Re: [PHP] load a URL and trap output

[Tom Meinlschmidt]

simple use fopen() or file()

as $fp = fopen(http://somedomain/some.url?blablah,r;);

and read via fread()

/tom

On Fri, 12 Mar 2004 10:54:53 -0500
Roger Spears [EMAIL PROTECTED] wrote:

 Hello,
 
 I have this application which is accessed via a web portal.  The first 
 thing my application must do is make sure the visitor is logged in via 
 the portal.  The only way to do this is by making a request to a 
 specific URL.  This URL (which includes the log in cookie id) will 
 return XML to my application.  Once I parse this XML, I will know if 
 visitors are logged in.
 
 Simple enough.  
 
 How do I make my application load a URL and trap the returned data so 
 that it never creates any browser output?
 
 My first reaction was header(Location: URL) but then I'd be handing 
 off control to the URL and the output would appear in the browser.
 
 I've done some research and found system(), exec(), and passthru().  But 
 I'm not sure if these functions are the proper way to do such a task 
 especially since I'm calling a URL and not a specific UNIX command.
 
 Thanks,
 Roger
 
 -- 
 PHP General Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php


-- 

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] load a URL and trap output

[Chris Boget]

 How do I make my application load a URL and trap the returned data so 
 that it never creates any browser output?

Aside from the fopen() and fread() that was suggested by another person
you can also use the ob_* functions.

Chris

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] load a URL and trap output

[Red Wingate]

Best way would be filegetcontents() and implode the content
with \n.
eg:

?php
$temp = filegetcontents('http://www.somedomain.com');
$temp = implode ( \n , $temp );
echo $temp ;
?
Chris Boget wrote:

How do I make my application load a URL and trap the returned data so 
that it never creates any browser output?


Aside from the fopen() and fread() that was suggested by another person
you can also use the ob_* functions.
Chris

--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] load a URL and trap output

[Roger Spears]

Tom Meinlschmidt wrote:


simple use fopen() or file()

as $fp = fopen(http://somedomain/some.url?blablah,r;);

and read via fread()

 

Then I replied with:

Perhaps I was mistaken, I thought:

$fp = fopen(http://somedomain/some.url?blablah,r;);
fread();
Would just return the actual HTML code of the page and NOT the results 
of running the page?.?.?.?.?

I will test it out and see.  Thank you for your suggestion!

Hello All,

It seems fopen() did not work.  However, it did stop the FORBIDDEN 
message I was receiving.  So I think I'm on the right track.  Here's 
what I tried...

$filename = actual URL;

$fd = fopen($filename, r);
$contents = fread($fd, $filename);
fclose($fd);
print strlen($contents);
print p.$contents;
I can open the URL, that works ( fopen() ).
I've tested out the fread(), file(), fgets(), and file_get_contents 
functions.  Nothing works.
I can close the URL, that works ( fclose() ).

With each attempt, I get 0 for the strlen of $contents and nothing else 
prints out.

I also tried adding this to the script right before fopen:
ini_set('allow_url_fopen','1');
That didn't work either...

Any idea(s) on what I'm doing wrong?  I'm using php 4.3.3 and I believe 
it's Apache 1.3

Thanks,
Roger
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php