managed to reach line 6194 without going through that block.
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rse back into a function you still need to return the result
of the recursion.
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dent on this course, perhaps they are setting exercises for
which they have not previously provided the necessary tuition. If that is
the case, I suggest you ask them to reimburse your course fees, and then
go and find better tutors.
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ble value to prompt for the next player.
After each player takes a turn, add 1 to the current player. If this is
greater than the number of players, set it back to 1.
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On Wednesday, December 16, 2015 at 6:45:50 PM UTC-6, Rick Johnson wrote:
> On Wednesday, December 16, 2015 at 6:03:55 PM UTC-6, Bruce Whealton wrote:
>
> > Surely, one is going to want to create GUI apps for users
> > that are not Python Developers. I would not think to ask
> > someone to install
20,height*20), Image.ANTIALIAS)
This appears to attempt to extrapolate 400 pixels from each pixel in the
original image.
That only works on TV crime dramas, you can't do it in real life.
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New submission from Denis Savenko:
In documentation from this page
https://docs.python.org/3.5/library/urllib.request.html#examples in examples
uses default address to python site with http. ( http://python.org/ ). But now
python.org use https. When i try use example in ipython i get I/0
e to post a short self contained example of the problem
here instead.
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original
> tutorial
> now). Do you remember there is such a list application?
bb = [ for i in range()]
will create bb as a list of size whatever elements each of which is
eg:
>>> bb = [ ['a'] for i in range(4)]
>>> bb
[['a'], ['a'], ['a'], ['a']]
>>> bb = [ 0
thing in badthings:
if thing in item:
return False
return True
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ternet search engines because of the
way newsgroups get gated to websites.
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On Thu, 03 Dec 2015 01:46:44 +0100, Laura Creighton wrote:
> In a message of Wed, 02 Dec 2015 22:51:13 +0000, Denis McMahon writes:
>>On Wed, 02 Dec 2015 11:32:25 -0600, Ian Kelly wrote:
>>
>>> In what way is discussion of a tangential topic feeding the troll?
&g
On Tue, 01 Dec 2015 16:18:49 -0500, Terry Reedy wrote:
> On 12/1/2015 3:32 PM, Denis McMahon wrote:
>> On Tue, 01 Dec 2015 03:32:31 +, MRAB wrote:
>>
>>> In the case of:
>>>
>>> tup[1] += [6, 7]
>>>
>>> what it's t
On Tue, 01 Dec 2015 14:44:38 -0600, Ian Kelly wrote:
> On Tue, Dec 1, 2015 at 2:32 PM, Denis McMahon <denismfmcma...@gmail.com>
> wrote:
>> On Tue, 01 Dec 2015 03:32:31 +, MRAB wrote:
>>
>>> In the case of:
>>>
>>> tup[1] += [6, 7]
&g
ot; or "license" for more information.
>>> tup = [1,2,3],[4,5,6]
>>> tup
([1, 2, 3], [4, 5, 6])
>>> tup[1]
[4, 5, 6]
>>> tup[1] += [7,8,9]
Traceback (most recent call last):
File "", line 1, in
TypeError: 'tuple' object does not support item assi
condly there's no mechanism in json that
tells you what class of object you have.
So you may have a __json_dumps__ that will dump your object out to a json
string representation, but then how does json.loads recognise that it's
loading your object to call your object's __json_loads__?
--
rn 'hammer'
if match == 'cat':
return 'dog'
if match == 'tree':
return 'fence'
return match
with open("input.txt","r") as inf, open("output.txt","w") as ouf:
line = inf.readline()
line = patt.sub(replfunc, line)
ouf.write(line)
(also not tested)
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name (first and last), student number, and mark out of 100
for each student;
4. Uses regular expressions or similar mechanisms to ensure the data
appears valid.
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ine a string? Is it just a line with the spaces removed?
