Re: [PHP] Grr SQL syntax error silghtly OT
Thanks
"Joakim Andersson" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I would try something like this...
>
> SELECT COUNT(tececo_stats.id) as num_hits, meta_data.title
> FROM tececo_stats, meta_data
> WHERE meta_data.id = tececo_stats.page_id
> GROUP BY tececo_stats.page_id
> ORDER BY num_hits DESC
>
> /Joakim
>
> > -Original Message-
> > From: JJ Harrison [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, July 09, 2002 11:07 AM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP] Grr SQL syntax error silghtly OT
> >
> >
> > table structure for tececo stats(Stores information about the
> > visitors to my
> > site.visited is either 0 or 1 depending on whether or not the
> > stats cookie
> > has been set):
> >
> > id int(11) unsigned NOT NULL auto_increment,
> > page_id int(11) NOT NULL default '0',
> > visited int(11) NOT NULL default '0',
> > time int(11) NOT NULL default '0',
> > remote_dns varchar(100) NOT NULL default '',
> > remote_ip varchar(15) NOT NULL default '',
> > referer varchar(200) NOT NULL default '',
> > browser varchar(100) NOT NULL default '',
> > system varchar(100) NOT NULL default '',
> > PRIMARY KEY (id),
> > KEY page_id (page_id,time)
> >
> > table structure for meta_data(contains information about the
> > pages in my
> > website):
> >
> > id int(11) unsigned NOT NULL auto_increment,
> > pid int(11) unsigned NOT NULL default '0',
> > title varchar(200) NOT NULL default '',
> > page_name varchar(75) NOT NULL default '',
> > description text NOT NULL,
> > keywords text NOT NULL,
> > PRIMARY KEY (id),
> > KEY pid (pid)
> >
> > main file(required.php automaticly does a DB connect and is
> > used elsewhere
> > so I know is not the problem).
> > > include "includes/required.php";
> > do_html_header('Page Detail Statistics');
> >
> > $query = "select
> > count(tececo_stats.*) as tececo_stats.views, meta_data.title
> > from
> > meta_data, tececo_stats
> > where
> > meta_data.id = tececo_stats.id
> > order by meta_data.id
> > group by meta_data.id";
> > $result = mysql_query($query) or die("Query failed: $query" .
> > mysql_error());
> > $num_results = mysql_num_rows($result);
> > ?>
> >
> > Page NameTota;Number of
> > Sessions
> > > for ($i=0; $i < $num_results; $i++)
> > {
> > $row = mysql_fetch_array($result);
> > echo
> > ''.$row['meta_data.title'].''.$row['tececo_st
> > ats.views'].'<
> > /td>';
> > }
> > ?>
> >
> > > do_html_footer();
> > ?>
> >
> > error message:
> > Query failed: select count(tececo_stats.*) as tececo_stats.views,
> > meta_data.title from meta_data and tececo_stats where meta_data.id =
> > tececo_stats.id order by meta_data.id
> > You have an error in your SQL syntax near '*) as tececo_stats.views,
> > meta_data.title from meta_data and tececo_stats whe' at line 2
> >
> > What I want to do: This is essentially a script for a stats
> > program that I
> > am writting that returns the number of hits for each page. Instead of
> > looping a query I decieded to try and join the two tables to
> > make it more
> > efficiant. I am trying to get it to work with hits now than
> > make it sessions
> > later.
> >
> > I hope this is enough info and thank you for your help.
> >
> >
> > --
> > JJ Harrison
> > [EMAIL PROTECTED]
> > www.tececo.com
> >
> >
> > "Joakim Andersson" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > I assume that 2count should really be count and 2 is just
> > the line-number
> > > you added in this post...
> > >
> > > tececo_stats.views is (probably) the name of a column and
> > cannot be used
> > as
> > > an alias. Change it to something else.
> > > change count(*) to count(tececo_stats.*) (I think that's
> > what you want)
> > > And you probably need a group by-statement at the end: GROUP BY
> > > whatever_you_need_to_group_by
> > >
> > > It's really difficult to answer your questions without the
> > tab
RE: [PHP] Grr SQL syntax error silghtly OT
Forgot. You have to change $row['tececo_stats.views'] to $row['num_hits']
/J
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, July 09, 2002 11:15 AM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP] Grr SQL syntax error silghtly OT
>
>
> I would try something like this...
