Re: [PHP] Help with CHdir

2002-10-02 Thread Rasmus Lerdorf
Your code makes no sense and the error message is telling you exactly what you did wrong. opendir() returns a directory handle to be passed to readdir(). Calling chdir() on a directory handle makes no sense. You want to chdir to the same string that you passed to opendir() -Rasmus On Wed, 2 O

[PHP] Help with CHdir

2002-10-02 Thread Nokar
I get this error from php when i execute this code can you help me ;) Warning: chdir() expects parameter 1 to be string, resource given in C:\\read.php on line 146 145 echo "Attachment :"; 146 $rep = opendir("C:\\xxx\\Attach\\$id\\"); 147 chdir($rep); 148 while ($zone = readdir($rep)) 149 { 1