Re: [PHP] simple yet weird... help pls

[Rasmus Lerdorf]

> Please take a look at the script below.
> If i want to show an image it doesnt work if it's under an if statement.
> Why in this case?
>
>  $feedb=0;
>   if($feedb==0){   echo "";}
>   echo "";
> ?>
> How can i solve this problem?

By spelling src correctly.

-Rasmus


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[PHP] simple yet weird... help pls

[Simon De Deyne]

Please take a look at the script below.
If i want to show an image it doesnt work if it's under an if statement.
Why in this case?

";}
echo "";
?>
How can i solve this problem?

thank you!
Simon


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