subject:"\[PHP\] testing for blank var"

RE: [PHP] testing for blank var

2002-03-21 Thread ROBERT MCPEAK

Beautiful! >>> Rick Emery <[EMAIL PROTECTED]> 03/21/02 09:19AM >>> if ( ! ISSET($img_url) ) -Original Message- From: ROBERT MCPEAK [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 8:18 AM To: [EMAIL PROTECTED] Subject: [PHP] testing for blank

RE: [PHP] testing for blank var

2002-03-21 Thread Rick Emery

if ( ! ISSET($img_url) ) -Original Message- From: ROBERT MCPEAK [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 8:18 AM To: [EMAIL PROTECTED] Subject: [PHP] testing for blank var if $img_url has a value, then I'd like to show the image, if it doesn't, the

[PHP] testing for blank var

2002-03-21 Thread ROBERT MCPEAK

if $img_url has a value, then I'd like to show the image, if it doesn't, then I'd like to show a message. What's wrong with my code? Am I incorrectly testing for the value? The else works fine, but not the if. Thanks! if (!$img_url) { echo "No Image URL Entered"";