Re: [PHP] 2 conditions why wont they work??
Most unusual indeed. The quick/ugly solution is to trim() the incoming $clientID. But that's not appropriate if you expect valid entries starting with a space (well, two spaces in your case) :) Gotta hit the sack now - check out the time over here! :) Bogdan Brad Wright wrote: > Bogdan, > It appears that $clientID is saved with a space at the start .. when i check > for its value (using session_encode() ) it gives that value " test 3" when > it should be "test 3". > > "> > > this is the extract form the form on the previous page which sets $clientID. > > I am sure that a space is being added but cant find where. > > Thanks for yr help, > Brad -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 2 conditions why wont they work??
Bogdan, It appears that $clientID is saved with a space at the start .. when i check for its value (using session_encode() ) it gives that value " test 3" when it should be "test 3". "> this is the extract form the form on the previous page which sets $clientID. I am sure that a space is being added but cant find where. Thanks for yr help, Brad > From: Bogdan Stancescu <[EMAIL PROTECTED]> > Date: Mon, 11 Feb 2002 05:53:46 +0200 > To: Brad Wright <[EMAIL PROTECTED]> > Cc: PHP General List <[EMAIL PROTECTED]> > Subject: Re: [PHP] 2 conditions why wont they work?? > > Well, that's probably because of the data - no entries with both conditions > satisfied... Use "or" if that's what you actually want to do. ;-) > > Bogdan > > Brad Wright wrote: > >> Ahh..that seems to have fixed it. Its now pulling NO data, but is not giving >> error msg >> thanks, 1/2 way there now :) >> >> brad >> >>> From: Bogdan Stancescu <[EMAIL PROTECTED]> >>> Date: Mon, 11 Feb 2002 05:46:46 +0200 >>> To: Brad Wright <[EMAIL PROTECTED]> >>> Cc: PHP General List <[EMAIL PROTECTED]> >>> Subject: Re: [PHP] 2 conditions why wont they work?? >>> >>> No, with your syntax it won't. You have to quote it in the query, as in >>> $query2 = "select * from Table where userNo = $userNo and clientID = >>> '$clientID'"; >>> >>> Bogdan >>> >>> Brad Wright wrote: >>> >>>> Thanks, >>>> >>>> $clientID is a string but is not empty...already tried echo($clientID) and >>>> it is not empty. >>>> >>>> Did you mean that if the value of $cientID is a string it wont work >>>> >>>> Thanks >>>> Brad >>>> >>>>> From: Bogdan Stancescu <[EMAIL PROTECTED]> >>>>> Date: Mon, 11 Feb 2002 05:38:31 +0200 >>>>> To: Brad Wright <[EMAIL PROTECTED]> >>>>> Cc: PHP General List <[EMAIL PROTECTED]> >>>>> Subject: Re: [PHP] 2 conditions why wont they work?? >>>>> >>>>> Do an echo($clientID) before - it most probably is either empty or it's a >>>>> string and MySQL actually issues errors there. >>>>> >>>>> Bogdan >>>>> >>>>> Brad Wright wrote: >>>>> >>>>>> Hi all, >>>>>> Im was sure you could select a row from a mySQL database based on 2 >>>>>> conditions. My code: >>>>>> >>>>>> $query2 = "select * from Table where userNo = $userNo and clientID = >>>>>> $clientID"; >>>>>> $result2 = mysql_query($query2,$db); >>>>>> >>>>>> This returns : >>>>>> Warning: Supplied argument is not a valid MySQL result resource >>>>>> >>>>>> b ut if i change the line to: >>>>>> $query2 = "select * from Table where userNo = $userNo; >>>>>> $result2 = mysql_query($query2,$db); >>>>>> >>>>>> it works (but get all the rows with userNo = $userNo. >>>>>> >>>>>> HELP Im sure this should work...what am i doing wrong??? >>>>>> >>>>>> -- >>>>>> PHP General Mailing List (http://www.php.net/) >>>>>> To unsubscribe, visit: http://www.php.net/unsub.php >>>>> >>>>> >>>>> -- >>>>> PHP General Mailing List (http://www.php.net/) >>>>> To unsubscribe, visit: http://www.php.net/unsub.php >>>>> >>> >>> >>> -- >>> PHP General Mailing List (http://www.php.net/) >>> To unsubscribe, visit: http://www.php.net/unsub.php >>> >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 2 conditions why wont they work??
