Hi
I'm a newbie to php and I'm using
require_once($_SERVER['DOCUMENT_ROOT']./includes/class.announcement.php);
to import pages in php. This works fine on a windows environment. However
when I move this application to a linux environment the files dont get
imported properly. This is
tbt wrote:
Hi
I'm a newbie to php and I'm using
require_once($_SERVER['DOCUMENT_ROOT']./includes/class.announcement.php);
to import pages in php. This works fine on a windows environment. However
when I move this application to a linux environment the files dont get
imported properly.
Hi, at first, read that bug report : http://bugs.php.net/bug.php?id=42065
I would like to say that it doesn't seem to be fixed as it's said.
When I execute the bug 42065 test case, it still fails.
In reality, another code brought me to that bug, please consider this :
?php
class a
{
public
Julien Pauli wrote:
Hi, at first, read that bug report : http://bugs.php.net/bug.php?id=42065
I would like to say that it doesn't seem to be fixed as it's said.
When I execute the bug 42065 test case, it still fails.
In reality, another code brought me to that bug, please consider this :
Wow, all right ; that's why casting to (array) before passing the variable ,
thus making a copy of it, works.
Thanks for that short but effective answer ;-)
However, except in the comments, this is not said in the original doc.
It should be written
ArrayObject ArrayObject::__construct ( mixed
Hello James,
in future we will implement the script with cron, i've already talk to
the support server guys... and i think this would be the best pratice...
But for now i was wondering if there's a workaround... because in the
moment my boss tell me to not change anything that could delay the
Hi everyone,
I'm having a hard time dealing with an error that appeared overnight
in one of my PHP script:
Fatal error: Undefined class constant 'self::TYPE_HIDDEN' in
/#/classes/framework/HTML/HTMLForm.php on line 120
HTMLForm.php snippet:
.
// Creates the HTMLFormFields
On Wed, 19 Sep 2007 15:56:22 +0300, Puiu Hrenciuc [EMAIL PROTECTED] wrote:
Hi everyone,
I'm having a hard time dealing with an error that appeared overnight
in one of my PHP script:
Fatal error: Undefined class constant 'self::TYPE_HIDDEN' in
/#/classes/framework/HTML/HTMLForm.php
Hello all,
I am having a problem with trying to display a set amount of records from my
result.
I have verified that the correct values for my variables are being passed to
the query.
The calculation for the records that should be displayed per page is
correct.
The total number of records
Here are the content for all used variables:
$_this-Name: (string) FilterForm
$_column:
StringColumn Object
(
[Table] = Roles
[Name] = RoleName
[Function] = like
[Type] = 4
[Min] =
[Max] =
[RegEx] =
[AllowedValues] = Array
(
)
[IsValid] =
On Wed, 19 Sep 2007 10:05:40 -0400, Dan Shirah [EMAIL PROTECTED]
wrote:
Hello all,
I am having a problem with trying to display a set amount of records from
my
result.
I have verified that the correct values for my variables are being passed
to
the query.
The calculation for the records
Becase I am using MSSQL not MYSQL. MSSQL does not have anything easy to use
like LIMIT in MYSQL. So, to achieve the same functionality you have to use
the subqueries.
Having the largest number as the inner most subquery value tells the query
to retrieve the records that are equal to that number
On Wed, 19 Sep 2007 10:23:58 -0400, Dan Shirah [EMAIL PROTECTED]
wrote:
Becase I am using MSSQL not MYSQL. MSSQL does not have anything easy to
use
like LIMIT in MYSQL. So, to achieve the same functionality you have to
use
the subqueries.
Having the largest number as the inner most
On Wed, 19 Sep 2007 17:13:02 +0300, Puiu Hrenciuc [EMAIL PROTECTED] wrote:
Here are the content for all used variables:
$_this-Name: (string) FilterForm
$_column:
StringColumn Object
(
[Table] = Roles
[Name] = RoleName
[Function] = like
[Type] = 4
[Min] =
tbt wrote:
Hi
I'm a newbie to php and I'm using
require_once($_SERVER['DOCUMENT_ROOT']./includes/class.announcement.php);
to import pages in php. This works fine on a windows environment. However
when I move this application to a linux environment the files dont get
imported properly.
Here is the HTMLFormField constructor, it is pretty simple :
/**
* Creates a new HTMLFormField object
*
* @param string $_formName Name of the form this field belongs to
* @param Column $_column Record object this column derives from
* @param int
Actually, the query you mentioned will select records 11-20 because it
counts 10 records backwards starting with record 20.
print_r($result) onyl returns Resource id #3 and not the actual data.
On 9/19/07, T. Lensselink [EMAIL PROTECTED] wrote:
On Wed, 19 Sep 2007 10:23:58 -0400, Dan Shirah
That gives me an array of the 10 records that are being displayed every
single time.
It's like even though the variables in my query are changing correctly from
0,10 to 10,20; the records being displayed are not updating.
The URL is reflecting the changes from page 1 to 2 correctly also.
On
I have my query echoing out. Upon initial display it looks like this:
SELECT DISTINCT * FROM ( SELECT TOP 10 Value1, Value2 FROM ( SELECT TOP 10
Value1, Value2 FROM my_table WHERE my_table.column = 'P' ) as newtbl order
by PKEY desc ) as newtbl2 order by PKEY asc
And then when I click on the
I found the easiest solution is to use the 'Pager' package in pear
http://pear.php.net/package/Pager
Ben
On Wednesday 19 Sep 2007 15:45, T.Lensselink wrote:
On Wed, 19 Sep 2007 10:23:58 -0400, Dan Shirah [EMAIL PROTECTED]
wrote:
Becase I am using MSSQL not MYSQL. MSSQL does not have anything
On Wed, 19 Sep 2007 10:48:20 -0400, Dan Shirah [EMAIL PROTECTED]
wrote:
Actually, the query you mentioned will select records 11-20 because it
counts 10 records backwards starting with record 20.
print_r($result) onyl returns Resource id #3 and not the actual data.
