x5 <- 5*round(x/5)
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
Chris Li [chri...@austwaterenv.com.au]
Sent: 16 September 2009 09:15
To: r-help@r-project.org
Subject: [R] Rounding to the nearest 5
Hi all,
I want to roun
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-con
Hi all,
I have got a dataset like the following:
a b c
1 5
2
3 7
I am taking the minimum of each column and use it as the minimum of the
y-axis of my graphs. My scripts (simplified version) are like the following:
f<-array
f[1]=a
f[2]=b
f[3]=c
for i in 1:3
name=f[i]
ymin<-min(datas
The R.batch package does most of this. It's been several years, but I
used it run batch jobs on multiple (30-40) machines with different
OS:es but sharing the same file system. No communication needed
between hosts. It worked like a charm and I could process 3-4 CPU
years in a few weeks for some
I have some security alert log data that I'm parsing and doing some stats on.
One of the fields is the "Classtype" which is the enumerated value of the
type of alert found.
classtypes = factor( alerts$Classtype )
fclass_types = table( classtypes )
fclass_types gives me a frequency table of the
Hi all,
I want to round my values to the nearest 5.
For example, if I have a value of 11, I want R to round it to 10.
I have been searching for this command on the web and in the help file, but
I couldn't find anything useful.
Any help would be greatly appreciated.
Many thanks,
Chris
--
View
Hi,
Thanks a lot. I think this is what I want.
actuar package get more distributions.
Zero~
David Winsemius wrote:
>
>
> On Sep 15, 2009, at 1:09 PM, TsubasaZero wrote:
>
>>
>> Hi all,
>>
>> I had generated 1000 random variates (u,v), and I would like to find
>> the
>> corresponding (x,y
Instead of eval(expr), use lapply(expr,eval)
HTH
Schalk Heunis
On Wed, Sep 16, 2009 at 5:50 AM, Michael Spiegel <
michael.m.spie...@gmail.com> wrote:
> Hi,
>
> I'm trying to use a list of symbols as one of the values to be
> substituted in a substitute expression, but I can't figure out how to
This might be of help, first applies the formatting:print(xtable(prettyNum(d,
decimal.mark=",")))
Schalk Heunis
On Tue, Sep 15, 2009 at 5:06 PM, Jakson A. Aquino wrote:
> Hello,
>
> How can I make xtable print a comma as decimal separator? Setting
> the option OutDec isn't enough for xtable:
Hi,
I'm trying to use a list of symbols as one of the values to be
substituted in a substitute expression, but I can't figure out how to
write the correct expression for my problem. Let me illustrate a
simple example of what I'm trying to do. The following code snippet
will evaluate to '5':
sym
Thomas, thanks for your comments. We weren't entirely sure we we even
framing the question right, your comments are encouraging. Here are our
results:
Call:
coxph(formula = Surv(lifespan, status) ~ group, data = four)
n= 573
coef exp(coef) se(coef) z Pr(>|z|)
groupT1
I think you do in fact want to just run the analysis for the four groups you
are interested in. The logrank chisquared test would then be of the hypothesis
that these four groups have the same survival and censoring distributions, with
the greatest power for detecting proportional-hazards diff
On Sep 15, 2009, at 9:58 PM, Bryan Hanson wrote:
R Folk:
Please forgive what I'm sure is a fairly naïve question; I hope it's
clear.
A colleague and I have been doing a really simple one-off survival
analysis,
but this is an area with which we are not very familiar, we just
happen to
hav
I am reading John R. Pierce's An Introduction to Information Theory and read
that any wave can be decomposed into simple sin waves by means of a Fourier
analysis. I would like to play with the idea a little and want to plot a
couple simple sin waves in R; add them together as if they were bei
On Tue, 15 Sep 2009, Keo Ormsby wrote:
Hi Murat,
I am not an expert in either statistics nor R, but I can imagine that since the
default is exact=TRUE, It numerically computes the probability, and it may
indeed be 0. if you use wilcox.test(x, y, exact=FALSE) it will give you a
normal aproxima
perhaps a long shot but maybe the package 'nws' could handle some of it.