>
> SELECT COUNT(tececo_stats.id) as num_hits, meta_data.title
> FROM tececo_stats, meta_data
> WHERE meta_data.id = tececo_stats.page_id
> GROUP BY tececo_stats.page_id
> ORDER BY num_hits DESC
>
> /Joakim
>
> > -Original Message-
> > From: JJ Harrison [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, July 09, 2002 11:07 AM
> > To: [EMAIL PROTECTED]
> > Subject: Re: [PHP] Grr SQL syntax error silghtly OT
> >
> >
> > table structure for tececo stats(Stores information about the
> > visitors to my
> > site.visited is either 0 or 1 depending on whether or not the
> > stats cookie
> > has been set):
> >
> > id int(11) unsigned NOT NULL auto_increment,
> > page_id int(11) NOT NULL default '0',
> > visited int(11) NOT NULL default '0',
> > time int(11) NOT NULL default '0',
> > remote_dns varchar(100) NOT NULL default '',
> > remote_ip varchar(15) NOT NULL default '',
> > referer varchar(200) NOT NULL default '',
> > browser varchar(100) NOT NULL default '',
> > system varchar(100) NOT NULL default '',
> > PRIMARY KEY (id),
> > KEY page_id (page_id,time)
> >
> > table structure for meta_data(contains information about the
> > pages in my
> > website):
> >
> > id int(11) unsigned NOT NULL auto_increment,
> > pid int(11) unsigned NOT NULL default '0',
> > title varchar(200) NOT NULL default '',
> > page_name varchar(75) NOT NULL default '',
> > description text NOT NULL,
> > keywords text NOT NULL,
> > PRIMARY KEY (id),
> > KEY pid (pid)
> >
> > main file(required.php automaticly does a DB connect and is
> > used elsewhere
> > so I know is not the problem).
> > > include "includes/required.php";
> > do_html_header('Page Detail Statistics');
> >
> > $query = "select
> > count(tececo_stats.*) as tececo_stats.views, meta_data.title
> > from
> > meta_data, tececo_stats
> > where
> > meta_data.id = tececo_stats.id
> > order by meta_data.id
> > group by meta_data.id";
> > $result = mysql_query($query) or die("Query failed: $query" .
> > mysql_error());
> > $num_results = mysql_num_rows($result);
> > ?>
> >
> > Page
> NameTota;Number of
> > Sessions
> > > for ($i=0; $i < $num_results; $i++)
> > {
> > $row = mysql_fetch_array($result);
> > echo
> > ''.$row['meta_data.title'].''.$row['tececo_st
> > ats.views'].'<
> > /td>';
> > }
> > ?>
> >
> > > do_html_footer();
> > ?>
> >
> > error message:
> > Query failed: select count(tececo_stats.*) as tececo_stats.views,
> > meta_data.title from meta_data and tececo_stats where meta_data.id =
> > tececo_stats.id order by meta_data.id
> > You have an error in your SQL syntax near '*) as tececo_stats.views,
> > meta_data.title from meta_data and tececo_stats whe' at line 2
> >
> > What I want to do: This is essentially a script for a stats
> > program that I
> > am writting that returns the number of hits for each page.
> Instead of
> > looping a query I decieded to try and join the two tables to
> > make it more
> > efficiant. I am trying to get it to work with hits now than
> > make it sessions
> > later.
> >
> > I hope this is enough info and thank you for your help.
> >
> >
> > --
> > JJ Harrison
> > [EMAIL PROTECTED]
> > www.tececo.com
> >
> >
> > "Joakim Andersson" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > I assume that 2count should really be count and 2 is just
> > the line-number
> > > you added in this post...
> > >
> > > tececo_stats.views is (probably) the name of a column and
> > cannot be used
> > as
> > > an alias. Change it to something else.
> > > change count(*) to count(tececo_stats.*) (I think that's
> > what you
RE: [PHP] Grr SQL syntax error silghtly OT
I would try something like this...
SELECT COUNT(tececo_stats.id) as num_hits, meta_data.title
FROM tececo_stats, meta_data
WHERE meta_data.id = tececo_stats.page_id
GROUP BY tececo_stats.page_id
ORDER BY num_hits DESC
/Joakim
> -Original Message-
> From: JJ Harrison [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, July 09, 2002 11:07 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] Grr SQL syntax error silghtly OT
>
>
> table structure for tececo stats(Stores information about the
> visitors to my
> site.visited is either 0 or 1 depending on whether or not the
> stats cookie
> has been set):
>
> id int(11) unsigned NOT NULL auto_increment,
> page_id int(11) NOT NULL default '0',
> visited int(11) NOT NULL default '0',
> time int(11) NOT NULL default '0',
> remote_dns varchar(100) NOT NULL default '',
> remote_ip varchar(15) NOT NULL default '',
> referer varchar(200) NOT NULL default '',
> browser varchar(100) NOT NULL default '',
> system varchar(100) NOT NULL default '',
> PRIMARY KEY (id),
> KEY page_id (page_id,time)
>
> table structure for meta_data(contains information about the
> pages in my
> website):
>
> id int(11) unsigned NOT NULL auto_increment,
> pid int(11) unsigned NOT NULL default '0',
> title varchar(200) NOT NULL default '',
> page_name varchar(75) NOT NULL default '',
> description text NOT NULL,
> keywords text NOT NULL,
> PRIMARY KEY (id),
> KEY pid (pid)
>
> main file(required.php automaticly does a DB connect and is
> used elsewhere
> so I know is not the problem).
