Re: [PHP] Regex help please
haliphax wrote:
> On Fri, Mar 27, 2009 at 9:40 AM, Shawn McKenzie wrote:
>> I'm normally OK with regex, especially if I fiddle with it long enough,
>> however I have fiddled with this one so long that I'm either totally
>> missing it or it's something simple. Does it have anything to do with
>> the backref, or the fact that the value of the backref has a $? I have:
>>
>> $out = '
>> {$sites}
>>
>>
>>{Site.id}
>>
>>
>> {/$sites}';
>>
>> And I want to capture the first {$tag}, everything in between and the
>> last {$/tag}. I have tried several things and here is my current regex
>> that looks like it should work, but doesn't:
>>
>> preg_match_all('|{\$([^}]+)}(.+)({/\1})|Us', $out, $matches);
>
> Shawn,
>
> First thing I see--your first capture group doesn't include the $, and
> so your final capture group will always fail given your current $out
> (because it's looking for {/sites} instead of {/$sites}). Also, your
> {} are outside of your capture group in \1, but inside in \3. Here's
> what I came up with:
>
> $out = '
> {$sites}
>
>
>{Site.id}
>
>
> {/$sites}';
> $matches = array();
> preg_match_all('#{(\$[^}]+)}(.*?){(/\1)}#s', $out, $matches);
> print_r($matches);
>
> Produces this:
>
> Array
> (
> [0] => Array
> (
> [0] => {$sites}
>
>
>{Site.id}
>
>
> {/$sites}
> )
>
> [1] => Array
> (
> [0] => $sites
> )
>
> [2] => Array
> (
> [0] =>
>
>
>{Site.id}
>
>
>
> )
>
> [3] => Array
> (
> [0] => /$sites
> )
>
> )
>
> Keep in mind, I had to view the page source in order to see the HTML
> tags, but it showed me everything I expected to see.
>
> HTH,
>
Yes, thank you. I was fiddling before I got your post and I came up
with roughly the same.
preg_match_all('|{(\$[^}]+)}(.+){(/\1)}|Us', $out, $matches);
--
Thanks!
-Shawn
http://www.spidean.com
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Re: [PHP] Regex help please
On Fri, Mar 27, 2009 at 9:40 AM, Shawn McKenzie wrote:
> I'm normally OK with regex, especially if I fiddle with it long enough,
> however I have fiddled with this one so long that I'm either totally
> missing it or it's something simple. Does it have anything to do with
> the backref, or the fact that the value of the backref has a $? I have:
>
> $out = '
> {$sites}
>
>
> {Site.id}
>
>
> {/$sites}';
>
> And I want to capture the first {$tag}, everything in between and the
> last {$/tag}. I have tried several things and here is my current regex
> that looks like it should work, but doesn't:
>
> preg_match_all('|{\$([^}]+)}(.+)({/\1})|Us', $out, $matches);
Shawn,
First thing I see--your first capture group doesn't include the $, and
so your final capture group will always fail given your current $out
(because it's looking for {/sites} instead of {/$sites}). Also, your
{} are outside of your capture group in \1, but inside in \3. Here's
what I came up with:
$out = '
{$sites}
{Site.id}
{/$sites}';
$matches = array();
preg_match_all('#{(\$[^}]+)}(.*?){(/\1)}#s', $out, $matches);
print_r($matches);
Produces this:
Array
(
[0] => Array
(
[0] => {$sites}
{Site.id}
{/$sites}
)
[1] => Array
(
[0] => $sites
)
[2] => Array
(
[0] =>
{Site.id}
)
[3] => Array
(
[0] => /$sites
)
)
Keep in mind, I had to view the page source in order to see the HTML
tags, but it showed me everything I expected to see.
HTH,
--
// Todd
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Re: [PHP] REGEX Help Please
On Monday 19 September 2005 09:03 am, Shaun wrote:
> Hi,
>
> I am trying to implement a regular expression so that I have a number
> between 0.00 and 1.00. the following works except I can go up to 1.99
>
> $regexp = "/^[0-1]{1}.[0-9]{2}/";
>
> Can anyone help here please?
>
> Thanks
$regexp = "/^(0\.[0-9]{2}|1\.00)/";
that should work :)
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Re: [PHP] REGEX Help Please
On Mon, 2005-09-19 at 10:11, John Nichel wrote:
> Shaun wrote:
> > Hi,
> >
> > I am trying to implement a regular expression so that I have a number
> > between 0.00 and 1.00. the following works except I can go up to 1.99
> >
> > $regexp = "/^[0-1]{1}.[0-9]{2}/";
> >
> > Can anyone help here please?
> >
> > Thanks
> >
>
> May have to go outside just a regex...
>
> if ( preg_match ( "/^\d{1}\.\d{2}$/", $number ) && $number >= 0 &&
> $number <= 1 )
$regexp = '/^((1\.00)|(0\.\d\d))$/';
Cheers,
Rob.
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Re: [PHP] REGEX Help Please
Shaun wrote:
Hi,
I am trying to implement a regular expression so that I have a number
between 0.00 and 1.00. the following works except I can go up to 1.99
$regexp = "/^[0-1]{1}.[0-9]{2}/";
Can anyone help here please?
Thanks
May have to go outside just a regex...
if ( preg_match ( "/^\d{1}\.\d{2}$/", $number ) && $number >= 0 &&
$number <= 1 )
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716.856.9675
[EMAIL PROTECTED]
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Re: [PHP] Regex help - PLease
>Sorry I to should have added this this is what im going with so far > >preg_match(/\d100.*/); This will match a digit, followed by '100', followed by anything. Go with Rob's suggestion. - michal migurski- contact info and pgp key: sf/cahttp://mike.teczno.com/contact.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regex help - PLease
On 03/16/2004 6:57 AM, Rob Ellis <[EMAIL PROTECTED]> wrote:
> On Tue, Mar 16, 2004 at 02:39:27PM +0200, Brent Clark wrote:
>> Hi there
>>
>> im in desperate need of help for a reg expression to ONLY allow 8 NUMBERS to
>> start with 100 and may not have any other kind of
>> letters or characters. Only numbers
>>
>> for example
>> 10064893
>>
>
> if (preg_match('/^100\d{5}/', $test))
> print "ok\n";
Unless you want to allow something like '10064893A' to match, use:
preg_match('/^100\d{5}$/', $test)
Pablo
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Re: [PHP] Regex help - PLease
On Tue, Mar 16, 2004 at 02:39:27PM +0200, Brent Clark wrote:
> Hi there
>
> im in desperate need of help for a reg expression to ONLY allow 8 NUMBERS to start
> with 100 and may not have any other kind of
> letters or characters. Only numbers
>
> for example
> 10064893
>
if (preg_match('/^100\d{5}/', $test))
print "ok\n";
- rob
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Re: [PHP] Regex help - PLease
Hello Brent,
Tuesday, March 16, 2004, 12:39:27 PM, you wrote:
BC> im in desperate need of help for a reg expression to ONLY allow 8
BC> NUMBERS to start with 100 and may not have any other kind of
BC> letters or characters. Only numbers
BC> for example
BC> 10064893
It's not a reg exp, but it will work:
if (is_numeric($val) == FALSE || strlen($val) <> 8 || substr($val, 0,
3) !== "100")
{
// $val doesn't match
}
Conversely:
if (is_numeric($val) == TRUE && strlen($val) == 8 && substr($val, 0,
3) == "100")
{
// $val does match
}
(Code not tested, but you get the idea I hope)
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Best regards,
Richard Davey
http://www.phpcommunity.org/wiki/296.html
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