I've recently begun looking into something similar lately as well.
-c
ivo welch wrote:
I am about to write a "cluster-lite" R solution for myself. I wanted to
know whether it already exists. If not, I will probably writ
R Folk:
Please forgive what I'm sure is a fairly naïve question; I hope it's clear.
A colleague and I have been doing a really simple one-off survival analysis,
but this is an area with which we are not very familiar, we just happen to
have gathered some data that needs this type of analysis. We'
Fast fingers. Had to change the test:
> vlarge <- c(numeric(20),1:20)
> system.time(
+ for (i in 1:3) {
+which.min(!(vlarge != 0))}) # test changed
user system elapsed
0.350.000.42
>
> #Method 2:
> system.time(
+ for (i in 1:3) {
+ for (i in 1:40) {
+ if (vlarge[
try .which.mine
Here is what is does on my system:
> vlarge <- c(numeric(20),1:20)
> system.time(
+ for (i in 1:3) {
+which.min(vlarge != 0)})
user system elapsed
0.300.000.35
>
> #Method 2:
> system.time(
+ for (i in 1:3) {
+ for (i in 1:40) {
+ if (vlarge[i] != 0
In the Windows cmd shell ^ means escape the next character
so try this (assuming the data you posted
is in genetest.dat in the current directory):
> readLines(pipe("findstr/b ^> genetest.dat"))
[1] ">gene A;." ">gene B;"
and on UNIX replace "..." with the corresponding grep command
making
you can also use:
round(x / 5) * 5
> for (i in 1:20) cat(round(i / 5) * 5, ' ')
0 0 5 5 5 5 5 10 10 10 10 10 15 15 15 15 15 20 20 20 >
On Tue, Sep 15, 2009 at 8:08 PM, J Chen wrote:
>
> hope this will help
>
> for (i in 1:10) {
> if (i%%5>2) {
> print((i%/%5+1)*5)
>
CHeck out this site:
http://www.quanetic.com/Regex
you can google 'regular expression tester' and find it. R uses the
standard (whatever that is) expressions so check out tutorials you
might find via google.
On Tue, Sep 15, 2009 at 8:16 PM, wrote:
> Thanks Jim and Rolf,
>
> grep("n.*mytype",m
Thanks Jim and Rolf,
grep("n.*mytype",mystr) will do.
I thought that * only applies on group of characters defined in a []
sequence. Would you be aware of any documentation/tutorial that would give
slightly more detail and examples that the ?regexp?
Also, would you be aware of any (online) tool t
hope this will help
for (i in 1:10) {
if (i%%5>2) {
print((i%/%5+1)*5)
}
else {
print((i%/%5)*5)
}
}
Jimmy
Chris Li wrote:
>
> Hi all,
>
> I want to round my values to the nearest 5.
>
> For example, if I have a value of 11, I want R to round it to 10.
>
> I have be
I am about to write a "cluster-lite" R solution for myself. I wanted to
know whether it already exists. If not, I will probably write up how I do
this, and I will make the code available.
Background: we have various linux and OSX systems, which are networked, but
not set up as a cluster. I have
Anyone familiar with a quicker method to find the position of the first
non-zero element of a vector?
#The first way:
print(min(which(vector != 0)))
#The second way:
for(i in 1:length(vector)) {
if (vector[i] != 0) {
print(i)
break
}
Hi Murat,
I am not an expert in either statistics nor R, but I can imagine that
since the default is exact=TRUE, It numerically computes the
probability, and it may indeed be 0. if you use wilcox.test(x, y,
exact=FALSE) it will give you a normal aproximation, which will most
likely be differen
On 16/09/2009, at 9:58 AM, jim holtman wrote:
try:
grep("n.*mytype",mystr)
[1] 1
with the [.] it is a class with a period. '.*' match zero, or
more, characters.
Perhaps the OP wants
grep("n[.].*mytype",mystr)
to insist that ``mystr'' contain the string ``n.'' (literal ``.'')
