Re: [PHP] update query not working

2003-02-23 Thread Jason Wong
On Monday 24 February 2003 06:56, Peter Gumbrell wrote:
> I wonder if anyone can see why the following code is not working. this is
> taken from a larger functions, the rest of which seems to be working well:
>
> print "";
> print "";
>
> print "";
> print "";
> if ($_POST['Update'])

[snip]

print_r($_POST) to see what it contains. It probably contains an entry named 
'Submit' as that is what you have named your submit button.

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
--
Search the list archives before you post
http://marc.theaimsgroup.com/?l=php-general
--
/*
Trying to be happy is like trying to build a machine for which the only
specification is that it should run noiselessly.
*/


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



Re: [PHP] update query not working

2003-02-23 Thread Chris Hayes


print "";
print "";



if ($_POST['Update'])
{
print "updated!!";
}
I do not see the statement "updated!!!" printed, but I cannot see anything
wrong with my syntax. Any help would be appreciated.
You are looking for a value, where the array is of the form
 $_POST['form_element_NAME'='form_element_VALUE'
So try looking for

if ($_POST['Submit']=='Update')
{
}


--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php


Re: [PHP] Update query

2002-12-12 Thread Jason Wong
On Thursday 12 December 2002 18:48, Steve Jackson wrote:
> It doesn't work in that it doesn't update the database.
> I have a form which when loaded takes a variable ItemCode from the
> previous page (which gets the Itemcode from the DB) and puts it into a
> hidden field which I call oldItemCode, then when I try to update the
> $ItemCode row in the database with the edited changes using the
> oldItemCode as an identifier it won't update - It goes to my error
> message shown below. So what I'm asking is there anything I'm doing
> wrong. I noted your points about the comma and have changed the code.
>
>  $query = "update products
>  set ItemCode='$ItemCode',
>  ItemName ='$ItemName',
>  catid ='$catid',
>price = '$price',
>  description = '$description',
>shortdesc = '$shortdesc',
>  where ItemCode='$oldItemCode'";
>   $result = mysql_query($query);

You've got an extra comma after '$shortdesc' which you should remove.

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *

/*
Conscious is when you are aware of something and conscience is when you
wish you weren't.
*/


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




Re: [PHP] Update query

2002-12-12 Thread Bastian Vogt
Hi,

did you "echo $query;" and put the output into phpmyadmin?
Perhaps there's an error message that may help you

HTH,
Bastian

Steve Jackson schrieb:

> It doesn't work in that it doesn't update the database.
> I have a form which when loaded takes a variable ItemCode from the
> previous page (which gets the Itemcode from the DB) and puts it into a
> hidden field which I call oldItemCode, then when I try to update the
> $ItemCode row in the database with the edited changes using the
> oldItemCode as an identifier it won't update - It goes to my error
> message shown below. So what I'm asking is there anything I'm doing
> wrong. I noted your points about the comma and have changed the code.
>
>  $query = "update products
>  set ItemCode='$ItemCode',
>  ItemName ='$ItemName',
>  catid ='$catid',
>  price = '$price',
>  description = '$description',
>  shortdesc = '$shortdesc',
>  where ItemCode='$oldItemCode'";
> $result = mysql_query($query);
> if (!$result)
> {
> echo " cellpadding='0' align='center' bgcolor='#629D39'>";
> echo " src='images/admin_orders_administrate.gif'>";
> echo " ";
> echo "Could not change
> details: please click
> here to email the administrator";
> echo "";
> echo "";
> echo "";
> }
> else
> {
> echo " cellpadding='0' align='center' bgcolor='#629D39'>";
> echo " src='images/admin_orders_administrate.gif'>";
> echo " ";
> echo "Your product has been
> successfully edited";
> echo "";
> echo "";
> echo "";
> echo "";
> echo " src='images/admin_orders_upload.gif' border='0'>";
> echo "";
> echo "";
> }
> ?>


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




RE: [PHP] Update query

2002-12-12 Thread Steve Jackson
It doesn't work in that it doesn't update the database.
I have a form which when loaded takes a variable ItemCode from the
previous page (which gets the Itemcode from the DB) and puts it into a
hidden field which I call oldItemCode, then when I try to update the
$ItemCode row in the database with the edited changes using the
oldItemCode as an identifier it won't update - It goes to my error
message shown below. So what I'm asking is there anything I'm doing
wrong. I noted your points about the comma and have changed the code. 