Well, that's probably because of the data - no entries with both conditions satisfied... Use "or" if that's what you actually want to do. ;-) Bogdan Brad Wright wrote: > Ahh..that seems to have fixed it. Its now pulling NO data, but is not giving > error msg > thanks, 1/2 way there now :) > > brad > > > From: Bogdan Stancescu <[EMAIL PROTECTED]> > > Date: Mon, 11 Feb 2002 05:46:46 +0200 > > To: Brad Wright <[EMAIL PROTECTED]> > > Cc: PHP General List <[EMAIL PROTECTED]> > > Subject: Re: [PHP] 2 conditions why wont they work?? > > > > No, with your syntax it won't. You have to quote it in the query, as in > > $query2 = "select * from Table where userNo = $userNo and clientID = > > '$clientID'"; > > > > Bogdan > > > > Brad Wright wrote: > > > >> Thanks, > >> > >> $clientID is a string but is not empty...already tried echo($clientID) and > >> it is not empty. > >> > >> Did you mean that if the value of $cientID is a string it wont work > >> > >> Thanks > >> Brad > >> > >>> From: Bogdan Stancescu <[EMAIL PROTECTED]> > >>> Date: Mon, 11 Feb 2002 05:38:31 +0200 > >>> To: Brad Wright <[EMAIL PROTECTED]> > >>> Cc: PHP General List <[EMAIL PROTECTED]> > >>> Subject: Re: [PHP] 2 conditions why wont they work?? > >>> > >>> Do an echo($clientID) before - it most probably is either empty or it's a > >>> string and MySQL actually issues errors there. > >>> > >>> Bogdan > >>> > >>> Brad Wright wrote: > >>> > >>>> Hi all, > >>>> Im was sure you could select a row from a mySQL database based on 2 > >>>> conditions. My code: > >>>> > >>>> $query2 = "select * from Table where userNo = $userNo and clientID = > >>>> $clientID"; > >>>> $result2 = mysql_query($query2,$db); > >>>> > >>>> This returns : > >>>> Warning: Supplied argument is not a valid MySQL result resource > >>>> > >>>> b ut if i change the line to: > >>>> $query2 = "select * from Table where userNo = $userNo; > >>>> $result2 = mysql_query($query2,$db); > >>>> > >>>> it works (but get all the rows with userNo = $userNo. > >>>> > >>>> HELP Im sure this should work...what am i doing wrong??? > >>>> > >>>> -- > >>>> PHP General Mailing List (http://www.php.net/) > >>>> To unsubscribe, visit: http://www.php.net/unsub.php > >>> > >>> > >>> -- > >>> PHP General Mailing List (http://www.php.net/) > >>> To unsubscribe, visit: http://www.php.net/unsub.php > >>> > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] 2 conditions why wont they work??
In your code below, mysql will throw an error if $clientID is empty or non-numeric because it is not surrounded with quotation marks.. mysql will treat it as a field name (or just throw a syntax error if it's empty). -Original Message- From: Brad Wright [mailto:[EMAIL PROTECTED]] Sent: 11 February 2002 03:45 To: Bogdan Stancescu Cc: PHP General List Subject: Re: [PHP] 2 conditions why wont they work?? Thanks, $clientID is a string but is not empty...already tried echo($clientID) and it is not empty. Did you mean that if the value of $cientID is a string it wont work Thanks Brad > From: Bogdan Stancescu <[EMAIL PROTECTED]> > Date: Mon, 11 Feb 2002 05:38:31 +0200 > To: Brad Wright <[EMAIL PROTECTED]> > Cc: PHP General List <[EMAIL PROTECTED]> > Subject: Re: [PHP] 2 conditions why wont they work?? > > Do an echo($clientID) before - it most probably is either empty or it's a > string and MySQL actually issues errors there. > > Bogdan > > Brad Wright wrote: > >> Hi all, >> Im was sure you could select a row from a mySQL database based on 2 >> conditions. My code: >> >> $query2 = "select * from Table where userNo = $userNo and clientID = >> $clientID"; >> $result2 = mysql_query($query2,$db); >> >> This returns : >> Warning: Supplied argument is not a valid MySQL result resource >> >> b ut if i change the line to: >> $query2 = "select * from Table where userNo = $userNo; >> $result2 = mysql_query($query2,$db); >> >> it works (but get all the rows with userNo = $userNo. >> >> HELP Im sure this should work...what am i doing wrong??? >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 2 conditions why wont they work??
