to
make it show the state selected it always defaults to first choice?
Thanks
- Original Message -
From: "David Robley" [EMAIL PROTECTED]
To: "Peter Houchin" [EMAIL PROTECTED]; "Php-General@Lists. Php. Net"
[EMAIL PROTECTED]
Sent: Monday, March 26, 2001 11:37
10:48 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] setting Check box
This worked for me as well, and helped me with a problem I was having!
How would you show what option was selected in a drop down box. I have a
form the user fills out, this goes to a confirmation page to ensure the data
. Efurd" [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Tuesday, March 27, 2001 7:08 PM
Subject: RE: [PHP] setting Check box
use
SELECT NAME="foo" OPTION VALUE="bar" ? if ($areacode == 'bar') { echo
'SELECTED '; }?foo bar/OPTION
Peter
Ps thanks again David Jason M Philli
ch 28, 2001 11:20 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] setting Check box
I thought about doing it this way, but repeating this 50 times seems a bit
ineffecient, perhaps i am looking for a shortcut that does not exist? I had
hoped I was missing something obivious.
Thanks
Steve
--
On Wed, 28 Mar 2001 10:18, S. Efurd wrote:
This worked for me as well, and helped me with a problem I was having!
How would you show what option was selected in a drop down box. I have
a form the user fills out, this goes to a confirmation page to ensure
the data enetered is correct. I have
Thanks, that did it.
Steve
- Original Message -
From: "David Robley" [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, March 27, 2001 7:58 PM
Subject: Re: [PHP] setting Check box
On Wed, 28 Mar 2001 10:18, S. Efurd wrote:
This worked for me as well, and
On Tue, 27 Mar 2001 13:55, Peter Houchin wrote:
Hiya can some one pls let me know if i am on the right track pls, this
is in a form that updates if there is an id else it inserts, now what i
want it if there is an id i want the check box to be either checked or
unchecked depending on the 'y'
Hiya can some one pls let me know if i am on the right track pls, this
is in a form that updates if there is an id else it inserts, now what i
want it if there is an id i want the check box to be either checked or
unchecked depending on the 'y' / 'n' value in the db
input
ok I've changed it the SELECT to CHECKED but it had no effect ...
input type="checkbox" name="avail" value="" ? if ($avail ==
'n') { echo 'CHECKED'; }?
I've also tried it with a "n" value so it reads like
input type="checkbox" name="avail" value="n" ? if ($avail
== 'n') { echo
Try setting up your code so that the following is the result:
input type="checkbox" name="avail" checked
or
input type="checkbox" name="avail"
Andrew Elliston
On Monday, March 26, 2001, at 11:54 PM, Peter Houchin wrote:
Hiya can some one pls let me know if i am on the right track pls, this
Use that code, $avail just isn't evaluating to 'n' so try this somewhere
above it :
$avail = 'n';
And it will be checked otherwise it won't. And btw, you tried setting
value="n" that won't work unless this script submits to itself AND the
user checks it before submitting so it'll remain
On Tue, 27 Mar 2001 14:24, Peter Houchin wrote:
Hiya can some one pls let me know if i am on the right track pls,
this
is in a form that updates if there is an id else it inserts,
now what i want it if there is an id i want the check box to be
either checked or unchecked depending on the
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