>>> "".join("this is a teststring my friends".split(" "))
'thisisateststringmyfriends'
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n you can do this
for thing in stuff:
print thing
(Python 2.7)
This may be adaptable to your requirement.
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(given by lat and lon) at that time.
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t
> list and returns Jordan's results i.e. (12) ?
You open a web browser and google for "python dictionary"
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sh": 13}
> }
>
> How do you get gengyang's maths scores ?
I refer to my previous answer. Open a web browser and google "python
dictionary"
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ion for anything useful, because it will just use all the
memory up. So perhaps you need to express your question in a better
manner.
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ne)
> (' likes ', 'what', '', None)
Or even:
>>> s = "{who} likes {what}"
>>> d = {'who': "Adam", 'what': "ants"}
>>> keys = [x[1] for x in string.Formatter().parse(s)]
>>> keys
['who', 'what']
then ...
for key in keys:
i
item.find_all('a'):
# write link to file
# close file
Alternatively, use the with form:
with open("blah","wb") as text_file:
for item in soup.find_all(class_='lister-list'):
for link in item.find_all('a'):
# write link to file
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d "real names".
TPEL has been trolling html, php and javascript newsgroups for years,
recently he seems to have discovered python newsgroups. :(
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s:
del row[k]
plotdata[key] = row
This generates a dictionary (plotdata) keyed by the key tuples where the
value for each key is a dictionary of 0:0n : value
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cution time varies with the size of the datafiles.
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provide executable tools at the OS level which are more efficient than
anything you will write in a scripting language.
Lesson 1 of computing. Use the right tool for the job. Writing a new
program is not always the right tool.
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can read the messages from there from time to time.
Read more carefully!
The earlier poster suggested options that would work if you set up your
own server, or already had one.
You can poll your gmail server using pop3 as the earlier reply suggested.
You may need to configure some options in y
is', sumscore / students
It was trivial to generate:
Sum of 50 scores is 3028
Average of 50 scores is 60
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31
compiled re, true 0.876382112503
char compare, false 0.26283121109
char compare, true 0.263465881348
The compiled re is about 3 times as fast as the uncompiled re. The
character comparison is about 3 times as fast as the compiled re.
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f c2:
if c3:
# c1 && c2 && c3
# 4 second open
else:
# c1 && c2
# 3 second open
else:
# only c1
# 2 second open
Each condition only gets evaluated once.
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On Wed, 21 Oct 2015 20:07:21 +, Grant Edwards wrote:
> On 2015-10-21, Denis McMahon <denismfmcma...@gmail.com> wrote:
>> On Wed, 21 Oct 2015 10:31:04 -0700, bigred04bd3 wrote:
>>
>>> So here what I have, I have a 3 IF's within the same level. If one IF
>>&
I'm not sure I understand why after m = deepcopy(l); m.remove(i); m is a
different value to that which it as after m = deepcopy(l).remove(i).
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On Sun, 18 Oct 2015 20:38:26 +, Denis McMahon wrote:
> On Sun, 18 Oct 2015 03:17:18 -0700, Beppe wrote:
>
>> hi to everybody, I must turn a tuple of lists into a dictionary.
>
> I went down a different path to Peter, and discovered something
> perplexing:
I
Changes by Denis Jacquerye <moy...@gmail.com>:
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___
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue6331>
___
Changes by Denis Jacquerye <moy...@gmail.com>:
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___
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue22612>
___
e all the permissions needed to write to the directories you're
asking it to put files in?
Did you run the installation process with those permissions?
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stop or end to exit: ")
print("you entered: ", x)
if x in ["stop","quit","end"]:
stop = True
print("Finished now")
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t; before you ask questions about it, then that would be even better.
> Knowing what piece of code would also help us to help you. As a starter
> here is a small piece of code.
>
> a = 1
>
> Is that adequate?
If not, perhaps:
b = [c for c in range(20)]
d = {e:b for e in
gic
wand. It should work now. If it still doesn't work, please provide more
details about the problem.