";
echo "";
echo " ";
echo "Could not change
details: please click
here to email the administrator";
echo "";
echo "";
echo "";
}
else
{
echo "";
echo "";
echo " ";
echo "Your product has been
successfully edited";
echo "";
echo "";
echo "";
echo "";
echo "";
echo "";
echo "";
}
?>


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




Re: [PHP] Update query

2002-12-12 Thread Jason Wong
On Thursday 12 December 2002 17:00, Steve Jackson wrote:
> How do you update MySQL in the following way?
> I have designed a form which has all the fields in the database
> available to edit based on a user query. The query is a field called
> $ItemCode.
>
> If the user wants to change that $ItemCode field how do I update it? In
> other words how do I use PHP to update the database row called $ItemCode
> with a new $ItemCode where $ItemCode is $ItemCode?
>
> Here is what I've tried and failed at!

Please, when something doesn't work, you got to describe _HOW_ it doesn't 
work!

> $oldItemCode = $ItemCode;
>   $query = "update products
>  set ItemCode='$newItemCode',
>  ItemName ='$ItemName',
>  catid = '$catid',
>  price = '$price',
>  description = '$description'
>shortdesc = '$shortdesc'
>  where ItemCode='$oldItemCode'";

You seem to be missing a comma after --> description = '$description'

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *

/*
We all know that no one understands anything that isn't funny.
*/


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




Re: [PHP] Update query

2002-12-12 Thread Tim Ward
The best way would be to design the table so that it had an
item_id field that was an auto-incremented integer and not
updateable. It shouldn't be too late to add such a field, then it
can be passed from the form as a hidden field (as I assume
you're currently doing with $oldItemCode).

Tim Ward
http://www.chessish.com
mailto:[EMAIL PROTECTED]
- Original Message - 
From: Steve Jackson <[EMAIL PROTECTED]>
To: PHP General <[EMAIL PROTECTED]>
Sent: Thursday, December 12, 2002 9:00 AM
Subject: [PHP] Update query


> How do you update MySQL in the following way?
> I have designed a form which has all the fields in the database
> available to edit based on a user query. The query is a field called
> $ItemCode.
> 
> If the user wants to change that $ItemCode field how do I update it? In
> other words how do I use PHP to update the database row called $ItemCode
> with a new $ItemCode where $ItemCode is $ItemCode?
> 
> Here is what I've tried and failed at!
> $oldItemCode = $ItemCode;
> $query = "update products
>  set ItemCode='$newItemCode',
>  ItemName ='$ItemName',
>  catid = '$catid',
>  price = '$price',
>  description = '$description'
> shortdesc = '$shortdesc'
>  where ItemCode='$oldItemCode'";
> 
> Steve Jackson
> Web Developer
> Viola Systems Ltd.
> http://www.violasystems.com
> [EMAIL PROTECTED]
> Mobile +358 50 343 5159
> 
> 
> -- 
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
> 
> 


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




RE: [PHP] update query based on array

2002-12-10 Thread Jason Dulberg
Thanks Mike, that fixed the problem that I had!

Jason

> -Original Message-
> From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]]
> Sent: December 10, 2002 6:21 AM
> To: 'Jason Dulberg'
> Cc: [EMAIL PROTECTED]
> Subject: RE: [PHP] update query based on array
> 
> 
> > -Original Message-
> > From: Jason Dulberg [mailto:[EMAIL PROTECTED]]
> > Sent: 09 December 2002 23:52
> > 
> > So you mean do something like:
> > 
> > 
> > 
> > 
> > 
> > Doesn't that create 2 additional arrays though?
> 
> Yes -- but how else are you going to get multiple values for each 
> name from
> your form to your PHP script?  Without the array subscripts on 
> both category
> and rank, you will only ever get one category and one rank passed to your
> script.
> 
> Using the above, just do:
> 
> foreach ($_POST['rankid'] as $row, $rankid):
> // in here, $rankid is the value of the current rankid[]
> // $_POST['category'][$row] is associated category[] value
> // $_POST['rank'][$row] is associated rank[] value
> endforeach;
> 
> Cheers!
> 
> Mike
> 
> -
> Mike Ford,  Electronic Information Services Adviser,
> Learning Support Services, Learning & Information Services,
> JG125, James Graham Building, Leeds Metropolitan University,
> Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
> Email: [EMAIL PROTECTED]
> Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211 
> 

