[PHP] Variable Question
I am trying to assign variables from an array into variables. This is
following a database query. Right now they are in an array:
$row[‘word_1’]
$row[‘word_2’]
$row[‘word_3’]
...
$row[‘word_25’]
I am trying to use this while look to assign them to variables:
$word_1
$word_2
$word_3
...
$word_25
This is the WHILE loop:
$i = 1;
while ( $i = 25 ) {
${'word_'.$i} = stripslashes( eval (echo $row['word_$i']) );
++$i;
}
What is confusing me is I don’t know how to represent the array variable.
The specific error message I am receiving is:
Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting
T_STRING or T_VARIABLE or T_NUM_STRING
Can anyone see what I have done wrong and help me correct it? Thank you. Ron
Ron Piggott
www.TheVerseOfTheDay.info
Re: [PHP] Variable Question
On 19 Apr 2012, at 15:46, Ron Piggott wrote:
I am trying to assign variables from an array into variables. This is
following a database query. Right now they are in an array:
$row[‘word_1’]
$row[‘word_2’]
$row[‘word_3’]
...
$row[‘word_25’]
Why those indices? Why isn't it just a numerically indexed array?
I am trying to use this while look to assign them to variables:
$word_1
$word_2
$word_3
...
$word_25
The first question that comes to mind is why the heck you would want to do such
a thing?
${'word_'.$i} = stripslashes( eval (echo $row['word_$i']) );
Eww, nasty. Why the eval? Why not just stripslashes($row['word_'.$i])?
Variable variables have their uses, but this seems to be one of those cases
where you're trying to get the square peg through the triangular hole. Take a
step back and give us some more context.
-Stuart
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Re: [PHP] Variable Question
I am trying to use this while look to assign them to variables: $word_1 $word_2 $word_3 ... $word_25 This should work for you: http://us3.php.net/manual/en/function.extract.php thnx, Christoph -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Variable Question
On 04/19/2012 09:55 AM, Christoph Boget wrote:
I am trying to use this while look to assign them to variables:
$word_1
$word_2
$word_3
...
$word_25
This should work for you:
http://us3.php.net/manual/en/function.extract.php
thnx,
Christoph
Yes and you can use array_map('stripslashes', $row) prior. However I
would just use the $row array as most people do instead of extracting.
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RE: [PHP] Variable question
-Original Message-
From: Ron Piggott [mailto:ron@actsministries.org]
Sent: 01 October 2011 18:59
To: php-general@lists.php.net
Subject: [PHP] Variable question
If $correct_answer has a value of 3 what is the correct syntax
needed to use echo to display the value of $trivia_answer_3?
I know this is incorrect, but along the lines of what I am wanting
to do:
echo $trivia_answer_$correct_answer;
Just for the record, one more way of doing what you asked for is:
echo ${trivia_answer_$correct_answer};
But I totally agree with all the suggestions to use an array instead.
Cheers!
Mike
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[PHP] Variable question
If $correct_answer has a value of 3 what is the correct syntax needed to use echo to display the value of $trivia_answer_3? I know this is incorrect, but along the lines of what I am wanting to do: echo $trivia_answer_$correct_answer; $trivia_answer_1 = “1,000”; $trivia_answer_2 = “1,250”; $trivia_answer_3 = “2,500”; $trivia_answer_4 = “5,000”; Ron www.TheVerseOfTheDay.info
Re: [PHP] Variable question
On Oct 1, 2011, at 1:59 PM, Ron Piggott wrote:
If $correct_answer has a value of 3 what is the correct syntax needed to use
echo to display the value of $trivia_answer_3?
I know this is incorrect, but along the lines of what I am wanting to do:
echo $trivia_answer_$correct_answer;
$trivia_answer_1 = “1,000”;
$trivia_answer_2 = “1,250”;
$trivia_answer_3 = “2,500”;
$trivia_answer_4 = “5,000”;
Ron
www.TheVerseOfTheDay.info
Best bet would to toss this into either an object or array for simplification,
otherwise that type of syntax would need the use of eval.
example: eval('echo $trivia_answer_'.$correct_answer.';');
best bet would be to..