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len(row[i]) == 0:
flags[i] = True
else:
blanks = True
if not blanks:
break
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, y):
return (x-y)
# this line
# print(funA(4,funB(2,3), funB(3,2)))
# can be written as the following 4 lines:
a = funB(2, 3) # 2 - 3 -> -1
b = funB(3, 2) # 3 - 2 -> 1
c = funA(4, a, b) # (4 + -1) * 1 -> 3
print(c) # 3
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On Wed, 30 Sep 2015 23:30:47 +, Denis McMahon wrote:
> On Wed, 30 Sep 2015 11:34:04 -0700, massi_srb wrote:
>
>> firstly the description of my problem. I have a string in the following
>> form: .
>
> The way I solved this was to:
>
> 1) replace all
u have given,
I have waved my magic wand. If this didn't work, the information you
supplied was insufficient.
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',', or if there's whitespace following '('?
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= int(num) for each num element (numpatt.match(thing))
with n depending on whether it was the first or second num following the
previous word
then:
d = {x:tuple(d[x]) for x in d}
to convert the lists in the new dic to tuples
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On Wed, 30 Sep 2015 23:06:13 +0530, Rusiri Jayalath wrote:
> Error code 0x80070570 appears when installing python 3.5.0 (32-bit)
> setup for my windows 8.1 system. Please help me to solve this problem.
This seems to be a windows error, not a python issue. Try google.
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) alice tom (1, 4) peter (2) andrew(3,4) janet( 7,6 ) james
( 7 ) mike ( 9 )"
d = {'mike': (9, 0), 'janet': (7, 6), 'james': (7, 0), 'jim': (1, 0),
'andrew': (3, 4), 'alice': (0, 0), 'tom': (1, 4), 'peter': (2, 0), 'fred':
(0, 0)}
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On Tue, 29 Sep 2015 10:16:04 +0530, Laxmikant Chitare wrote:
> Is there any similar elegant way to check if a value is out of certain
> range?
What about:
if not (0 < x < 10):
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o convert km to miles
def convert_km_mi(km):
return convert_float_a_b(km, 0.6214)
# now call main to kick it all off
main()
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he intent of the question you meant to ask, you
might find that the following code does something interesting:
x = 9876543210
y = []
while x > 0:
y.append(x % 10)
x = int(x / 10)
y = list(reversed(y))
print y
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ing to nuke Beijing and Moscow .
(I really really really hope that this is indeed fiction!)
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", "/a/c.htm"]
page = "\n"
fmt = "var frames=Array({});\n"
page += fmt.format(",".join(map(lambda x:'"'+x+'"', files)))
page += "\n"
print page
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>
> Now in the calling function If I use that object to read or write to
> terminal I'm getting ERROR "AttributeError: 'NoneType' object has no
> attribute 'read_very_eager'".
My best guess would be that something failed and has returned None
instead of the object / class you'r
question leads to which next question.
This way also makes for an interesting talking point about separating
data and code, especially given the multiple if statements issue.
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comprehension.
>>> def tofloat(x):
... try:
... return float(x)
... except ValueError:
... return None
...
>>> l = [ '300', '"N"', '1140', '"E"' ]
>>> l = [ tofloat(x) or x for x in l ]
>>> l
[300.0, '"N"', 1140.0, '"E"']
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da:a4
00:16:3e:57:be:d2
00:16:3e:6b:e5:ae
00:16:3e:54:0e:f0
00:16:3e:57:5e:50
00:16:3e:21:99:6b
00:16:3e:12:e6:05
00:16:3e:53:02:6d
00:16:3e:79:17:1b
00:16:3e:02:ff:b8
00:16:3e:4e:ff:0d
Observation: No point in declaring mac1 as global in the global scope.
Is it possible that you've tried to run p
func()
Would you expect the last two calls to func() to return 999 or "Awesome"?
Why? What is the material difference if any between interpreter (a)
displaying the return value and (b) comparing the return value with
another value.
