Re: [PHP] checking date is not greater than today
On 30 Jun 2002 at 22:31, Timothy J. Luoma wrote: > > I am trying to compare a given date string (i.e. June 30, 2002 is > 20020630). I want to make sure that the input string that is given is > not greater than today (i.e. if today is June 30, and you ask for > 20020701, I want to be able to throw an error). > I'm a newbie, so I'm not sure the best way to do this. My thought was > that if I take the year () and add on the day-of-year (i.e. Feb 10 > = 041) then I would be able to compare them as you would any other > numbers. [...] snipped I ignored the rest as it was beyond me. I'm also a newbie to PHP but I looked into dates in Perl. I quickly began using a module from CPAN as I realized this was more complicated than meets the eye and you seem to indcate that when you mention leap years. I would question why you accept input as a particular format. It's certainly easier to work with timestamps than arbitrary representations of dates. I would not be so quick to assume you have to accept input as is. Or at least have it fixed to a format ... but the Perl modules I've worked with are liberal with what they receive :) Anyhow, I'd just find a PHP module ot handle this. I found this: http://www.phpbuilder.com/columns/akent2610.php3 but I'd just want a class (guess you call it that in PHP). And then this looks real interesting: > Date/Time Processing with PHP > By The Disenchanted Developer > March 19, 2002 http://zope1.devshed.com/zope.devshed.com/Server_Side/PHP/DateTime/page1.html In Perl I happen to use this moduel for date manipulation: http://search.cpan.org/doc/STBEY/Date-Calc-5.0/Calc.pod There must be something similar in PHP but since I too am a newbie (and lazy to boot) I don't know what it is. Peter -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] checking date is not greater than today
On Sun, 30 Jun 2002, John Holmes wrote:
> $today = date("Ymd");
> if($input_date > $today)
> { echo "Date must be before today!"; }
*thwaps self*
DUH! Thanks... been staring at this for too long.
> It looks like you're dealing with MySQL dates. There are a ton of useful
> functions you can use in your queries that make any time manipulation in
> PHP unnecessary. Chapter 6, Date and Time Functions of the MySQL manual.
I'm not dealing with MySQL dates yet, just simple query strings, but I'll
check that out before I get into MySQL.
Thanks
TjL
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RE: [PHP] checking date is not greater than today
$today = date("Ymd");
if($input_date > $today)
{ echo "Date must be before today!"; }
It looks like you're dealing with MySQL dates. There are a ton of useful
functions you can use in your queries that make any time manipulation in
PHP unnecessary. Chapter 6, Date and Time Functions of the MySQL manual.
---John Holmes...
> -Original Message-
> From: Timothy J. Luoma [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, June 30, 2002 10:31 PM
> To: PHP Mailing List
> Subject: [PHP] checking date is not greater than today
>
>
> I am trying to compare a given date string (i.e. June 30, 2002 is
> 20020630). I want to make sure that the input string that is given is
not
> greater than today (i.e. if today is June 30, and you ask for
20020701, I
> want to be able to throw an error).
>
> I'm a newbie, so I'm not sure the best way to do this. My thought was
> that if I take the year () and add on the day-of-year (i.e. Feb 10
=
> 041) then I would be able to compare them as you would any other
numbers.
>
> The problem I have then run into is that strftime and date seem to
have
> different opinions as to what day of the year it is.
>
> date
> z - day of the year; i.e. "0" to "365"
>
> strftime
> %j - day of the year as a decimal number (range 001 to 366)
>
>
> I have these variables defined
>
> $SEARCHYEAR =
> i.e 2002
>
> $SEARCHMONTH = MM
> i.e. 06
>
> $SEARCHDAY = DD
> i.e. 30
>
>
> $TODAYCMP=date ("Yz");
>
>
$SEARCHCMP=strftime("%Y%j",mktime(0,0,0,$SEARCHMONTH,$SEARCHDAY,$SEARCHY
EA
> R));
>
> and then I tried it for today and got
>
> echo " ";
>
> as a result I get
>
>
>
>
> So I'm trying to figure out:
>
> A) Why strftime and date don't handle leap years the same way
>
> and (more importantly)
>
> B) The best way to make sure a given date MMDD is not greater than
> "today"
>
> I did some googling & php.net searching without luck.
>
> Thanks
> TjL
>
>
>
>
>
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> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
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[PHP] checking date is not greater than today
I am trying to compare a given date string (i.e. June 30, 2002 is
20020630). I want to make sure that the input string that is given is not
greater than today (i.e. if today is June 30, and you ask for 20020701, I
want to be able to throw an error).
I'm a newbie, so I'm not sure the best way to do this. My thought was
that if I take the year () and add on the day-of-year (i.e. Feb 10 =
041) then I would be able to compare them as you would any other numbers.
The problem I have then run into is that strftime and date seem to have
different opinions as to what day of the year it is.
date
z - day of the year; i.e. "0" to "365"
strftime
%j - day of the year as a decimal number (range 001 to 366)
I have these variables defined
$SEARCHYEAR =
i.e 2002
$SEARCHMONTH = MM
i.e. 06
$SEARCHDAY = DD
i.e. 30
$TODAYCMP=date ("Yz");
$SEARCHCMP=strftime("%Y%j",mktime(0,0,0,$SEARCHMONTH,$SEARCHDAY,$SEARCHYEAR));
and then I tried it for today and got
echo " ";
as a result I get
So I'm trying to figure out:
A) Why strftime and date don't handle leap years the same way
and (more importantly)
B) The best way to make sure a given date MMDD is not greater than
"today"
I did some googling & php.net searching without luck.
Thanks
TjL
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