the failure of this code.
I'd highly appreciate it if anyone could drop me a line with any advice.
Many thanks,
Wei Wang
http://www.awtrey.com/support/dbeweb/ for more information
1.1 - Oct. 20, 1999 - changed the SQL statement that reads data
back out of the database to reve
some php tutorials but I think I must've missed a very fundamental point
that led to the failure of this code.
I'd highly appreciate it if anyone could drop me a line with any advice.
Many thanks,
Wei Wang
http://www.awtrey.com/support/dbeweb/ for more information
1.1 - Oct. 20
hi, all,
I have a piece of code stuck at the point of "if (($REQUEST_METHOD=='post'))".
"var_dump($REQUEST_METHOD);" shows that the variable doesn't exist.
Since I grabbed the code from a 2001 update, is there any chance that this is already
obsolete? I checked the documentation but didn't find
hi,
This may sound very newbie. But since html comment uses which doesn't comment
out the
php code. And the php comment /**/ // apparently doesn't work on html. So how do I
comment out
a chunk of html/php mixed code?
Many thanks,
Wei Wang
nd be stuck at this one.
Any advice would be greatly appreciated.
Wei Wang
Untitled Document
Simple Form Example
First Name:
Last Name:
";
show_form($first,$last);
}
else {
echo "Thank you, $first $last";
}
}
?>
AIL PROTECTED]>
Sent: Tuesday, September 16, 2003 1:22 AM
Subject: Re: [PHP] simple online form stuck at !isset($first) condition
> * Thus wrote Wei Wang ([EMAIL PROTECTED]):
> >
> >
> >
> >
> note the method --
>
> > First Name:
> &
I am not sure if this is the right place to ask this naive question.
I got a simple form addform.html and add.php look like the following.
But everytime I got empty value from firstname and lastname. It seems like
the input value in the html page was not passed on to the php variable $firstname i
Do you mind telling me where this php.ini is?
And I tried the second attempt like this:
$query = "INSERT INTO friends (id, firstname, surname) values
(nextval('friends_id_seq'), $_POST['firstname'], $_POST['surname'])";
which returns error:
Parse error: parse error, unexpected T_ENCAPSED_AND_
>
> Create a php script containing just . That page will tell
> you where your php.ini is (or should be).
>
it told me it's in php/lib, but it's not there.
>
> Try this...
>
> $query = "INSERT INTO friends (id, firstname, surname) values
> (nextval('friends_id_seq'), ".$_POST['firstname'].", "
Sorry. When I input "Andras" as firstname in the form, ...
On Sat, 1 Jun 2002 17:22:02 +0100
[EMAIL PROTECTED] (Wei Wang) wrote:
> >
> > Create a php script containing just . That page will tell
> > you where your php.ini is (or should be).
> >
> it
Is there anything I should do to make the php.ini come into effect? I did
put the register_global = On but still got empty values.
And my $_POST version is like this:
On Sat, 1 Jun 2002 17:08:11 +0100
[EMAIL PROTECTED] (Stuart Dallas) wrote:
> On Saturday, June 1, 2002 at 5:00:18 PM, you w
Sorry.
I restared apache and php.ini came into effect.
On Sat, 1 Jun 2002 17:29:13 +0100
[EMAIL PROTECTED] (Stuart Dallas) wrote:
> On Saturday, June 1, 2002 at 5:22:02 PM, you wrote:
> >> Create a php script containing just . That page will tell
> >> you where your php.ini is (or should be).
Changed the query and get this error when input dave as firstname:
ERRORERROR: Attribute 'dave' not found
add2.php is:
addform.php is:
First Name :
Surname :
On Sat, 1 Jun 2002 17:44:57 +0100
[EMAIL PROTECTED] (Stuart Dallas) wrote:
> On Saturday, June 1, 2002 at 5:35:03 P
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