$trivia_answer = array();
$trivia_answer[1] = 1000;
$trivia_answer[2] = 1250;
$trivia_answer[3] = 2500;
$trivia_answer[4] = 5000;
echo $trivia_answer[$correct_answer];
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Re: [PHP] Variable question
On Sat, Oct 1, 2011 at 10:59 AM, Ron Piggott ron@actsministries.orgwrote: If $correct_answer has a value of 3 what is the correct syntax needed to use echo to display the value of $trivia_answer_3? You can use variable variables [1] to access the variable by building its name in a string: $name = 'trivia_answer_' . $correct_answer; echo $$name; Peace, David [1] http://php.net/manual/en/language.variables.variable.php
Re: [PHP] Variable question
On 11-10-01 02:03 PM, Mike Mackintosh wrote:
On Oct 1, 2011, at 1:59 PM, Ron Piggott wrote:
If $correct_answer has a value of 3 what is the correct syntax needed to use
echo to display the value of $trivia_answer_3?
I know this is incorrect, but along the lines of what I am wanting to do:
echo $trivia_answer_$correct_answer;
$trivia_answer_1 = “1,000”;
$trivia_answer_2 = “1,250”;
$trivia_answer_3 = “2,500”;
$trivia_answer_4 = “5,000”;
Ron
www.TheVerseOfTheDay.info
Best bet would to toss this into either an object or array for simplification,
otherwise that type of syntax would need the use of eval.
example: eval('echo $trivia_answer_'.$correct_answer.';');
best bet would be to..
$trivia_answer = array();
$trivia_answer[1] = 1000;
$trivia_answer[2] = 1250;
$trivia_answer[3] = 2500;
$trivia_answer[4] = 5000;
echo $trivia_answer[$correct_answer];
Agreed the OP's value list isn't optimal, but eval is not needed to
address the solution:
?php
$trivia_answer_1 = 1,000;
$trivia_answer_2 = 1,250;
$trivia_answer_3 = 2,500;
$trivia_answer_4 = 5,000;
$answer
= isset( ${'trivia_answer_'.$correct_answer} )
? ${'trivia_answer_'.$correct_answer}
: 'Not found';
echo $answer.\n;
?
Cheers,
Rob.
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Re: [PHP] Variable question
On 01 Oct 2011 at 18:59, Ron Piggott ron@actsministries.org wrote: If $correct_answer has a value of 3 what is the correct syntax needed to use echo to display the value of $trivia_answer_3? I know this is incorrect, but along the lines of what I am wanting to do: echo $trivia_answer_$correct_answer; $trivia_answer_1 = “1,000”; $trivia_answer_2 = “1,250”; $trivia_answer_3 = “2,500”; $trivia_answer_4 = “5,000”; Not completely obvious to me what you're trying to do but I assume its: echo '\$trivia_answer_' . $correct_answer . = \ . $somevalue . \;; -- Cheers -- Tim -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Variable question
On Sat, 1 Oct 2011, Mike Mackintosh wrote:
Best bet would to toss this into either an object or array for
simplification, otherwise that type of syntax would need the use of
eval.
example: eval('echo $trivia_answer_'.$correct_answer.';');
You could do:
$var = trivia_answer_.$correct_answer;
echo $$var;
But I agree that an array would be simpler.
best bet would be to..
$trivia_answer = array();
$trivia_answer[1] = 1000;
$trivia_answer[2] = 1250;
$trivia_answer[3] = 2500;
$trivia_answer[4] = 5000;
echo $trivia_answer[$correct_answer];
You can define this a bit more simply:
$trivia_answer = array (
1 = 1000,
2 = 1250,
3 = 2500,
4 = 5000
);
You can do it even more simply by just giving the values, but indexes wil
start at 0:
?php
$trivia_answer = array (1000, 1250, 2500, 5000);
print_r ($trivia_answer);
?
Array
(
[0] = 1000
[1] = 1250
[2] = 2500
[3] = 5000
)
While manually defining an array like this is only slightly less tedius
than using 4 numbered variables, it's a lot easier to do if you're getting
data from somewhere else (e.g. a database of trivia questions). To use
the original way proposed, you'd have to keep constructing variable names,
which arrays avoid quite nicely.
