eat pasta type fasta wrote:
> $result = mysql_query("SELECT some_id, some_description, some_feature
> FROM '$pop-up1' WHERE some_description LIKE '%$texfield%' AND
> some_feature LIKE '%$pop-up2'");
have this query echoed to video and then cut it and paste it to mysql
terminal. Most probably
On Thursday 04 July 2002 12:32, eat pasta type fasta wrote:
> $result = mysql_query("SELECT some_id, some_description, some_feature
> FROM '$pop-up1' WHERE some_description LIKE '%$texfield%' AND
> some_feature LIKE '%$pop-up2'");
Again:
echo $result;
--
Jason Wong -> Gremlins Associates -> w
I already got some replies for this but it wasn't it, here is the problem:
I have a simple form which queries the database based on 2 pop-up menu
choices and keywords entered by the user,
it passes on the variables as follows:
pop-up1=choice1, pop-up2=choice2, textfield=user specified data
the
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