manual http://us.php.net/manual/en/function.empty.php:
 Note: empty() only checks variables as anything else will result in a
 parse error. In other words, the following will not work:
 empty(trim($name)).

 -nathan



Re: [PHP] Function return

2007-11-02 Thread Nathan Nobbe
On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:

 TGIF!!

 I have an insert statement that checks to see if a condition is met.  If
 it
 is, then it adds that value to the insert statement.  However, when I try
 to
 run it I get the error: Can't use function return value in write context

 Below is a sample of what I am using which gives me the error(The error
 occurs while trying to insert the due_date)

 $insert2 = INSERT INTO misc_service_payment_request SET;
if(empty($_POST['max_id'])) {
   $insert2.= id = scope_identity(),;
   } else {
   $insert2.= id = '$max_id',;
   }
if(!empty(trim('$due_date'))
$insert2.=, due_date='$due_date';
 mssql_query($insert2) or die (Query failed: br
 /.mssql_get_last_message());

 Any ideas?



dont call trim() as an argument to empty(); it doesnt work that way.
see the manual http://us.php.net/manual/en/function.empty.php:
Note: empty() only checks variables as anything else will result in a parse
error. In other words, the following will not work: empty(trim($name)).

-nathan


Re: [PHP] Function return

2007-11-02 Thread Dan Shirah
Ah, okay.  So I could probably simplfy it more by trimming it from the start
like this??

$due_date = trim($_POST['due_date']);


On 11/2/07, Nathan Nobbe [EMAIL PROTECTED] wrote:

 On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:
 
  Okay, so instead I should probably use:
 
  if($due_date != )
  $insert2.=, due_date='$due_date';
 
  Instead of using empty()
 


 using emtpy is fine; just store the results of trim in a temporary variable:

 $trimmed = trim($due_date);
 if(!empty($trimmed)) {

  $insert2 .= , due_date='$due_date';

 }

 -nathan






Re: [PHP] Function return

2007-11-02 Thread Dan Shirah
That is correct, the due_date field should only accept a valid date format,
such as MM/DD/.  To bypass the need for a validation check for this
field I simply set the text field to disabled and supplied the user with a
javascript popup calendar that upon selection populates the date in the
format I want. :)

On 11/2/07, Nathan Nobbe [EMAIL PROTECTED] wrote:

 On 11/2/07, Dan Shirah [EMAIL PROTECTED] wrote:
 
  Ah, okay.  So I could probably simplfy it more by trimming it from the
  start like this??
 
  $due_date = trim($_POST['due_date']);
 


 that works;
 i personally prefer to initialize a variable then only set it if the user 
 input meets some

 conditions; its called white-box validation.

 $due_date = '';

 if(isset($_POST['due_date']))  !empty($POST['due_date'])) {
 $due_date = trim($_POST['due_date']);
 }


 the more you know about what the contents of due_date are supposed to be, the

 stronger you can make the check; for instance here, it sounds like it should 
 be a date
 so you wouldnt allow, say 'somecrazySting', to pass the validation.

 -nathan





Re: [PHP] Function return

2007-11-02 Thread Dan
I know that while you should be doing proper validation on the server side 
and everything, you could somewhat diminish the risk of someone building 
their own form and just posting.  If you were to check the referring site 
which made the post then you could be pretty sure someone didn't make their 
own form.  Although this too is insecure, since all you need is a Firefox 
extension, firebug or grease monkey which let you execute JavaScript could 
let you change the page however you want while it's live, the refer would be 
proper, etc.  What I'm really saying is there is NO secure way to validate 
client side, none, absolutely none.


Check that the date coming in is a valid date then create a date object with 
it, that way even if they somehow do slip past your date validation then the 
object just won't be created correctly.


There's lots to validate.

