Dear Steven,
Thanks for your post. It explains a lot.
The reason I wanted to use multiple sessions simultaneously is that
because when I run something it usually takes quite a while (calculating
distance matrices), meaning that I have to wait before R can handle the
next task. Also RAM is reaching
Try this,
source("http://gridextra.googlecode.com/svn/trunk/inst/test/expressions.r";)
library(grid)
e = expression(p[Wilcoxon], "<"*2.2%*%10^{-16})
grid.expr(e)
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
> Hi Baptiste,
>
> This is, I fear a bit beyond my level of com
Hi Arnaud,
It is slightly confusing what you are asking but if you just want a
dataframe with the two zz$"PL" and av$"PL" columns concatenated then
merge is not what you are after.
Try something like this.
t <- rbind(data.frame(PL=zz$PL), data.frame(PL=av$PL))
> t
PL
1 307
You might also find match and pmatch of use here.
On Aug 3, 2010, at 12:05 AM, Daniel Malter wrote:
>
> Hi, I have a good grasp of grep() and gsub() for finding and
> extracting
> character strings. However, I cannot figure out how to use a search
> term
> that is stored in a
Olga
There was a presentation at the London R user group about doing what you
ask using the bigmemory package
(http://www.londonr.org/LondonR-20090331/realtimeR.pdf). I believe you
can do the same thing with ff. This wouldn't share the whole workspace
but just the objects you choose.
Regards
On Wed, Aug 4, 2010 at 8:43 AM, allany wrote:
>
> Hi guys,
>
> I have a large text file with a bunch of Time in "HH:MM" format, what would
> be the best way to process it into a Time Object so that I can use
> comparisons like (1:00<"1:15") or (13:00>"2:00") to both return true.
>
> Right now if I
Hi guys,
I have a large text file with a bunch of Time in "HH:MM" format, what would
be the best way to process it into a Time Object so that I can use
comparisons like (1:00<"1:15") or (13:00>"2:00") to both return true.
Right now if I do a comparison like (3:00 < "1:59") I get a true, but if I
On 04/08/2010 7:47 AM, Liviu Andronic wrote:
Dear all
Is there an easier way to retrieve the name of an object? For example,
> tmp <- 1:10
> as.character(quote(tmp))
[1] "tmp"
> as.character(quote(mtcars$cyl))
[1] "$" "mtcars" "cyl"
> as.character(quote(mtcars$cyl))[3]
[1] "cyl"
The l
?jpeg
On 04-Aug-10 14:28, linda.s wrote:
Can I make a group of jpeg instead of pdfs?
Thanks.
Linda
On Wed, Aug 4, 2010 at 6:47 AM, John Kane wrote:
Yes, ?jpeg
--- On Tue, 8/3/10, linda.s wrote:
From: linda.s
Subject: Re: [R] save plot
To: gavin.simp...@ucl.ac.uk
Cc: r-help@r-project.org
On 08/04/2010 05:38 PM, Roslina Zakaria wrote:
Hi all,
I would like to draw a side by side bar plot. How can I adjust the the font
size for the x-axis? Furthermore, I'm not sure what to write for 'at=?'. I
tried cex.axis and cex.lab but still fail. Here is my data and code:
t(all)
Can I make a group of jpeg instead of pdfs?
Thanks.
Linda
On Wed, Aug 4, 2010 at 6:47 AM, John Kane wrote:
> Yes, ?jpeg
>
> --- On Tue, 8/3/10, linda.s wrote:
>
>> From: linda.s
>> Subject: Re: [R] save plot
>> To: gavin.simp...@ucl.ac.uk
>> Cc: r-help@r-project.org
>> Received: Tuesday, Augus
On Aug 4, 2010, at 7:52 AM, Dieter Vanderelst wrote:
Dear List,
(self-contained example + version info at the bottom)
I'm having trouble producing a barplot using the functions in
ggplot2. When I use the position="dodge" option, the bars are
plotted but also a number of spurious markers.
Try this:
library(RDCOMClient)
## Criando a conexao com o SAP
oLogonControl <- COMCreate("SAP.Logoncontrol.1")
## Conectando com o usuario ao SAP
g_connection <- oLogonControl$NewConnection()
g_connection[["System"]]<- "PD4"
g_connection[["ApplicationServer"]] <- "server_ip"
g_connec
Tryu this:
deparse(substitute(mtcars))
On Wed, Aug 4, 2010 at 8:47 AM, Liviu Andronic wrote:
> Dear all
> Is there an easier way to retrieve the name of an object? For example,
> > tmp <- 1:10
> > as.character(quote(tmp))
> [1] "tmp"
> > as.character(quote(mtcars$cyl))
> [1] "$" "mtcars" "c
I am not sure what you mean by a "hack"? Can you elaborate further,
give details on the problem you are trying to solve.