> include "includes/required.php";
> do_html_header('Page Detail Statistics');
>
> $query = "select
> count(tececo_stats.*) as tececo_stats.views, meta_data.title
> from
> meta_data, tececo_stats
> where
> meta_data.id = tececo_stats.id
> order by meta_data.id
> group by meta_data.id";
> $result = mysql_query($query) or die("Query failed: $query" .
> mysql_error());
> $num_results = mysql_num_rows($result);
> ?>
>
> Page NameTota;Number of
> Sessions
> for ($i=0; $i < $num_results; $i++)
> {
> $row = mysql_fetch_array($result);
> echo
> ''.$row['meta_data.title'].''.$row['tececo_st
> ats.views'].'<
> /td>';
> }
> ?>
>
> do_html_footer();
> ?>
>
> error message:
> Query failed: select count(tececo_stats.*) as tececo_stats.views,
> meta_data.title from meta_data and tececo_stats where meta_data.id =
> tececo_stats.id order by meta_data.id
> You have an error in your SQL syntax near '*) as tececo_stats.views,
> meta_data.title from meta_data and tececo_stats whe' at line 2
>
> What I want to do: This is essentially a script for a stats
> program that I
> am writting that returns the number of hits for each page. Instead of
> looping a query I decieded to try and join the two tables to
> make it more
> efficiant. I am trying to get it to work with hits now than
> make it sessions
> later.
>
> I hope this is enough info and thank you for your help.
>
>
> --
> JJ Harrison
> [EMAIL PROTECTED]
> www.tececo.com
>
>
> "Joakim Andersson" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > I assume that 2count should really be count and 2 is just
> the line-number
> > you added in this post...
> >
> > tececo_stats.views is (probably) the name of a column and
> cannot be used
> as
> > an alias. Change it to something else.
> > change count(*) to count(tececo_stats.*) (I think that's
> what you want)
> > And you probably need a group by-statement at the end: GROUP BY
> > whatever_you_need_to_group_by
> >
> > It's really difficult to answer your questions without the
> table designs,
> > the error message and what you expect this query to do.
> And, it's not
> > slightly OT. It's totally OT. :-)
> >
> > Regards
> > Joakim Andersson
> >
> >
> > > -Original Message-
> > > From: JJ Harrison [mailto:[EMAIL PROTECTED]]
> > > Sent: Tuesday, July 09, 2002 10:10 AM
> > > To: [EMAIL PROTECTED]
> > > Subject: [PHP] Grr SQL syntax error silghtly OT
> > >
> > >
> > > Sorry :}
> > >
> > > I get a SQL syntax error at line two of the query:
> > >
> > > $query = "select
> > > 2count(*) as tececo_stats.views, meta_data.title
> > > from
> > > meta_data, tececo_stats
> > > where
> > > meta_data.id = tececo_stats.id";
> > >
> > > I have stared at this 'till i felt dizzy. can someone tell me
> > > what I am
> > > doing wrong so that I can learn from it?
