-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Raul Miller
Sent: Friday, November 02, 2012 10:46 AM
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] Taylor series
On Fri, Nov 2, 2012 at 5:18 AM, Linda Alvord lindaalv...@verizon.net
wrote
: Re: [Jprogramming] Taylor series
On Fri, Nov 2, 2012 at 5:18 AM, Linda Alvord lindaalv...@verizon.net
wrote:
Raul, I haven't gotten to t. yet, but I did manage not to use (f*g) or
p.
f=: 1 2 1p.
g=: 1 3 3 1p.
x=: 10%~i=: i.8
]c=: (f*g) t. iNB. This still
-Original Message-
From: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Raul
Miller
Sent: Friday, November 02, 2012 10:46 AM
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] Taylor series
On Fri, Nov 2
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] Taylor series
On Thu, Nov 1, 2012 at 5:12 AM, Linda Alvord lindaalv...@verizon.net
wrote:
Trudging back to my days in calculus I go to the dictionary..
f=: 1 2 1p.
g=: 1 3 3 1p.
x=: 10%~i=: i.8
]c=: (f*g) t. i
1 5 10 10 5 1 0 0
On Fri, Nov 2, 2012 at 5:18 AM, Linda Alvord lindaalv...@verizon.net wrote:
Raul, I haven't gotten to t. yet, but I did manage not to use (f*g) or p.
f=: 1 2 1p.
g=: 1 3 3 1p.
x=: 10%~i=: i.8
]c=: (f*g) t. iNB. This still has problems
1 5 10 10 5 1 0 0
What problems?
: [Jprogramming] Taylor series
On Fri, Nov 2, 2012 at 5:18 AM, Linda Alvord lindaalv...@verizon.net
wrote:
Raul, I haven't gotten to t. yet, but I did manage not to use (f*g) or
p.
f=: 1 2 1p.
g=: 1 3 3 1p.
x=: 10%~i=: i.8
]c=: (f*g) t. iNB. This still has problems
1 5 10 10 5 1 0
from i. 8. try i. 6
On Fri, Nov 2, 2012 at 4:34 PM, Linda Alvord lindaalv...@verizon.net wrote:
Where did the two zero's at the end come from?
Linda
--
(B=)
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For information about J forums see
I
10 5 1 0 0
What problems?
1 2 1 +//.@:(*/) 1 3 3 1
1 5 10 10 5 1
Thanks,
--
Raul
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For information about J forums see http://www.jsoftware.com/forums.htm
Brian, a dictionary page for t.
http://www.jsoftware.com/help/dictionary/dtdotu.htm says:
x u t.y is the product of (x^y) and u t. y .
The complex verb in my previous email was built to satisfy this definition.
Does this make sense?
--
Raul
On Mon, Oct 29, 2012 at 10:09 AM, Brian
Yes, it does make sense. My bad.
---
(B=)
On Oct 29, 2012, at 10:27 AM, Raul Miller rauldmil...@gmail.com wrote:
Brian, a dictionary page for t.
http://www.jsoftware.com/help/dictionary/dtdotu.htm says:
x u t.y is the product of (x^y) and u t. y .
The complex verb in my previous
I cannot get the dyadic verb u t. to work as described in the Vocabulary:
x u t.y is the product of (x^y) and u t. y
For example:
^t. 4
0.0416667
(2^4) * ^t. 4
0.67
2 ^t. 4
0.17
Clearly I must be misunderstanding something!
Richard Vaughan
I suspect you want something like this:
^ t. i. 5
1 1 0.5 0.17 0.0416667
--
Raul
On Fri, Oct 26, 2012 at 5:19 PM, rlvaug...@comcast.net wrote:
I cannot get the dyadic verb u t. to work as described in the Vocabulary:
x u t.y is the product of (x^y) and u t. y
For example:
^t.
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