On Sep 15, 2009, at 5:47 PM, Nick Matzke wrote:
Hi all, a quick question I couldn't find the answer to in the usual
places:
Is there a way to turn off line-wrapping in the R console? Or set
the line width-before-wrapping manually? Currently it looks like
the console linewraps after abo
try:
> grep("n.*mytype",mystr)
[1] 1
with the [.] it is a class with a period. '.*' match zero, or more, characters.
On Tue, Sep 15, 2009 at 5:52 PM, Sebastien Bihorel
wrote:
> Dear R-users,
>
> I am trying to use the grep function to test whether a particular string is
> of the form "n.../my
See ?options, particularly the "width" setting.
> options(width=200)
Might do what you want, by default it is 80...
Best,
Erik Iverson
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Nick Matzke
Sent: Tuesday, September 15, 2
Hi all, a quick question I couldn't find the answer to in the usual places:
Is there a way to turn off line-wrapping in the R console? Or set the
line width-before-wrapping manually? Currently it looks like the
console linewraps after about 70 characters, this occurs even if I
increase the w
Dear R-users,
I am trying to use the grep function to test whether a particular string
is of the form "n.../mydir/myfile.mytype.myext". Anything between n and
mytype could vary, and anything after mytype could vary. I tried to
proceed by steps to build my regular expression... but I do not rea
Along those lines, python is so easy to use for stuff like this. Sample
code would be
# Read in a file with the data
filename = raw_input("Please enter the name of the original file: ")
new_file = raw_input("Enter the name of the file to output: ")
# create a new file defined by the user
f = ope
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of J Chen
> Sent: Tuesday, September 15, 2009 2:00 PM
> To: r-help@r-project.org
> Subject: [R] how to load only lines that start with a
> particular symbol
>
>
> Dear all,
>
> I
> PS: Any speed suggestions are appreciated. This is "experimenting time" for
> me.
You might want to check out the plyr package - it incorporates
everything I know about making these sorts of operations fast. The
next version will do even better.
Hadley
--
http://had.co.nz/
'by' works with data.frames. Look at what happens if you don't send
in a dataframe to 'by':
> by.default
function (data, INDICES, FUN, ..., simplify = TRUE)
{
dd <- as.data.frame(data)
if (length(dim(data)))
by(dd, INDICES, FUN, ..., simplify = simplify)
else {
if (!is
interestingly, in my case, the opposite seems to be the case. data frames
seem faster than matrices when it comes to "by" computation (which is where
most of my calculations are in):
### here is my data frame and some information about it
> dim(rets.subset)
[1] 132508 3
> names(rets.subset)
Well, how about the nomatch argument to the match function, see ?match . The
nomatch argument is NA by default.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Peng Yu
Sent: Tuesday, September 15, 2009 4:05 PM
To: r-h...@stat.math.
couple of different ways depending on what you want to do with the data:
> match(c(3,4), c(3,2,1))
[1] 1 NA
> match(c(3,4), c(3,2,1), nomatch=0)
[1] 1 0
> x <- match(c(3,4), c(3,2,1))
> x[!is.na(x)]
[1] 1
>
On Tue, Sep 15, 2009 at 5:05 PM, Peng Yu wrote:
> Hi,
>
>> match(c(3,4), c(3,2,1))
> [1
Hi,
> match(c(3,4), c(3,2,1))
[1] 1 NA
The above result has 'NA' in. Is there a way to make 'match' does not
produce any 'NA's?
Regards,
Peng
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
read in the data with 'readLines' and then use 'grep'
> x
[1] ">gene A;." "A" "T" "CCCTT"
">gene B;" "C" "G"
> x <- x[grep("^>", x)]
> x
[1] ">gene A;." ">gene B;"
>
On Tue, Sep 15, 2009 at 4:59 PM, J Chen wrote:
>
> Dear all,
>
>
hi, folks,
how have you gone about reporting a p-value from a test when the
returned value from a test (in this case a rank-sum test) is
numerically equal to 0 according to the machine?
the next lowest value greater than zero that is distinct from zero on
the machine is likely algorithm-dependent
Dear all,
I have DNA sequence data which are fasta-formatted as
>gene A;.
