1) Why are you using JavaScript to open the window? HTML will do just fine
() and will work on all browsers as well as search
engines.
2) Your sample page has some password on it and I can't decipher from your
message what's actually going on, so without seeing it in action, I'm
stumped.
miguel
On Thu, 6 Jun 2002, Igor Portnoy wrote:
> I am having hard time passing the variable to the next page. May be you
> can help me. Let me explain:
>
>
>
> I am using mySQL database to store information about images (ID, name,
> author, description, etc). I am pulling some of the information to
> create this (look at the example here:
> http://www.gibsonusa.com/test/page/index.php) Now, I want a new window
> appear when user clicks on the image. I have achieved it with the
> following script:
>
>
>
> echo "";
>
> echo" function pop1() {";
>
> echo" window.open(\"info.php?prod_id=$result[0]\"); }"; \\ $result[0]
> is variable that stores id of the image in database
>
> echo "";
>
>
>
> I am calling this function in the following manner: echo" onclick=\"pop1();\"";
>
>
>
> You can see the result if you click on the image. The new page opens
> up, BUT the id (product_id in this case) value is not passed to the next
> page correctly. If you click on the first or second image on the first
> page it shows that the ID is the same for both of them. However if you
> look at the source code you can see that the ids are assigned correctly.
> The same thing happens if you click on any image that says "no image
> available" (I am using different script to generate those). It seems
> that the script picks up and stores in the memory the value of an ID of
> the last image generated with the script (I don't know if that make
> sense).
>
>
>
> Oh, by the way the contents of info.php that I am calling in the script
> above are as following:
>
>
> $myid = $_GET['prod_id'];
>
> echo" Product ID: $myid";
>
> ?>
>
>
>
> What am I doing wrong? Can you help?
>
>
>
> Thank you.
>
> Sorry for lengthy e-mail.
>
>
>
>
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