Debugging nightmare!
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:
s = sum(list_a)
print (s)
And if you only want to display the answer:
print (sum(list_a))
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On Wed, 09 Sep 2015 20:45:57 +, John Gordon wrote:
> In any case, I saved your code and ran it, and did not get an error.
+1
I think "Execution Succesful!" might be coming from his IDE?
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On Sun, 06 Sep 2015 16:09:42 -0700, babi pepek wrote:
> I wand update
update
There, now you have update.
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On Sun, 06 Sep 2015 23:23:14 +1000, Chris Angelico wrote:
> WSGIScriptAlias / /path/to/scripts/MinstrelHall/mh.wsgi
One wonders if the OP has mod_wsgi installed.
https://code.google.com/p/modwsgi/wiki/WhereToGetHelp might be useful too.
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ht
ect, you could come back here and post your code with a description of
what you think it should do, what it actually does, and why you think
that's wrong, and we'll try and help you fix.
What we won't do is write your application from scratch.
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--
ht
are receiving and how the xml nodes and their attributes and values
should be mapped into the csv file you want to create.
Unfortunately I don't think that there is a single standard mechanism for
doing that bit, although there are some tools and libraries that can help.
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' ] },
}
The multiple parenting means that you need to use something as
references. You can't represent the hierarchy as a simple tree, because
in a simple tree a node only has one parent.
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position, as well as additional indenting to take account
of that addition.
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in each line in the file, and
that the hours record always at position Y in the timestamp.
You have to replace X and Y in that line with numbers that represent the
positions in the lists returned by the relevant split commands of the
actual text elements that you want to extract.
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at position Y in the
timestamp.
c = [0 for i in range(24)]
f = open(filename,'r')
for l in f:
h = int(l.strip().split()[X].split(':')[Y])
c[h] = c[h] + 1
f.close()
for i in range(24):
print '{:02d} {}'.format(i, c[i])
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On Wed, 12 Aug 2015 09:29:50 -0700, Ltc Hotspot wrote:
Using the attached file of a diagram as a frame, why is there an
attribute message?
Perhaps you should read the message. It's very clear.
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to floor-scrubbing 101.
[1] You have repeatedly ignored advice and instructions that you have
been given. This is de-facto proof that you are not capable of learning
to program computers.
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), incrementing counts[x]
where x is the hour field of the timestamp.
Then I'd create a list of tuples:
ncounts = [(k,v) for k,v in counts.items()]
sort it by the hour field:
ncounts.sort(key = lambda x: x[0])
and print it:
for x in ncounts:
print x[0], x1
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trying to sort ncount?
Do you want results ordered by count?
First, change your dictionary into a list of tuples:
ncount = [(a,c) for a,c in count.items()]
Then sort ncount on the second field of the tuple:
ncount.sort(key = lambda x: x[1], reverse=True)
print ncount
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can make your fun less uncertain,
Pierre Denis
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Support the Python Software Foundation:
http://www.python.org/psf/donations/
= json.dumps( { $and:[ { $gt: {age: 5} }, { $not:
{name: curly} } ] } )
query
'{$and: [{$gt: {age: 5}}, {$not: {name: curly}}]}'
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to see what comes out.
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b,38
$
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and the main code to work together, but as the existing problem is that
they don't seem to work together to create the data structure you expect
them to create, that's not going to be a bad thing.
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On Sun, 19 Jul 2015 17:35:03 +0100, MRAB wrote:
rsplit - one line.
def lastWordFirst(s):
return .join(reversed(s.rsplit( , 1)))
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On Sat, 18 Jul 2015 12:35:10 +0200, Sibylle Koczian wrote:
Am 18.07.2015 um 02:40 schrieb Denis McMahon:
Having a list of words, get a copy of the list in reverse order. See
the reversed function (and maybe the list function).
That won't really help, because the desired order
the elements of a list into a string, see the join method of
strings.