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




RE: [PHP] update query based on array

2002-12-10 Thread Ford, Mike [LSS]
> -Original Message-
> From: Jason Dulberg [mailto:[EMAIL PROTECTED]]
> Sent: 09 December 2002 23:52
> 
> So you mean do something like:
> 
> 
> 
> 
> 
> Doesn't that create 2 additional arrays though?

Yes -- but how else are you going to get multiple values for each name from
your form to your PHP script?  Without the array subscripts on both category
and rank, you will only ever get one category and one rank passed to your
script.

Using the above, just do:

foreach ($_POST['rankid'] as $row, $rankid):
// in here, $rankid is the value of the current rankid[]
// $_POST['category'][$row] is associated category[] value
// $_POST['rank'][$row] is associated rank[] value
endforeach;

Cheers!

Mike

-
Mike Ford,  Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211 


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




Re: [PHP] update query based on array

2002-12-09 Thread Jason Wong
On Tuesday 10 December 2002 07:06, Jason Dulberg wrote:
> I am displaying a list of data (from an sql query) and some of the fields
> in that list are editable through a form. If the user chooses to edit one
> or more of the rows of data, they must click on a checkbox to add that row
> to an "update array". The problem is that when I read that array to pass to
> an UPDATE sql statement, it only passes the last entry of the array.
>
> Here's an example of the data being passed:
> 13 - 4 - UPDATE ranking SET category='Prep School', rank='30' WHERE pid=4
> 14 - 169 - UPDATE ranking SET category='Prep School', rank='30' WHERE
> pid=169
> 15 - 166 - UPDATE ranking SET category='Prep School', rank='30' WHERE
> pid=166
>
> The above is created based on the following html code:
> //the last row
> 
> 

The above two are named the same for ALL your rows so it will take the value 
of the last row, hence your problem. In general, each of your form elements 
must have a unique name.

> 
>
> So as you can see, its only reading the last row and assigning its values
> to the data above as well.

Name your rows something along the lines of:









Then to process:

  foreach ($rows as $row) {
echo "$row['category'], $row['rank'], $row['rankid']";
  }

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *

/*
Fudd's First Law of Opposition:
Push something hard enough and it will fall over.
*/


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




RE: [PHP] update query based on array

2002-12-09 Thread Jason Dulberg
So you mean do something like:





Doesn't that create 2 additional arrays though?

Basically my form is just row after row of the html code above... each row
has a different ID of course. The update query should only update fields
with checked checkboxes.

Thanks for your input!

Jason


> -Original Message-
> From: Jimmy Brake [mailto:[EMAIL PROTECTED]]
> Sent: December 9, 2002 6:29 PM
> To: Jason Dulberg
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP] update query based on array
>
>
> not real sure of the setup of the form but if you have mutiple groups of
> items to be updated then you should make the rank an array -- rank[pid#]
>
> you should make all the items -- that are related part of the same group
> -- by using []
>
> On Mon, 2002-12-09 at 15:06, Jason Dulberg wrote:
> > I am displaying a list of data (from an sql query) and some of
> the fields in
> > that list are editable through a form. If the user chooses to
> edit one or
> > more of the rows of data, they must click on a checkbox to add
> that row to
> > an "update array". The problem is that when I read that array
> to pass to an
> > UPDATE sql statement, it only passes the last entry of the array.
> >
> > Here's an example of the data being passed:
> > 13 - 4 - UPDATE ranking SET category='Prep School', rank='30'
> WHERE pid=4
> > 14 - 169 - UPDATE ranking SET category='Prep School', rank='30' WHERE
> > pid=169
> > 15 - 166 - UPDATE ranking SET category='Prep School', rank='30' WHERE
> > pid=166
> >
> > The above is created based on the following html code:
> > //the last row
> > 
> > 
> > 
> >
> > So as you can see, its only reading the last row and assigning
> its values to
> > the data above as well.
> >
> > Here's what I'm using for the sql query:
> >
> > while(list($key,$val)=each($rankid)) {
> >$upd=mysql_query("UPDATE ranking SET category='$category',
> rank='$rank'
> > WHERE pid=$val");
> > }
> >
> > If anyone has any suggestions for fixing this problem, please
> let me know :)
> > THanks
> >
> >
> > __
> > Jason Dulberg
> > Extreme MTB
> > http://extreme.nas.net
> --
> Jimmy Brake <[EMAIL PROTECTED]>
>