On 9/19/07, T.
2007. 09. 19, szerda keltezéssel 11.08-kor Dan Shirah ezt írta:
I have my query echoing out. Upon initial display it looks like this:
SELECT DISTINCT * FROM ( SELECT TOP 10 Value1, Value2 FROM ( SELECT TOP 10
Value1, Value2 FROM my_table WHERE my_table.column = 'P' ) as newtbl order
by PKEY
Dan Shirah wrote:
Hello all,
I am having a problem with trying to display a set amount of records from my
result.
I have verified that the correct values for my variables are being passed to
the query.
The calculation for the records that should be displayed per page is
correct.
The total
At 11:52 AM -0400 9/17/07, brian wrote:
tedd wrote:
Richard Kurth wrote:
$Campaign_array| = array('0','1','3','5','8','15','25');|
I know that I can find the next recored in a array using next.
What I do not understand is if I know the last number was say 5
how do I tell the script that
Whenever the query has the NOT IN included in it, I get the following error:
Warning: mssql_query()
[function.mssql-queryhttp://develop1/credit%20card%20processing/Process/function.mssql-query]:
message: Incorrect syntax near the keyword 'as'. (severity 15)
On 9/19/07, Jim Lucas [EMAIL
Dan Shirah wrote:
Whenever the query has the NOT IN included in it, I get the following error:
Warning: mssql_query()
[function.mssql-queryhttp://develop1/credit%20card%20processing/Process/function.mssql-query]:
message: Incorrect syntax near the keyword 'as'. (severity 15)
?php
# Get page
Awesome.
I just had to modify the outter query:
$SQL = SELECT TOP {$max_results}
Value1, Value2
FROMmy_table
WHERE credit_card_id NOT IN (
To read:
$SQL = SELECT TOP {$max_results}
Value1, Value2
FROMmy_table
WHERE
Dan Shirah wrote:
Awesome.
I just had to modify the outter query:
$SQL = SELECT TOP {$max_results}
Value1, Value2
FROMmy_table
WHERE credit_card_id NOT IN (
To read:
$SQL = SELECT TOP {$max_results}
Value1, Value2
FROMmy_table
Hi,
I have 2 problems.
First: When an user type a number that have comma the numbers after of
comma doesnt safe.
example:
the user wants save the number:
10,85
I dont know but the symfony just save the number 10. The 85 is ignored.
How i fix it ?
Second problem:
i'm trying format
tedd wrote:
At 11:52 AM -0400 9/17/07, brian wrote:
tedd wrote:
Richard Kurth wrote:
$Campaign_array| = array('0','1','3','5','8','15','25');|
I know that I can find the next recored in a array using next. What
I do not understand is if I know the last number was say 5 how do I
tell the
I am new to PHP and to email lists so I apologize in advance.
What I am trying to do is to take a password from user input, check
it to make sure it is == to something, say burgers
My problem is, I do not know how to make the Else statement...
How do I
What do I have to do to get off this list. Murder someone?
Please take me off the list as I have already tried to unsubscribe several
times.
The email is registered under [EMAIL PROTECTED]
-Original Message-
From: Jim Lucas [mailto:[EMAIL PROTECTED]
Sent: Thursday, September 20, 2007
Andrew Wilson wrote:
What do I have to do to get off this list. Murder someone?
Please take me off the list as I have already tried to unsubscribe several
times.
The email is registered under [EMAIL PROTECTED]
-Original Message-
From: Jim Lucas [mailto:[EMAIL PROTECTED]
Sent:
Andrew Prostko wrote:
I am new to PHP and to email lists so I apologize in advance.
What I am trying to do is to take a password from user input, check
it to make sure it is == to something, say “burgers”
My problem is, I do not know how to make the Else
On Wednesday 19 September 2007 15:50:08 Andrew Prostko wrote:
My problem is, I do not know how to make the Else statement...
How do I get it to open a new url?
I want it IF yes open this page, else open this page
Andrew,
try the header() function:
?php
if ($_POST['pw'] != $password)
Julien Pauli wrote:
Wow, all right ; that's why casting to (array) before passing the
variable , thus making a copy of it, works.
Thanks for that short but effective answer ;-)
However, except in the comments, this is not said in the original doc.
It should be written
ArrayObject
Hi Arvid,
thank you very much for your remark. It is useful for me.
===
On Fri, 14 Sep 2007 12:01:40 +0300
Arvids Godjuks [EMAIL PROTECTED] wrote:
Don't use SQL_CALC_FOUND ROWS on simple queries, when you have to run a
simple query on one or two (with join) tables with a simple WHERE.
Dear Brian,
My problem is solved. thank you very much for your help.
===
On Wed, 12 Sep 2007 14:04:11 -0400
brian [EMAIL PROTECTED] wrote:
Patrik Hasibuan wrote:
Dear my friends...
I am trying to display the content of a table. Each page must content
only 5 records maximum. Each page
Dear mike,
your thread solved my problem.
I really appreciate your help.
Thank you very much.
On Thu, 13 Sep 2007 14:49:29 -0700
mike [EMAIL PROTECTED] wrote:
warning: this is VERY UGLY CODE. i wrote it 3-4 years ago now i think
and it just keeps working.
you call it this way:
#
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