Well, I guess what you can do is embed the PHP within the table cell and
call an if statement. Like this...
table
tr
td
// if the user is online, then display the online image
?php
If ($user = online) {
?
img src=online.gif
// else if the user is offline, display the offline image
?php
}
elseif ($user = offline) {
?
img src=offline.gif
// This is just some error checking
?php
} else {
echo $some_error;
?
?php
}
?
/td
/tr
/table
Try that, it's simple and short, and it works within the table cell you
would specify. Of course, you may have to alter the code and the code
structure a bit to fit your scheme. If you're new to PHP then stripping away
the comments I placed for you might help to make the code look more clear to
you. Good luck...
Navid Yar
-Original Message-
From: Johan Vikerskog (ECS) [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 12, 2001 2:30 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Silly table and php question.
Hi all.
I know this is a silly question but i dont know how to do it so thats why i
am asking.
Be gentle towards me. Im just a stupid swede! ;-)
statement:
I have a table cell in my upper right corner.
I have a small php script which checks wheter my user is online or not. If
the user is i want to update that cell
with an gif that i made that says online.
How do i update just that cell? Is there a special function in PHP to do
that?
I know the question is silly but bare with me.
//Johan
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