> Hello all, I am writing an application where I need to open a shared
> file on a remote machine using python script. I tried using the
> following function: f =
> urllib.open("\\remote_machine\\folder1\\file1.doc") I also tried using
> class urllib.FancyURLopener(...) but didn't work.
> Can so
Try using the normal file access functions, eg: open("file","r"), etc.
~G
On Mon, Feb 23, 2009 at 6:14 AM, venu madhav wrote:
> Hello all, I am writing an application where I need to open a shared file on
> a remote machine using python script. I tried using the following function:
> f = urllib.
Hello all, I am writing an application where I need to open a shared file on
a remote machine using python script. I tried using the following function:
f = urllib.open("\\remote_machine\\folder1\\file1.doc") I also tried using
class urllib.FancyURLopener(...) but didn't work. Can some one help me