A
T
CCCTT
>gene B;
C
G
I want to load only the lines that start with ">" where the annotation
information for the gene is contained. In principle, I can remove the
sequences bef
On 9/15/2009 4:24 PM, ivo welch wrote:
hi david---no, this time I actually know what I was asking ( ;-) ). I do
need speed computed on many data sets, each of which is created by a "by"
statement. so, no iterative programming on my side.
thanks, hadley for the pointer to .row_names_info() in
hi david---no, this time I actually know what I was asking ( ;-) ). I do
need speed computed on many data sets, each of which is created by a "by"
statement. so, no iterative programming on my side.
thanks, hadley for the pointer to .row_names_info() in lieu of dim() or
nrows(). I don't seem t
Michael Pearmain wrote:
I'd like to see the function code behind the barplots2() function in the
gplots package, however i come across a bit of a stumbling block of a hidden
function, can anyone help?
library(gplots)
methods(barplot2)
[1] barplot2.default*
Non-visible functions are asteri
See the reference to ?getAnywhere in the following post:
http://www.nabble.com/The-code-behind-the-function-td25370743.html
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Michael Pearmain
Sent: Tuesday, September 15, 2009 3:14 PM
Hi All,
I'd like to see the function code behind the barplots2() function in the
gplots package, however i come across a bit of a stumbling block of a hidden
function, can anyone help?
> library(gplots)
> methods(barplot2)
[1] barplot2.default*
Non-visible functions are asterisked
> barplot2
f
On Sep 15, 2009, at 1:09 PM, TsubasaZero wrote:
Hi all,
I had generated 1000 random variates (u,v), and I would like to find
the
corresponding (x,y) for a bivariate pareto distribution. Which
x=inverse
pareto of u and y=inverse pareto of v.
What is the code I should use to find (x,y).
Hello,
I do not know whether my package "colbycol" may help you. It can help
you read files that would not have fitted into memory otherwise.
Internally, as the name indicates, data is read into R in a column by
column fashion.
IO times increase but you need just a fraction of "intermediate memo
Should the help file for identical() say that it mainly
useful for testing code (as part of a QA program)
and it is not recommended for general use? Currently
help(identical) gives, IMO, inappropriate advice:
A call to identical is the way to test exact equality
in if and while statements,
Hi,
Maybe you can put the sqlite database somewhere else in the package, for
example:
inst/sqlite/data.sqlite
and access it like this :
db <- system.file( "sqlite", "data.sqlite", package = "YourPackage" )
Romain
On 09/15/2009 09:07 PM, Steve Lianoglou wrote:
Hi all,
I'm putting togethe
Steve,
I can't speak to your exact question, but perhaps suggest a simple alternative.
What I do is simply make changes to the .R file containing my code, and use
the "source" function to read in the new definitions of my functions while I'm
tweaking them. Then, at the end of the day, I do my
Has there been any progress in enabling R to take advantage of multiple
processors?
Rajiv Garg wrote:
>
> Hi,
>
> We are seeing performance degradation when running the same R script in
> multiple instances of R on a multi-processor system. We are a bit
> surprised by this because we figured
Hi all,
I had generated 1000 random variates (u,v), and I would like to find the
corresponding (x,y) for a bivariate pareto distribution. Which x=inverse
pareto of u and y=inverse pareto of v.
What is the code I should use to find (x,y).
Thanks a lot~~~
Zero~~
--
View this message in context:
Hi all,
I'm putting together some common code + data into a custom package,
everything is working out fine, but the ``R CMD INSTALL MyPackage``
call seems to take a particularly long time in the "**data" step:
$ R CMD INSTALL MyPackage/
* installing to library ‘/Library/Frameworks/R.framewo
On Sep 15, 2009, at 4:58 AM, filip rendel wrote:
Hello! I've generated multiple data frames that I wish to export to
excel using the function write.table. When I do so all the data is
merged into a single column in excel. I Would like the columns of my
data frame in separate columns in ex
On 9/15/2009 10:43 AM, Peng Yu wrote:
Hi,
I tried the command 'where' in browser(). But it does not give me the
current line number (or the content of the current line). Is there a
command for this?
