On Thu, Mar 08, 2012 at 09:49:20PM -0800, Ghandalf wrote:
Hi,
I am currently attempting to write a small program for a randomization test
(based on rank/combination) for matched pairs. If you will please allow me
to introduce you to some background information regarding the test prior to
my
On Mar 11, 2012, at 03:17 , R. Michael Weylandt wrote:
In general, I *think* this is a hard problem (it sounds knapsack-ish)
but since you are on small enough data sets, that's probably not so
important: if I understand you right, this little function will help
you.
plusminus -
On 03/10/2012 11:37 AM, Michael wrote:
Hi all,
I am trying hard to do the following and have already spent a few hours in
vain:
I wanted to do the scatter plot.
But given the high dispersion on those dots, I would like to bin the x-axis
and then for each bin of the x-axis, plot the quantiles
Dear all
I was wondering, if there are reasons for R-Users to use (commercial) solver
packages like GAMS, AMPL, Matlab, etc.
These packages can solve all kind of mathematical optimization problems like
(non-) linear problems, mixed complementarity problems, etc.
Why I want to know? GAMS
Dear list,
I understand that to raise matrix A to power (-1/2) we should use something
like this:
eigen(A)$vectors%*%diag(1/sqrt(eigen(A)$values))%*%t(eigen(A)$vectors)
[from previous discussions:
http://r.789695.n4.nabble.com/matrix-power-td900335.html]
But this will only do it for negative
You missed a lot of indications, most prominently the task view
http://cran.r-project.org/web/views/Optimization.html
On 11/03/2012 07:18, Renger van Nieuwkoop wrote:
Dear all
I was wondering, if there are reasons for R-Users to use (commercial) solver
packages like GAMS, AMPL, Matlab, etc.
Hi Manuel,
I've taken the liberty of adding the r-help list back to this email, even though
you sent your reply just to me, so that others may contribute.
On Fri, Mar 9, 2012 at 6:27 PM, Manuel Spínola mspinol...@gmail.com wrote:
Thank you Sarah,
I am thinking more on habitat mapping and
On Sat, Mar 10, 2012 at 04:01:21PM -0800, casperyc wrote:
Sorry if I wasn't stating what I really wanted or it was a bit confusing.
Basically, there are MANY datasets to run suing the same function
I have written a function to analyze it and returns a LIST of useful out put
in the variable
Many thanks for your answer. I am using someone else's code that has
worked fine for some time and don't know much about R graphics.
Windows are being opened, the clutter is definitely there, and it
looks like dev.off is not being used. So at least it probably is not a
stupid attack on my part. So
On Sun, Mar 11, 2012 at 1:46 AM, Ebrahim Jahanshiri
e.jahansh...@gmail.com wrote:
Dear list,
I understand that to raise matrix A to power (-1/2) we should use something
like this:
eigen(A)$vectors%*%diag(1/sqrt(eigen(A)$values))%*%t(eigen(A)$vectors)
[from previous discussions:
On Sun, Mar 11, 2012 at 8:56 AM, Peter Langfelder
peter.langfel...@gmail.com wrote:
On Sun, Mar 11, 2012 at 1:46 AM, Ebrahim Jahanshiri
e.jahansh...@gmail.com wrote:
Dear list,
I understand that to raise matrix A to power (-1/2) we should use something
like this:
Hi,
I have a long list of lists from which I want to efficiently extract
and rbind elements. So I'm using the approach below:
f - function(i){
out - replicate(5, list(matrix(rnorm(80), nc=20)))
names(out) - letters[1:5]
out
}
set.seed(1)
lst - lapply(1:1.5e6, f)
(t0 -
Thank you very much Peter,
Indeed this should be left to the reader/practitioner. But I think -at
least for the sake of comparison with matlab- we could have it in the core
R. I would definitely try to learn more about R and implement it later.
Cheers,
Ebrahim
On Sun, Mar 11, 2012 at 11:56 PM,
If my memory is correct, the archives of this list contains
several discussions of round off error problems associated with
different methods for computing things like this. The Matrix package
(part of the base distribution) contains a function expm, whose help
file says, The expm
On 11-03-2012, at 17:52, Spencer Graves wrote:
If my memory is correct, the archives of this list contains several
discussions of round off error problems associated with different methods for
computing things like this. The Matrix package (part of the base
distribution) contains a
On 11-03-2012, at 18:18, Berend Hasselman wrote:
On 11-03-2012, at 17:52, Spencer Graves wrote:
If my memory is correct, the archives of this list contains several
discussions of round off error problems associated with different methods
for computing things like this. The Matrix
Thank you everyone for your reply.