> > >
> > > Thanks in advance
> > >
> > >
> > > --
> > > JJ Harrison
> > > [EMAIL PROTECTED]
> > > www.tececo.com
> > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
> > > To unsubscribe, visit: http://www.php.net/unsub.php
> > >
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Grr SQL syntax error silghtly OT
table structure for tececo stats(Stores information about the visitors to my site.visited is either 0 or 1 depending on whether or not the stats cookie has been set): id int(11) unsigned NOT NULL auto_increment, page_id int(11) NOT NULL default '0', visited int(11) NOT NULL default '0', time int(11) NOT NULL default '0', remote_dns varchar(100) NOT NULL default '', remote_ip varchar(15) NOT NULL default '', referer varchar(200) NOT NULL default '', browser varchar(100) NOT NULL default '', system varchar(100) NOT NULL default '', PRIMARY KEY (id), KEY page_id (page_id,time) table structure for meta_data(contains information about the pages in my website): id int(11) unsigned NOT NULL auto_increment, pid int(11) unsigned NOT NULL default '0', title varchar(200) NOT NULL default '', page_name varchar(75) NOT NULL default '', description text NOT NULL, keywords text NOT NULL, PRIMARY KEY (id), KEY pid (pid) main file(required.php automaticly does a DB connect and is used elsewhere so I know is not the problem). " . mysql_error()); $num_results = mysql_num_rows($result); ?> Page NameTota;Number of Sessions '.$row['meta_data.title'].''.$row['tececo_stats.views'].'< /td>'; } ?> error message: Query failed: select count(tececo_stats.*) as tececo_stats.views, meta_data.title from meta_data and tececo_stats where meta_data.id = tececo_stats.id order by meta_data.id You have an error in your SQL syntax near '*) as tececo_stats.views, meta_data.title from meta_data and tececo_stats whe' at line 2 What I want to do: This is essentially a script for a stats program that I am writting that returns the number of hits for each page. Instead of looping a query I decieded to try and join the two tables to make it more efficiant. I am trying to get it to work with hits now than make it sessions later. I hope this is enough info and thank you for your help. -- JJ Harrison [EMAIL PROTECTED] www.tececo.com "Joakim Andersson" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > I assume that 2count should really be count and 2 is just the line-number > you added in this post... > > tececo_stats.views is (probably) the name of a column and cannot be used as > an alias. Change it to something else. > change count(*) to count(tececo_stats.*) (I think that's what you want) > And you probably need a group by-statement at the end: GROUP BY > whatever_you_need_to_group_by > > It's really difficult to answer your questions without the table designs, > the error message and what you expect this query to do. And, it's not > slightly OT. It's totally OT. :-) > > Regards > Joakim Andersson > > > > -Original Message- > > From: JJ Harrison [mailto:[EMAIL PROTECTED]] > > Sent: Tuesday, July 09, 2002 10:10 AM > > To: [EMAIL PROTECTED] > > Subject: [PHP] Grr SQL syntax error silghtly OT > > > > > > Sorry :} > > > > I get a SQL syntax error at line two of the query: > > > > $query = "select > > 2count(*) as tececo_stats.views, meta_data.title > > from > > meta_data, tececo_stats > > where > > meta_data.id = tececo_stats.id"; > > > > I have stared at this 'till i felt dizzy. can someone tell me > > what I am > > doing wrong so that I can learn from it? > > > > Thanks in advance > > > > > > -- > > JJ Harrison > > [EMAIL PROTECTED] > > www.tececo.com > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Grr SQL syntax error silghtly OT
I assume that 2count should really be count and 2 is just the line-number you added in this post... tececo_stats.views is (probably) the name of a column and cannot be used as an alias. Change it to something else. change count(*) to count(tececo_stats.*) (I think that's what you want) And you probably need a group by-statement at the end: GROUP BY whatever_you_need_to_group_by It's really difficult to answer your questions without the table designs, the error message and what you expect this query to do. And, it's not slightly OT. It's totally OT. :-) Regards Joakim Andersson > -Original Message- > From: JJ Harrison [mailto:[EMAIL PROTECTED]] > Sent: Tuesday, July 09, 2002 10:10 AM > To: [EMAIL PROTECTED] > Subject: [PHP] Grr SQL syntax error silghtly OT > > > Sorry :} > > I get a SQL syntax error at line two of the query: > > $query = "select > 2count(*) as tececo_stats.views, meta_data.title > from > meta_data, tececo_stats > where > meta_data.id = tececo_stats.id"; > > I have stared at this 'till i felt dizzy. can someone tell me > what I am > doing wrong so that I can learn from it? > > Thanks in advance > > > -- > JJ Harrison > [EMAIL PROTECTED] > www.tececo.com > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Grr SQL syntax error silghtly OT
2count(*)? don't look right > -Original Message- > From: JJ Harrison [mailto:[EMAIL PROTECTED]] > Sent: 09 July 2002 9:10 AM > To: [EMAIL PROTECTED] > Subject: [PHP] Grr SQL syntax error silghtly OT > > > Sorry :} > > I get a SQL syntax error at line two of the query: > > $query = "select > 2count(*) as tececo_stats.views, meta_data.title > from > meta_data, tececo_stats > where > meta_data.id = tececo_stats.id"; > > I have stared at this 'till i felt dizzy. can someone tell me > what I am > doing wrong so that I can learn from it? > > Thanks in advance > > > -- > JJ Harrison > [EMAIL PROTECTED] > www.tececo.com > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