In my opinion, the only real usefulness for a syntax like $$var (above) is
if you want to do something with a bunch of variables in one go. For
example:
foreach (array (title, artist, album, label) as $field)
echo ucwords($field) . ': ' . $$field . 'BR';
The above comes from a function which manages only a single record, so no
real need to use an array. I could of course, e.g. record['title'] etc,
but I don't see much could be gained unless I needed to be able to manage
an entire record as a single unit.
Geoff.
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Re: [PHP] variable question
How about: eval( '$lie' . x ) ; is there a way to use one variable to create another? Example $poo=1 and i want $lie1 OR $poo=2 and i want $lie2 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] variable question
is there a way to use one variable to create another? Example $poo=1 and i want $lie1 OR $poo=2 and i want $lie2 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] variable question
On Sat, 19 Jun 2004 14:25:27 -0600, water_foul
[EMAIL PROTECTED] wrote:
is there a way to use one variable to create another?
Example
$poo=1
and i want
$lie1
OR
$poo=2
and i want
$lie2
If I understand you right, you want:
${'lie' . $poo}
when $poo is 1, that will give you $lie1, and when $poo is 2, it'll
give you $lie2.
You're almost certain to be better off using arrays though,,,
-robin
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Re: [PHP] variable question
Thanks oh so much
Robin Vickery [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Sat, 19 Jun 2004 14:25:27 -0600, water_foul
[EMAIL PROTECTED] wrote:
is there a way to use one variable to create another?
Example
$poo=1
and i want
$lie1
OR
$poo=2
and i want
$lie2
If I understand you right, you want:
${'lie' . $poo}
when $poo is 1, that will give you $lie1, and when $poo is 2, it'll
give you $lie2.
You're almost certain to be better off using arrays though,,,
-robin
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RE: [PHP] variable question...
-Original Message-
From: Justin Blake [mailto:[EMAIL PROTECTED]]
Sent: 16 April 2002 09:43
You can use variable variable names by adding another '$'.
so if $i == 1 and $var1 == one, you can do this:
$var_name = var.$i;
if($$var_name == one) echo Hello!;
That should work,
So should:
if (${var.$i} == one) echo Hello!;
Cheers!
Mike
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[PHP] variable question
Hey Guys and Gals, I'm writing this little script that takes two inputs: $name and $welcomemssg from a form and puts them in a text file. Now i only want to extract one of those variables open it with welcome.php, how do i go about this? when i just do fopen and fwrite it prints both variables. any thoughts? thanks, Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] variable question
On Tuesday 16 April 2002 00:41, Jule Slootbeek wrote: Hey Guys and Gals, I'm writing this little script that takes two inputs: $name and $welcomemssg from a form and puts them in a text file. Now i only want to extract one of those variables open it with welcome.php, how do i go about this? when i just do fopen and fwrite it prints both variables. any thoughts? Show us your code. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Kissing your hand may make you feel very good, but a diamond and sapphire bracelet lasts for ever. -- Anita Loos, Gentlemen Prefer Blondes */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] variable question
You would need to read in the line and explode the line into an array using explode(). How you do this depends on how you wrote the variables to a file. If you separated them using a , you could use $values = explode(,, $inputstring); see also: http://www.php.net/manual/en/function.explode.php David McInnis -Original Message- From: Jason Wong [mailto:[EMAIL PROTECTED]] Sent: Monday, April 15, 2002 10:49 AM To: [EMAIL PROTECTED] Subject: Re: [PHP] variable question On Tuesday 16 April 2002 00:41, Jule Slootbeek wrote: Hey Guys and Gals, I'm writing this little script that takes two inputs: $name and $welcomemssg from a form and puts them in a text file. Now i only want to extract one of those variables open it with welcome.php, how do i go about this? when i just do fopen and fwrite it prints both variables. any thoughts? Show us your code. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Kissing your hand may make you feel very good, but a diamond and sapphire bracelet lasts for ever. -- Anita Loos, Gentlemen Prefer Blondes */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] variable question
Here's my code, teh $welcomemssg is one of the two variable store in
index.php the other one is $name
?php
$File = welcome/index.php;
$Open = fopen ($File, r);
if ($Open) {
print ($welcomemssg);
}
fclose ($Open);
?
