Hi Bill,
If you make them all children of one container, then you can process
them in a loop like so:
var divsToSuppress, n;
divsToSuppress = $('containerName').children();
for (n = divsToSuppress.length - 1; n = 0; --n) {
divsToSuppress[n].setStyle({'zIndex': '4'}); // = Or
T.J. Crowder wrote:
Hi Bill,
If you make them all children of one container, then you can process
them in a loop like so:
var divsToSuppress, n;
divsToSuppress = $('containerName').children();
for (n = divsToSuppress.length - 1; n = 0; --n) {
Where xyz is the class name ?
Yup.
-- T.J. :-)
On Sep 20, 2:47 pm, bill will...@techservsys.com wrote:
T.J. Crowder wrote:
Hi Bill,
If you make them all children of one container, then you can process
them in a loop like so:
var divsToSuppress, n;
divsToSuppress =
T.J. Crowder wrote:
Where xyz is the class name ?
Yup.
Thanks
--
Bill Drescher
william {at} TechServSys {dot} com
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