On Sun, Feb 8, 2015 at 8:44 PM, Suharto Anggono Suharto Anggono via
R-devel r-devel@r-project.org wrote:
Sorry to intervene.
No, I'm very happy you intervened. You're comment is 100%
valid/correct making my wish moot.
Your explanation is very clear and nails it; one should use
Sorry to intervene.
Argument passed to 'eval' is evaluated first.
So,
eval(x - 2)
is effectively like
{ x - 2; eval(2) } ,
which is effectively
{ x - 2; 2 } .
The result is visible.
eval(expression(x - 2))
or
eval(quote(x - 2))
or
evalq(x - 2)
gives the same effect as
x - 2 .
The result is
On 07/02/2015 12:40 PM, Henrik Bengtsson wrote:
Would it be possible to have the value of eval() preserve the
visibility of the value of the expression?
PROBLEM:
# Invisible
x - 1
# Visible
eval(x - 2)
[1] 2
TROUBLESHOOTING:
withVisible(x - 1)
$value
[1] 1
$visible
[1]
Would it be possible to have the value of eval() preserve the
visibility of the value of the expression?
PROBLEM:
# Invisible
x - 1
# Visible
eval(x - 2)
[1] 2
TROUBLESHOOTING:
withVisible(x - 1)
$value
[1] 1
$visible
[1] FALSE
withVisible(eval(x - 2))
$value
[1] 2
$visible
[1] TRUE