Jule
On Monday 15 April 2002 13:49, you typed on your keyboard, and you sent me
the following:
On Tuesday 16 April 2002 00:41, Jule Slootbeek wrote:
Hey Guys and Gals,
I'm writing this little script that takes two inputs: $name and
$welcomemssg from a form and puts them in a text file. Now i only want to
extract one of those variables open it with welcome.php, how do i go
about this? when i just do fopen and fwrite it prints both variables.
any thoughts?
Show us your code.
--
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[EMAIL PROTECTED]
http://blindtheory.cjb.net
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Re: [PHP] variable question
store $name on one line and $welcomemssg on a separate line. Then just
remember that all odd numbered liens are names and even numbered lines are
messages.
=C=
*
* Cal Evans
* Techno-Mage
* http://www.calevans.com
*
- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, April 15, 2002 1:30 PM
Subject: Re: [PHP] variable question
Here's my code, teh $welcomemssg is one of the two variable store in
index.php the other one is $name
?php
$File = welcome/index.php;
$Open = fopen ($File, r);
if ($Open) {
print ($welcomemssg);
}
fclose ($Open);
?
Jule
On Monday 15 April 2002 13:49, you typed on your keyboard, and you sent me
the following:
On Tuesday 16 April 2002 00:41, Jule Slootbeek wrote:
Hey Guys and Gals,
I'm writing this little script that takes two inputs: $name and
$welcomemssg from a form and puts them in a text file. Now i only want
to
extract one of those variables open it with welcome.php, how do i go
about this? when i just do fopen and fwrite it prints both variables.
any thoughts?
Show us your code.
--
Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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[PHP] variable question...
Let's say I a variable called $var1 and it's values is one ...I want to access them by doing something like this... $i = 1; if (var.$i == one) echo Hello!; ...I want the combination of var and $i to equal $var1 How do I do this?? The code I just wrote will not print out Hello! THANKS!!! Phil
Re: [PHP] variable question...
Phil Schwarzmann [EMAIL PROTECTED] wrote: Let's say I a variable called $var1 and it's values is one ...I want to access them by doing something like this... $i = 1; if (var.$i == one) echo Hello!; ...I want the combination of var and $i to equal $var1 How do I do this?? The code I just wrote will not print out Hello! You can use variable variable names by adding another '$'. so if $i == 1 and $var1 == one, you can do this: $var_name = var.$i; if($$var_name == one) echo Hello!; That should work, Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Variable question, yet another
put the array indices in single quote like :
echo [a href=\myscript.php?username={$userdata['username']}\]Goto
MyScript.php[/a];
- Original Message -
From: Jason Stechschulte [EMAIL PROTECTED]
To: King, Justin [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: 2001. május 8. 21:22
Subject: Re: [PHP] Variable question, yet another
On Tue, May 08, 2001 at 01:20:49PM -0500, King, Justin wrote:
So when the line hits type 1, it evals like this
echo [a href=myscript.php?username={$userdata[username]}]Goto
MyScript.php[/a];
Of course this yields an error because of the 's in the anchor tag.
But if I add slashes the evaluated code will be
echo [a href=\myscript.php?username={$userdata[\username\]}\]Goto
MyScript.php[/a];
Why not just break out of the string to print the username?