That is not supported in released versions of R, but it's in R-devel
(which will become R 2.10
On Tue, 2009-09-15 at 18:04 +0100, Corrado wrote:
> On Tuesday 15 September 2009 17:28:02 Gavin Simpson wrote:
> > [note you don't give us your x so I'm making this up - This is what
> > Duncan was going on about in an earlier thread, give us something we can
> > just paste into R and it works]
>
It works, great!
Thank you, Phil.
/Stefan
Phil Spector schrieb, Am 15.09.2009 18:28:
Stefan -
Have you tried surrounding the problem names with
backticks (`) instead of quotes (' or ")?
- Phil Spector
Statis
Corrado writes:
> I do not understand what more information! Take any vector of length 1,
for
> example x<-1. Plus all the command that where in my previous email
>
> What is the logic behind
>
> identical(length(x),1)
>
> being false?
identical() returns FALSE because they are not iden
On Sep 15, 2009, at 1:04 PM, Corrado wrote:
On Tuesday 15 September 2009 17:28:02 Gavin Simpson wrote:
[note you don't give us your x so I'm making this up - This is what
Duncan was going on about in an earlier thread, give us something
we can
just paste into R and it works]
Dear Gavin,
On Tue, 15 Sep 2009, Corrado wrote:
On Tuesday 15 September 2009 17:28:02 Gavin Simpson wrote:
[note you don't give us your x so I'm making this up - This is what
Duncan was going on about in an earlier thread, give us something we can
just paste into R and it works]
Dear Gavin,
I do not und
On Tue, 15 Sep 2009, Moumita Das wrote:
Hi All,
There were lot of diffrences in the R and SPSS results for Exploratory
Factor Analysis.why is it so ?I used standard factor analysis functions
like:--
factanal(m, factors=3, rotation="varimax")
princomp(m, cor = FALSE, scores = TRUE, subset = rep(
On Tuesday 15 September 2009 17:28:02 Gavin Simpson wrote:
> [note you don't give us your x so I'm making this up - This is what
> Duncan was going on about in an earlier thread, give us something we can
> just paste into R and it works]
Dear Gavin,
I do not understand what more information! Take
On Tue, 2009-09-15 at 17:28 +0100, Gavin Simpson wrote:
> On Tue, 2009-09-15 at 17:16 +0100, Corrado wrote:
> > Dear R,
>
> Are you really looking for all.equal()?
>
> > isTRUE(all.equal(length(x), 1))
> [1] TRUE
Please ignore that bit of rubbish above, clearly that is not what is
required or w
On Tue, 2009-09-15 at 12:22 -0400, Steve Lianoglou wrote:
> Hi,
> I guess the lesson learned is that:
>
> identical() != ==
Indeed, and ?identical explains some of the motivation behind the
function identical and the examples of said help page include the
problem the OP faced... now where was t
On Tue, 2009-09-15 at 17:16 +0100, Corrado wrote:
> Dear R,
>
> the condition:
>
> identical(length(x),1) returns FALSE
>
> but
>
> print(length(x))
>
> returns 1 and:
>
> is.vector(x) is TRUE.
> is.integer(length(x)) is TRUE
> length(x) ==1 is TRUE
>
> I am puzzled.
The key is noticing t
Dear R friends,
I have developed the function here below attached.
Strangely, when I apply it to a vector it behaves very differently than when I
apply it separately to each value of the vector itself.
Is there any reason why?
Here is the function:
# TODO: Add comment
#
# Author: ct529, 3 Se
Hi,
On Sep 15, 2009, at 12:16 PM, Corrado wrote:
Dear R,
the condition:
identical(length(x),1) returns FALSE
but
print(length(x))
returns 1 and:
is.vector(x) is TRUE.
is.integer(length(x)) is TRUE
length(x) ==1 is TRUE
I am puzzled.
But is.integer(1) is FALSE
and identical(length(x)
Corrado wrote:
Dear R,
the condition:
identical(length(x),1) returns FALSE
but
print(length(x))
returns 1 and:
is.vector(x) is TRUE.
is.integer(length(x)) is TRUE
length(x) ==1 is TRUE
I am puzzled.
