Re: [PHP] PHP Syntax Help - Check?
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
Cheers,
Rob.
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Re: [PHP] PHP Syntax Help - Check?
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
This is true. But perhaps more importantly, check() is not a native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
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Paul M. Foster
--
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Re: [PHP] PHP Syntax Help - Check?
OK... external function... that would explain why I could not locate it.
Let me get right to the problem I am having with this code as someone
may be able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact
form they do so to formcheck.php and if formcheck.php sees a required
field is blank, it throws it back to mypage.php with an alert. BUT, I
lose the value of the variable $my_id. SO, I created a hidden field
on mypate.php with value=?php echo $my_id; ? and on
formcheck.php, I added $my_id = $_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is still
blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
This is true. But perhaps more importantly, check() is not a native
PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Syntax Help - Check?
if you do the redirection with header('Location: /mypage.php'),
setting a variable on formcheck.php is not enough.
if you modify the header('Location: /mypage.php') to..
header('Location: /mypage.php?my_id=5')
it will take the variable to mypage.php as $_GET['my_id]
you can not expect a variable value set in to $_POST array to reflect
on a totally different page without making it a form post (aka use of
proper headers).
i guess, it's time to you to read about session_start() method and the
array $_SESSION available in php :)
~viraj
On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer rpdw...@earthlink.net wrote:
OK... external function... that would explain why I could not locate it.
Let me get right to the problem I am having with this code as someone may be
able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact form
they do so to formcheck.php and if formcheck.php sees a required field is
blank, it throws it back to mypage.php with an alert. BUT, I lose the value
of the variable $my_id. SO, I created a hidden field on mypate.php with
value=?php echo $my_id; ? and on formcheck.php, I added $my_id =
$_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is still blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with parameter
'element8'.
This is true. But perhaps more importantly, check() is not a native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
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PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
~viraj
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Re: [PHP] PHP Syntax Help - Check?
On Thu, Feb 25, 2010 at 4:22 PM, Rick Dwyer rpdw...@earthlink.net wrote: OK... external function... that would explain why I could not locate it. Let me get right to the problem I am having with this code as someone may be able to help directly. I have a link on a page that opens a contact form. The link is mypage.php?my_id=5 So on mypage.php, I capture this value with: $my_id=$_GET['my_id']; I understand this much. But when the end user submits this contact form they do so to formcheck.php and if formcheck.php sees a required field is blank, it throws it back to mypage.php with an alert. BUT, I lose the value of the variable $my_id. SO, I created a hidden field on mypate.php with value=?php echo $my_id; ? and on formcheck.php, I added $my_id = $_Post['my_id']; However, when formcheck.php returns me to mypage.php, $my_id is still blank. Use the right varialble for the method you're using, so if you're posting, use $_POST, if you're getting use $_GET.. Going by your example, $_GET is what you should probably be using, this is usually the default method if no method is specified on the form tag. Cheers -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Syntax Help - Check?
Hmm. OK with the help below, I am closer.
The other fields on the page are getting passed via form fields that
look like this:
input type=text value=?php echo check('element9'); ?
name=form[element9] size=40 maxlength=255
so I added:
input type=text value=?php echo check('my_id'); ?
name=form[my_id] size=40 maxlength=255
and formcheck.php has:
?php
//start the session
session_start();
//array of fields in form. (In the format field_name = field_label)
$form_fields = array(
element0 = 'Your Name:',
element1 = 'Your Email:',
element4 = 'Item Number:',
.
);
and I added:
my_id = 'My ID Is:',
And this works!
So when I am on mypage.php and I enter a value into the form field
my_id it carries over and repopulates should the form fail validation.
But upon initial load of the page from my link of mypage.php?my_id=5
(so I am not getting there via a form submit) how do I get the value
into the form field?
--Rick
On Feb 25, 2010, at 1:02 AM, viraj wrote:
if you do the redirection with header('Location: /mypage.php'),
setting a variable on formcheck.php is not enough.
if you modify the header('Location: /mypage.php') to..
header('Location: /mypage.php?my_id=5')
it will take the variable to mypage.php as $_GET['my_id]
you can not expect a variable value set in to $_POST array to reflect
on a totally different page without making it a form post (aka use of
proper headers).
i guess, it's time to you to read about session_start() method and the
array $_SESSION available in php :)
~viraj
On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer rpdw...@earthlink.net
wrote:
OK... external function... that would explain why I could not
locate it.
Let me get right to the problem I am having with this code as
someone may be
able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact
form
they do so to formcheck.php and if formcheck.php sees a required
field is
blank, it throws it back to mypage.php with an alert. BUT, I lose
the value
of the variable $my_id. SO, I created a hidden field on mypate.php
with
value=?php echo $my_id; ? and on formcheck.php, I added $my_id =
$_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is
still blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what check means?
In the above, check is a function. It is being called with
parameter
'element8'.
This is true. But perhaps more importantly, check() is not a
native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
~viraj
--
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To unsubscribe, visit: http://www.php.net/unsub.php
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