echo [a href=\myscript.php?username=.$userdata[username].\]Goto
Myscript.php[/a];
--
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[EMAIL PROTECTED]
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[PHP] Variable question, yet another
Alright... here's my situation for those that didn't read my string of
messages yesterday.. (plus a bit more background information as to why
I'm doing this)
I'm writing an engine for a content managing system. Part of the system
is a menu builder. I use 2 tables, (this is a mysql database) menu and
menu_parts. They look like this
Table menu
ID : Integer; (auto increments, key)
Name : Varchar[128];
Type : Integer; (unused now)
Table menu_parts
ID : Integer;
Menu : Integer; (which menu this belongs to)
Order : Tinyint; (all menu items have incremental numbers)
Type : Tinyint;
Data : Text;
My code looks like this
[code]
$query=SELECT type,data FROM menu_parts WHERE menu='1' ORDER BY
m_order;
$result=mysql_query($query);
if($myrow=mysql_fetch_array($result))
{ do {
if($myrow[type]==1)
eval(echo
\.$myrow[data].\;);
elseif($myrow[type]==2)
eval($myrow[data]);
else
echo $myrow[data];
} while($myrow=mysql_fetch_array($result));
}
[/code]
So depending on the menu_parts type, it will display the data field
differently.
If the type=0, it simple outputs the data field plain text.
If the type=1, it adds echo to both sides and outputs data.
If the type=2, it evaluates the code as is.
The problem I'm having, is with type 1. The main reason for this type
is say I want to send the user to a php script and pass parameters (I'm
going to use []'s so those of you with html email readers don't parse
it)
[a href=myscript.php?username={$userdata[username]}]Goto
MyScript.php[/a]
So when the line hits type 1, it evals like this
echo [a href=myscript.php?username={$userdata[username]}]Goto
MyScript.php[/a];
Of course this yields an error because of the 's in the anchor tag.
But if I add slashes the evaluated code will be
echo [a href=\myscript.php?username={$userdata[\username\]}\]Goto
MyScript.php[/a];
Which will cause the $userdata[username] variable to not process
properly. I thought about making type one do echo ''; instead of echo
; but then if the user has a ' in their menu it won't function
properly.
I wish I could do this with regular expressions, but I'm not fluent with
them (and also doubt I could succeed in my task if I did).
I think I described my problem as thorough as I could have. Any help,
comments, etc would be greatly appreciated.
-Justin
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Re: [PHP] Variable question, yet another
On Tue, May 08, 2001 at 01:20:49PM -0500, King, Justin wrote:
So when the line hits type 1, it evals like this
echo [a href=myscript.php?username={$userdata[username]}]Goto
MyScript.php[/a];
Of course this yields an error because of the 's in the anchor tag.
But if I add slashes the evaluated code will be
echo [a href=\myscript.php?username={$userdata[\username\]}\]Goto
MyScript.php[/a];
Why not just break out of the string to print the username?
echo [a href=\myscript.php?username=.$userdata[username].\]Goto
Myscript.php[/a];
--
Jason Stechschulte
[EMAIL PROTECTED]
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bigotry at worst.
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[PHP] Variable question
How can I evaluate a variable in a string? For example if I have a string defined as my user name is $user_data[username], how do I echo that string and have php evaluate $user_data[username]. Thanks in advance.. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
you can do it a couple ways...
echo my user name is . $user_data[username];
or
echo my username is ${user_data[username]};
-Original Message-
From: King, Justin [mailto:[EMAIL PROTECTED]]
Sent: Monday, May 07, 2001 3:49 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Variable question
How can I evaluate a variable in a string? For example if I have a
string defined as my user name is $user_data[username], how do I
echo that string and have php evaluate $user_data[username].
Thanks in advance..
-Justin
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Re: [PHP] Variable question
Try this one :
$user_data['username'] = 'Alphonse';
$str = my user name is {$user_data['username']};
Papp Gyozo
- [EMAIL PROTECTED]
- Original Message -
From: King, Justin [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: 2001. május 7. 21:48
Subject: [PHP] Variable question
How can I evaluate a variable in a string? For example if I have a
string defined as my user name is $user_data[username], how do I
echo that string and have php evaluate $user_data[username].
Thanks in advance..
-Justin
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RE: [PHP] Variable question
I think you're misunderstanding my question. I'm pulling
$user_data[username] from a databse so the string my user name is
$user_data[username] is exactly as the database hands it to me. I
know how to simply concat information.