Like I said in my original post, this is just a demonstrative example of my
'big' self written script.
My 'big' function take several inputs, of which the first 1 is the dataset
and returns a LIST variable 'res-list()' to the workspace with many
information.
On Sun, Mar 11, 2012 at 9:18 AM, Benilton Carvalho
beniltoncarva...@gmail.com wrote:
Hi,
I have a long list of lists from which I want to efficiently extract
and rbind elements. So I'm using the approach below:
f - function(i){
out - replicate(5, list(matrix(rnorm(80), nc=20)))
Thanks Henrik!!! Hope to pay your beer soon. :) b
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
On 08.03.2012 21:03, Mark Seeto wrote:
Dear R-help,
I recently upgraded from R 2.13.1 to R 2.14.2 and now get warning
messages when plotting after using x11(). Example:
plot(rnorm(10))### no warnings
x11(); plot(rnorm(10))
Warning messages:
1: In axis(side = side, at = at, labels =
Dear R community,
I have the following problem I hoped you could help me with.
My data is save in thousand of files with a weird extension containing for
numbers and a z. For example *.1405z. With list.files I managed to load this
data into R. It looks like this (the row numbers are not in the
Can you at least provide a subset of 2 files so we can see how the
data is really stored in the file and what the separators are between
the 'columns' of data. Also how do you determine where the data
actually starts for the rows that you want to pull off. This will aid
in determining how to
Hi Frauke,
Try unix commands with R's system() function.
Example:
Let's say you have a matrix like this in the file (note: the first element
is missing) called hello.txt
10 100
2 20 200
3 30 300
4 40 400
5 50 500
You can try something like:
hello = system(cut -f1 hello.txt, intern=T)
VP.
On
Hello
I have recently installed R 2.14.2 on a brand new pc running Windows 64.
One of things I would like to do is to recompile my R package (with C and
fortran source codes) for this new environment (it works on a mac and on a
linux box). To this end, I had rtools 2.14 downloaded and installed
On 11/03/2012 19:43, Eduardo Mendes wrote:
Hello
I have recently installed R 2.14.2 on a brand new pc running Windows 64.
One of things I would like to do is to recompile my R package (with C and
fortran source codes) for this new environment (it works on a mac and on a
linux box). To this
Thank you for the quick reply! I have attached two files.
http://r.789695.n4.nabble.com/file/n4464511/sample1.1339z sample1.1339z
http://r.789695.n4.nabble.com/file/n4464511/sample2.1949z sample2.1949z
--
View this message in context:
Dear Prof. Ripley
Many thanks. rtools 2.15 did the job.
One note if I may - In the rtools site one reads
rtools215.exe - r2.14.1 to R 2.15.x No
rtoosl214.exe - r 2.13.x or R.2.14.x yes
which can mislead the reader. 2.14.x could mean 2.14.2 and no could mean
that rtools-2.15 is not read for
Update:
The siegel Tukey code is now fixed (both on the github page, and the blog's
post):
https://github.com/talgalili/R-code-snippets/blob/master/siegel.tukey.r
http://www.r-statistics.com/2010/02/siegel-tukey-a-non-parametric-test-for-equality-in-variability-r-code/
Best,
Tal
On Sat, Mar
Here is one way assuming the data start after QPF FORECAST:
setwd('/temp') # where the data is
files - c('sample1.htm', 'sample2.htm') # files to read
# assumes 4 columns of data
fields - list(c(19, 24), c(30, 35), c(41, 46), c(52, 57)) #columns of data
results - lapply(files,
CRAN (and crantastic) updates this week
New packages
* EffectStars (1.0)
Maintainer: Unknown
Author(s): Gunther Schauberger
License: GPL-2
http://crantastic.org/packages/EffectStars
The package provides functions to visualize regression models with
categorical response.