Regards
> is.integer(length(x))
[1] TRUE
> is.integer(1)
[1] FALSE
Hence:
> iden
Dear R,
the condition:
identical(length(x),1) returns FALSE
but
print(length(x))
returns 1 and:
is.vector(x) is TRUE.
is.integer(length(x)) is TRUE
length(x) ==1 is TRUE
I am puzzled.
Regards
--
Corrado Topi
Global Climate Change & Biodiversity Indicators
Area 18,Department of Biology
U
On Tue, Sep 15, 2009 at 9:48 AM, ivo welch wrote:
> dear R wizards: here is the strange question for the day. It seems to me
> that nrow() is very slow. Let me explain what I mean:
>
> ds= data.frame( NA, x=rnorm(1) ) ## a sample data set
>
>> system.time( { for (i in 1:1) NA } ) #
On Mon, 2009-09-14 at 23:46 -0700, swertie wrote:
> oh yes of course. It is quite simple. I have two presence/absence matrices
> (one for plants, one for butterflies) and I would like to test if the
> butterfly community similarities is correlated with the plant community
> similarities. The think
On Sep 15, 2009, at 10:48 AM, ivo welch wrote:
dear R wizards: here is the strange question for the day. It seems
to me
that nrow() is very slow. Let me explain what I mean:
ds= data.frame( NA, x=rnorm(1) ) ## a sample data set
system.time( { for (i in 1:1) NA } ) ## doing
Hi,
I run the following commands. 'A' has 3 levels and 'B' has 4 levels.
Should there be totally 3+4 = 7 coefficients (A1, A2, A3, B1, B2, B3,
B4)?
> a=3
> b=4
> n=1000
> A = rep(sapply(1:a,function(x){rep(x,n)}),b)
> B = as.vector(sapply(sapply(1:b, function(x){rep(x,n)}),
> function(x){rep(x,a
For maintaining my R search page at http://finzi.psych.upenn.edu (also
used for RSiteSearch(), I have been extracting only the html help
pages and the vignettes from most packages. (Many will not compile on
Linux. And, more generally, this saves wear and tear on the computer
and me.)
I wrote a v
Hi there,
Question 1:
Anybody out there know if there is a way to retrieve a list/table of ctree
terminal node stats? If I could get a list containing each terminal node,
and distributional stats for the training observations allocated to it
(e.g., mean, standard deviation, range), I would be a
Hi Filip,
Try also:
write.table(object, "yourpath_with_xls_extension",sep="\t", quote = FALSE)
HTH,
Jorge
On Tue, Sep 15, 2009 at 5:58 AM, filip rendel <> wrote:
>
> Hello! I've generated multiple data frames that I wish to export to excel
> using the function write.table. When I do so all the
Hello,
How can I make xtable print a comma as decimal separator? Setting
the option OutDec isn't enough for xtable:
library(xtable)
options(OutDec = ",")
x <- c(1.1, 1.2, 1.3)
y <- c(2.3, 2.2, 2.1)
d <- data.frame(x, y)
d
print(xtable(d))
Thanks!
Jakson Aquino
__
Hi, all,
I am thinking to compare a group of slopes from regression lines to see if
they are different overall, and then make specific comparisons between
groups. How can I achieve that in R? I searched the archives and there are
only discussions about comparing two lines a time. Thanks.
A samp
Hi jorgusch,
First, do not call your data, "data" :-)
require(fortunes)
fortune('dog')
Here are two suggestions to do what you asked for:
# your data
id <- 1:5
idnew <- 3:10
# to get the indexes
id %in% idnew
# to get the id's matching the new vector
id[ id %in% idnew ]
# another way
inters
I use sep="\t" for Excel files and sep="," for csv files.
# Save to Excel
write.table(objectname, file = "C:/Documents
andSettings/Desktop/myfile.xls",sep="\t")
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US Fish & Wildlife Service
California, USA
--- On
On Sep 15, 2009, at 10:36 AM, Robert Baer wrote:
Is there a good search tool, either in R itself or in a public
place, to search for R Journal (R News) articles on a given package
or topic? I found the Table of Contents and the BibTex file, but I
was looking for something a little more fl
have a look at ?"%in%"
Best,
Dimitris
jorgusch wrote:
Hello,
I have a large matrix (data), in which there is a column offerid. The values
are numbers (lets say 1:5)
There is another vector (idnew), which contains some of the offerids and
many more (3:10).