-Justin
-Original Message-
From: Jack Dempsey [EMAIL PROTECTED]
Sent: Monday, May 07, 2001 12:55 PM
To: King, Justin; [EMAIL PROTECTED]
Subject: RE: [PHP] Variable question
you can do it a couple ways...
echo my user name is . $user_data[username];
or
echo my username is ${user_data[username]};
-Original Message-
From: King, Justin [mailto:[EMAIL PROTECTED]]
Sent: Monday, May 07, 2001 3:49 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Variable question
How can I evaluate a variable in a string? For example if I have a
string defined as my user name is $user_data[username], how do I
echo that string and have php evaluate $user_data[username].
Thanks in advance..
-Justin
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RE: [PHP] Variable question
I'm not sure what you mean...
[code]
$query = SELECT username FROM Users WHERE userid=1;
$result = mysql_query($query, $link);
$user_data = mysql_fetch_assoc($result);
echo my user name is .$user_data[username];
[/code]
Is that _not_ what you mean?
- John Vanderbeck
- Admin, GameDesign (http://gamedesign.incagold.com/)
- GameDesign, the industry source for game design and development issues
-Original Message-
From: King, Justin [mailto:[EMAIL PROTECTED]]
Sent: Monday, May 07, 2001 3:58 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP] Variable question
I think you're misunderstanding my question. I'm pulling
$user_data[username] from a databse so the string my user name is
$user_data[username] is exactly as the database hands it to me. I
know how to simply concat information.
-Justin
-Original Message-
From: Jack Dempsey [EMAIL PROTECTED]
Sent: Monday, May 07, 2001 12:55 PM
To: King, Justin; [EMAIL PROTECTED]
Subject: RE: [PHP] Variable question
you can do it a couple ways...
echo my user name is . $user_data[username];
or
echo my username is ${user_data[username]};
-Original Message-
From: King, Justin [mailto:[EMAIL PROTECTED]]
Sent: Monday, May 07, 2001 3:49 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Variable question
How can I evaluate a variable in a string? For example if I have a
string defined as my user name is $user_data[username], how do I
echo that string and have php evaluate $user_data[username].
Thanks in advance..
-Justin
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RE: [PHP] Variable question
Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
ok, look into eval() -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:07 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that -Justin -Original Message- From: Jack Dempsey [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:13 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question ok, look into eval() -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:07 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
How about manually parsing the string out to give you chunks, that can then be eval'd easy. - John Vanderbeck - Admin, GameDesign (http://gamedesign.incagold.com/) - GameDesign, the industry source for game design and development issues -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:18 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that -Justin -Original Message- From: Jack Dempsey [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:13 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question ok, look into eval() -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:07 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Variable question
In article [EMAIL PROTECTED], [EMAIL PROTECTED] (King, Justin) wrote: A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that The code being eval'd has to be a valid PHP statement. So if you want to echo that string, then echo must be part of the eval'd code. Terminated with semi-colon, etc. eval(echo 'Your username is ' . $userdata['username'];); -- CC -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
I understand that, but that's what I'm trying to get around doing. -Justin -Original Message- From: CC Zona [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:24 PM To: [EMAIL PROTECTED] Subject: Re: [PHP] Variable question In article [EMAIL PROTECTED], [EMAIL PROTECTED] (King, Justin) wrote: A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that The code being eval'd has to be a valid PHP statement. So if you want to echo that string, then echo must be part of the eval'd code. Terminated with semi-colon, etc. eval(echo 'Your username is ' . $userdata['username'];); -- CC -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
I'm trying to get around having to do that, I don't know regular expressions so it makes it difficult :( -Justin -Original Message- From: John Vanderbeck [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:21 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question How about manually parsing the string out to give you chunks, that can then be eval'd easy. - John Vanderbeck - Admin, GameDesign (http://gamedesign.incagold.com/) - GameDesign, the industry source for game design and development issues -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:18 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that -Justin -Original Message- From: Jack Dempsey [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:13 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question ok, look into eval() -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:07 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question (eval is cool)
