Re: [Proto-Scripty] Re: Problem using invoke()

2009-12-09 Thread Frédéric
Le mardi 8 décembre 2009 15:43, T.J. Crowder a écrit :     this._navButtons.each(function(item) {         _opacity(item, ...);     }); The problem is to give additionnal params (for Effect.Oppacity); it does not seem to be possible with each(). That's why I tried invoke()...

[Proto-Scripty] Re: Problem using invoke()

2009-12-08 Thread T.J. Crowder
Hi, this._navButtons = [this._view.prevButton, this._view.nextButton, this._view.hideButton); I assume in your real code, that ends with `]`, not with `)` as above? As above, it's a syntax error. this._navButtons.invoke(_opacity, {'from': 0,

Re: [Proto-Scripty] Re: Problem using invoke()

2009-12-08 Thread Frédéric
Le mardi 8 décembre 2009 10:07, T.J. Crowder a écrit : I assume in your real code, that ends with `]`, not with `)` as above? As above, it's a syntax error. this._navButtons.invoke(_opacity, {'from': 0, 'to': 1,

Re: [Proto-Scripty] Re: Problem using invoke()

2009-12-08 Thread Frédéric
Le mardi 8 décembre 2009 10:36, T.J. Crowder a écrit : First check that scripty hasn't already done that (without the underscore). Scripty methodizes effects (at least sometimes, I don't know the details), so that (for instance) Effect.Fade can be used as a #fade method on element instances.

[Proto-Scripty] Re: Problem using invoke()

2009-12-08 Thread T.J. Crowder
Hi, this._navButtons.each(function(item) { _opacity(item, ...); }); The problem is to give additionnal params (for Effect.Oppacity); it does not seem to be possible with each(). That's why I tried invoke()... Look again at my example. You'd fill in the ... with the