RE: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Johnson, Kirk
http://www.php.net/manual/en/function.eval.php Kirk > -Original Message- > From: Christopher Raymond [mailto:[EMAIL PROTECTED]] > Sent: Friday, November 09, 2001 1:11 PM > To: PHP List > Subject: Re: [PHP] Eval()??? A variables contents? > > > on 11/9/01

Re: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Christopher Raymond
on 11/9/01 2:01 PM, Kurt Lieber at [EMAIL PROTECTED] wrote: > What you're doing doesn't make any sense. If it were to work, it would look > like the following: > > ; ?>, > > or something similar. I think what you want to do is: > $content = query_database($category); > echo $content; > ?> >

Re: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Chris Hobbs
I just asked a similar question yesterday. The answer is, conveniently enough, eval(). One trick from the php.net page on the function is to do somehting like this: $content = ""; echo eval ("?>$content"); Christopher Raymond wrote: > > PHP Gurus: > > I have one for you. I'm sure there is a

Re: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Kurt Lieber
On Friday 09 November 2001 11:51 am, Christopher Raymond wrote: > Let's say I have: > > $content = ""; > > > If I use , it doesn't evaluate that content. What am > I doing wrong here? What you're doing doesn't make any sense. If it were to work, it would look like the following: ; ?>, or som