Does this work as a "lesser hack":
> tail(as.character(quote(mtcars$cyl)),1)
[1] "cyl"
> tail(as.character(quote(cyl)),1)
[1] "cyl"
>
On Wed, Aug 4, 2010 at 7:47 AM, Liviu A
Dear List,
(self-contained example + version info at the bottom)
I'm having trouble producing a barplot using the functions in ggplot2. When I
use the position="dodge" option, the bars are plotted but also a number of
spurious markers. More specifically, a number of black dots are plotted in t
Dear all
Is there an easier way to retrieve the name of an object? For example,
> tmp <- 1:10
> as.character(quote(tmp))
[1] "tmp"
> as.character(quote(mtcars$cyl))
[1] "$" "mtcars" "cyl"
> as.character(quote(mtcars$cyl))[3]
[1] "cyl"
The last call more than anything seems a hack. Is ther
On Aug 3, 2010, at 7:59 PM, Johann Hibschman wrote:
> Duncan Murdoch writes:
>> On 29/07/2010 6:18 PM, chipmaney wrote:
>>>
>>> -Why does R recognize '[' as a function?
>>
>> Because it is a function.
>
> More explicitly, '[' is a string. sapply then calls match.fun to look
> up that strin
On Aug 4, 2010, at 7:04 AM, Megh Dal wrote:
Hi, I want to split a text to seperate numerical and non-numerical
portions of that. For example suppose I have a text "abc 3456" and I
want to split in 2 parts like "abc" & "3456".
Is there any function to do that?
?strsplit
?regex
--
David W
On Wed, Aug 4, 2010 at 7:04 AM, Megh Dal wrote:
> Hi, I want to split a text to seperate numerical and non-numerical portions
> of that. For example suppose I have a text "abc 3456" and I want to split in
> 2 parts like "abc" & "3456".
>
> Is there any function to do that?
>
If the parts of you
TY Petr, it works. I will then replace NA by 0.
2010/8/4 Petr PIKAL :
> Hi
>
> you tried OK
>
> result <- merge(zz, av, by="DESCRIPTION", all=TRUE)
>
> and as you did not specify what to do when one value is NA here is one
> possible solution
>
> rowSums(cbind(result$PL.x, result$PL.y), na.rm=T)
On 04/08/2010 5:38 AM, Sander wrote:
L.S.
I am trying to get data from an excel sheet using the RODBC library, quite
like the example on page 34 of the 'Data manipulation with R' book written
by Phil Spector. It seems very straightforward, yet I get the same error
everytime I try it, with differ
Hi, I want to split a text to seperate numerical and non-numerical portions of
that. For example suppose I have a text "abc 3456" and I want to split in 2
parts like "abc" & "3456".
Is there any function to do that?
Thanks,
__
R-help@r-project.org ma
L.S.
I am trying to get data from an excel sheet using the RODBC library, quite
like the example on page 34 of the 'Data manipulation with R' book written
by Phil Spector. It seems very straightforward, yet I get the same error
everytime I try it, with different excel sheets and trying to tweek t
Hi,
I am trying to plot several time series plots with R, but I can't seem to get
the x-axis properly formatted. What I am doing at the moment is:
dates <- seq(as.Date("2007/06/10", "%Y/%m/%d"),
as.Date("2010/03/28", "%Y/%m/%d"), 7)
par(mfrow=c(5,2))
plot(DateJonEnd1, End1Jon, main="Weekly Tr
Yes, ?jpeg
--- On Tue, 8/3/10, linda.s wrote:
> From: linda.s
> Subject: Re: [R] save plot
> To: gavin.simp...@ucl.ac.uk
> Cc: r-help@r-project.org
> Received: Tuesday, August 3, 2010, 5:36 PM
> > [I presume you addressed this to
> Duncan Murdoch for a good reason???]
> >
> > Open a new device
Hi,
a <- c("ID=NM_182905.1;Name=NM_182905;Alias=FLJ00038;Note=hypothetical
protein
+ LOC375690
+ ","ID=NM_001005484;Alias=OR4F5;Note=olfactory receptor%2C family 4%2C
+ subfamily F
+ ","ID=NM_001005224.1;Name=NM_001005224;Alias=OR4F3;Note=olfactory
+ receptor%2C family 4%2C subfamily F
+ ")
f
Hi
Is there any way to find out at what points two timeseries cross over
perhaps with some information on how they cross?
Alternatively, I could write a loop that solves pairs of adjacent points
using linear algebra but looking for a simpler way.
Thanks in advance,
Blair
[[alternative H
Questions about geoR should be directed to R-SIG-GEO.
Anyway, you should provide more info about your problem.
Read the Posting Guide.
