Awk variable NF contains number of fieds. So:
awk 'NF==8 { print }'
Will print lines with 8 fields.
Best, Tomas
On Sat, Oct 30, 2021, 11:31 Rich Shepard wrote:
> I've a 351K line file with 8 fields. About 50K of those lines has $8 blank.
> I want awk to print only rows with values in all 8
On Sat, 30 Oct 2021, Robert Citek wrote:
Simplified version of your script:
BEGIN {FS="|"}
$8 != " "
Robert,
Thanks for the insights. I've not been aware of some before.
Regards,
Rich
A few pointers:
- {print $0} and {print} are the same
- {print} is the default action for any pattern match
- since you are printing the entire line, the OFS isn't used and,
therefore, doesn't need to be specified
- you don't need to specify an "if" as that is part of the structure of an
awk
On Sat, 30 Oct 2021, Robert Citek wrote:
Here's a sample:
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '{print}'
a b c d
a b d
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '$3=="" {print}'
a b d
My script uses if and awk doesn't like how I've used it:
BEGIN {FS="|";OFS="|"}
if
... and to negate the conditional use an exclamation point (!) :
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '$3 != "" {print}'
a b c d
Regards,
- Robert
On Sat, Oct 30, 2021 at 9:46 AM Robert Citek wrote:
> Sorry, this item didn't get pasted in my last post:
>
> $ echo -e
Sorry, this item didn't get pasted in my last post:
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk '{print $1" = "$2" = "$3" = "$4}'
a = b = c = d
a = b = d =
Notice that you have to specify the field separator with the -F option,
otherwise awk compresses consecutive whitespace characters by default.
Hello Rich,
Here's a sample:
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '{print}'
a b c d
a b d
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '$3=="" {print}'
a b d
Good luck and let us know how it goes.
Regards,
- Robert
On Sat, Oct 30, 2021 at 9:31 AM Rich Shepard
wrote:
> I've
I've a 351K line file with 8 fields. About 50K of those lines has $8 blank.
I want awk to print only rows with values in all 8 fields. I'm not finding
how to tell awk to print $0 if $8 is not blank.
My awk/sed book doesn't seem to have this information and my web searches
aren't finding the
