On 04/08/11 12:04, Gelonida N wrote:
I posted already a question, but perhaps the subject line wasn't clear.
Subject line was Text to image with same results on any platform
Oh, your original message was perfectly clear, and if I knew the answer,
I might have responded. Anyway, into
Gelonida N wrote:
I wondered what library would be appropriate and would yield the same
result independent of the OS (assuming the versions of the python
libraries are the same)
Images should be pixel identical independent on the platform on which
the image is created.
Short answer: you
On 08/04/2011 12:32 PM, Thomas Jollans wrote:
On 04/08/11 12:04, Gelonida N wrote:
Thanks for your answer.
From within a django application
I'd like create a small image file (e.g. .png)
which just contains some text.
I wondered what library would be appropriate and would yield the same
On 4-8-2011 20:54, Gelonida N wrote:
The reason why I want the images to look identical is very simple.
Though the final web server will run on a linux server, I use sometimes
windows for development or as test server.
For automated tests I would have liked pixel identical images.
this
On 4-8-2011 21:30, Irmen de Jong wrote:
As far as I know, I did not see any difference in output on windows, linux
and mac os x
as long as the code used the same ttf file and PIL versions. (but I'll double
check now
and see if I remember this correctly).
To follow up on myself, I've just
Thanks again to everybody,
Your answers helped me to understand better.
My pragmatic solution is now to package my program
with an open source .ttf font,
which will be used on both platforms.
On 08/04/2011 10:24 PM, Irmen de Jong wrote:
On 4-8-2011 21:30, Irmen de Jong wrote:
As far as I
[PyNewbie]
Question: I can't seem to find the captured image, where does it go?
for me, it just goes to the current working directory:
$ python -i
Python 2.5.4 (r254:67916, Dec 23 2008, 15:10:54) [MSC v.1310 32 bit
(Intel)] on win32
Type help, copyright, credits or license for more
On Sun, May 1, 2011 at 1:50 PM, PyNewbie ryan.morr...@gmail.com wrote:
Hi,
I'm new with Python and PIL. I have a very simple question regarding an image
capture function I'm attempting.
Here is the code:
from PIL import ImageGrab
ImageGrab.grab().save(screen_capture.jpg, JPEG)
On 5/1/2011 9:00 PM, Chris Rebert wrote:
I would think to a file named screen_capture.jpg in the current
working directory. What that is for IDLE, I don't know.
At least on windows with 3.2, if one just starts up the shell, it is in
the Pythonxy directory. If one runs a file from an edit
Tim Eichholz wrote:
I'm trying to cut a BMP with 80 adjacent frames down to 40 using the
Image.copy and .paste functions but I'm getting error ValueError:
images do not match on the paste line.
newimage.paste(cols[f], (f*framew, 0, (f*framew)+192, 192))
The 4-tuple doesn't match the size of
On Apr 6, 3:05 am, Peter Otten __pete...@web.de wrote:
Tim Eichholz wrote:
I'm trying to cut a BMP with 80 adjacent frames down to 40 using the
Image.copy and .paste functions but I'm getting error ValueError:
images do not match on the paste line.
newimage.paste(cols[f], (f*framew, 0,
Tim Eichholz wrote:
I think maybe I am using the wrong function. I want to paste the
entire 192x192 contents of cols[f] into newimage. I would think it
works like newimage.paste(cols[f], (x, 0, 192+x, 192)) if that's not
it I think I'm missing a function
Don't think! Read the documentation
On 04/06/10 19:47, Peter Otten wrote:
Tim Eichholz wrote:
I think maybe I am using the wrong function. I want to paste the
entire 192x192 contents of cols[f] into newimage. I would think it
works like newimage.paste(cols[f], (x, 0, 192+x, 192)) if that's not
it I think I'm missing a
The problem is likely to do with the line
picMap = [[0] * width ] * height
yeah the problem was with that specific line. The snippet from your link
worked by
replacing the previous declaration by
picMap = [[0] * 3 for x in xrange(height)]
Thanks,
-Sid
--
Hi,
I am tryin to copy an image into my own data structure(a sort of 2d array
for further FFT). I've banged my head over the code for a couple of hours
now. The simplified version of my problem is below.
#-Code
import Image
pic =
On Oct 20, 2:14 pm, Sid [EMAIL PROTECTED] wrote:
Hi,
I am tryin to copy an image into my own data structure(a sort of 2d array
for further FFT). I've banged my head over the code for a couple of hours
now. The simplified version of my problem is below.