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




Re: [PHP] update query based on array

2002-12-09 Thread Jimmy Brake
not real sure of the setup of the form but if you have mutiple groups of
items to be updated then you should make the rank an array -- rank[pid#]

you should make all the items -- that are related part of the same group
-- by using [] 

On Mon, 2002-12-09 at 15:06, Jason Dulberg wrote:
> I am displaying a list of data (from an sql query) and some of the fields in
> that list are editable through a form. If the user chooses to edit one or
> more of the rows of data, they must click on a checkbox to add that row to
> an "update array". The problem is that when I read that array to pass to an
> UPDATE sql statement, it only passes the last entry of the array.
> 
> Here's an example of the data being passed:
> 13 - 4 - UPDATE ranking SET category='Prep School', rank='30' WHERE pid=4
> 14 - 169 - UPDATE ranking SET category='Prep School', rank='30' WHERE
> pid=169
> 15 - 166 - UPDATE ranking SET category='Prep School', rank='30' WHERE
> pid=166
> 
> The above is created based on the following html code:
> //the last row
> 
> 
> 
> 
> So as you can see, its only reading the last row and assigning its values to
> the data above as well.
> 
> Here's what I'm using for the sql query:
> 
> while(list($key,$val)=each($rankid)) {
>$upd=mysql_query("UPDATE ranking SET category='$category', rank='$rank'
> WHERE pid=$val");
> }
> 
> If anyone has any suggestions for fixing this problem, please let me know :)
> THanks
> 
> 
> __
> Jason Dulberg
> Extreme MTB
> http://extreme.nas.net
-- 
Jimmy Brake <[EMAIL PROTECTED]>


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




Re: [PHP] UPDATE Query

2002-09-01 Thread Tony Harrison

What about multiple tables? Can that be done?


"Mark Charette" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> No, only one db at a time may be updated. The "where" clauses can contain
> multiple db.
>
> -Original Message-
> From: Sascha Braun [mailto:[EMAIL PROTECTED]]
> Sent: Saturday, August 31, 2002 7:04 PM
> To: PHP Mailingliste
> Subject: [PHP] UPDATE Query
>
>
> I want to know if its possible to update two databases with one query?
>
> Please look at this example:
>
> UPDATE news_db, newsreferenz_db SET news_db.head = 'DFB Pokalasfasf',
> news_db.text = 'alkfhaslk fl akshf lakshf lkahs lfk aslf yxvyxvyxvyxv',
> newsreferenz_db.kat_id = '3' WHERE news_db.id = '6' AND
> newsreferenz_db.news_id = '6'
>
> it doesn't work.
>



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




RE: [PHP] UPDATE Query

2002-08-31 Thread Mark Charette

No, only one db at a time may be updated. The "where" clauses can contain
multiple db.

-Original Message-
From: Sascha Braun [mailto:[EMAIL PROTECTED]]
Sent: Saturday, August 31, 2002 7:04 PM
To: PHP Mailingliste
Subject: [PHP] UPDATE Query


I want to know if its possible to update two databases with one query?

Please look at this example:

UPDATE news_db, newsreferenz_db SET news_db.head = 'DFB Pokalasfasf',
news_db.text = 'alkfhaslk fl akshf lakshf lkahs lfk aslf yxvyxvyxvyxv',
newsreferenz_db.kat_id = '3' WHERE news_db.id = '6' AND
newsreferenz_db.news_id = '6'

it doesn't work.