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-50 .. 50
if x -50:
x = -50.0
ix x = 50:
x = 50.0
# step 2, scale x to the range 0 .. 12
x = x * 0.12 + 6.0
If you want an integer value, you need to determine which method is most
relevant. I would suggest rounding.
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the structure to json.
import json
thing = {}
msg = {}
cols = []
for row in data:
col = {}
col['x'] = row['timestamp']
col['y'] = row['counter_volume']
cols.append(col)
msg['columns'] = cols
thing['message'] = msg
print thing
print json.dumps(thing)
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On Sun, 28 Jun 2015 17:07:00 -0700, Ned Batchelder wrote:
On Sunday, June 28, 2015 at 5:02:19 PM UTC-4, Denis McMahon wrote:
things
thingstring 3/thing
thingstring 2/thing
thingstring 1/thing
/things
Each thing is just a member of the collection things, the xml does
not contain
On Sun, 28 Jun 2015 09:46:36 +0200, Stefan Behnel wrote:
Denis McMahon schrieb am 26.06.2015 um 09:44:
xml data is an unordered list, and are trying to assign an order to it.
If the xml data was ordered, either each tag would be different, or
each tag would have an attribute specifying
.
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New submission from Denis Gordeev:
My code is:
mypath = 'Z:\Pr Files\norma'
file_list = [ f for f in listdir(mypath) if isfile(join(mypath,f))]
Error:
Traceback (most recent call last):
File C:\Documents and Settings\Administrator\Desktop\uni\click zhenilo
workshop\noise.py, line 13
like this I expect a few 10s of $ per hour.
There may be a generic method to do what you want involving parsing the
xml to a nested dictionary / list data object, and then flattening that
object, but I don't see that generating you one line of CSV for each
Int32 in MonthDayCount.
--
Denis
On Sun, 21 Jun 2015 06:57:01 -0700, sahluwalia wrote:
On Sunday, 21 June 2015 02:47:31 UTC-4, Denis McMahon wrote:
On Wed, 17 Jun 2015 08:00:11 -0700, Saran A wrote:
I would like to have this JSON object written out to a CSV file so
that the keys are header fields (for each
turn out in a day or
so, it's hardly rocket science as long as you have a clear description of
what is required. If you don't have a clear description of what is
required, you have to keep asking questions until you get one.
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Denis McMahon, denismfmcma...@gmail.com
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that they face.
I do agree with you Denis that this is an unconventional approach. I was
wondering then that perhaps I should add additional functionality at the
XML to JSON step? So far, with JSON objects without nested lists (as
values) I have been successful with this (the following is rather
lengthy
describe it.
At least, it seems that every time you do try and describe it either the
data format or the task description changes.
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Denis McMahon, denismfmcma...@gmail.com
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seems to have the same key used for two elements at the
same level, are you sure this is legal json?
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, there is
little added value in using some arbitrary intermediate format unless
you're actually going to use the data in the intermediate format for
something other than converting to the final format.
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Denis McMahon, denismfmcma...@gmail.com
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environment, then the best
place to look is probably forums dedicated to that simulation environment.
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Denis McMahon, denismfmcma...@gmail.com
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the advanced topic in my system.
I don't consider using library x to do y as advanced python, it's just
gluing together existing functions with your own basic programming, no
matter whether the library is for hardware IO, interfacing to a database
etc.
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Denis McMahon, denismfmcma...@gmail.com
'something' is not defined
means that you might have spelled something differently on the line in
the error message to the word you meant, so next time you see this error
message you know to carefully check the spellings of function names and
variables.
--
Denis McMahon, denismfmcma
2014, 19:10:20)
[GCC 4.6.3] on linux2
Type help, copyright, credits or license for more information.
.join(list(reversed(fred)))
'derf'
.join([x for x in reversed(fred)])
'derf'
So reversed can do it, but needs a little help
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Denis McMahon, denismfmcma...@gmail.com
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