- Dan

Nathan Nobbe [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]

On 11/2/07, Stut [EMAIL PROTECTED] wrote:


Dan Shirah wrote:
 That is correct, the due_date field should only accept a valid date
format,
 such as MM/DD/.  To bypass the need for a validation check for this
 field I simply set the text field to disabled and supplied the user 
 with

a
 javascript popup calendar that upon selection populates the date in the
 format I want. :)

Client-side limits are not an effective defense against dangerous
inputs. Server-side validation is a must regardless of any client-side
checking that goes on.



this is an excellent point; consider the scenario where someone posts
directly
to your page,  bypasing the client side checks.  this is a trival 
technique;
inspect the form attributes; determine the submission url and the 
submission
method.  look at the name attributes of inputs on the page; and then build 
a

simple
form that posts those inputs to the same url with the same method.

-nathan



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RE: [PHP] Function: return multple values

2002-09-23 Thread Jon Haworth

Hi Faisal,

 Is it possible to return multiple values in a function.
 For instance, i want to do something like this:
 
 function calculate_money($sum)
 {
   // some hanky panky calculations
   return $type;
   return $amount;
 }

You have to return the values in an array, and use list() to break them up.
Try this:

function calculate_money($sum)
{
  // do stuff
  return array($type, $amount);
}

list($type, $amount) = calculate_money($whatever);

Cheers
Jon



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Re: [PHP] function return

2002-05-28 Thread RIVES Sergio

Hi,

I don't know if there is an easier way to do this but why don't you concatenate
the two values to be returned and then split the returned value ?
ex :
function myFunction($some_vars)
{
 $max=count($some_vars);
 $some_value=($max/2);
$result = $some_value.;.$max;
 return $result;
}
$resultado = myFunction($some_other_name_vars);
list($var1,$var2) = split(;,$resultado);

I hope it helps.

SR




$var1=should be the value of  $some_value
$var2=should be the value of $max

W. Enserink a écrit :

 Hi all,

 I have a Q about functions. My function should return 2 values. What syntax
 should I use and how do I call these values outside the function? Are these
 values returned as en array or something?

 this is what I have now,
 -
 function myFunction($some_vars)
 {
  $max=count($some_vars);
  $some_value=($max/2);
  return($some_value  $max);
 }

 $var1=should be the value of  $some_value
 $var2=should be the value of $max

 thx. Wilbert

 -
 Pas de Deux
 Van Mierisstraat 25
 2526 NM Den Haag
 tel 070 4450855
 fax 070 4450852
 http://www.pdd.nl
 [EMAIL PROTECTED]
 -

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RE: [PHP] function return

2002-05-28 Thread David Freeman

   I have a Q about functions. My function should return 2 
  values. What 
   syntax should I use and how do I call these values outside the 
   function? Are these values returned as en array or something?

  I don't know if there is an easier way to do this but why 
  don't you concatenate the two values to be returned and then 
  split the returned value ? ex : function 
  myFunction($some_vars) {  $max=count($some_vars);  

Personally, I'd put both values to be returned into an array and then
return the array.

CYA, Dave




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RE: [PHP] function return

2002-05-28 Thread Rudolf Visagie

Hi,

function myFunction($some_vars, $max, $some_value)
{
 $max=count($some_vars);
 $some_value=($max/2);
 //return true;
}

Rudolf Visagie
Principal Software Developer
Digital Healthcare Solutions
mailto:[EMAIL PROTECTED]
Tel: + 27 011 2655478
Cell: + 27 82 895 1598
 

-Original Message-
From: W. Enserink [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, May 28, 2002 10:02 AM
To: [EMAIL PROTECTED]
Subject: [PHP] function return


Hi all,


I have a Q about functions. My function should return 2 values. What syntax
should I use and how do I call these values outside the function? Are these
values returned as en array or something?


this is what I have now,
-
function myFunction($some_vars)
{
 $max=count($some_vars);
 $some_value=($max/2);
 return($some_value  $max);
}