$bob = Roy; $s = 'Hey there $bob'; $s = 'print '. $s .';'; eval ($s); prints: Hey there Roy; perhaps that's what you're looking for? -Original Message- From: John Vanderbeck [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:21 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question How about manually parsing the string out to give you chunks, that can then be eval'd easy. - John Vanderbeck - Admin, GameDesign (http://gamedesign.incagold.com/) - GameDesign, the industry source for game design and development issues -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:18 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that -Justin -Original Message- From: Jack Dempsey [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:13 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question ok, look into eval() -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:07 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Variable question
this also works, since you mentioned that you're trying to get away from evalling an echo statement. $bob = Roy; $s = 'Hey there $bob'; $s = '$somevar = '. $s .';'; eval ($s); print $somevar; prints: Hey there Roy; personally, i think that using regexps to implement an entire symbol parsing engine to do what you ask is something that you really do not need to do. instead of trying to reinvent the wheel, use the free ferarri that PHP provides you :) -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:29 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question I'm trying to get around having to do that, I don't know regular expressions so it makes it difficult :( -Justin -Original Message- From: John Vanderbeck [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:21 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question How about manually parsing the string out to give you chunks, that can then be eval'd easy. - John Vanderbeck - Admin, GameDesign (http://gamedesign.incagold.com/) - GameDesign, the industry source for game design and development issues -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:18 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question A simple eval($mysqldata) isn't going to do it though since the string is Your username is $userdata[username]; it'll just spit a parse error. I've already tried that -Justin -Original Message- From: Jack Dempsey [EMAIL PROTECTED] Sent: Monday, May 07, 2001 1:13 PM To: King, Justin; [EMAIL PROTECTED] Subject: RE: [PHP] Variable question ok, look into eval() -Original Message- From: King, Justin [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 4:07 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] Variable question Here let me flesh this out a bit more Consider the query SELECT datafield FROM myTable WHERE id=1; This would return My username is $userdata[username]; I want to then output what the database returns, and have php evaluate my variables. -Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] variable question
Put them in an array? PHP allows for variable variables, but I'm not sure they
work with classes.
This works:
$foo0 = 'a';
$foo1 = 'b';
$foo2 = 'c';
$foo3 = 'd';
$foo4 = 'e';
for($i = 0 ; $i 5 ; ++$i)
{
$var = 'foo'.$i;
echo $$var;
}
Try it with an object...
--Joe
On Fri, Jan 19, 2001 at 05:15:25PM -0500, Michael Zornek wrote:
ok so i have an object that has (among other things) the following properties:
$vendor_data-s9
$vendor_data-s10
$vendor_data-s11
$vendor_data-s12
...
$vendor_data-s40
The values are 1 or 0
I'd like to write a loop to say:
for ($count=9; $count40; $count++) {
if ($vendor_data-s(insert_number_here) == 1) {
echo something;
}
}
any thoughts?
Mike
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Re: [PHP] variable question
thats right you could do that, but it sucks. (IMHO)
$test-s0
$test-s1
$test-s2
for($c = 0; $c 3; $c++)
{
$name = "s$c";
echo $test-$name;
}
but this is better, more modular.
$test-s[0]
$test-s[1]
$test-s[2]
foreach($test-s as $pos = $val)
echo $val;
with the second example you can add another element to $test-s and the loop
will auto adjust for this.
but both methods work.
Chris Lee
Mediawaveonline.com
Joe Stump [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Put them in an array? PHP allows for variable variables, but I'm not sure
they
work with classes.
This works:
$foo0 = 'a';
$foo1 = 'b';
$foo2 = 'c';
$foo3 = 'd';
$foo4 = 'e';
for($i = 0 ; $i 5 ; ++$i)
{
$var = 'foo'.$i;
echo $$var;
}
Try it with an object...
--Joe
On Fri, Jan 19, 2001 at 05:15:25PM -0500, Michael Zornek wrote:
ok so i have an object that has (among other things) the following
properties:
$vendor_data-s9
$vendor_data-s10
$vendor_data-s11
$vendor_data-s12
...
$vendor_data-s40
The values are 1 or 0
I'd like to write a loop to say:
for ($count=9; $count40; $count++) {
if ($vendor_data-s(insert_number_here) == 1) {
echo something;
}
}
any thoughts?
Mike
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