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php




RE: [PHP] UPDATE Query works in odbc/Mysql, but fails in odbc/MS Access

2001-12-06 Thread Andrew Hill

mweb,

MS points to a datetime issue:
http://support.microsoft.com/default.aspx?scid=kb;EN-US;q246570

As far as a reference - I'm guessing somewhere on MS's site?

Best regards,
Andrew Hill
Director of Technology Evangelism
OpenLink Software  http://www.openlinksw.com
Universal Data Access & Data Integration Technology Providers


> -Original Message-
> From: mweb [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, December 06, 2001 7:30 AM
> To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: [PHP] UPDATE Query works in odbc/Mysql, but fails in odbc/MS
> Access
>
>
> Hello,
>
> I have one MS Access DB on the server, and an exact
> (theoretically) copy of
> it in MySQL on my machine, so I can test PHP pages on Linux and
> install them
> on an NT server (using odbc of course).
>
> I can insert and select just fine, thankl to all your help. The
> problem is
> that this UPDATE query:
> UPDATE rec SET Aut = 1 WHERE Un = 2927230327;
>
> works perfectly on PHP/ODBC/MySQL on Linux, while on PHP/ODBC/ACCESS/
> it gives this error:
>
> Warning: SQL error: [Microsoft][ODBC Microsoft Access Driver] Data type
> mismatch in criteria expression., SQL state 22005 in SQLExecDirect in
> C:\domini\m.net\update_db.php on line 54
> No cursor
>
> Initially I though well, maybe I'm trying to write a string into
> a number, or
> something like that, but I can SELECT from that same table using the same
> format, so what is the trick? Different UPDATE syntax between MySQL and
> ACCESS? If so, where is an online ACCESS syntax reference?
>
>   TIA,
>   mweb
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>
>
>



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




Re: [PHP] Update Query - Urgent

2001-10-23 Thread Beeman

Does the form you are using to update use checkboxes??
what kind of values are being passed?
"Mak" <[EMAIL PROTECTED]> wrote in message
008001c15bc8$3c73e6a0$7e8f9cca@athlon700delta">news:008001c15bc8$3c73e6a0$7e8f9cca@athlon700delta...
> What does the error message say? What sort of error is it?
> - ycmak
>
> - Original Message -
> From: "Mark Roedel" <[EMAIL PROTECTED]>
> To: "Srinivasan Ranganathan" <[EMAIL PROTECTED]>;
> <[EMAIL PROTECTED]>
> Sent: Tuesday, October 23, 2001 9:35 PM
> Subject: RE: [PHP] Update Query - Urgent
>
>
> > -Original Message-
> > From: Srinivasan Ranganathan [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, October 23, 2001 7:22 AM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP] Update Query - Urgent
> >
> >
> > I have a php script generate a sql update statement.
> > when i query the database, the update doesn't happen.
> > but when i echo the sql string and copy and paste it
> > in my mysql client window, the update happens like it
> > should!
>
> After the update fails, does an 'echo mysql_error()' tell you anything
> useful?
>
>
> ---
> Mark Roedel   | "Blessed is he who has learned to laugh
> Systems Programmer|  at himself, for he shall never cease
> LeTourneau University |  to be entertained."
> Longview, Texas, USA  |  -- John Powell
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>
>
> _
> Do You Yahoo!?
> Get your free @yahoo.com address at http://mail.yahoo.com
>



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




Re: [PHP] Update Query - Urgent

2001-10-23 Thread Mak

What does the error message say? What sort of error is it?
- ycmak

- Original Message -
From: "Mark Roedel" <[EMAIL PROTECTED]>
To: "Srinivasan Ranganathan" <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Tuesday, October 23, 2001 9:35 PM
Subject: RE: [PHP] Update Query - Urgent


> -Original Message-
> From: Srinivasan Ranganathan [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, October 23, 2001 7:22 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Update Query - Urgent
>
>
> I have a php script generate a sql update statement.
> when i query the database, the update doesn't happen.
> but when i echo the sql string and copy and paste it
> in my mysql client window, the update happens like it
> should!

After the update fails, does an 'echo mysql_error()' tell you anything
useful?


