Re: [PHP] Unable to return object references from functions
Hello, Tom Rogers wrote: Hi again Got a bit sidetracked ... here is your original code :) Thanks, I managed to make it work for me similarly to that. Now, a different problem, I already have array variable with a object. Is there a way to make a function return a reference to that object in a variable passed by reference to a function? Regards, Manuel Lemos -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Unable to return object references from functions
Hi What is the scope of the array that holds the object ? Maybe a bit of code to show what you are after :) Tom At 03:37 PM 17/12/01, Manuel Lemos wrote: Hello, Tom Rogers wrote: Hi again Got a bit sidetracked ... here is your original code :) Thanks, I managed to make it work for me similarly to that. Now, a different problem, I already have array variable with a object. Is there a way to make a function return a reference to that object in a variable passed by reference to a function? Regards, Manuel Lemos -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Unable to return object references from functions
Hello,
Tom Rogers wrote:
Hi
What is the scope of the array that holds the object ?
global
Maybe a bit of code to show what you are after :)
It is to implement another function that will return a reference (not a
copy) of a object stored in a global array passing the index of the
array. It would be like this, except that this code does not work as I
need:
$objects=array();
Function CreateObject($index)
{
global $objects;
$index=count($objects);
$objects[$index]=new my_class;
}
Function GetObject($index,$object)
{
global $objects;
$object= $objects[$index];
}
CreateObject($index);
GetObject($index,$my_object);
Regards,
Manuel Lemos
Tom
At 03:37 PM 17/12/01, Manuel Lemos wrote:
Hello,
Tom Rogers wrote:
Hi again
Got a bit sidetracked ... here is your original code :)
Thanks, I managed to make it work for me similarly to that.
Now, a different problem, I already have array variable with a object.
Is there a way to make a function return a reference to that object in a
variable passed by reference to a function?
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Re: [PHP] Unable to return object references from functions
Hi
Is this doing what you want, seems you have to use an array to create the
ref (just getting a handle on objects :)
?
class test_class
{
var $dummy=nothing;
};
Function assigning($returned,$copy,$object)
{
global $success;
$object-dummy=original;
$success=1;
$copy=$object;
$copy-dummy=copy;
$returned[] = $object;
var_dump(In the function,$success,$returned[0],$copy,$object);
return $object;
}
$object = assigning($returned,$copy,new test_class);
echo brbr;
var_dump(Out the function,$success,$returned[0],$copy,$object);
?
At 03:06 PM 15/12/01, you wrote:
Hello,
I am trying to return a reference from an object created inside a
function and at the same time have the object stored in a global
variable.
It seems that when I try doing it by assigning the object reference to a
function argument that is passed by reference, nothing is returned in
that variable despite inside the function the argument variable seems to
have the right value.
Is this a PHP bug or this is not the right way to do it?
Try the example below.
Manuel Lemos
?
class test_class
{
var $dummy=nothing;
};
Function not_assigning($not_returned,$copy)
{
global $object;
$object=new test_class;
$object-dummy=original;
$success=1;
$not_returned= $object;
$copy=$object;
$copy-dummy=copy;
var_dump(In the function,$success,$not_returned,$copy,$object);
return $success;
}
$success=not_assigning($not_returned,$copy);
var_dump(Out the function,$success,$not_returned,$copy,$object);
?
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Re: [PHP] Unable to return object references from functions
Hi again
Got a bit sidetracked ... here is your original code :)
class test_class2
{
var $dummy=nothing;
};
Function not_assigning($not_returned,$copy)
{
global $object;
$object = new test_class;
$object-dummy=original;
$success=1;
$not_returned[] = $object;
$copy=$object;
$copy-dummy=copy;
var_dump(In the function,$success,$not_returned[0],$copy,$object);
return $success;
}
$success = not_assigning($not_returned,$copy);
echo brbr;
var_dump(Out the function,$success,$not_returned[0],$copy,$object);
?
At 02:15 PM 16/12/01, Tom Rogers wrote:
Hi
Is this doing what you want, seems you have to use an array to create the
ref (just getting a handle on objects :)
?
class test_class
{
var $dummy=nothing;
};
Function assigning($returned,$copy,$object)
{
global $success;
$object-dummy=original;
$success=1;
$copy=$object;
$copy-dummy=copy;
$returned[] = $object;
var_dump(In the function,$success,$returned[0],$copy,$object);
return $object;
}
$object = assigning($returned,$copy,new test_class);
echo brbr;
var_dump(Out the function,$success,$returned[0],$copy,$object);
?
At 03:06 PM 15/12/01, you wrote:
Hello,
I am trying to return a reference from an object created inside a
function and at the same time have the object stored in a global
variable.
It seems that when I try doing it by assigning the object reference to a
function argument that is passed by reference, nothing is returned in
that variable despite inside the function the argument variable seems to
have the right value.
Is this a PHP bug or this is not the right way to do it?
Try the example below.
Manuel Lemos
?
class test_class
{
var $dummy=nothing;
};
Function not_assigning($not_returned,$copy)
{
global $object;
$object=new test_class;
$object-dummy=original;
$success=1;
$not_returned= $object;
$copy=$object;
$copy-dummy=copy;
var_dump(In the function,$success,$not_returned,$copy,$object);
return $success;
}
$success=not_assigning($not_returned,$copy);
var_dump(Out the function,$success,$not_returned,$copy,$object);
?
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