I want a subset of the matrix wiith
Guozhu.Wen wrote:
>
> Hi, I wrote a C extension for R. Within the C code I wanted to invoke the
> R's sort function, with the argument "index.return = TRUE". I found it is
> a
> difficult problem, how can I do that? I have implemented the decreasing
> sorting by the code "PROTECT(R_fcall = lang
Hi All,
There were lot of diffrences in the R and SPSS results for Exploratory
Factor Analysis.why is it so ?I used standard factor analysis functions
like:--
factanal(m, factors=3, rotation="varimax")
princomp(m, cor = FALSE, scores = TRUE, subset = rep(TRUE,
nrow(as.matrix(m
print(summary(pr
Dear R-help,
I am trying to print a graph with an additional legend to a pdf() or
jpeg() file. Unfortunately the legend has completely disappeared in the
file (pdf of jpeg) compared to what is in the graphics device of the Rgui.
I positioned the legend after retrieving the x,y coordinates by th
Dear List,
I have a problem with RODBC on a Paradox-DB, sqlQuery, and special
characters in table names. Unfortunately, some of the latter include the
underscore <_>. And I am not able to change them.
That's not a problem, when I quote the table name:
> sqlQuery(channel2, 'SELECT * FROM "anme
There is a package called 'xlsReadWrite', which has functions like
read.xls & write.xls that might be helpful for you. You can also use
write.table to produce .csv files, but you'll have to use it in the
following manner:
write.table(DataFrame, 'ExcelFile.csv', sep=",", col.names=T,
row.names=F)
dear R wizards: here is the strange question for the day. It seems to me
that nrow() is very slow. Let me explain what I mean:
ds= data.frame( NA, x=rnorm(1) ) ## a sample data set
> system.time( { for (i in 1:1) NA } ) ## doing nothing takes
virtually no time
user system elap
Dear All,
As I am doing a project in java and in that we need to integrate R software for
displaying statistical graph using the different set of data.
I don't have any idea on how to integrate R software in our java project.
Kindly give basic idea about the R software and how to integrate in java
Hi,
I am trying to find in FAQ, in the manual, everywhere, the reason and
most importantly, how to solve:
Error: protect(): protection stack overflow
It appeared after requesting a plot.
Thanks,
--
Inez
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https://s
Hi
I'm trying to interpret the output from the coxph command. One of the outputs
is:
Rsquare= 0.01 (max possible= 0.069 )
Given that the methods for calculating R squared and its validity with
proportional hazards regression are debated in the literature - can anyone tell
me exactly how this
Hello,
I have a large matrix (data), in which there is a column offerid. The values
are numbers (lets say 1:5)
There is another vector (idnew), which contains some of the offerids and
many more (3:10).
I want a subset of the matrix wiith only those rows, which match the
criteria of the vector.
oh yes of course. It is quite simple. I have two presence/absence matrices
(one for plants, one for butterflies) and I would like to test if the
butterfly community similarities is correlated with the plant community
similarities. The think is also that I don't really see the purpose of doing
a PC
Hi,
On Sep 15, 2009, at 8:07 AM, MERAL YAY wrote:
Hello,
does any one know how to interpret this output in R?
Classification with logitboost
fit <- logitboost(xlearn, ylearn, xtest, presel=50, mfinal=20)
summarize(fit, ytest)
Minimal mcr: 0 achieved after 6 boosting step(s)
Fixed mcr:
Hi,
I tried the command 'where' in browser(). But it does not give me the
current line number (or the content of the current line). Is there a
command for this?
Regards,
Peng
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Is there a good search tool, either in R itself or in a public place, to search
for R Journal (R News) articles on a given package or topic? I found the Table
of Contents and the BibTex file, but I was looking for something a little more
flexible. These lists are getting impressively long afte
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