---
Mark Roedel   | "Blessed is he who has learned to laugh
Systems Programmer|  at himself, for he shall never cease
LeTourneau University |  to be entertained."
Longview, Texas, USA  |  -- John Powell

--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]


_
Do You Yahoo!?
Get your free @yahoo.com address at http://mail.yahoo.com


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




RE: [PHP] Update Query - Urgent

2001-10-23 Thread Mark Roedel

> -Original Message-
> From: Srinivasan Ranganathan [mailto:[EMAIL PROTECTED]] 
> Sent: Tuesday, October 23, 2001 7:22 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Update Query - Urgent
> 
> 
> I have a php script generate a sql update statement.
> when i query the database, the update doesn't happen.
> but when i echo the sql string and copy and paste it
> in my mysql client window, the update happens like it
> should!

After the update fails, does an 'echo mysql_error()' tell you anything
useful?


---
Mark Roedel   | "Blessed is he who has learned to laugh
Systems Programmer|  at himself, for he shall never cease
LeTourneau University |  to be entertained."
Longview, Texas, USA  |  -- John Powell 

--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




Re: [PHP] Update Query - Urgent

2001-10-23 Thread Valentin V. Petruchek

What if use mysql_select_db()?
- Original Message -
From: "Srinivasan Ranganathan" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, October 23, 2001 4:22 PM
Subject: [PHP] Update Query - Urgent -- Yes, Full Rights!


> Hi
>
> Yes, I do have full rights!
>
>
>
> 
> *NEW*   Connect to Yahoo! Messenger through your mobile phone   *NEW*
>Visit http://in.mobile.yahoo.com/smsmgr_signin.html
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>
>




-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




RE: [PHP] Update Query - Urgent

2001-10-23 Thread Nicolas Guilhot

Do you login to the database with a write access or a read only account ??

-Message d'origine-
De : Srinivasan Ranganathan [mailto:[EMAIL PROTECTED]]
Envoyé : mardi 23 octobre 2001 14:22
À : [EMAIL PROTECTED]
Objet : [PHP] Update Query - Urgent


Hi

I have a php script generate a sql update statement.
when i query the database, the update dosent happen.
but when i echo the sql string and copy and paste it
in my mysql client window, the update happens like it
should!

what am i missing/doing wrong here?

Thanks in advance
Srinivasan Ranganthan


*NEW*   Connect to Yahoo! Messenger through your mobile phone   *NEW*
   Visit http://in.mobile.yahoo.com/smsmgr_signin.html

--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]





-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




RE: [PHP] Update Query - Urgent

2001-10-23 Thread Niklas Lampén

How about some code to see?


Niklas

-Original Message-
From: Srinivasan Ranganathan [mailto:[EMAIL PROTECTED]] 
Sent: 23. lokakuuta 2001 15:22
To: [EMAIL PROTECTED]
Subject: [PHP] Update Query - Urgent


Hi

I have a php script generate a sql update statement.
when i query the database, the update dosent happen.
but when i echo the sql string and copy and paste it
in my mysql client window, the update happens like it
should!

what am i missing/doing wrong here?

Thanks in advance
Srinivasan Ranganthan


*NEW*   Connect to Yahoo! Messenger through your mobile phone   *NEW*
   Visit http://in.mobile.yahoo.com/smsmgr_signin.html

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED] To
contact the list administrators, e-mail: [EMAIL PROTECTED]


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]




Re: [PHP] Update Query - Urgent

2001-10-23 Thread Valentin V. Petruchek

Send your codes to mailing list.
If they are not very secret :)
- Original Message -
From: "Srinivasan Ranganathan" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, October 23, 2001 3:21 PM
Subject: [PHP] Update Query - Urgent


> Hi
>
> I have a php script generate a sql update statement.
> when i query the database, the update dosent happen.
> but when i echo the sql string and copy and paste it
> in my mysql client window, the update happens like it
> should!
>
> what am i missing/doing wrong here?
>
> Thanks in advance
> Srinivasan Ranganthan
>
> 
> *NEW*   Connect to Yahoo! Messenger through your mobile phone   *NEW*
>Visit http://in.mobile.yahoo.com/smsmgr_signin.html
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>
>



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]