Casey wrote:
I'm doing some image processing that requires accessing the individual
pixels of the image. I'm using PIL 1.1.6 and creating a 2D array of
pixel RGB tuples using the Image class instance load() method.
load returns an access object that's attached to the image; to modify
the
On Aug 16, 3:53 am, Fredrik Lundh [EMAIL PROTECTED] wrote:
Casey wrote:
I'm doing some image processing that requires accessing the individual
pixels of the image. I'm using PIL 1.1.6 and creating a 2D array of
pixel RGB tuples using the Image class instance load() method.
load returns
En Mon, 14 Jul 2008 12:11:55 -0300, greg [EMAIL PROTECTED] escribi�:
I am able to use the PIL module to capture a screen or specific
window. My problem is when capturing a window (on windows XP) I can
only capture the visible portion of the window. Is there any way to
capture the entire
greg wrote:
I am able to use the PIL module to capture a screen or specific
window. My problem is when capturing a window (on windows XP) I can
only capture the visible portion of the window. Is there any way to
capture the entire window? specifically the scrolled portion of a
window that is
I am able to use the PIL module to capture a screen or specific
window. My problem is when capturing a window (on windows XP) I can
only capture the visible portion of the window. Is there any way to
capture the entire window? specifically the scrolled portion of a
window that is not visible on
On Jul 14, 8:11 am, greg [EMAIL PROTECTED] wrote:
Is there any way to capture the entire window? specifically
the scrolled portion of a window that is _not_visible_on_the_screen_.
I don't think there is. That is why it is called a _screen_ capture.
Matt
--
I know there is an easy way to do this, but I can't figure it out, how
do I get the color of a pixel? I used the ImageGrab method and I want
to get the color of a specific pixel in that image. If you know how
to make it only grab that pixel, that would also be helpful.
Basically I'm trying to
Adam W. wrote:
I know there is an easy way to do this, but I can't figure it out, how
do I get the color of a pixel? I used the ImageGrab method and I want
to get the color of a specific pixel in that image. If you know how
to make it only grab that pixel, that would also be helpful.
Gary Herron:
Try image.getpixel((x,y)) to retrieve the pixel at (x,y).
If the OP needs to access many pixels, then he can use the load()
method on the image object, and then read/write pixels (tuples of 3
ints) using getitem []
import Image
im = Image
img = im.load()
img[x,y] = ...
... =
Alex K wrote:
Would anyone know how to generate thumbnails with rounded corners
using PIL? I'm also considering imagemagick if PIL turns out not to be
appropriate for the task.
create a mask image with round corners (either with your favourite image
editor or using ImageDraw/aggdraw or some
Fredrik Lundh wrote:
create a mask image with round corners (either with your favourite image
editor or using ImageDraw/aggdraw or some such).
and for people stumbling upon via a search engine some time in the
future, Stani just posted a complete example over at the image-sig
mailing list.
Thomas Heller schrieb:
I'm trying to read an image with PIL, crop several subimages out of it,
and try to combine the subimages again into a combined new one. This is
a test script, later I want to only several single images into a combined one.
[...]
Here is the code; I'm using Python 2.4
I want to do something very simple:
I want to read a palette image (256 color PNG or BMP for instance), and
then just to output the image data as numbers (palette indexes, I
guess). Makes sense? How do I do that?
/David
--
http://mail.python.org/mailman/listinfo/python-list
[EMAIL PROTECTED] wrote:
I want to do something very simple:
I want to read a palette image (256 color PNG or BMP for instance), and
then just to output the image data as numbers (palette indexes, I
guess).
it's explained in the documentation, of course:
Fredrik Lundh wrote:
it's explained in the documentation, of course:
http://effbot.org/imagingbook/image.htm#Image.getdata
But as I read it, this gives me pixel values, i.e. colors. I want
palette indexes instead (which is what is really stored in a palette
image). I guess I can make a
John Salerno schrieb:
I might be way off target even looking into this method for what I need
to do, but I'm still a little confused about the description of it:
crop
im.crop(box) = image
Returns a rectangular region from the current image. The box is a
4-tuple defining the left,
John Salerno wrote:
I might be way off target even looking into this method for what I need
to do, but I'm still a little confused about the description of it:
crop
im.crop(box) = image
Returns a rectangular region from the current image. The box is a
4-tuple defining the left, upper, right,
Diez B. Roggisch wrote:
Alternatively you can see it as boundary lines, in the order left, top,
right, bottom.