Ahh..that seems to have fixed it. Its now pulling NO data, but is not giving error msg thanks, 1/2 way there now :) brad > From: Bogdan Stancescu <[EMAIL PROTECTED]> > Date: Mon, 11 Feb 2002 05:46:46 +0200 > To: Brad Wright <[EMAIL PROTECTED]> > Cc: PHP General List <[EMAIL PROTECTED]> > Subject: Re: [PHP] 2 conditions why wont they work?? > > No, with your syntax it won't. You have to quote it in the query, as in > $query2 = "select * from Table where userNo = $userNo and clientID = > '$clientID'"; > > Bogdan > > Brad Wright wrote: > >> Thanks, >> >> $clientID is a string but is not empty...already tried echo($clientID) and >> it is not empty. >> >> Did you mean that if the value of $cientID is a string it wont work >> >> Thanks >> Brad >> >>> From: Bogdan Stancescu <[EMAIL PROTECTED]> >>> Date: Mon, 11 Feb 2002 05:38:31 +0200 >>> To: Brad Wright <[EMAIL PROTECTED]> >>> Cc: PHP General List <[EMAIL PROTECTED]> >>> Subject: Re: [PHP] 2 conditions why wont they work?? >>> >>> Do an echo($clientID) before - it most probably is either empty or it's a >>> string and MySQL actually issues errors there. >>> >>> Bogdan >>> >>> Brad Wright wrote: >>> >>>> Hi all, >>>> Im was sure you could select a row from a mySQL database based on 2 >>>> conditions. My code: >>>> >>>> $query2 = "select * from Table where userNo = $userNo and clientID = >>>> $clientID"; >>>> $result2 = mysql_query($query2,$db); >>>> >>>> This returns : >>>> Warning: Supplied argument is not a valid MySQL result resource >>>> >>>> b ut if i change the line to: >>>> $query2 = "select * from Table where userNo = $userNo; >>>> $result2 = mysql_query($query2,$db); >>>> >>>> it works (but get all the rows with userNo = $userNo. >>>> >>>> HELP Im sure this should work...what am i doing wrong??? >>>> >>>> -- >>>> PHP General Mailing List (http://www.php.net/) >>>> To unsubscribe, visit: http://www.php.net/unsub.php >>> >>> >>> -- >>> PHP General Mailing List (http://www.php.net/) >>> To unsubscribe, visit: http://www.php.net/unsub.php >>> > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 2 conditions why wont they work??