Have you tried changing the model? Sometimes falling back from Matern to
exponential or Gaussian allows successful convergence.
HTH
Rubén
Godfrey van der Linden wrote:
G'day, All.
I've recently started writing up my dissertation and need to consider how to
store the research results. I'd like to use the binary compressed save() format
as it is considerably smaller than the raw data. However, will a future R be
able to read it
On Wed, Aug 4, 2010 at 6:00 AM, LogLord wrote:
>
> Hi,
>
> I have a dataframe with a rather complicated descriptive column (V9):
>
>> test3[(1:3), ]
> V1 V4 V5
> 10 1 4559 7173
> 17 1 58954 59871
> 19 1 357522 358458
>
> V9
> 10 ID=NM_182905.1;Name=NM_182905;Alias=FLJ00038;Note=h
I'm dealing with count data that's nested and has spatial dependence.
I ran a glmm in lmer with a random factor for nestedness. Spatial dependence
seems to have been accommodated by model. However I can't add a variance
strcuture to this model (to accommodate heterogeneity).
Is there a model that
On Wed, Aug 4, 2010 at 12:29 AM, Suphajak Ngamlak
wrote:
> Dear all,
>
> I would like to do sample statistics, e.g. mean, median from very large
> dataset. This is part of commands I use routinely with several dataset
> so I would like to make it into function. The simplified examples are
>
> Test
Hi
you tried OK
result <- merge(zz, av, by="DESCRIPTION", all=TRUE)
and as you did not specify what to do when one value is NA here is one
possible solution
rowSums(cbind(result$PL.x, result$PL.y), na.rm=T)
Regards
Petr
r-help-boun...@r-project.org napsal dne 04.08.2010 11:52:00:
> Dear li
Hi,
I have a dataframe with a rather complicated descriptive column (V9):
> test3[(1:3), ]
V1 V4 V5
10 1 4559 7173
17 1 58954 59871
19 1 357522 358458
V9
10 ID=NM_182905.1;Name=NM_182905;Alias=FLJ00038;Note=hypothetical protein
LOC375690
17 ID=NM_001005484;Alias=OR4F5;Note=ol
Dear list,
here are my two data frames:
av <-
structure(list(DESCRIPTION = c("COFFEE C Sep/10", "COPPER Sep/10",
"CORN Dec/10", "CRUDE OIL miNY Sep/10", "GOLD Aug/10", "HENRY HUB
NATURAL GAS Sep/10",
"PALLADIUM Sep/10", "SILVER Sep/10", "SOYBEANS Nov/10", "SPCL HIGH
GRADE ZINC USD",
"SUGAR NO.11
So you *can* do it. There is a question
remaining of whether you *should* do it.
More R-ish is to use a list.
On 04/08/2010 01:39, jim holtman wrote:
?paste
?assign
On Tue, Aug 3, 2010 at 8:29 PM, Hey Sky wrote:
hey, Rers
in Stata therer is a loop command ` ' which could do the following:
Hi list,
As title, under windows, the method of ~/.inputrc won't work, is it
possible to let Rterm be vi style on windows?
P.S. I've sent it serveral days ago, get no response, so I send it again
to check if I've failed to send it.
--
Regards,
Yue Wu
Key Laboratory of Modern Chinese Medi
Hi
> I made some design matrix X(in linear regression model)
>
> I there any method to normalize X?
You can normalize a matrix column-wise like this:
# m is a matrix
apply(m, 2, function(x) x / max(x) )
Or normalize row-wise like this:
t(apply(m, 1, function(x) x / max(x) ))
I'm sure there are
Hi
I'm using geoR package to perform linear spatial interpolation(OK).
The function likfit() fails to compute REML.
The error meassage is : Error in solve.default(v$varcov, xmat);
How I can find out that likfit() is failed to process and retrieving the error
message ?
Thank you so much for
Hi!
Your example is not really easy to copy paste. Next time, try using
dput(), this would help a lot.
I haven't tried, but I think that cex.axis is correct. The problem is in
your call to barplot(). You have to specify xaxt="n" so that the x-axis
won't be plotted. You then plot it with your
Sometimes we try to make things behave the way we think they ought to and find
it surprisingly difficult. Later we discover that our original premise was
flawed and we wasted our time trying to force fit our ideas to work.
Since all of the i-th elements of the columns of a data table are suppose
I made some design matrix X(in linear regression model)
I there any method to normalize X?
--
View this message in context:
http://r.789695.n4.nabble.com/question-tp2312938p2312938.html
Sent from the R help mailing list archive at Nabble.com.
__
R-he
Hi all,
I would like to draw a side by side bar plot. How can I adjust the the font
size for the x-axis? Furthermore, I'm not sure what to write for 'at=?'. I
tried cex.axis and cex.lab but still fail. Here is my data and code:
> t(all)
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