Hello Bert,
Thanks so much for these suggestions. They led me to the package
LPCM, which I found worked best with minimum tuning.
lpc1 = lpc(cbind(X,Y), scaled=TRUE, h=c(0.05,0.05))
plot(lpc1)
... et voila!
All the best,
Emmanuel
On 11 March 2012 00:37, Bert Gunter gunter.ber...@gene.com
Could you please show me an example for my two cases?
Thanks a lot!
On Sun, Mar 11, 2012 at 3:55 AM, Jim Lemon j...@bitwrit.com.au wrote:
On 03/10/2012 11:37 AM, Michael wrote:
Hi all,
I am trying hard to do the following and have already spent a few hours in
vain:
I wanted to do the
Wow Jim, this is much more than I expected. Thank you!!
It took me a while to figure out what exactly you are doing in that code.
But I think I understand and it definitely runs. May I ask you two follow up
questions?
First, some of my files have data from two or more cities in them. So I have
Hello,
Ive fitted a Garch(2,1) model with function 'garchFit()' from the package
'fGarch':
m1 - garchFit(formula = ~garch(2,1),data = X,trace = F)
* See 'summary(m1)' OUTPUT BELOW *
PROBLEM: My alpha1 term is not significant and I would like to make a NEW
model, say m2, that does not contain
Hi Michael,
I am trying the solution you've suggested below:
DAT - data.frame(x = runif(1000, 0, 20), y = rnorm(1000))
DAT$xbin - with(DAT, cut(x, seq(0, 20, 2)))
p - ggplot(DAT, aes(x = x, y = y)) + geom_point(alpha = 0.2) +
stat_quantile(aes(colour = ..quantile..), quantiles = seq(0.05, 0.95,
And also, no matter how I changed the quantiles = seq(0.05, 0.95,
by=0.05)) line,
the number of lines in each bin and the number of legends on the right side
of the each plot are different...
What's the catch? Am I missing something here?
I thought the number of quantile lines and the number of
Hi,
I am trying to normalize some data. First I fitted a principal curve
(using the LCPM package), but now I would like to apply a
transformation so that the curve becomes a straight diagonal line on
the plot. The data used to fit the curve would then be normalized by
applying the same
Using R-studio, I am trying to run a structural equation model and I am
running into problems with testing my primary model. Once I specify
everything and try to run it I get this error:
Error in eigen(S, symmetric = TRUE, only.values = TRUE) : 0 x 0 matrix
And when I look at the object for my
Aren't you just reinventing the inverse of a function?
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Hello HelpeRs,
The last print statement in the code segment below results in :
Error in data$x[data$x == -Inf] - range$x.range[1] :
replacement has length zero
R version 2.14.1 Patched (2011-12-23 r57982)
ggplot2: version 0.90
OS : Linux (64bit)
Any thoughts?
Many Thanks,
A.
##
Dear expert
How can we plot diagonal across (from bottom-left-hand corner to top
right-hand corner),
at any given coordinate range
For example
plot(c(-2,3), c(-1,5), type = n, xlab=x, ylab=y, asp = 1)
or
plot(c(0,1000), c(0,334), type = n, xlab=x, ylab=y, asp = 1)
I tried abline with the
Your requirement that the line go from bottom-left to top-right regardless of
the coordinates is inconsistent with a slope of 1. Are you sure that is your
requirement?
---
Jeff NewmillerThe .
Hi G.V.
Does it fit to your request?
plot(c(-2,3), c(-1,5), type = n, xlab=x, ylab=y, asp = 1)
dg - par(usr)
segments(dg[1],dg[3],dg[2],dg[4], col='red')
Regards,
Pascal
- Mail original -
De : Gundala Viswanath gunda...@gmail.com
À : r-h...@stat.math.ethz.ch
Cc :
Envoyé le : Lundi
43 matches
Mail list logo