No, with your syntax it won't. You have to quote it in the query, as in $query2 = "select * from Table where userNo = $userNo and clientID = '$clientID'"; Bogdan Brad Wright wrote: > Thanks, > > $clientID is a string but is not empty...already tried echo($clientID) and > it is not empty. > > Did you mean that if the value of $cientID is a string it wont work > > Thanks > Brad > > > From: Bogdan Stancescu <[EMAIL PROTECTED]> > > Date: Mon, 11 Feb 2002 05:38:31 +0200 > > To: Brad Wright <[EMAIL PROTECTED]> > > Cc: PHP General List <[EMAIL PROTECTED]> > > Subject: Re: [PHP] 2 conditions why wont they work?? > > > > Do an echo($clientID) before - it most probably is either empty or it's a > > string and MySQL actually issues errors there. > > > > Bogdan > > > > Brad Wright wrote: > > > >> Hi all, > >> Im was sure you could select a row from a mySQL database based on 2 > >> conditions. My code: > >> > >> $query2 = "select * from Table where userNo = $userNo and clientID = > >> $clientID"; > >> $result2 = mysql_query($query2,$db); > >> > >> This returns : > >> Warning: Supplied argument is not a valid MySQL result resource > >> > >> b ut if i change the line to: > >> $query2 = "select * from Table where userNo = $userNo; > >> $result2 = mysql_query($query2,$db); > >> > >> it works (but get all the rows with userNo = $userNo. > >> > >> HELP Im sure this should work...what am i doing wrong??? > >> > >> -- > >> PHP General Mailing List (http://www.php.net/) > >> To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 2 conditions why wont they work??
Thanks, $clientID is a string but is not empty...already tried echo($clientID) and it is not empty. Did you mean that if the value of $cientID is a string it wont work Thanks Brad > From: Bogdan Stancescu <[EMAIL PROTECTED]> > Date: Mon, 11 Feb 2002 05:38:31 +0200 > To: Brad Wright <[EMAIL PROTECTED]> > Cc: PHP General List <[EMAIL PROTECTED]> > Subject: Re: [PHP] 2 conditions why wont they work?? > > Do an echo($clientID) before - it most probably is either empty or it's a > string and MySQL actually issues errors there. > > Bogdan > > Brad Wright wrote: > >> Hi all, >> Im was sure you could select a row from a mySQL database based on 2 >> conditions. My code: >> >> $query2 = "select * from Table where userNo = $userNo and clientID = >> $clientID"; >> $result2 = mysql_query($query2,$db); >> >> This returns : >> Warning: Supplied argument is not a valid MySQL result resource >> >> b ut if i change the line to: >> $query2 = "select * from Table where userNo = $userNo; >> $result2 = mysql_query($query2,$db); >> >> it works (but get all the rows with userNo = $userNo. >> >> HELP Im sure this should work...what am i doing wrong??? >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] 2 conditions why wont they work??
Yes - that's most likely the answer.. if the echo doesn't help, try something like this.. $result2 = mysql_query($query2,$db) or die(mysql_error()); If mysql is throwing up an error, that'll present it too you and stop execution.. -Original Message- From: Bogdan Stancescu [mailto:[EMAIL PROTECTED]] Sent: 11 February 2002 03:39 To: Brad Wright Cc: PHP General List Subject: Re: [PHP] 2 conditions why wont they work?? Do an echo($clientID) before - it most probably is either empty or it's a string and MySQL actually issues errors there. Bogdan Brad Wright wrote: > Hi all, > Im was sure you could select a row from a mySQL database based on 2 > conditions. My code: > > $query2 = "select * from Table where userNo = $userNo and clientID = > $clientID"; > $result2 = mysql_query($query2,$db); > > This returns : > Warning: Supplied argument is not a valid MySQL result resource > > b ut if i change the line to: > $query2 = "select * from Table where userNo = $userNo; > $result2 = mysql_query($query2,$db); > > it works (but get all the rows with userNo = $userNo. > > HELP Im sure this should work...what am i doing wrong??? > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 2 conditions why wont they work??
Do an echo($clientID) before - it most probably is either empty or it's a string and MySQL actually issues errors there. Bogdan Brad Wright wrote: > Hi all, > Im was sure you could select a row from a mySQL database based on 2 > conditions. My code: > > $query2 = "select * from Table where userNo = $userNo and clientID = > $clientID"; > $result2 = mysql_query($query2,$db); > > This returns : > Warning: Supplied argument is not a valid MySQL result resource > > b ut if i change the line to: > $query2 = "select * from Table where userNo = $userNo; > $result2 = mysql_query($query2,$db); > > it works (but get all the rows with userNo = $userNo. > > HELP Im sure this should work...what am i doing wrong??? > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