(10, 20, 30, 100)
So in the above, from where are the numbers being counted? 10 is ten
pixels from the left border of the image? 20 is twenty pixels from the
top border? But is
John Salerno wrote:
Diez B. Roggisch wrote:
Alternatively you can see it as boundary lines, in the order left,
top, right, bottom.
(10, 20, 30, 100)
So in the above, from where are the numbers being counted? 10 is ten
pixels from the left border of the image? 20 is twenty pixels from
Yes
John Salerno wrote:
John Salerno wrote:
Diez B. Roggisch wrote:
Alternatively you can see it as boundary lines, in the order left,
top, right, bottom.
(10, 20, 30, 100)
So in the above, from where are the numbers being counted? 10 is ten
pixels from the left border of the
John Salerno wrote:
John Salerno wrote:
Diez B. Roggisch wrote:
Alternatively you can see it as boundary lines, in the order left,
top, right, bottom.
(10, 20, 30, 100)
So in the above, from where are the numbers being counted? 10 is ten
pixels from the left border of the
On Thursday 13 October 2005 02:58 pm, Andrea Gavana wrote:
# that is the old colour -- GREY
rgb_old = (0.7, 0.7, 0.7)
So, no matter what colour I choose as a new colour, the
Hue part of the new colour doesn't change in RGB. In other
words, leaving the old value for Saturation and Value
Andrea Gavana wrote:
I have tried your solution, Terry:
new_hue # your 'basic color', just the hue part
rgb_base # color from the basic button image
rgb_new # the new color you want to replace rgb_base with
rgb_new = hsv_to_rgb( (new_hue,) + rgb_to_hsv(rgb_base)[1:])
thanks a
Confusion about applying hue to a grey value
Try this:
import colorsys as cs
grey = (.7, .7, .7)
blue = (0., 0., 1.)
hsv_grey = cs.rgb_to_hsv(*grey)
hsv_blue = cs.rgb_to_hsv(*blue)
hsv_grey
(0.0, 0.0, 0.69996)
hsv_blue
(0.3, 1.0, 1.0)
The problem is that
I have tried your solution, Terry:
new_hue # your 'basic color', just the hue part
rgb_base # color from the basic button image
rgb_new # the new color you want to replace rgb_base with
rgb_new = hsv_to_rgb( (new_hue,) + rgb_to_hsv(rgb_base)[1:])
thanks a lot for your suggestion!
On Wednesday 12 October 2005 05:28 pm, Andrea Gavana wrote:
Now my question: is it possible to transform the pixels
colours in order to have another basic colour (say blue)?
In other words, the predominant colour will become the
blue, with other pixels in a brighter or darker blue to
give the
If you're always going from grey to tinted, then the easiest way is to
treat it as a 'P' image with a special palette.
I believe this function will prepare the palette:
def make_palette(tr, tg, tb):
l = []
for i in range(255):
l.extend([tr*i / 255,
Hello,
I'm using latest PIL version with Python 2.4.1. (for solving a level in
Python Challenge actually...). Anyway, I'm trying to draw a picture. My
question is, why is it that putdata() won't work? Even this won't run:
import Image
im = Image.open(something.jpg)
seq = im.getdata()
image =
On Sunday 14 August 2005 12:34 pm, Ray wrote:
import Image
im = Image.open(something.jpg)
seq = im.getdata()
image = Image.Image()
image.putdata(seq)
image.show()
I always get:
Traceback (most recent call last):
File Script1.py, line 31, in ?
image.putdata(seq)
File
Ray [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
image = Image.Image()
Anybody has any idea why this is the case?
Image.Image() isn't the way to get a new image object in PIL. Try
Image.new(), which needs at least mode and size arguments. You can get
those from your original
Try Image.new in place of Image.Image if you want to build a new image.
At which level are you?
CyrilOn 14 Aug 2005 10:34:38 -0700, Ray [EMAIL PROTECTED] wrote:
Hello,I'm using latest PIL version with Python 2.4.1. (for solving a level inPython Challenge actually...). Anyway, I'm trying to draw
Ilpo Nyyssönen napisał(a):
Is there any way of keeping this info in PIL?
I don't think so... when I investigated in the past, I think I
discovered that the PIL can't write EXIF data (I might be wrong,
though, or my information might be outdated).
There is this:
Is there any way of keeping this info in PIL?
I don't think so... when I investigated in the past, I think I
discovered that the PIL can't write EXIF data (I might be wrong,
though, or my information might be outdated).
Alternatively, is there a simple image
processing package that does it?
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