$var1=should be the value of  $some_value
$var2=should be the value of $max


thx. Wilbert

- 
Pas de Deux 
Van Mierisstraat 25 
2526 NM Den Haag 
tel 070 4450855 
fax 070 4450852 
http://www.pdd.nl 
[EMAIL PROTECTED] 
-

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Re: [PHP] function return

2002-05-28 Thread 1LT John W. Holmes

Return an array

function whatever($var1, $var2)
{
  // do whatever
  $ret[0] = $var1 + $var2;
  $ret[1] = $var1 - $var2;
  $ret['something'] = ($var1/$var2) * 100;
  return $ret;
}

$value = whatever(5,4);

echo $value[0];
echo $value['something'];

---John Holmes...

- Original Message -
From: W. Enserink [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, May 28, 2002 4:01 AM
Subject: [PHP] function return


 Hi all,


 I have a Q about functions. My function should return 2 values. What
syntax
 should I use and how do I call these values outside the function? Are
these
 values returned as en array or something?


 this is what I have now,
 -
 function myFunction($some_vars)
 {
  $max=count($some_vars);
  $some_value=($max/2);
  return($some_value  $max);
 }

 $var1=should be the value of  $some_value
 $var2=should be the value of $max


 thx. Wilbert

 -
 Pas de Deux
 Van Mierisstraat 25
 2526 NM Den Haag
 tel 070 4450855
 fax 070 4450852
 http://www.pdd.nl
 [EMAIL PROTECTED]
 -

 --
 PHP General Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php



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Re: [PHP] function return

2002-05-28 Thread Miguel Cruz

On Tue, 28 May 2002, W. Enserink wrote:
 I have a Q about functions. My function should return 2 values. What
 syntax should I use and how do I call these values outside the function?
 Are these values returned as en array or something?
 
 
 this is what I have now,
 -
 function myFunction($some_vars)
 {
  $max=count($some_vars);
  $some_value=($max/2);
  return($some_value  $max);
 }

  function myFunction ($some_vars)
  {
$max = count($some_vars);
$some_value = ($max / 2);
return array($some_value, $max);
  }

  list($x, $y) = myFunction($_SERVER);
  echo returned $x and $y;

miguel


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Re: [PHP] function return

2001-04-06 Thread Adrian Murphy

should work(works for me).probly something simple.
?php
function conn(){

$db = mysql_pconnect("localhost", "" ,"");
mysql_select_db("database",$db);
return $db;
}


 $db = conn();
 $result= mysql_query("select * from table",$db);

while($myrow=MySQL_fetch_array($result))
{ 
$thing=$myrow["item"]; 
echo "$thing br
"; 
} 


?
- Original Message - 
From: Kurth Bemis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, April 06, 2001 4:10 PM
Subject: [PHP] function return


 
 i'm trying to make all my include files into functions for 
 manageability.  I have one function that i'd like to get to work.heres 
 teh code..
 
 ?php
 $db = mysql_pconnect("localhost", "user" ,"pass");
 mysql_select_db("database",$db);
 ?
 
 i had it in a function and had the function return $db.but didn't 
 work.any ideas?
 
 ~kurth
 
 
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 For additional commands, e-mail: [EMAIL PROTECTED]
 To contact the list administrators, e-mail: [EMAIL PROTECTED]
 



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Re: [PHP] function return

2001-04-06 Thread Plutarck

I usually declare $db as global in the function, so I can just execute the
function and continue with my querys.


--
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Should be working on something...
...but forgot what it was.


"Kurth Bemis" [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...

 i'm trying to make all my include files into functions for
 manageability.  I have one function that i'd like to get to work.heres
 teh code..

 ?php
 $db = mysql_pconnect("localhost", "user" ,"pass");
 mysql_select_db("database",$db);
 ?

 i had it in a function and had the function return $db.but didn't
 work.any ideas?

 ~kurth


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PHP General Mailing List (http://www.php.net/)
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